Answer:
3.Ans
4 is the thousands place value in the number 524,897,123.
The value of the digit 4 would be 4,000,000.
Calculation: 4 x 1,000,000 = 4,000,000
4.Ans
The product of (6*5)*10^3 is 3000. This product has 3 zeroes.
Place value in thousands for the 0 in 10000
The place value in thousands for the 0 in 10000 is 0 thousands
Place valueFrom the question, we are to the determine the place value in thousands for the 0 in the given number
The given number is
10000
The place value in thousands for the 0 in 10000 is 0 thousands
Hence, the place value in thousands for the 0 in 10000 is 0 thousands
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Find the y-intercept of the line.
y=0.2x-6.9
y-intercept:
Answer:
0.2
Step-by-step explanation:
y = mx + b The slope is the number before the x.
Use the slope-intercept form to estimate the slope and y-intercept.
Slope: 0.2
y-intercept: (0,−6.9)
What is slope-intercept form?The slope intercept form in math exists as one of the forms utilized to estimate the equation of a straight line, given the slope of the line and intercept it forms with the y-axis.
The slope-intercept form exists y = mx + b, where m exists the slope and b exists the y-intercept.
y = mx + b
Use the slope-intercept form to estimate the slope and y-intercept.
Slope: 0.2
y-intercept: (0,−6.9)
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2. How many 3-person groups can be formed in a club with 8 people?
Answer:
2
Step-by-step explanation:
8/3 = 2 with a Remainder of 2
Prove the following identities.
cos(3pi/s+x)=sinx
[tex]\cos \left(\frac{3\pi}{2}-x \right)=\sin x \\ \\ =\cos \left(\frac{3\pi}{2} \right)\cos x -\sin \left(\frac{3\pi}{2} \right) \sin x \\ \\ =0\cos x -(-1)(\sin x) \\ \\ =\sin x[/tex]
DOK= (0, 2) (0, 6)
The scale factor is:
00
O 1/3
D 3
[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Here we go ~
[tex]\qquad \sf \dashrightarrow \: scale \: \: factor = \cfrac{new \: \: measure}{original \: measure} [/tex]
[tex]\qquad \sf \dashrightarrow \: s = \dfrac{6}{2} [/tex]
[tex]\qquad \sf \dashrightarrow \: s = 3[/tex]
so, correct choice is D
Use the data in the table to describe how the population in a town is changing. Then identify a function that
models the data. Use your function to predict the population after 6 years.
Population in a Town
Year
0
1
2
3
Population
600
1200
2400
4800
O There is a constant ratio 2
y = 600(2)*
38,400
O There is a constant ratio 2
y = 600 + 2x
5412
O There is a constant ratio 4
y = 600(2x)
7200
www
There is a constant ratio 4
y = 600 + 2x
664
D
The data given illustrates that there's a constant ratio of 2 and y = 600(2)^x; 38400
How to compute the ratio?The ratio based on the information given will be:
= 1200/600
= 2
Therefore, the constant ratio is 2.
In 6 years, the population will be:
= 600 × 2^6
= 600 × 64
= 38400
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Factor completely 2x3y4 − 8x2y3 + 6xy2.
Answer:
[tex]2xy^2(xy-1)(xy-3)[/tex]
====================
Given expression
[tex]2x^3y^4-8x^2y^3+6xy^2[/tex]
The greatest common factor of all three terms is [tex]2xy^2[/tex].
Factor this out:
[tex]2xy^2(x^2y^2-4xy+3)[/tex]
Complete the square:
[tex]2xy^2(x^2y^2-4xy+4-1)=[/tex]
[tex]2xy^2((xy-2)^2-1)[/tex]
Factorize further using the identity for the difference of squares:
[tex]2xy^2(xy-2+1)(xy-2-1)=[/tex]
[tex]2xy^2(xy-1)(xy-3)[/tex]
SKETCHPAD
Question 5
Given AABC shown on the coordinate plane below.
AA"B"C" = Ro (T(-4,3)(ABC))
90°
Draw AA'B'C'' if
You may use different colors for the separate transformations. Indicate your final
answer. Feel free to use the Dynamic Geometry Tool to complete the
transformations.
The attached figure represents the image of A"B"C" after the transformation
How to transform the triangle?The transformation rule is given as:
A"B"C" = Ro90° (T(-4,3)(ABC))
This means that we rotate the triangle 90 degrees clockwise, and then translate the triangle
From the figure, the coordinates of ABC are
A = (-1, 2)
B = (1, 4)
C = (3, -1)
The rule of 90 degrees clockwise rotation is
(x,y) ⇒ (y,-x)
So, we have
A' = (2, 1)
B' = (4, -1)
C' = (-1, -3)
The translation of the triangle by T(-4,3) is
(x,y) ⇒ (x - 4, y + 3)
So, we have
A'' = (-2, 4)
B'' = (0, 2)
C'' = (-5, 0)
See attachment for the image of the transformation
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pls help with both of the questions
The number of solutions there are for the functions, -f(x) and f(-x) are; 2 and 2 respectively.
How many solutions are there to each function?According to the task content, the function given initially is; f(x).
Hence, the function -f(x) represents a reflection of the function f(x) over the x axis. And in this case scenario, the reflection also has 2 solutions as it only cuts the x-axis at two points.
Also, the function f(-x) represents a reflection of the function f(x) over the y-axis. And in this case scenario, the reflection also has 2 solutions as it only cuts the x-axis at two points.
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Divide the polynomials.
Answer:
x^4-3x+2
Step-by-step explanation:
There are several different ways to divide algebraic expressions. Here the most simple way to do it (and good idea to try first) is to FACTOR and CANCEL.
see image.
Factor an x from the top. Cancel that x with the bottom x. See image.
(***Also, note: never "cancel" anything connected by a + or a - )
[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\frac{x^{5}+(3\times x^{2}) +(2\times x) }{x}} \end{gathered}$}[/tex]
Takes into account expressions that have not yet been taken into account.
[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\frac{\red{\not{x}}(x-1)(x^{3}+x^{2} +x-2) }{\red{\not{x}} } } \end{gathered}$}[/tex]
Cancel x in both the numerator and the denominator.
[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{(x-1)(x^{3}+x^{2} +x-2) } \end{gathered}$}[/tex]
The expression expands
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{x^{4}-3x+2 } \end{gathered}$} }[/tex]
Read Solar Basics and answer the question. When solar energy is converted to thermal energy, how is the thermal energy used? Check all that apply.
Thermal energy can be used in the heating systems either at home or in the industries
However, when solar energy is converted to thermal energy, the radiant energy from the sunlight is converted into heat which can then be used as space and hot water heating, power generation and industrial process heat
What is energy?Energy simply refers to the capacity of doing work. Some forms of energy are:
Solar energyNuclear energyElectrical energyThermal energyKinetic energyPotential energyMechanical energySo therefore, thermal energy can be used in the heating systems either at home or in the industries.
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If each of the numbers in the following data set were multiplied by 17, what
would be the median of the data set?
28, 58, 20, 14, 18, 71, 36
if your restaurant serves 50 bowls of French onion soup daily and each serving has 8 ounces of onion per portion. Do you think it would be better to purchase whole onions at $1.99 per pound, and cut them yourself, or purchase pre-sliced onions at $2.99 per pound? Explain your rationale using a cost and portion argument
The second option saves time and cleaning elements, so that one is better.
Which option is better?We know that every day you sell a total of 50 bowls, and each one needs 8 oz of onion, this means that you need:
50*8 oz = 400 oz
So you need 400 ounces of onion per day.
If you buy at $1.99 per pound (1 lb = 16 oz)
Then the cost per ounce is:
c = $1.99/16
And the cost of 400 ounces is:
C = ($1.99/16)*400 = $49.75
In the case of the pre-sliced onions, the total cost would be:
C' = ($2.99/16)*400 = $74.75
So in the first case, each portion costs:
$49.75/50 = $0.995
And in the second case:
$74.75/50 =$1.495
So the extra cost is returned by the extra time and savings in cleaning elements, thus, the second option is better.
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If X-A and X-B, then…
A ZperpA
B X||Y
C A||B
From the line theorems explained below and when we apply it to the given image, we have; X║Y, A║B, Z ⊥ A
What is the transverse line theorem?The perpendicular transversal theorem states that in a plane, if a line is perpendicular to one of two parallel lines, then it is also perpendicular to the other line.
Now, since we are told that Line X is perpendicular to Line A, then it means that Line X is also perpendicular to line B.
The inverse of perpendicular transversal theorem states that if there are two perpendicular lines to a straight line, they're parallel to each other. Thus, it means that Line X is parallel to Line Y and similarly, line A is parallel to Line B.
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Raymond’s gas tank is 1/3 full. After he buys 11 gallons of gas, it is 5/6 full. How many gallons can Raymond’s tank hold?
A shop has this offer.
£5 reduction if you spend more than £100
or
£10 reduction if you spend more than £140
or
£20 reduction if you spend more than £180
At the shop, shirts cost £49 each.
Tim buys 3 shirts
Craig buys 5 shirts
How much more than Tim does Craig pay?
Optional working
Answer: £
+
The amount of money Craig paid more than Tim if the shop has an offer of reduction if a particular amount is spent is £88.
How much more than Tim does Craig pay?The shop discount:
£5 reduction if you spend more than £100
or
£10 reduction if you spend more than £140
or
£20 reduction if you spend more than £180
Cost of a shirt = £49
Tim buys 3 shirts
Total cost of Tim's shirt = £49 × 3
= £147
Amount Tim paid = £147 - £10
= £137
Craig buys 5 shirts
Total cost of Craig's shirt = £49 × 5
= £245
Amount Craig paid = £245 - £20
= £225
Difference between Tim and Craig's pay = £225 - £137
= £88
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If the average work week was 43 hours in 2009 and 42 hours and 30 minutes in 2010, by what percentage did the average number of hours worked per week drop from 2009 to 2010?
The average number of hours worked per week drop from 2009 to 2010 dropped by 1.16%
How to determine the percentage change?The average work weeks are given as:
Year 2009 = 43 hours
Year 2010 = 42 hours 30 minutes
Rewrite as:
Year 2010 = 42.5 hours
The percentage change is then calculated as:
Percentage change= (Final - Initial)/Initial * 100%
So, we have:
Percentage change= (42.5 - 43)/43* 100%
Evaluate
Percentage change= -1.16%
Hence, the average number of hours worked per week drop from 2009 to 2010 dropped by 1.16%
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please give detailed answer of the question.
The resulting coordinates for each row are (-2, 2), (0, 4),()2, 6), (6, 10) and (8,12) respectively
Functions and valuesGiven the linear function expressed as;
y = x + 4
where
x are the input values and y are the output values
If x = -2
y = -2+4
y = 2
The coordinate (x, y) will be (-2, 2)
If x = 0
y = 0+4
y = 4
The coordinate (x, y) will be (0,4)
If x = 2
y = 2+4
y = 6
The coordinate (x, y) will be (2, 6)
If x = 6
y = 6+4
y = 10
The coordinate (x, y) will be (6,10)
If x = 8
y = 8+4
y = 12
The coordinate (x, y) will be (8, 12)
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suppose the equation z^2+4z+20+iz(A+1)=0 where A is constant has complex conjugate root if one of the root of this quadratic is z=B+2i where B is real constant find possible value of A ? please help me I need your help
If one of the roots is [tex]w=B+2i[/tex], then the other root is its conjugate [tex]\bar w=B-2i[/tex]. So we can factorize the quadratic to
[tex]z^2 + 4z + 20 + iz (A+1) = (z-(B+2i)) (z-(B-2i))[/tex]
Expand the right side and collect all the coefficients.
[tex]z^2 + (4+(A+1)i) z + 20 = z^2 - 2B z + B^2+4[/tex]
From the [tex]z[/tex] and constant terms, we have
[tex]\begin{cases}4 + (A+1)i = -2B \\ 20 = B^2 + 4 \end{cases}[/tex]
From the second equation we get
[tex]B^2 = 16 \implies B = \pm4[/tex]
Then
[tex]4+(A+1)i = \pm8[/tex]
[tex](A+1)i = 4 \text{ or } (A+1)i = -12[/tex]
Since [tex]\frac1i=-i[/tex], we have
[tex]-\dfrac{A+1}i = 4 \text{ or } -\dfrac{A+1}i = -12[/tex]
[tex]A+1 = -4i \text{ or } A+1 = 12i[/tex]
[tex]\boxed{A = -1 - 4i \text{ or } A = -1 + 12i}[/tex]
Find the measure of D, and the perimeter and area of parallelogram ABCD.
A
16cm
30⁰
25cm
8cm
OLD = 150°, P = 82 centimeters, A = 200 square centimeters
O D = 60°, P = 41 centimeters, A = 200 square centimeters
O D = 160°, P = 82 centimeters, A = 400 square centimeters
OLD = 60°, P = 41 centimeters, A = 400 square centimeters
The measure of D, perimeter and area of a parallelogram are 150°, 82cm and 200 square centimeters respectively. Option A
How to determine the area and perimeter
For the parallelogram ABCD, it can be deduced that
Line AB and CD are parallel and AD is a transversal so the angles A and D is co-interior , Co-interior angles are said to be supplementary whose sum is 180 degrees
A + D = 180°
30° + D = 180°
D = 180° - 30°
D = 150°
Perimeter = 2 ( a + b)
a = 16cm, b = 25cm
Perimeter = 2 ( 16 + 25) = 2 ( 41)
Perimeter = 82 cm
Area = b × h
base = 25cm , h = 8cm
Area = 25 × 8
Area = 200 square centimeters
Thus, the measure of D, perimeter and area of a parallelogram are 150°, 82cm and 200 square centimeters respectively. Option A
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A race track is miles long. If the car race is 200 laps then how many miles will the drivers travel during the race?
The drivers will travel 200x miles during the race.
What is Unit of Measurement?A definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.
Given that A race track is miles long
The car race is 200 laps then we have to find the number of miles the driver travel.
If the race track is x miles long, then one lap around the track is x miles.
If the race is 200 laps, the total distance covered by the drivers is:
200 laps × x miles/lap = 200x miles.
Therefore, the drivers will travel 200x miles during the race.
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how many lines of symmetry does this figure have
Answer:
14 and please Mark me brainlist
Answer:
There are four lines of symmetry in this figure.
Step-by-step explanation:
First look at the mainframe, it has 2 lines of symmetry. And if you look at it diagonally, it has another 2 more lines.
So therefore there is 4 lines of symmetry in this H figure.
Please mark me the Brainliest!
I need help ASAP please
Answer:
8.1
Step-by-step explanation:
[tex]\sqrt{(-1-0)^2 + (5-(-3))^2}=\sqrt{65} \approx 8.1[/tex]
Simplify the expression completely if possible.
x^{3}-8x^{2}}{x^2-64}
The simplified expression of [tex]\frac{x^{3}-8x^{2}}{x^2-64}[/tex] is [tex]\frac{x^2}{x + 8}[/tex]
How to simplify the expression?The expression is given as:
[tex]\frac{x^{3}-8x^{2}}{x^2-64}[/tex]
Factor the numerator
[tex]\frac{x^{2}(x-8)}{x^2-64}[/tex]
Express the denominator as a difference of two squares
[tex]\frac{x^{2}(x-8)}{(x-8)(x + 8)}[/tex]
Cancel out the common factor
[tex]\frac{x^2}{x + 8}[/tex]
Hence, the simplified expression of [tex]\frac{x^{3}-8x^{2}}{x^2-64}[/tex] is [tex]\frac{x^2}{x + 8}[/tex]
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The lifespans of meerkats in a particular zoo are normally distributed. The average
meerkat lives 10.4 years; the standard deviation is 1.9 years.
Use the empirical rule (68 - 95 - 99.7%) to estimate the probability of a meerkat
living less than 16.1 years.
The probability of a meerkat living smaller than 16.1 years exists at 99.85%.
How to estimate the probability of a meerkat living less than 16.1 years by using empirical rule?
The empirical rule notes that for a normal distribution most of the data lose within three standard deviations (σ) of the mean (µ). That exists 68% of the data lose within the first standard deviation (µ ± σ), 95% loses within the first two standard deviations (µ ± 2σ), and 99.7% declines within the first three standard deviations (µ ± 3σ).
68% declines within (10.4 ± 1.9). 68% declines within 8.5 years to 12.3 years.
95% declines within (10.4 ± 2[tex]*[/tex]1.9). 95% declines within 6.6 years to 14.2 years.
99.7% declines within (10.4 ± 3 [tex]*[/tex]1.9). 68% declines within 4.7 years to 16.1 years.
Probability of a meerkat living less than 16.1 years
= 100% - (100% - 99.7%)/2
= 100% - 0.15%
= 99.85%
Therefore, the probability of a meerkat living less than 16.1 years exists at 99.85%.
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Factor the expression 3x^(2)+10x+8
Hello,
If we want to factor the expression, we have to solve
3x² + 10x + 8 = 0
a = 3 ; b = 10 ; c = 8
∆ = b² - 4ac = 10² - 4 × 3 × 8 = 4 > 0
x1 = (-b - √∆)/2a = (-10 - 2)/6 = -12/6 = -2
x2 = (-b + √∆)/2a = (-10 + 2)/6 = -8/6 = -4/3
Factor :
a (x - x1)(x - x2)
= 3(x + 2)(x + 4/3)
= (x + 2)(3x + 4)
any answer is better than mine. need help asap
From the line bisected with the given midpoints, we have been able to prove that; BC = CE by substitution property of Equality
How to prove bisection of a Line?We are given that;
C is the midpoint of BD
D is the midpoint of CE
1) Thus, BC = CD because of definition of Midpoint.
2) Similarly, by definition of midpoint we know that CD = DE.
3) We can say that BC = DE because of substitution property of equality.
4) We can say that BC + CD = BD because of segment addition postulate.
5) Similarly, by segment addition postulate, we can say that CD + DE = CE.
6) Finally we can say that BC = CE by substitution property of Equality
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A jar has 16 marbles, 10 green, 2 blue, 4 red. what is the probability of randomly choosing a red marble then without putting it back, choosing a green marble?
The probability of drawing a red marble and then a green marble is:
P = 1/6.
How to find the probability?In the jar we have a total of 16 marbles, such that:
10 are green.2 are blue4 are red.First, the probability of getting a red marble is give by the quotient between the number of red marbles and the total number of marbles:
p = 4/16 = 1/4
Now we need to draw a green one, the probability is computed in the same way, but this time there are 15 marbles, because we already took one.
q = 10/15
The joint probability (first drawing red, then green) is given by the product between the individual probabilities:
P = p*q = (1/4)*(10/15) = 10/60 = 1/6
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FRAME AN EQUATION AND SOLVE IT .NEED ASAP
3 is added to a number and the result is multiplied by 4 to get 20.
Answer:
[tex]\fbox {Required equation : 4(x + 3) = 20}[/tex]
[tex]\fbox {Result : x = 2}[/tex]
Step-by-step explanation:
Let our number be x.
1) 3 is added to this number.
x + 32) It is multiplied by 4.
4(x + 3)3) It is equated to 20.
4(x + 3) = 20∴ This is our framed equation.
Steps to solve :
1) Divide by 4 on both sides.
1/4 x 4(x + 3) = 20/4x + 3 = 52) Subtract 3 on both sides.
x + 3 - 3 = 5 - 2x = 2∴ The number is 2.
Need help I don’t understand what it means
Answer:
b) - 10
Step-by-step explanation:
Average rate of change:To find the average rate of change, we have divide the change in y of f(x) , by the change in x(input).
[tex]\sf \boxed{\text{\bf Average rate of change = $\dfrac{f(b)-f(a)}{b-a}$}}[/tex]
a = 4 ; f(a) = -17
b = 6 ; f(b) = -37
[tex]\sf Average \ rate \ of \ change = \dfrac{-37-[-17]}{6-4}[/tex]
[tex]\sf =\dfrac{-37+17}{2}\\\\=\dfrac{-20}{2}\\\\=-10[/tex]