how fast would u have to throw a baseball for it to catch on fire? (explanation in step by step equations)

Answer:

9 times the KE

Explanation:

KE = 1/2 mv^2     now triple  'v'

KE = 1/2 m 9 v^2    

less than 20 Hz

The frequency of subsonic sound is less than 20 Hz

subsonic sound refers to a sound which has a wave that travels slower than the speed of sound.

Thus subsonic sound < 20 Hz

Answer:

less than 20Hz

Explanation:

Bats can hear below 20Hz ,so they use this to travel in air

Answer:

Inertia = angular momentum / angular velocity

Answer:

The newton (lowercase n!) is a derived unit because its definition consists of multiplication of three defined base units and nothing else. Its meaning is thus derived, not independently defined.

Answer:Cars enter a car wash at a mean rate of 4 cars per half an hour. 

Explanation:

The probability that, in any hour, exactly 22 cars will enter the car wash will be 0.0920.

Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1.

Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.

The  mean rate of car is,[tex]\rm \lambda = 66 \ car/hour[/tex]

[tex]P(x=K) = \frac{8^k e^{-8}}{k\!}\\\\P(x=22) = \frac{66^{22} e^{-22}}{22\!}\\\\ P(x=22)=\frac{0.000000000000691\times 1.07\times 10^{40}}{22} \\\\\ P(x=22)=0[/tex]

Hence the probability that, in any hour, exactly 22 cars will enter the car wash will be 0

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Answer:

Inertia is that quantity which depends solely upon mass. The more mass, the more inertia. Momentum is another quantity in Physics which depends on both mass and speed.

Explanation:

Answer:

B. by blending in with the trees

Answer:

B. by blending in with the trees

Explanation:

If the distance between the two charges is doubled, the attraction or repulsion becomes weaker.

Explanation:

The answers on the model of the human centrifuge ready for the launch to each question of the statement are listed below:

a) A force of 2479.210 newtons is acting on the astronaut's back.

b) A net centripetal force of 2479.210 newtons is acting on the astronaut.

c) The centripetal acceleration of the astronaut is 30.990 meters per square second.

d) The astronaut has a linear speed of approximately 19.284 meters per second.

e) The angular speed of the astronaut is 1.607 radians per second (15.346 revolutions per minute).

The human centrifuge experiments a centripetal acceleration when it reaches a peak angular speed. In this question we must apply Newton's laws of motion and concepts of centripete and centrifugal forces to answer the questions. Now we proceed to answer the questions:

By the third Newton's law the astronaut experiments a rection force (F), in newtons, which has the same magnitude to centrifugal force but opposed to that force. The magnitude of the force acting on the back of the astronaut is equal to:

[tex]F = 3.16\cdot (80\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]

[tex]F = 2479.210\,N[/tex]

A force of 2479.210 newtons is acting on the astronaut's back. [tex]\blacksquare[/tex]

By the second and third Newton's laws we know that the net centripetal force on the astronaut is equal to the magnitude of the force found in the previous question. Thus, a net centripetal force of 2479.210 newtons is acting on the astronaut. [tex]\blacksquare[/tex]

The centripetal acceleration of the astronaut (a), in meters per square second, is found by dividing the result of the previous question by the mass of the astronaut (m), in kilograms:

[tex]a = \frac{F}{m}[/tex]   (1)

If we know that F = 2479.210 newtons and m = 80 kilograms, then the centripetal acceleration of the astronaut is:

[tex]a = \frac{2479.210\,N}{80\,kg}[/tex]

[tex]a = 30.990\,\frac{m}{s^{2}}[/tex]

The centripetal acceleration of the astronaut is 30.990 meters per square second. [tex]\blacksquare[/tex]

By definition of uniform circular motion, we have the following formula for the linear velocity of the astronaut (v):

[tex]v = \sqrt{a\cdot r}[/tex]   (1)

Where r is the radius of the human centrifuge, in meters.

If we know that [tex]a = 30.990\,\frac{m}{s^{2}}[/tex] and [tex]r = 12\,m[/tex], then linear velocity of the astronaut is:

[tex]v = \sqrt{\left(30.990\,\frac{m}{s^{2}} \right)\cdot (12\,m)}[/tex]

v ≈ 19.284 m/s

The astronaut has a linear speed of approximately 19.284 meters per second. [tex]\blacksquare[/tex]

The angular speed of the astronaut (ω), in radians per second, is found by the following kinematic relationship:

[tex]\omega = \frac{v}{R}[/tex]   (1)

If we know that v ≈ 19.284 m/s and R = 12 m, then the angular speed is:

[tex]\omega = \frac{19.284\,\frac{m}{s} }{12\,m}[/tex]

ω = 1.607 rad/s (15.346 rev/m)

The angular speed of the astronaut is 1.607 radians per second (15.346 revolutions per minute). [tex]\blacksquare[/tex]

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I believe most activity takes place during daylight hours.So the life move fast in day. If we talk about the -Sound. At night , the air is denser due to humidity (obviously nights are cooler). sound requires medium to travel and so DENSER the medium,FASTER the sound travels.

Explanation:

it's a unit used to measure charge (C)

1C=1000millicoulombs

1millicoulomb=1000microcoulumbs

Answer:

1 column - 3 x 10⁹ start columb

= 1 / 10 e mu

column is a bigger unit so in practice the smaller unit micro column is also used the smaller unit of charge

1 Milli column - 10-³

1 micro column 10-⁶

the force of attraction or illusion between the two point charge is directly proportional to the product of the magnitude and inversely proportional to the square of distance between them the direction of force along line joining the two charge

hope it's helpful

An  example of diffraction is being able to hear sounds from outside a room throughout the whole room.

The term diffraction has to do with the bending of waves around an obstacle which causes the waves to spread out as they emerge on the other side.

One typical example of diffraction is being able to hear sounds from outside a room throughout the whole room.

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Answer:

(Option B)The car travels 15km in 15 minutes.

Explanation:

Notice that the speed is written using units of km/h and the time is written using units of minutes.

Convert the time interval to hours. Remember that 1 hour equals 60 minutes:

15 min = 15 min × [tex]\frac{1h}{60~min}=0.25h[/tex]

The distance d that a particle travels during a time t if it moves at an average speed v is given by the formula:

d = v · t

Replace v=60km/h and t=0.25h to find the distance traveled by car:

[tex]d=(60\frac{km}{h}) ~x~(0.25h)=15km[/tex]

Therefore, the car travels 15km in 15 minutes.

Hope this helps!

If you have any queries please ask.

Answer:

Force=10N

Velocity=13m/s

Explanation:

Given,

Mass = 5kg

initial velocity=3m/s

Final velocity=7m/s

Time=2s

Now acceleration= v-u/t

=7-3/2

=4/2

=2m/s²

So, acceleration=2m/s²

Now,

F=ma

=5*2

=10N

Answer:

Lunar eclipses are more widely visible because Earth casts a much larger shadow on the Moon during a lunar eclipse than the Moon casts on Earth during a solar eclipse.

[tex]\text{Given that,}\\\\\text{Initial velocity,}~ u = 10 ~ms^{-1}\\\\\text{Final velocity,}~ v = 40 ~ ms^{-1}\\\\\text{Acceleration,}~ a = 8 ~ ms^{-2}\\ \\\text{Time ,}~ t =?\\\\\text{Displacement, }~ s = ?\\\\\text{We know that,}\\\\a= \dfrac{v-u}{t}\\ \\\implies t = \dfrac{v-u}{a} = \dfrac{40-10}{8} = \dfrac{30}{8} = 3.75 ~sec \\\\s=\left(\dfrac{u+v}2\right)t=\left(\dfrac{10+40}2 \right)3.75 = \left(\dfrac{50}{2}\right)3.75 = 25 \times 3.75 = 93.75~m[/tex]

[tex]\text{Hence, the displacement of the car is 93.75 m}[/tex]

Answer:

Each body spray cost $ 21.25

Explanation:

If the buzzer in this connection fails to make a sound, it follows that the switch or the key is open.

A circuit is a path designed for the flow of current. We have to take note of the fact that the switch or key must be closed before electric current can pass through the circuit and the buzzer will make a sound.

Therefore, were the buzzer in this connection fails to make a sound, it follows that the switch or the key is open.

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Answer:

C
- CONNECTIONS

--------------------------------

much love! <33

The stopwatch will be the most useful in determining the kinetic energy of a 50 g battery- powered car traveling a distance of 10 m.

Kinetic energy is the energy of a body possessed due to motion.

This means that for an object to possess kinetic energy, it must be in motion.

The kinetic energy is measured in Joules, which is a product of the mass of the substance and the time taken to travel a distance.

A stopwatch is an instrument used to measure time as one of the components of kinetic energy.

Therefore, the stopwatch will be the most useful in determining the kinetic energy of a 50 g battery- powered car traveling a distance of 10 m.

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Answer:

14,400

Explanation:

I guessed and I think it's right Soo

If all the mass of fuel and oxygen is burned to form gases of combustion, the downward velocity of these gases would be 12,505 m/s.

The principle of conservation of linear momentum states that, the total momentum of an isolated system is constant.

The downward velocity of thes gases is calculated as follows;

v1(m1 + m2) = v2(m2)

305(1000 + 25) = v2(25)

312,625 = 25v2

v2 = 312,625/25

v2 = 12,505 m/s

Thus, If all the mass of fuel and oxygen is burned to form gases of combustion, the downward velocity of these gases would be 12,505 m/s.

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if the primary winding has 50 coils and the secondary winding has 20 coils then the secondary  voltage will be equal to 2400V

Voltage is defined as the potential difference which apply a force on the charge to flow in the circuit.

This is a question on transformer. A transformer is a device used to step up or step down current and voltage. It consists of the primary windings and secondary windings. Each windings possesses both coil and amount of voltage across each coil.

The transformer formula is

[tex]\dfrac{V_S}{V_P}=\dfrac{N_S}{N_P}[/tex]

Where;

Vs is the voltage across the secondary coil

Vp is the voltage across the primary coil

Ns is the number of turn in the primary coil

Np is the number of turns in the primary coil.

According to the question,

Vs is unknown

Vp is 6000V

Ns is 20turns

Np is 50turns

Substituting the values in the formula given

[tex]\dfrac{V_S}{6000}=\dfrac{20}{50}[/tex]

Vs = 2400V

Therefore the secondary voltage is 2400V

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Answer:

2400

Explanation:

edge 2022

Answer:

7.9 x 10^21 pound-force

Explanation:

The average distance between the Earth and sun is 150 trillion meters, or 1.5 x 10^11 meters. The mass of the sun is 1.99 x 10^30 kilograms, while the Earth weighs in at 6.0 x 10^24 kilograms. The gravitational constant is 6.67 x 10^-11 meter^3 / (kilogram - second^2). So the Earth and sun pull on each other with a force equal to 3.52 x 10^22 newtons. The newton is a unit of force equal to a kilogram-meter/second^2. One newton is equal to 0.22 of the rarely used English unit called pound-force, so 3.52 x 10^22 newtons is 7.9 x 10^21 pound-force.

The time period of the simple pendulum is 2.4 seconds.

Given the data in the question;

Period is the time needed for a complete cycle of vibration to pass a given point.

Period of a pendulum is the of time needed for it to complete one full back-and-forth motion. It is the time required to for the pendulum to swing from leftmost point to rightmost point and back to leftmost point.

Now, if it took the pendulum [tex]1.2s[/tex] to swing from leftmost point to rightmost point, it will also take the pendulum [tex]1.2s[/tex] to swing back to its original position( leftmost point )

Hence,

[tex]T[/tex] = time taken to swing from leftmost to rightmost + time taken to swing from rightmost point to leftmost point.

[tex]T = 1.2s + 1.2s\\\\T = 2.4s[/tex]

Therefore, the time period of the simple pendulum is 2.4 seconds.

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Answer: See below

Explanation:

[tex]\\ \mathrm{Given:} \\\mathrm{Mass \ of \ first \ car}$\left(m_{1}\right)=1383 \mathrm{~kg}$ \\ Velocity $\left(\overrightarrow{V_{1}}\right)=-11.2\ {\math} \mathrm{m} / \mathrm{s}$\\ Mass of second car -$\left(m_{2}\right)=1732 \mathrm{~kg}$\\ Velocity $\left(\vec{v}_{2}\right)=31.3 {\math} \mathrm{m} / \mathrm{s}$[/tex]

[tex]m_{1} \vec{v}_{1}+m_{2} \vec{v}_{2}=\left(m_{1}+m_{2}\right) \vec{v} \\1383(-11.2 {\math})+1732(31.3 {\math}) \\=(1383+1732) \vec{v} \\-15489.6 {\math}+54211.6 {\math}=3115 \vec{v} \\ \vec{v}=(17.4 {\math}-4.972 {\math}) \ \mathrm{m/s}[/tex]

[tex]\text { So magnitude } \vec{|v|} =\sqrt{(17.4)^{2}+(-4.972)^{2}} \\ =\sqrt{327.605} \\ =18.099 \mathrm \ {m/s} \\[/tex]

[tex]\text { Direction } \\\theta=\tan ^{-1}\left(\frac{-4.972}{17.4}\right) \\\theta=-15.945^{\circ}\end{gathered}[/tex]

Therefore, both cars move with a velocity of 18.099 m/s in the direction of 15.945° downward from the x-axis (east)

Answer:

Explanation:

Apply conservation of momentum in N-S direction:

Initial momentum: 1383*(-11.2) + 1732*(0) = -15490

Final momentum: (1383 + 1732) * Final N-S velocity = -15490

Final velocity = 1549/(1383+1732) = -4.97 m/s (-ve means South)

Repeat the same for E-W direction:

Initial momentum: 1383*(0) + 1732*(31.3) = 54211.6

Final momentum: (1383 + 1732) * Final E-W velocity = 54211.6

Final velocity = 54211.6/(1383+1732) = 17.4 m/s (+ve means East)

Combining, the final velocity = sqrt (-4.97^2 + 17.4^2) = 18.10 m/s

at direction of arctan(17.4/4.97) = 74 degree South of East.

Explanation:

Nope, displacement is a vector quantity, whereas distance is the scalar (magnitude) of the total displacement.

Hope this clears things up :))

The type of pure substances that can create elaborate structures is :

( D ) Atoms that are not attracted to each other because they will stay still and end up laying on top of each other.

An elaborate structure is a complex structure formed by the combination of different unrelated parts. Atoms that are un attracted to each other are made of different parts therefore when they come together they will lay on each other, forming an elaborate structure which is complex in nature.

Hence we can conclude that the type of pure substance that can create elaborate structures is Atoms that are not attracted to each other because they will stay still and end up laying on top of each other.

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For two planets orbiting a star in a distant galaxy, having the first semimajor axis of 150 x 10^6 km,  the period of the second plane  is mathematically given as

T=2.2earth year

Generally, the equation for the time period  is mathematically given as

[tex]T^{2} \appox a^{3}[/tex]

Therefore, for planet one

[tex]1^2\approx (150 x 10^6)^3[/tex]

In conclusion, For planet 2

T^2=(250/150)^3

T=√4.632

T=2.2earth year

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The period of the second planet for two planets circling a star in a faraway galaxy with a first semimajor axis of 150× 10⁶ km. The time period of the planet will be 2.2 earth years.

The time period of the revolution is the time required to complete one revolution. It is guven by T. It is measured in seconds.

The equation of the time period is found as;

[tex]\rm T = \frac{250}{150} ^3 \\\\ T= \sqrt{4.632} \\\\ T=2.2 \ earth \ year[/tex]

Hence the time period of the planet will be 2.2 earth years.

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