I need someone to explain this to me, I am confuse when it comes to this worksheet

There will be no reaction force acting on the object

Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

The motion of a free falling object can be described by Newton's second law of motion,

Force (F) = mass * acceleration

a = F / m

The net external force is just the weight of the object (F = W).

Substituting into the second law equation gives:

a = W / m = m * g / m = g .

The acceleration (change of velocity) of the object then becomes the gravitational acceleration.

On freely falling body their is no normal acting on that object

hence , there will be no reaction force acting on the object

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Answer:

Fe

Explanation:

Dựa vào dãy hoạt động hóa học của kim loại

The forces listed are considered fundamental forces (2) gravitational (4) strong nuclear (6) electroweak.

Fundamental force, also called fundamental interaction, in physics, is any of the four primary forces—gravitational, electromagnetic, sturdy, and weak—that govern how gadgets or particles interact and how certain particles decay. All of the regarded forces of nature may be traced to those essential forces.

Now, physicists say they have discovered viable symptoms of a fifth essential force of nature. The findings come from studies performed at a laboratory near Chicago. The four fundamental forces govern how all of the objects and particles inside the Universe engage with each other.

The strong nuclear pressure pulled definitely and negatively charged quarks collectively to form undoubtedly charged protons and neutrally charged neutrons. The strong nuclear force also binds protons and neutrons within the nucleus of atoms. The weak nuclear force enabled complicated atoms to form through nuclear fusion.

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The value of the coefficient  is μ=0.18.

Find the value of this coefficient.​

The particles are in equilibrium, meaning the net force on them is zero.

Thus, repulsion due to their charge = friction due to the table.

As the equilibrium is limiting, friction reaches its maximum value.

[tex]\frac{kQ^{2} }{r^{2} }[/tex]=μmg

[tex]k=9*10^{9} Nm^{2} C^{-2}[/tex]The electrostatic constant [tex]Q=10^{-7} C[/tex]  is the charge, and r=0.1m is the distance between the charges.

[tex]\frac{(9*10^{2})(10^{-7})^{2} }{(0.1)^{2} }[/tex]=μ*[tex](5*10^{-3})(10)[/tex]

Therefore, The answer is μ=0.18.

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Answer:

The requried number of outer-orbital electrons in an atom of Na is 1, P is 5, Br is 7, I is 7, Te is 6, and Sr is 2.

An orbital is a region of space around the nucleus of an atom where there is a high probability of finding an electron. The electrons in an atom are arranged in specific energy levels or shells, and each shell contains one or more subshells, which in turn contain one or more orbitals.

Here,
To determine the number of outer-orbital electrons in an atom, we need to look at the position of the element in the periodic table. The number of outer-orbital electrons is equal to the group number of the element for groups 1, 2, and 13 to 18. For groups 3 to 12, we need to subtract the group number from 10.

a) Na is in group 1, so it has 1 outer-orbital electron.

b) P is in group 15, so it has 5 outer-orbital electrons.

c) Br is in group 17, so it has 7 outer-orbital electrons.

d) I is in group 17, so it has 7 outer-orbital electrons.

e) Te is in group 16, so it has 6 outer-orbital electrons.

f) Sr is in group 2, so it has 2 outer-orbital electrons.

Therefore, the number of outer-orbital electrons in an atom of Na is 1, P is 5, Br is 7, I is 7, Te is 6, and Sr is 2.

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The SI unit of current is the ampere, which is defined as the flow of charge in units of coulomb over a period of time measured in seconds.

Electrical charge carriers, often electrons or atoms deficient in electrons, travel as current. The capital letter I is a typical way to represent the current. The ampere, denoted by the letter A, is the common unit. An ampere is a unit of measure of the rate of electron flow or current in an electrical conductor. One coulomb of electrical charge (6.24 x 1018 charge carriers) traveling by a given place in one second is represented by one ampere of current.

Conventional current, also known as Franklin current, is thought by physicists to flow from relatively positive points to comparatively negative locations. The most prevalent charge carriers, electrons, are negatively charged. From somewhat negative to relatively good points, they move.

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The rarest type of stars is those that are more than 50 solar masses.

How are stars categorized?

Stars are categorized on the basis of mass, spectral behavior, and temperature.

There are 7 spectral types of stars:

Thus, the rarest type of stars are the O-type stars that have more than 50 times the solar mass of the sun.

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If the strength of a magnetic field at B is three units the strength of the magnetic field at A, means that point B has three times more turns as compared to point A.

We can increase the strength of the magnetic field by increasing the number of turns which increases the strength of the current flow.

So we can conclude that point B has three times more turns as compared to point A.

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The new moment of inertia of the gymnast is 9kgm^2.

To find the answer, we need to know about the conservation of angular momentum.

                      I₁×w₁= I₂×w₂

                      I₂= I₁×w₁/w₂

                         = (6×12)/8

                         = 9kgm^2

Thus, we can conclude that the new moment of inertia of the gymnast is 9kgm^2.

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The new magnitude of the force of attraction will be 6 times the original force of attraction

F = Gm₁m₂ / r²

F₁ = Gm₁m₂ / r²

F = Gm₁m₂ / r²

F₂ = G × 2m₁ × 3m₂ / r²

F₂ = 6Gm₁m₂ / r²

But

F₁ = Gm₁m₂ / r²

Therefore

F₂ = 6Gm₁m₂ / r²

F₂ = 6F₁

Thus, the new magnitude of the force of attraction will be 6 times the original force of attraction

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The magnitude of the average friction force on the box is 400 N

What is energy conservation?

It is the principle by which the total energy remains constant in a system that is not subject to external influence.

It states that energy can neither be created nor be destroyed, It may be transformed from one form to another.

Here,

length of the plane, d = 4 m

height of the plane, h = 2 m

work done total, w = 3200 J

kinetic energy on top, KE = 0

Potential energy on top,

PE = weight x height

PE = 800 *2

PE = 1600 J

Now,

Total work done = KE + PE + W (friction)

W (friction) = 3200 - 1600

W (friction)  = 1600 J

W (friction) = F (friction) x d

F (friction) = 1600 / 4

F (friction) = 400 N

Hence,

The magnitude of the average friction force on the box is 400 N

option A is correct

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Hydrogen, the element that is by far the most prevalent in the universe, exhibits radio emissions with a wavelength of 21 centimetres.

This makes it practical for using radio waves to explore space objects. An object in space emits radio waves that are more noticeable the more hydrogen it has.

The majority of a disk-shaped galaxy's mass is located on the galactic plane. The galactic poles are shown by directions that are perpendicular to the galactic plane.

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The distance traveled by the sprinter in meters is determined as 1.88 m.

The acceleration of the sprinter is the rate of change of velocity of the sprinter with time.

The acceleration of the sprinter is calculated as follows;

Apply Newton's second law of motion as follows;

F = ma

a = F/m

where;

a = 693 N / 64 kg

a = 10.83 m/s²

The distance traveled by the sprinter is calculated as follows;

s = ut + ¹/₂at²

where;

s = ¹/₂at²

where;

s = (0.5)(10.83)(0.59²)

s = 1.88 m

Thus, the distance traveled by the sprinter in meters is determined as 1.88 m.

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Galaxy X contains more total mass within 25,000 light-years of its center than Galaxy Y.

A light-year, a significant unit of length used to express astronomical distances, is roughly 9.46 trillion kilometers, or 5.88 trillion miles. A light-year is the distance that light travels in a vacuum in one Julian year, according to the International Astronomical Union. The name "light-year" is occasionally misunderstood as a unit of time since it contains the time measurement word "year". When expressing distances to stars and other distances on a galactic scale, the light-year is most frequently employed, especially in non-specialized situations and popular science publications. The parsec, which comes from astrometry and is the distance at which one astronomical unit subtends an angle of one second of arc, is the unit that is most frequently used in professional astronomy.

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Hudson Bay is the  restricted basin that has the coolest temperatures

Hudson Bay is a restricted basin which  remains frozen or is dominated by ice over the summer solstice and through- out much of the high-sun season. This basin experiences a harsh continental climate.

The average annual temperature in almost the entire bay is around 0 °C (32 °F) or below. In the extreme northeast, winter temperatures average as low as −29 °C or −20.2 °F. The region of this basin has very low year-round average temperatures.

This basin starts freezing up by early November, and the northern part of the basin is typically entirely iced over by the end of the month.

correct answer is Hudson bay

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The electric field due to the nucleus at the location of the electron is 4.101 × 10¹² N/C.

Given:

Distance between the electron and nucleus, r = 26.5 × 10⁻¹² m

Charge on an electron, Q = 1.6 × 10⁻¹⁹ C

Calculation:

We know that the Helium atom (He²⁺) has an atomic number Z = 2  and an atomic mass number A = 2 ( 2 protons + 2 neutrons). Thus the charge of a helium atom can be calculated as:

Q' = +2e = 2(+1.6 × 10⁻¹⁹ C) = 3.2 × 10⁻¹⁹ C

We know that the electric field on charge Q due to the nucleus is given as:

E = kQ' / r²

where E is the electric field

           k is Coulomb's force constant

           Q' is a  charge ona  Helium atom

           r is the separation distance between the electron and nucleus

Applying values in the above equation we get:

E = (9×10⁹ Nm²/C²) (3.2 × 10⁻¹⁹ C) / (26.5 × 10⁻¹² m)²

  = 4.101 × 10¹² N/C

Thus, the electric field on electrons due to the Helium nucleus is of magnitude 4.101 × 10¹² N/C.

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V = 0.9375 m3 is minimum volume .

Given,

            1000 kg/m3 = density of water

             920 kg/m3 = density of ice

BF = Woman Weight + Slab Weight

Pvg = 75 + Pvg

V = 75 kg / (1000 - 920)

V = 75 / 80

V = 0.9375 m3

Therefore, V = 0.9375 m3 is minimum volume .

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Sport-type motorcycles typically feature a higher than average power-to-weight ratio.

What is scrambler motorcycle?

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A firm current ratio is 1. 0 and its quick ratio is 1. 0. If current liabilities are 12300 then its inventories will be 12300

Inventory is the accounting of items, component parts and raw materials that a company either uses in production or sells

The quick and current ratios are liquidity ratios that help investors and analysts gauge a company's ability to meet its short-term obligations. The current ratio divides current assets by current liabilities. The quick ratio only considers highly-liquid assets or cash equivalents as part of current assets.

current ratio = current assets / current liabilities

current assets = current ratio  * current liabilities

                        = 1 * 12300 = 12300

since , inventory is a current asset for accounting purpose , hence inventories will be 12300

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The area of Piston A is 13.88 in^2

What is a hydraulic system?

The hydraulic system functions by using pressurized fluid.  The power of liquid fuel in hydraulics is significant and as a result, they are commonly used in heavy equipment.

Hydraulic system simply means a mechanical function that operates through the force of liquid pressure.

Here

A hydraulic system contains 3 pistons.

Pressure, P = 1440 psi

for piston A:

Area, A= 0.625 in^2

Force, F = 20,000 lb

We know that,

Force = Pressure x Area

F = P x A

Area ( piston A) = F / P

A = 20,000 / 1440

A = 13.88 in^2

Hence,

The area of Piston A is 13.88 in^2

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Gate-control theory

According to the Gate Control Theory of Pain, the spinal cord has a system that allows pain signals to be amplified in the brain before being processed at the spinal cord itself, or attenuated there. 

The mechanism that allows or prevents the passage of pain signals is known as the gate. The gate may be open or it may be closed, one of two possibilities: 

The administration of a non-noxious (soothing or light rubbing) stimulus can help engage the gate control mechanism and alleviate pain in those who are exposed to painful (noxious) stimuli.

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Option b) Stomach is most likely to have the most muscles.

There are five main muscles in stomach pyramidalis, rectus abdominus, external obliques, internal obliques, and transversus abdominis.

Muscles circulate frame parts by contracting after which relaxing. muscular tissues can pull bones, however, they cannot push them to return to their unique role. so they paintings in pairs of flexors and extensors. The flexor contracts to bend a limb at a joint.

The muscle groups that circulate our frame elements are called skeletal muscles, and they're a form of striated muscle. We will actively manipulate those with our brains. another sort of striated muscle is those that maintain our hearts pumping, which we are not able to actively control.

Muscles pull at the joints, allowing us to move. a couple of muscular tissues are used for any sort of motion of a bone. Although we are sitting flawlessly nevertheless, muscle tissues at some point in the frame are constantly shifting.

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True

In place of photographic plates or films, charge coupled devices, or CCDs, are sensitive photon detectors that can be employed in telescopes to create images. CCDs were created in the late 1960s and are now found in various devices, including digital cameras and photocopiers.

CCDs are more light-efficient, catch a greater proportion of incoming photons, can store and transfer digital data, and don't require development like film does. They respond linearly and capture up to 80% of the light that strikes them.

I understand the question you are looking for is this:

One of the primary advantages of CCDs over photographic plates is the former's high efficiency in detecting light. True or false.

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The maximum height above the point of release it rises is 8.82 m

The force exerted by a spring on objects attached to its ends is proportional to the spring's change in length away from its equilibrium length.

F(spring) = k*x

here,

mass, m=0.240 kg

vertical spring constant, k = 5050 N/m

compression, x=0.090 m

When the spring is compressed, the spring potential energy is:

E = (k*x^2) / 2

substituting the values,

E = 5050* 0.090^2 / s

E = 20.91 J

This energy would be converted to kinetic, so the mass gains speed, which is then converted to gravitational potential energy once the mass reaches its highest point

E(p) = m*g*h

where, h is the maximum height

E(p) = E

m*g*h = 20.91

h = 20.91 / ( 9.8 * 0.248 )

h = 8.82 m

hence

The maximum height above the point of release is 8.82 m

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She should use shorter focal length to fit the entire landscape which she is trying to photograph into her picture.

What is focal length?

The focal length is a measure of how strongly the system converges or diverges light.

A positive focal length indicates that a system converges light, while a negative focal length indicates that the system diverges light.

For a standard rectilinear lens,

FOV = 2 arctan (x/2f)

FOV ∝ 1 / f

where x is the diagonal of the film.

Focal length (f) and field of view (FOV) of a lens are inversely proportional.

From the equation we can say that,

A shorter focal length gives you a wide angle of view which allows more view to fit in the frame.

Hence,

She should use shorter focal length to fit the entire landscape which she is trying to photograph into her picture.

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Answer: The end point of a spring oscillates with a period of 2.0 s when a block with mass m is attached to it. When this mass is increased by 2.0 kg, the period is found to be 3.0 s.  Then the mass m is 0.625kg.

Explanation: To find the answer, we need to know more about the simple harmonic motion.

                                          [tex]T=2\pi \sqrt{\frac{m}{k} }[/tex]

               [tex]T_1=2s\\m_1=m\\m_2=m+2kg\\T_2=3s[/tex]

              [tex]T_1=2\pi \sqrt{\frac{m}{k} } \\T_2=2\pi \sqrt{\frac{m+2}{k} } \\\frac{T_1}{T_2} =\sqrt{\frac{m}{m+2} }\\\frac{2}{3} =\sqrt{\frac{m}{m+2} }\\\\[/tex]

               [tex]m=\frac{5}{8} =0.625kg[/tex]

Thus, we can conclude that, the mass m will be 0.625kg.

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The tangential speed of a lug nut on a wheel of a car will be 4.68 m/s

Given:

Distance of lug nut = 0.114 m

wheel is rotating at speed = 6.53 rev/sec

To Find:

tangential speed of a lug nut

Solution: Tangential velocity is the linear speed of any object moving along a circular path. A point on the outside edge of a turntable moves a greater distance in one complete rotation than a point near to the center

Vr = r.ω

(0114 m)(41.03 rad/s) = Vr

Vr = 4.68 m/s

Hence, tangential speed of lug nut on wheel of car is 4.68 m/s

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The angular speeds of the wheels is 1,647.28 rad/min

angular velocity is the speed at which the angle between two bodies changes as an item rotates or revolves around an axis.

The diameter of a bicycle, d = 20inches

Radius, r = 10 inches

The bicycle is travelling at 16 mi/h.

We need to find the angular speed of the wheels in rad/min.

We know that,

1 mi/h = 0.0166667 mi/min

It means,

16 mi/h = 0.26 mi/min

Also,

10 inch = 0.0001578356 miles

The angular speeds of the wheels is given by :

v = rω

ω = v/r

ω = 0.26/0.0001578356

ω = 1,647.28 rad/min

So, the angular speeds of the wheels is 1,647.28 rad/min

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0.07  is the magnitude of the magnetic field at a distance of 2d from the wire

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