The amount, in moles, of carbon that are needed to produce 562 grams of carbon dioxide would be 12.77 mols.
Stoichiometric problemCarbon dioxide can be produced from the reaction of carbon and oxygen according to the following equation:
[tex]C + O_2 --- > CO_2[/tex]
From the reaction, the mole ratio of carbon to carbon dioxide is 1;1.
Recall that: mole = mass/molar mass
Thus, the mole equivalent of 562 grams of carbon dioxide would be:
562/44 = 12.77 mol
This amount of carbon dioxide will also be the amount of carbon that will be required to react since the mole ratio is 1 to 1.
In other words, from the established stoichiometric mole ratio, the number of moles of carbon needed to produce 562 grams of carbon dioxide would be 12.77 mol.
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Which set of elements contains a metalloid?
Oa. Ba, Ag, Sn, Xe
O b. Fr, F, O, Rn
O c. Li, Mg, Ca, Kr
O d. K, Mn, As, Ar
Answer:
D.) K, Mn, As, Ar
Explanation:
The metalloids are located in the p-block on the periodic table and have a ladder-like arrangement.
The most commonly recognized metalloids are:
boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te)
Organic chemistry is defined as the study of compounds containing which element?
Organic chemistry is defined as the study of compounds containing carbon element .
In an organic chemistry, we study about structure, properties , composition, reaction and preparation of carbon congaing compounds.The organic compound is contains mainly carbon and hydrogen and other elements. The other elements in organic compounds are nitrogen, oxygen,sulfur, phosphorus, halogen and etc.
Organic chemistry is also refer as carbon chemistry .The carbon element is important because it is center elements of living organism and it is very basic for all live in the earth. By studying about organic chemistry , scientist get to know about human body and living organism.
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Which of the following is a statement that describes a problem that can be solved using technology design?
The cat will be sprayed with water when it jumps on the couch.
A hockey player needs a stronger shot.
The smoke from a forest fire is causing health issues.
The living room needs to be cleaned.
Answer:
the smoke one
Explanation:
it can be made aware of and people can raise money to stop it/ help it
A 25. 00 ml sample of acetic acid containing phenolphthalein indicator is titrated with 0. 1067 m naoh. The solution changes color after 30. 07 ml naoh has been added. What is the concentration of the acetic acid before titration?.
The concentration of the acetic acid before titration is 0.128M
For weak acid and strong base titration-
Moles of acetic acid = moles of NaOH
Given concentration of NaOH = 0.1067M
Volume of NaOH = 30.07ml = 0.03007L
Using the formula, Concentration = Moles/Volume
Moles of NaOH = concentration X volume = 0.1067 X 0.03007 = 0.0032
Therefore, moles of acetic acid = 0.0032mole
Using the formula, Concentration = Moles/Volume
Concentration of acetic acid = 0.0032/0.025 = 0.128M
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Suppose you had to titrate a solution of NaOH of unknown concentration with a solution of HCl of known concentration using phenolphthalein as an indicator. How will you determine the color change
When the system turns pink, then the end point has been attained.
What is the end point?The end point or the equivalence point is the time when the reactants have undergone transformation in accordance with the reaction equation. The reaction in this case is; HCl + NaOH -----> NaCl + H2O.
We know that phenolphthalein is colorless in acid but red in a base. The color at end point is pink. Thus, when the system turns pink, then the end point has been attained.
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Which element is the most reactive?
A. sodium
B. nickel
C. carbon
D. oxygen
Answer:
correct answer is sodium
Explanation:
element is most active in this question is sodium please make me Brilliant to this correct answer
during a neutralization reaction phosphoric acid reacts with potassium hydroxide to produce potassium phosphate and water. if the reaction occurs with 64.9% yield, what mass of potassium phosphate would be made if 13.32g of potassium hydroxide is added to excess phosphoric acid?
During a neutralization reaction phosphoric acid reacts with potassium hydroxide to produce potassium phosphate and water, the reaction occurs with a 64.9% yield.
A neutralization reaction is a chemical process in which an acid and a base combine to produce salt and water as the end products. In a neutralization process, a mixture of H+ ions and OH- ions results in the formation of water.
Potassium phosphate and water are created when potassium hydroxide and phosphoric acid combine. The reaction's balanced equation is as follows: K3PO4(aq) + 3H2O = 3KOH(aq) + H3PO4(aq) (l) If six moles of potassium hydroxide react, phosphoric acid is used in the reaction.
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Control rods in a nuclear reactor...
Select one:
a. remove heat from the reactor core.
b. provide fuel for the reaction.
c. control a chain reaction by absorbing neutrons.
d. prevent the leakage of radiation into the environment.
Control rods in a nuclear reactor control a chain reaction by absorbing neutrons. Option C
What are control rods?The control rods are rods that are inserted into the nuclear reactor in order to absorb the neutrons thereby preventing the nuclear reaction from going out of hand.
Hence, control rods in a nuclear reactor control a chain reaction by absorbing neutrons. Option C
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A student dissolves a spoon full of table salt (sodium chloride) in a glass of water.
After the salt is completely dissolved, the major entities in the glass (other than the
water itself) are:
(select all that apply)
Sodium chloride crystals
Aqueous sodium ions
Chlorine gas
Solid sodium metal
Liquid sodium metal
Aqueous chloride ions
Answer:
Aqueous sodium ions, Aqueous chloride ions
Explanation:
Sodium chloride dissociates into Na+ and Cl- ions in water
Sodium chloride crystals may also be present in case of saturated solution
Given an end diastolic volume (EDV) of 120 ml / beat and an end systolic volume (ESV) of 50 ml / beat, the stroke volume (SV) would be ________.
70 ml would be the stroke volume (SV) every beat.
Given,
End Diastolic Volume(EDV) = 120 ml/beat
End Systolic Volume(ESV) = 50 ml/beat
According to the formula
Stroke volume = End Diastolic Volume(EDV) - End Systolic Volume(ESV)
Stoke volume = 120 ml/beat - 50 ml/beat
Stroke volume = 70 ml/beat
The amount of blood in the ventricles just before the heart contracts is known as end-diastolic volume.
End-systolic volume (ESV) is the amount of blood in a ventricle at the point where systole, or contraction, ends and diastole, or filling, begins.
At any time during the cardiac cycle, the ESV has the lowest blood volume in the ventricle.
The amount of blood that is pumped out of the left ventricle of the heart with each systolic cardiac contraction is referred to as the stroke volume.
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Which rule for assigning oxidation numbers is correct?
Hydrogen is usually –1.
Oxygen is usually –2.
A pure group 1 element is +1.
A monatomic ion is 0.
The incorrect rule for assigning oxidation numbers is Hydrogen is usually –1.
Hydrogen is usually +1
What is oxidation number?Oxidation numbers can be defined as that number which is assigned to an element in chemical reaction which represents the number of electrons lost or gained.
So therefore, the incorrect rule for assigning oxidation numbers is Hydrogen is usually –1.
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Answer:
B: Oxygen is usually –2.
Explanation:
How many grams of CO2 will be produced when 8.50 g of methane react with 15.9 g of O2, according to the following reaction? CH4(g) +2 O2(g) = CO2(g) +2 H2O(g)
Taking into account the reaction stoichiometry, 10.93 grams of CO₂ are formed when 8.50 g of methane react with 15.9 g of O₂.
Reaction stoichiometryIn first place, the balanced reaction is:
CH₄ + 2 O₂ → CO₂ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
CH₄: 1 mole O₂: 2 molesCO₂: 1 moleH₂O: 2 molesThe molar mass of the compounds is:
CH₄: 16 g/moleO₂: 32 g/moleCO₂: 44 g/moleH₂O: 18 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
CH₄: 1 mole ×16 g/mole= 16 gramsO₂: 2 moles ×32 g/mole= 64 gramsCO₂: 1 mole ×44 g/mole= 44 gramsH₂O: 2 moles ×18 g/mole=36 gramsLimiting reagentThe limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
Limiting reagent in this caseTo determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 16 grams of CH₄ reacts with 64 grams of O₂, 8.50 grams of CH₄ reacts with how much mass of O₂?
[tex]mass of O_{2} =\frac{8.50 grams of CH_{4}x64 grams of O_{2} }{16grams of CH_{4}}[/tex]
mass of O₂= 34 grams
But 34 grams of O₂ are not available, 15.9 grams are available. Since you have less mass than you need to react with 8.50 grams of CH₄, O₂ will be the limiting reagent.
Mass of CO₂ formedThe following rule of three can be applied: if by reaction stoichiometry 64 grams of O₂ form 44 grams of CO₂, 15.9 grams of O₂ form how much mass of CO₂?
[tex]mass of CO_{2} =\frac{15.9 grams of O_{2}x44 grams of CO_{2} }{64grams of O_{2}}[/tex]
mass of CO₂= 10.93 grams
Then, 10.93 grams of CO₂ are formed when 8.50 g of methane react with 15.9 g of O₂.
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A lake experiences episodic acidification, in which the pH drops to 5.0. A scientist studying the lake sees trout and perch disappear from the lake over time. What would be a reasonable explanation for the disappearance of these fish
A reasonable explanation for the disappearance of these fish is the high acidity affecting fish metabolism.
What is the ideal pH for fish?pH is a very important parameter to consider, as it has a direct effect on the metabolism and physiological processes of fish and other aquatic organisms. The pH tolerance range for fish is between 4.0 and 9.0, while the ideal index is between 6.5 and 8.0
With this information, we can conclude that The various fish species differ in terms of the best pH. The pH range between 6.5 – 9.0 is generally recommended for freshwater species. For marine species, the most recommended PH range is between 7.8-8.4.
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Alright, now you actually have an aqueous solution of your salt! Though perhaps not all of the salt has dissolved yet, but we'll get to that. How sure would you say you are about the concentration at this point?
a) What I've prepared is not yet an aqueous solution
b) It's not that accurate, but similar to what we need in the end
c) It's quite accurate
d) It's really inaccurate
If not all of the salt has dissolved then the measurement of the concentration at the time is really inaccurate.
What is concentration?The concentration is the amount of substance that is present in solution. We know that we can not measure the concentration unless all of the solute have been dissolved in the solution.
Thus, if not all of the salt has dissolved then the measurement of the concentration at the time is really inaccurate.
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A sample of neon gas occupies a volume of 414 mL at a pressure of 1.15 atm. What will be the pressure of the gas if the volume is increased to 825 mL
Answer:
.577 atm
Explanation:
P1 V1 = P2 V2
RE-ARRANGE TO P2 = P1 V1 / V2
Sub in the given values
P2 = 1.15 * .414 / .825 = .577 atm
1. Name each of the following binary compounds or ionic compounds with polyatomic ions.
a) LiBr
b)Cal2
A gas sample of 2.31 atm of oxygen gas and 3.75 atm of hydrogen gas that react to form water vapor. Assume the volume of the container and the temperature inside the container does not change.
Mole fraction of Oxygen=0.381
Mole fraction of Oxygen= (range of moles of oxygen) ÷(general moles)
also, mole fraction of oxygen = (partial stress of oxygen) ÷ (total strain)
consequently , mole fraction of Oxygen= (2.31 atm)÷(2.31 atm + 3.75 atm)
= 0.381
The mole fraction may be calculated by means of dividing the variety of moles of 1 element of a solution by the entire quantity of moles of all the additives of a solution. It is cited that the sum of the mole fraction of all of the components inside the solution should be identical to 1.
Mole fraction is a unit of awareness. in the solution, the relative amount of solute and solvents are measured by way of the mole fraction and it's far represented through “X.” The mole fraction is the variety of moles of a selected aspect inside the answer divided by way of the entire range of moles in the given answer.
Mole fraction is the ratio between the moles of a constituent and the sum of moles of all ingredients in a mixture. Mass fraction is the ratio between the mass of a constituent and the full mass of a mixture.
The question is incomplete. Please read below to find the missing content.
Assuming that only the listed gases are present, what would the mole fraction of oxygen gas be for each of the following situations? A gas sample of 2.31 atm of oxygen gas and 3.75 atm of hydrogen gas react to form water vapor. Assume the volume of the container and the temperature inside the container does not change.
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The enthalpy of fusion for Hg is 2.29 kJ/mol. What is the energy change when 78.0 g of Hg melts at −38.8°C?
The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.
What is Enthalpy of Fusion ?The amount of energy needed to change 1 mole of substance under state change at constant temperature and pressure is called enthalpy of fusion. It is also known as Latent heat of fusion. Unit of enthalpy of fusion is kJ/mol.
How to find the change in energy ?To find the change in energy use this expression:
q = n ΔH
where
q = Energy change
n = number of moles
ΔH = Molar enthalpy
Number of moles (n) = [tex]\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
= [tex]\frac{78.0\ g}{200\ \text{g/mol}}[/tex]
= 0.39 mol
Now put the values in above formula we get
q = n ΔH
= 0.39 mol × 2.29 kJ/mol
= 0.89 kJ
Thus from the above conclusion we can say that The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.
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Describe the effect of leaving the following substances in humid air
a) anhydrous copper (ii) sulphate
Answer:
the effect of leaving the following substances in humid air is
ii) sulphate
A ground test utilizing an auxiliary current electrode and an auxiliary potential electrode is known as the______.
Answer:
The three-point test
Explanation:
The three-point test refers to a ground test utilizing an auxiliary current electrode and an auxiliary potential electrode.
How many moles of water are
in 1.23x10¹8 water molecules?
[ ? ]×10[?]
Answer:
2.04 x 10⁻⁶ moles H₂O
Explanation:
To find the moles H₂O, you need to multiply the given value by Avogadro's Number. This number is a ratio between molecules and moles, thus granting you the way to convert between both units. It is important to arrange the ratio in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (1.23 x 10¹⁸ molecules).
Avogadro's Number:
6.022 x 10²³ molecules = 1 mole
1.23 x 10¹⁸ molecules H₂O 1 mole
--------------------------------------- x ------------------------------------- =
6.022 x 10²³ molecules
= 2.04 x 10⁻⁶ moles H₂O
C 3 H 6 (g) + O 2(g) --------------> CO 2(g) + H 2 O (g)
What volume of C 3 H 6 to produce 34.7 L of H 2 O at a temperature of 29.4◦ C and a pressure of 0.762 atm?
Using the equation above solve the following: How many liters of CO 2 can be produced from 18.7 g of O 2 at STP?
As per ideal gas equation ,
[tex]C_{3}H_{6}[/tex] Volume = 11.56 L
[tex]CO_{2\\}[/tex] volume = 8.62L
What is Ideal gas equation?
PV = nRT
[tex]C_{3} H_{6}[/tex] gas burns in air according to following equation:
[tex]2C_{3}H_{6}[/tex] + [tex]9O_{2}[/tex] → [tex]6CO_{2}[/tex] + [tex]6H_{2} O[/tex]
Volume of [tex]C_{3} H_{6}[/tex] produced;
Step 1 : Calculate the moles of [tex]H_{2} O[/tex]
PV = nRT
n = PV / RT
n = 0.762 × 34.7 / 0.08206 × 302.55
n = 1.065 mol
Step 2: Calculate the moles of [tex]C_{3} H_{6}[/tex]
1.065 mol [tex]H_{2} O[/tex]× 2 mol [tex]C_{3} H_{6\\}[/tex] / 6 mol [tex]H_{2} O[/tex]
= 0.355 mol
Step 3 : Calculate new volume
V = 0.355 × 0.08206 × 302.55 / 0.762
V = 11.56 L
Volume of [tex]CO_{2}[/tex] produced;
Step 1: Calculate the moles of [tex]O_{2}[/tex]
18.7g [tex]O_{2}[/tex] × 1 mol [tex]O_{2}[/tex] / 32 g [tex]O_{2}[/tex]
= 0.58 mol
Step 2: calculate the moles of [tex]CO_{2}[/tex]
0.58 mol × 6mol [tex]CO_{2}[/tex] / 9 mol [tex]O_{2}[/tex]
= 0.38 mol
Step3: convert mol to litres
0.38 × 22.7L / 1mol [tex]CO_{2}[/tex] [22.7L = 1mol]
= 8.62 L
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a) What volume of butane (C 4 H 10 ) can be produced at STP, from the reaction of 13.45 g of carbon with 17.65 L of hydrogen gas at STP?
b) Which reactant is in excess and how much of this reactant is left over?
From the stoichiometry of the reaction, carbon is in excess and 5.856 g s left over.
What is the volume of butane produced?The reaction can be written as; 4C(s) + 5H2(g) -----> C4H10(g)
Number of moles of C = 13.45 g/1 2g/mol = 1.12 moles
If 1 mole of hydrogen occupies 22.4 L
x moles of hydrogen occupies 17.65 L
x = 0.79 moles
Now;
4 moles of carbon reacts with 5 moles of hydrogen
1.12 moles of carbon reacts with 1.12 moles * 5 moles/4 moles
= 1.4 moles of hydrogen
Hence hydrogen is the limiting reactant here and carbon is in excess.
If 4 moles of carbon reacts with 5 moles of hydrogen
x moles of carbon reacts with 0.79 moles of hydrogen
x = 0.632 moles
Number of moles of carbon unreacted = 1.12 moles - 0.632 moles
= 0.488 moles
Mass of carbon unreacted = 0.488 moles * 12 g/mol
= 5.856 g
Volume of butane produced is obtained from;
5 moles of hydrogen produces 1 mole of butane
0.79 moles of hydrogen produces 0.79 moles * 1 mole/ 5 moles
= 0.158 moles
1 mole of butane occupies 22.4 L
0.158 moles of butane occupies 0.158 moles * 22.4 L/ 1 mole
= 3.53 L
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What is the total number of pairs of electrons that one carbon atom shares?
Answer:
4
Explanation:
A carbon atom has 4 electrons in its outermost shell (2s^2p^2). All are unpaired (none share their orbital with another electron). So all four are anxious to pair with another electron. Once it has found 4 more electrons contributed from other atom(s), it will have 4 pairs of shared electrons.
Hydrogen has one lone electron. An atom of H is downright gleeful in sharing it's electron with elements such as carbon, C. Since carbon has 4 unpaied electrons, it will combine with 4 H atoms. At that point, cabon is sharing 4 electron pairs.
In the electrolysis of water, how long will it take to produce 165.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 113.0 mA?
In the electrolysis of water, 3490 hour will it take to produce 165.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 113.0 mA.
What is Ideal Gas Law ?The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.
It is expressed as
PV = nRT
where,
P = Pressure
V = Volume in liters
n = number of moles of gas
R = Ideal gas constant
T = Temperature in kelvin
Here,
P = 1.0 atm
V = 165.0 L
R = 0.0821 atm. L/mol.K (Ideal gas constant)
T = 273 K
n = ?
Now put the value in above expression, we get
PV = nRT
1.0 atm × 165.0 L = n × 0.0821 atm. L/mol.K × 273 K
165.0 atm. L = n × 22.4 atm. L/mol
[tex]n = \frac{165.0\ \text{atm. L}}{22.4\ \text{atm. L/mol}}[/tex]
n = 7.36 mol
The reaction is
2H⁺ + 2e⁻ → H₂
1 mol of electrons is produced from 96500 C
So,
[tex]96500 \frac{C}{\text{mol} \times e} \times 2e \times 7.36\ \text{mol}[/tex]
= 1,420,480 C
Convert milliampere to C/s
1mA = 0.001 C/s
113.0 mA = 113.0 × 0.001
= 0.113 c/s
What is relationship between current, charge and time ?The relation between current, charge and time is expressed as:
[tex]I = \frac{Q}{t}[/tex]
where,
I = Current
Q = Charge in Coulomb
t = time
Now put the value in above formula we get
[tex]I = \frac{Q}{t}[/tex]
[tex]= \frac{1,420,480\ C}{0.113\ C/s}[/tex]
= 12,570,619.469 s
= 3490 hour
Thus from the above conclusion we can say that In the electrolysis of water, 3490 hour will it take to produce 165.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 113.0 mA.
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Ionization energy is the energy required to remove an electron from an atom in the gas phase. The ionization energy of gold is 890.1 kJ/mol. Calculate the maximum wavelength of light that will ionize gold.
Ionization of Gold:
The maximum wavelength of light that will ionize gold is 134.5 x 10 ⁻⁴m
Calculation:
1 mole requires = 890.1kJ = 8.901×10⁵ J
The energy needed to ionize a single atom = Divide it by Avogadro's number (6.0221409×10²³)
Thus, 1 atom requires = 8.901×10⁵ J / 6.0221409×10²³ J
= 1.478×10⁻¹⁸ J
The Energy of photon = E = hc/λ where,
h = Planck constant (6.626070040Ă—10â’34 Js)
λ = the wavelength
c = the speed of light
Putting the values:
E = 1.478×10⁻¹⁸ J
h =6.63x10⁻³⁴ Js
c = 3 x 10⁸ m/s
λ = ?
λ = hc/E
= (6.63x10⁻³⁴ x 3 x 10⁸ ) / 1.478×10⁻¹⁸
= 134.5 x 10 ⁻⁴m
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You arrive at a crime scene and are told the body of the victim is in the 10 m deep pool. You walk over to what you are told is a 12 m in diameter, cylindrical pool. From the outside of the pool, you can see that the body looks badly burnt. Your partner says, “It looks like our victim had been burned alive and tried to put out the fire by jumping in the pool. The victim likely drowned to death.”
Something does not sit right with you though. If there was a fire, where did it start? There are no signs of combustion anywhere. You aren’t so sure and ask the crime scene investigator to run a sample of the pool water before letting anybody try to pull the body out.
The CSI comes back to you and tells you that normal pool water pH is roughly around 7.2, but the pool pH is actually highly basic at a level of 13 with a concentration of hydroxide ions at 1.0 x 10-1 mol/L. It becomes obvious to you that the body wasn’t burned before going in to the pool , but AFTER and there was no fire needed!
You order the body to be removed from the pool, but the CSI interjects, “It would be too dangerous with a pH that high. I suggest you get some vinegar from the store and pour it in to the pool before hand to drop the pH to 7. Draining the pool would take far too long and we need to examine the body as soon as possible.” She asks one of your constables to go to the store to purchase 5 – 4L jugs of vinegar (pH = 2) to pour in the pool, as she states it is enough to bring the pH to a safe level of 7.
It sounds like it could be enough vinegar based on your knowledge of acids and bases, but you want to double-check her estimate before sending your constable to the store. Verify whether or not she is correct using calculations. A diagram may help you with your calculations.
Hint 1: 1m3 = 1000L
Hint 2: Vcylinder = πr2h
Answer:
The pool cannot be neutralized with only vinegar.
Explanation:
The pool's [OH] concentration is 1.0x101mol/L. You must determine the volume of the pool in order to determine how many moles of OH there are in the solution:
r2h = V(pool)
Where h is the depth of the pool, which is equal to 10 meters, and r is the radius,
V(pool) = π (6m)
V(pool) = 2*10 = 1131 m3.
As 1m³ = 1000L
The pool holds 1131m3 x (1000L / 1m3) = 1131000L.
And the OH moles are:
The pool has 131100 moles of OH, or 1.0x101mol per liter times 1131000 liters.
The following is how H+ neutralizes OH:
OH⁻ + H⁺ → H₂O
In order to neutralize the pool, 131100 moles of H+ must be added.
H+ levels in vinegar with a pH of 2 are as follows:
[H+] = -log pH
2 = -log [H⁺]
1x10⁻²M = [H⁺]
Only 4x102 moles of [H+] make up 4L. As necessary, 131100 moles of H⁺:
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IF 500 ml 0.1 mol Hcl reacts with 500 ml 0.01 mol NaoH... calculate the no. of moles of nacl formed
Answer:
0.01 moles NaCl
Explanation:
It seems that the given volumes are unnecessary information.
To find the moles NaCl, you need to convert moles HCl and NaOH to moles NaCl via the balanced chemical equation. Specifically, you need to use the mole-to-mole ratio made up of the reaction coefficients. The reason why you need to convert both reactants is because you have not been given a limiting reagent. The smallest amount of moles NaCl calculated will be the final answer.
The balanced reaction:
HCl + NaOH -----> NaCl + H₂O
0.1 moles HCl 1 mole NaCl
---------------------- x ---------------------- = 0.1 moles NaCl
1 mole HCl
0.01 moles NaOH 1 mole NaCl
----------------------------- x ----------------------- = 0.01 moles NaCl
1 mole NaOH
NaOH produces the smallest amount of product. This means it is completely used up before HCl runs out. Therefore, NaOH is the limiting reagent and 0.01 moles NaCl are actually produced.
What is the primary function of phosphoglycerides mentioned in this module?
Answer:
which one is isn't the one that is wrong
Explanation:
bang bang chocho train
What is the stoichiometric coefficient in front of the oxygen (o2) in the balanced version of this reaction? c4h8(l) o2(g) â co2(g) h2o(g) (unbalanced)
The stoichiometric coefficient in front of the oxygen ([tex]O_{2}[/tex]) in the balanced version of the reaction will be 6.
The number that must be present before the atoms, molecules, or ions is known as the stoichiometric coefficient. Fractions, as well as whole numbers, can be used as stoichiometric coefficients. Essentially, the coefficients assist us in determining the mole ratio of reactants to products.
The balanced chemical reaction will be
[tex]C_{4} H_{8} +6O_{2}[/tex] → [tex]4CO_{2} +4H_{2} O[/tex]
It can be seen that the stoichiometric coefficient in front of oxygen is 6.
Therefore, stoichiometric coefficient in front of oxygen will be 6.
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