Answers
Answer:
Step-by-step explanation:
the first time you add 10, the second time you add 20, the third time you add 40, and you keep doubling up to the eighth time
15 + 10 = 2525 + 20 = 4545 + 40 = 8585 + 80 = 165165 + 160 = 325325 + 320 = 645645 + 640 = 12851285Related Questions
Suppose a is an invertible nxn matrix and v is an eigenvector of a with associated eigenvalue, prove that v is an eigenvector of a^2 and find the associated eigenvalue.
Answers
This result shows that the eigenvalues of A^2 are the squares of the eigenvalues of A, and the eigenvectors of A and A^2 are the same
Let λ be the eigenvalue associated with eigenvector v of matrix A. Then by definition, we have:
Av = λv
Now consider the matrix A^2. We can write A^2 as the product A * A, so we have:
A^2 v = A(Av) = A(λv) = λ(Av)
Note that Av = λv, so we have:
A^2 v = λ(Av) = λ(λv) = λ^2 v
This shows that v is an eigenvector of A^2 with associated eigenvalue λ^2. To see why, note that we have shown that A^2 v is a scalar multiple of v, with the scalar being λ^2. This means that v is an eigenvector of A^2 with associated eigenvalue λ^2.
Therefore, we have shown that if v is an eigenvector of A with associated eigenvalue λ, then v is an eigenvector of A^2 with associated eigenvalue λ^2.
To summarize:
If Av = λv, then A^2 v = λ^2 v.
So, v is an eigenvector of A^2 with associated eigenvalue λ^2.
This result shows that the eigenvalues of A^2 are the squares of the eigenvalues of A, and the eigenvectors of A and A^2 are the same
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,determine whether the three vectors lie in a plane in R3.
(a) v1 =(2,−2,0), v2 =(6,1,4), v3 =(2,0,−4)
(b) v1 =(−6,7,2), v2 =(3,2,4), v3 =(4,−1,2)
Answers
a) The determinant of A is non-zero, the vectors v1, v2, and v3 are linearly independent and do not lie in a plane in R3.
b) The determinant of B is non-zero, the vectors v1, v2, and v3 are linearly independent and do not lie in a plane in R3.
To determine whether three vectors lie in a plane in R3, we need to check if they are linearly dependent or independent. If they are linearly dependent, then they lie in a plane; if they are linearly independent, then they do not lie in a plane.
(a) To check if v1, v2, and v3 lie in a plane, we need to see if they are linearly dependent or independent. One way to do this is to find the determinant of the matrix A whose columns are the three vectors:
| 2 6 2 |
|−2 1 0 |
| 0 4 −4 |
We can expand this determinant along the first row to get:
det(A) = 2 × | 1 0 |
- (-2) × | 6 4 |
+ 0 × | 1 −4 |
= 2(1 × 4 - 0 × (-4)) - (-2)(6 × 4 - 1 × 1) + 0
= 8 + 47 + 0
= 55
(b) To check if v1, v2, and v3 lie in a plane, we need to see if they are linearly dependent or independent. One way to do this is to find the determinant of the matrix B whose columns are the three vectors:
|−6 3 4 |
| 7 2 −1 |
| 2 4 2 |
We can expand this determinant along the third column to get:
det(B) = 4 × |−6 3 |
- (-1) × | 7 2 |
+ 2 × | 2 4 |
= 4(-6 × 2 - 3 × 7) - (-1)(7 × 4 - 2 × 2) + 2(2 × 2 - 4 × 3)
= -96 + 30 + (-8)
= -74
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Select the correct answer.
Which expression is equivalent to
3
2
?
A.
6
2
y
−
9
y
2
−
3
y
B.
9
y
−
6
y
+
2
C.
3
y
2
y
−
6
+
9
2
y
−
6
D.
Answers
The correct equivalent expression is,
⇒ - 3 (2x - 3y)
We have to given that;
Expression is,
⇒ - 6x + 9y
Now, We can simplify as;
⇒ - 6x + 9y
⇒ - 3 (2x - 3y)
Thus, The correct equivalent expression is,
⇒ - 3 (2x - 3y)
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Complete question is,Which expression is equivalent to −6x + 9y?
A) −3(2x + 3y)
B) −3(2x − 3y)
C) 3(2x − 3y)
D) −3(2x + 9)
URGENT
3
2-
-2
7777
-3
2 3 456
What is the domain of the function?
x<0
X>0
O x < 1
all real numbers
Answers
The domain of the function is given as follows:
x > 0.
How to define the domain and range of a function?The domain of a function is defined as the set containing all possible input values of the function, that is, all the values assumed by the independent variable x in the context of the function.The range of a function is defined as the set containing all possible output values of the function, that is, all the values assumed by the dependent variable y in the context of the function.The function in this problem is defined for values of x to the right of x = 0, hence the domain is given as follows:
x > 0.
Missing InformationThe graph is given by the image presented at the end of the answer.
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let f ( x , y ) = x 2 y . find ∇ f ( x , y ) at the point ( 1 , − 2 )
Answers
To find the gradient vector of the function f(x, y) = x^2y at the point (1, -2), we need to compute the partial derivatives of f with respect to x and y and evaluate them at the given point. The partial derivative of f with respect to x is obtained by treating y as a constant and differentiating x^2 with respect to x, giving 2xy.
The partial derivative of f with respect to y is obtained by treating x as a constant and differentiating xy with respect to y, giving x^2. Therefore, the gradient vector of f at (1, -2) is given by:∇f(1, -2) = [2xy, x^2] evaluated at (x, y) = (1, -2)
∇f(1, -2) = [2(1)(-2), 1^2] = [-4, 1]
So, the gradient vector of f at the point (1, -2) is [-4, 1]. This vector points in the direction of the steepest increase in f at (1, -2), and its magnitude gives the rate of change of f in that direction. Specifically, if we move a small distance in the direction of the gradient vector, the value of f will increase by approximately 4 units for every unit of distance traveled. Similarly, if we move in the opposite direction of the gradient vector, the value of f will decrease by approximately 4 units for every unit of distance traveled.
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equal monthly payments (starting end of first month) on a 6-year, $50,000 loan at a nominal annual interest rate of 10ompounded monthly are:
Answers
To calculate the equal monthly payments for a 6-year, $50,000 loan at a nominal annual interest rate of 10% compounded monthly, we can use the formula for the monthly payment on a loan:
P = (r(PV))/(1 - (1 + r)^(-n))
where P is the monthly payment, r is the monthly interest rate (which is the nominal annual rate divided by 12), PV is the present value of the loan (which is $50,000), and n is the total number of monthly payments (which is 6 years times 12 months per year, or 72).
First, we need to calculate the monthly interest rate:
r = 0.10/12 = 0.0083333
Next, we can substitute these values into the formula to calculate the monthly payment:
P = (0.0083333(50000))/(1 - (1 + 0.0083333)^(-72)) = $843.86
Therefore, the equal monthly payments for this loan would be $843.86, starting at the end of the first month.
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(LOTS OF POINTS) How tall is the tree? Show work
Answers
The height of the tree, found using the distances in the diagram and Pythagorean Theorem is about 92.49 feet
What is the Pythagorean Theorem?The Pythagorean Theorem express the relationship between the lengths of the sides of a right triangle. The theorem states that the square of the hypotenuse side of a right triangle is equivalent to the sum of the squares of the other two sides of the triangle.
The distances in the drawing, whereby the tree is vertical indicates;
The distance line from the person to the top of the tree, the height of the person, and the distance from the base of the tree to the person forms a right triangle
Hypotenuse side = The distance line from the person to the top of the tree, h
The legs = The height of the tree, y and the distance from the person to the base of the tree, x
Pythagorean theorem indicates that we get;
h² = y² + x²
h = 102, x = 43, therefore;
102² = y² + 43²
y² = 102² - 43² = 8555
The height of the tree, y = √(8555) ≈ 92.49
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Quadrilateral ABCD is a rhombus. Given that m∠EDA=37°, what are the measures of m∠AED,m∠DAE , and m∠BCE? Show all calculations and work
Answers
The measure of the angles are;
m<AED = 90 degrees
m<DAE = 43 degrees
m<BCE = 37 degrees
How to determine the anglesTo determine the measure of the angles, we need to know the following;
Adjacent angles are equalCorresponding angles are equalThe sum of angles in a triangle is 180 degreesThe sum of the interior angles of a rhombus is 360 degreesAngles on a straight line is 180 degreesFrom the information given, we have that;
m<AED is right- angled thus is equal to 90 degrees
But we have that;
m<DAE + m<EDA + m<AED = 180
Then,
m<DAE + 37 + 90 = 180
collect the like terms
m<DAE = 180 - 137
m<DAE = 43 degrees
m<BCE = m<EDA
Hence, m<BCE = 37 degrees
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Suppose the amount of a certain drug in the bloodstream is modeled by C(t)=15te-.4t. Given this model at t=2 this function is: Select one:
a. At the inflection point
b. Increasing
c. At a maximum
d. Decreasing
Answers
The function is decreasing and at a maximum at t=2.
At t=2, the function C(t)=15te-.4t evaluates to approximately 9.42. To determine whether the function is at the inflection point, increasing, at a maximum, or decreasing, we need to examine its first and second derivatives. The first derivative is C'(t) = 15e-.4t(1-.4t) and the second derivative is C''(t) = -6e-.4t.
At t=2, the first derivative evaluates to approximately -2.16, indicating that the function is decreasing. The second derivative evaluates to approximately -3.03, which is negative, confirming that the function is concave down. Therefore, the function is decreasing and at a maximum at t=2.
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change variables in the system by letting x(t)=x0+u(t), y(t)=y0+v(t). the system for u,v is
u’=
v’=
Use u and v for the two functions, rather than u(t) and v(t) For the n, v system, the Jacobean matrix at the origin is A =[ ]
Answers
It seems like you want an explanation of changing variables in a dynamical system using the given transformation x(t)=x0+u(t), y(t)=y0+v(t). In this case, u(t) and v(t) represent perturbations from the equilibrium point (x0, y0).
By substituting the transformed variables into the original system, you obtain a new system with u and v as the dependent variables.
To analyze the stability of the equilibrium point, you can linearize the new system near the origin using the Jacobian matrix, denoted by A. The Jacobian matrix contains the partial derivatives of the system's functions with respect to u and v, evaluated at the origin.
The eigenvalues of A will give you information about the system's stability, such as whether it's stable, unstable, or neutrally stable.
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The Jacobian matrix at the origin is: A = [ 0 0
0 0 ]
It looks like you want to change variables in a system using a transformation and then find the Jacobian matrix for the new system involving u and v functions.
1. Given the change of variables, x(t) = x0 + u(t) and y(t) = y0 + v(t).
2. Differentiate both equations with respect to t to get the new system:
u'(t) = x'(t)
v'(t) = y'(t)
3. Now, we need to find the Jacobian matrix for this new system. The Jacobian matrix is a matrix of partial derivatives of the functions u'(t) and v'(t) with respect to the new variables u(t) and v(t). So, we have:
A = [∂u'/∂u ∂u'/∂v]
[∂v'/∂u ∂v'/∂v]
4. To find these partial derivatives, we need the expressions for u'(t) and v'(t) in terms of u(t) and v(t). Since you haven't provided these expressions, I can't give you the exact Jacobian matrix. However, you can use the above formula tofind the Jacobian matrix once you have those expressions.
To determine the Jacobian matrix at the origin, we need to calculate the partial derivatives of the system with respect to u and v.
The Jacobian matrix A is given by:
A = [ ∂u'/∂u ∂u'/∂v
∂v'/∂u ∂v'/∂v ]
Please let me know if you have any questions or need further clarification.
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3.2−1/2(+4)=4.8+2−5.2
Answers
Answer:
x = -8
Step-by-step explanation:
3.2 - 1/2(x + 4) = 4.8x + 2 - 5.2x
3.2 - 0.5x - 2 = - 0.4x + 2
1.2 - 0.5x = -0.4x + 2
1.2 - 0.1x = 2
-0.1x = 0.8
x = -8
Answer: 6.8 = 1.6
Step-by-step explanation:
3.2-1/2 (+4) 4.8+2-5.2
2.8+4 6.8-5.2
6.8 = 1.6
(a) Sketch the conic section. Find and label any foci, vertices, and asymptotes. (x - 3)^2 – 9y^2 = 36
(b) Find the equation of the ellipse with foci (0,+2) and semi-major axis length 3.
Answers
a) the vertices are (9, 0) and (-3, 0).
the foci are (3 ± 2√10, 0)
the asymptotes are y = ±x/3 - 1
b) the equation of the ellipse is x² + (y-√5/2)² = 5/4
a) To find the foci, vertices, and asymptotes of the ellipse (x - 3)² - 9y² = 36, we can first divide both sides by 36 to get:
[tex]\frac{(x-3)^2}{36} - \frac{y^2}{4}=1[/tex]
Therefore, the center of the ellipse is (3, 0).
The semi-major axis length is √36 = 6, and the semi-minor axis length is √4 = 2.
Therefore, the vertices are (3 ± 6, 0) = (9, 0) and (-3, 0).
The foci are located at a distance of √(6²-2²) = 2√10 from the center along the major axis. Therefore, the foci are (3 ± 2√10, 0) and the equation of the major axis is x = 3.
To find the asymptotes, we will use the formula:
[tex]\frac{y-k}{b} = \pm\frac{x-h}{a}[/tex]
where (h, k) is the center of the ellipse, a is the length of the semi-major axis, and b is the length of the semi-minor axis. Therefore, the equations of the asymptotes are:
(y-0)/2 = ±(x-3)/6
y = ±x/3 - 1
b) To find the equation of the ellipse with foci (0, 2) and semi-major axis length 3, we can first find the center of the ellipse. Since the foci are located on the y-axis, the center must also be located on the y-axis. Therefore, the center is (0, c), where c is the distance between the center and one of the foci.
Since the semi-major axis length is 3, the distance between the center and one of the vertices is 3. Therefore, we have:
c² + (3/2)² = (3/2+2)²
c² = 5/4
Therefore, the center of the ellipse is (0, √5/2). The distance between the center and one of the foci is √5/2 - 2. Therefore, the distance between the center and one of the vertices is √{(√5/2)² - (√5/2 - 2)²} = √5.
Therefore, the semi-minor axis length is √5/2, and the equation of the ellipse is:
[tex]\frac{x^2}{\frac{5}{4} } +\frac{(y-\frac{\sqrt{5}}{2} )^2}{\frac{5}{4} } =1[/tex]
x² + (y-√5/2)² = 5/4
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A membership at Gisele's Gym costs $145 to join and $3 for each visit.
A membership at Freddie's Fitness costs $75 to join and $5 for each visit.
At how many visits will both cost the same?
1) define the variables: c = cost and v = total visits.
2) write the equations.
3) solve using substitution OR elimination
Answers
1. Define the variables: C = cost and V = total visits.2. Write the equations.Gisele's Gym CostFreddie's Fitness CostC = 145 + 3VC = 75 + 5V3V = 5V - 70.
Simplify the equations by subtracting 3V and 5V from both sides:2V = 70V = 35Using V = 35, substitute 35 into one of the equations to determine the cost of membership at both places:C = 145 + 3(35)C = 145 + 105C = 250This means that membership will cost the same at both gyms at 35 visits and the cost will be $250. Answer: 35 visits.
Variables:
Let c be the total cost and v be the number of visits.
Equations:
For Gisele's Gym:
c = 145 + 3v
For Freddie's Fitness:
c = 75 + 5v
Solve using substitution:
Since both costs are equal, we can set the two equations equal to each other and solve for v:
145 + 3v = 75 + 5v
Rearranging the equation:
145 - 75 = 5v - 3v
Simplifying:
70 = 2v
Dividing both sides by 2:
v = 35
Therefore, both Gisele's Gym and Freddie's Fitness will cost the same after 35 visits.
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Help me find the x please (image attached)
Answers
The measure of the arc is:
x = 120°
How to find the measure of arc x?The arc of a circle is the part or segment of the circumference of a circle. A straight line drawn by connecting the two ends of the arc is called chord of a circle.
Check the attached image for labeling.
y = 180° (semicircle)
The measure of inscribed angle is half the measure of its intercepted arc. That is:
30° = 1/2 * U
U = 2 * 30
U = 60°
x = 360 - U - y (sum of angles in a circle is 360°)
x = 360 - 60 - 180
x = 120°
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Plot this into a graph.
y = tan (x + 90°) - 1
Answers
The attached is a graph of y = tan (x + 90°) - 1. The graph will exhibit the periodic nature of the tangent function, with oscillations between positive and negative values.
Understanding Tan GraphThe function y = tan(x) represents the tangent function, which is a periodic function that oscillates between positive and negative infinity as x increases or decreases. The tangent function has vertical asymptotes at intervals of π radians (or 180°).
In the given equation y = tan(x + 90°) - 1, the entire function is shifted to the left by 90°. This means that for each x value, we are evaluating the tangent of x + 90°.
The -1 term in the equation shifts the graph downward by 1 unit.
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exponential equation 4= in x
Answers
The exponential equation of 4 = ln x is [tex]e^{4} = x\\[/tex]
The ln equation
ln x = 4
The ln equation is written in the form
[tex]ln_{b} x = y[/tex]
According to the logarithm rule
[tex]b^{y} = x[/tex]
condition of the rule are x > 0, b > 0 and b ≠ 0
Here b = e , y = 4 and x = x
Natural log ln have base e
[tex]e^{4} = x[/tex]
About logarithm - A logarithm is the opposite of a power. In other words, if we take a logarithm of a number, we undo an exponentiation. The logarithmic function log x is the inverse function of the exponential function .
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describe the level curve f(x,y)=-2x^3 5x^2-11x 8/ln(y)=30
Answers
The level curve of the function f(x,y)=-2x^3 + 5x^2 - 11x + 8/ln(y)=30 is the set of points in the (x,y) plane where the function takes a constant value of 30. To find this curve, we can start by setting the given function equal to 30:
-2x^3 + 5x^2 - 11x + 8/ln(y) = 30
We can then solve for y in terms of x:
ln(y) = 8/(30 + 2x^3 - 5x^2 + 11x)
y = e^(8/(30 + 2x^3 - 5x^2 + 11x))
This equation defines the level curve of f(x,y) at the level 30. To visualize this curve, we can plot it in the (x,y) plane using a graphing calculator or software. The resulting curve will be a smooth, continuous curve that varies in shape and size depending on the values of x and y. The curve may have multiple branches or intersect itself, depending on the nature of the function f(x,y).
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prove or disprove: if the columns of a square (n × n) matrix a are linearly independent, so are the rows of a 3 = aaa.
Answers
This statement may be true for certain matrices, but it is not true in general.
To answer this question, we first need to understand what it means for a set of vectors to be linearly independent. A set of vectors is linearly independent if no vector in the set can be expressed as a linear combination of the others. In other words, the only way to get the zero vector as a linear combination of the vectors in the set is to set all the coefficients to zero.
Now, let's consider the statement that if the columns of a square matrix A are linearly independent, then so are the rows of A^3. To disprove this statement, we just need to find a counterexample - a square matrix A whose columns are linearly independent, but whose rows are not linearly independent in A^3.
Consider the following matrix A:
A = [ 1 0 0
0 1 0
0 0 0 ]
The columns of A are clearly linearly independent, since there are no non-zero coefficients that can be used to get the zero vector. However, if we calculate A^3, we get:
A^3 = [ 1 0 0
0 1 0
0 0 0 ]
The rows of A^3 are not linearly independent, since the third row is all zeros and can be expressed as a linear combination of the first two rows.
Therefore, we have disproved the statement that if the columns of a square matrix A are linearly independent, then so are the rows of A^3. It is important to note that this statement may be true for certain matrices, but it is not true in general.
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Find the Maclaurin series for the function. (Use the table of power series for elementary functions.) f(x)=ln(x−4) f(x)=∑ n=1[infinity] ()
Answers
The series converges for values of x such that |x-4| < 1, since the series for ln(1+x) converges for |x| < 1.
To find the Maclaurin series for f(x) = ln(x-4), we can use the formula for the Maclaurin series of ln(1+x), which is:
ln(1+x) = ∑ n=1[infinity] ((-1)^ⁿ⁺ / n) * xⁿ
We can apply this formula by replacing x with (x-4), which gives us:
ln(x-3) = ln(1 + (x-4)) = ∑ n=1[infinity] ((-1)^(n+1) / n) * (x-4)ⁿ
Therefore, the Maclaurin series for f(x) = ln(x-4) is:
f(x) = ∑ n=1[infinity] ((-1)^ⁿ⁺¹ / n) * (x-4)ⁿ
This series converges for values of x such that |x-4| < 1, since the series for ln(1+x) converges for |x| < 1.
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Consider the given vector equation. r(t) = 4 sin(t)i – 2 cos(t)j (a) Find r'(t). 4 cos(t)i + 2 sin(t); (b) Sketch the plane curve together with position vector r(t) and the tangent vector r(t) for the given value of t = 37/4.
Answers
(a) The sketch of the plane curve with the given vector equation is illustrated below.
(b) The resulting picture is a curve in the xy-plane with the position vector r(37/4) and the tangent vector r'(37/4) at that point.
(c) The sketch of the position vector r(t) and the tangent vector r'(t) for the given value of t is illustrated below.
To find r'(t), we need to take the derivative of r(t) with respect to t. Since the coefficients of i and j are functions of t, we need to use the chain rule. The result is r'(t) = 4 cos(t)i + 2 sin(t)j. This vector represents the tangent vector to the curve at the point r(t) for any given value of t.
Now, let's sketch the curve together with the position vector r(t) and the tangent vector r'(t) for t = 37/4.
To do this, we can plot the point (4sin(37/4), -2cos(37/4)) on the xy-plane and draw a vector from the origin to this point, which represents r(37/4). We can also draw a tangent vector to the curve at this point, which represents r'(37/4).
Since
=> r'(37/4) = 4cos(37/4)i + 2sin(37/4)j,
we can plot this vector starting at the point r(37/4) and extending in the direction of the vector.
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Complete Question:
Consider the vector equation r ( t ) = 4 sin t i − 2 cos t j , t = 3 π / 4 .
(a) Sketch the plane curve with the given vector equation.
(b) Find r'(t).
(c) Sketch the position vector r(t) and the tangent vector r'(t) for the given value of t.
In Exercises 9-14, compute the solution of the given initial-value problem. d2 de y dr2 d2y dt2 y (0) = y(0) = 0 diy 12. +9y = sin 31 d2 14. + 4y sin 3r dr y(0) = 2, y'(0) = 0
Answers
The solution of the given initial value problem is y(r) = (1/9) cos(3r) + (1/9) sin(3r) - (1/9) sin(3r) = (1/9) cos(3r)
We are given the initial value problem:
d^2y/dr^2 + 9y = sin(3r), y(0) = y'(0) = 0 ---------(1)
We can write the characteristic equation for the given differential equation as:
r^2 + 9 = 0
The roots of the characteristic equation are: r = 0 ± 3i
So, the general solution of the homogeneous differential equation d^2y/dr^2 + 9y = 0 is:
y_h(r) = c1 cos(3r) + c2 sin(3r) ------------(2)
Now, we will find the particular solution of the given differential equation. We use the method of undetermined coefficients and assume the particular solution to be of the form:
y_p(r) = A sin(3r) + B cos(3r)
Differentiating y_p(r) w.r.t r, we get:
y_p'(r) = 3A cos(3r) - 3B sin(3r)
Differentiating y_p'(r) w.r.t r, we get:
y_p''(r) = -9A sin(3r) - 9B cos(3r)
Substituting these values in the differential equation (1), we get:
-9A sin(3r) - 9B cos(3r) + 9(A sin(3r) + B cos(3r)) = sin(3r)
Simplifying the above equation, we get:
-9A sin(3r) + 9B cos(3r) = sin(3r)
Comparing the coefficients of sin(3r) and cos(3r) on both sides, we get:
-9A = 1 and 9B = 0
Solving the above equations, we get:
A = -(1/9) and B = 0
So, the particular solution of the given differential equation is:
y_p(r) = -(1/9) sin(3r)
Therefore, the general solution of the given differential equation is:
y(r) = y_h(r) + y_p(r) = c1 cos(3r) + c2 sin(3r) - (1/9) sin(3r) ------------(3)
Now, we will apply the initial conditions to find the values of c1 and c2.
Given that y(0) = 0. Substituting r = 0 in equation (3), we get:
c1 - (1/9) = 0
So, c1 = 1/9
Differentiating equation (3) w.r.t r, we get:
y'(r) = -3c1 sin(3r) + 3c2 cos(3r) - (1/3) cos(3r)
Given that y'(0) = 0. Substituting r = 0 in the above equation, we get:
3c2 = (1/3)
So, c2 = (1/9)
Therefore, the solution of the given initial value problem is:
y(r) = (1/9) cos(3r) + (1/9) sin(3r) - (1/9) sin(3r) = (1/9) cos(3r)
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a farming community collected data on the effect of different amounts of fertilizer, x, in 100 kg/ha, on the yield of carrots, y, in tonnes. The resulting quadratic regression model is y=-0.5x^2 + 1.4x +0.1. Determine the amount of fertilizer needed to produce the maximum yield.
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The given quadratic regression model is y = -0.5x^2 + 1.4x + 0.1.
The x-coordinate of the vertex can be found using the formula: x = -b / (2a), where a and b are the coefficients of the quadratic equation (ax^2 + bx + c).
In this case, a = -0.5 and b = 1.4. Substituting these values into the formula, we get:
x = -(1.4) / (2 * (-0.5))
x = -1.4 / (-1)
x = 1.4
Therefore, the amount of fertilizer needed to produce the maximum yield is 1.4 kg/ha.
A central angle of a circle measures (2pi)/3 radians and its radius is 6 cm. What is the length of the arc intercepted by the angle?
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Okay, let's solve this step-by-step:
* The central angle measures (2pi)/3 radians
* Converting to degrees: (2pi)/3 radians = (2*3.14)/3 = 120 degrees
* The radius of the circle is 6 cm
To find the length of an arc intercepted by an angle (in degrees) and radius, we use the formula:
Arc Length = (Degrees * pi * Radius) / 180
So in this case:
Arc Length = (120 * 3.14 * 6) / 180 = 36 cm
Therefore, the length of the arc intercepted by the central angle is 36 cm.
Let me know if you have any other questions!
PLEASEEEE HELP !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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Answer:.
Step-by-step explanation:
Consider a sample of tissue cells infected in a laboratory treatment. For 225 tissues, the standard deviation for the number of cells infected was 80 and the mean was 350. What is the standard error of the sample mean?
O 0.36
O 0.50
O 5.33
O 4.33
Answers
The standard error of the sample mean is 5.33. The answer is option (C).
The standard error (SE) of a statistic is the standard deviation of its sampling distribution or an estimate of that standard deviation
The standard error of the sample mean can be calculated using the formula:
Standard error = standard deviation / square root of sample size
In this case, the standard deviation is 80 and the sample size is 225. Substituting these values in the formula, we get:
Standard error = 80 / √225 = 80 / 15 = 5.33
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A pendulum is exactly 70 cm long. If its period is 1.68 s, what is the value of g at the location of the pendulum?
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9.81 m/s².
Given that the pendulum is 70 cm long and its period is 1.68 s, we can use the formula for the period of a simple pendulum to find the value of g at the location of the pendulum:
T = 2π√(L/g)
Where T is the period (1.68 s), L is the length of the pendulum (0.7 m), and g is the acceleration due to gravity. We can rearrange the formula to solve for g:
g = 4π²L/T²
Substituting the given values:
g = 4π²(0.7 m) / (1.68 s)²
g ≈ 9.81 m/s²
The value of g at the location of the pendulum is approximately 9.81 m/s².
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convert the following equation to cartesian coordinates. describe the resulting curve. rsinθ=4the cartesian equation is ___. (type an equation.)
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The Cartesian equation is x^2 + y^2 = (4/y)^2, and the resulting curve is a circle centered at the origin with radius r = 16/y for all values of y except y = 0.
How to convert the polar equation into Cartesian coordinates?To convert the polar equation r sin(θ) = 4 into Cartesian coordinates, we can use the identities x = r cos(θ) and y = r sin(θ).
Substituting r sin(θ) = 4 into the second equation gives y = 4/r cos(θ). We can now substitute r^2 = x^2 + y^2 into this equation to get:
y = 4/√(x^2 + y^2) * x/√(x^2 + y^2)
Simplifying this equation gives:
x^2 + y^2 = (4/y)^2
This is the equation of a circle centered at the origin with radius r = 16/y. However, we need to be careful because the original polar equation is only defined for θ values where sin(θ) ≠ 0, or in other words, θ ≠ kπ for any integer k.
When we look at the Cartesian equation x^2 + y^2 = (4/y)^2, we can see that it is undefined at y = 0. However, we know that the original polar equation is defined for all values of θ except θ = kπ. Therefore, we can say that the resulting curve is a circle centered at the origin with radius r = 16/y for all values of y except y = 0.
In summary, the Cartesian equation is x^2 + y^2 = (4/y)^2, and the resulting curve is a circle centered at the origin with radius r = 16/y for all values of y except y = 0.
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reate a recursive definition for the set of all positive integers that have a 2 as at least one of its digits
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Thus, S recursively as follows:
Base case: 2 is in S.
Recursive step: If n is in S, then n2 and 2n are also in S.
A recursive definition for the set of all positive integers that have a 2 as at least one of its digits can be created as follows. Let S be the set of all positive integers that have a 2 as at least one of its digits.
Base case: The number 2 is in the set S.
Recursive step: For any n in S, we can obtain a new number in S by adding 2 as a digit to the left of n, or by appending 2 to the right of n. This means that any number in S can be obtained by starting with 2 and applying the recursive step a finite number of times.
Thus, we have defined S recursively as follows:
Base case: 2 is in S.
Recursive step: If n is in S, then n2 and 2n are also in S.
This recursive definition ensures that any positive integer that has a 2 as at least one of its digits can be generated by starting with 2 and applying the recursive step a finite number of times. It also ensures that every number generated in this way will have a 2 as at least one of its digits.
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show that if a basis i is not optimal, then there is an improving swap, which means thtat there is a pair of indices
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I think you may have accidentally cut off the question. Can you please provide the full question so that I can assist you better?
calculate the taylor polynomials t2(x) and t3(x) centered at x=4 for f(x)=ln(x+1).
Answers
The Taylor polynomials t2(x) and t3(x) centered at x=4 for f(x)=ln(x+1) are:
t2(x) = ln(5) + (x-4)/(5) - ((x-4)^2)/(50)
t3(x) = ln(5) + (x-4)/(5) - ((x-4)^2)/(50) + ((x-4)^3)/(150)
The general formula for the Taylor polynomial of degree n centered at a for a function f(x) is:
t_n(x) = f(a) + f'(a)(x-a)/1! + f''(a)(x-a)^2/2! + ... + f^n(a)(x-a)^n/n!
To find the Taylor polynomials t2(x) and t3(x) for f(x) = ln(x+1) centered at x=4, we need to evaluate the function and its derivatives at x=4.
f(4) = ln(5)
f'(x) = 1/(x+1), so f'(4) = 1/5
f''(x) = -1/(x+1)^2, so f''(4) = -1/25
f'''(x) = 2/(x+1)^3, so f'''(4) = 2/125
Using these values, we can plug them into the general formula and simplify to get:
t2(x) = ln(5) + (x-4)/(5) - ((x-4)^2)/(50)
t3(x) = ln(5) + (x-4)/(5) - ((x-4)^2)/(50) + ((x-4)^3)/(150)
Therefore, the Taylor polynomials t2(x) and t3(x) centered at x=4 for f(x)=ln(x+1) are ln(5) + (x-4)/(5) - ((x-4)^2)/(50) and ln(5) + (x-4)/(5) - ((x-4)^2)/(50) + ((x-4)^3)/(150), respectively.
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