How can a LAN be changed into a WAN?

Answer:

Here is the Coin class:

public class Coin {  //class names

 private int value;  // private member variable of type int of class Coin to store the value

 private String coinName;  // private member variable of type String of class Coin to store the coint name

 private double weight;      //private member variable of type double of class Coin to store the weight

  public void setValue (int v) {  //mutator method to set the value field

    value = v;  }  

 public void setName(String n){  //mutator method to set coinName field

    coinName = n;}  

 public void setWeight (double w) {  //mutator method to set weight field

    weight = w;  }  

 public int getValue () {  //accessor method to get the value

   return value;  }  // returns the current value

 public String getName () {  //accessor method to get the coin name

   return coinName;  }  //returns the current coin name

 public double getWeight () {   //accessor method to get the weight

   return weight;  } } //returns the current weight

Explanation:

Here is the Main.java

public class Main{ //class name

public static void main(String[] args) { //start of main method

Coin penny = new Coin(); //creates object of Coin class called penny

penny.setName("Penny");  //calls setName method of Coin using object penny to set the coinName to Penny

penny.setValue(1); //calls setValue method of Coin using object penny to set the coin value to 1

penny.setWeight(0.003); //calls setWeight method of Coin using object penny to set the coin weight to 0.003

   System.out.println("Coin name: " + penny.getName()); // calls getName method of Coin using penny object to get the current coin name stored in coinName field    

   System.out.println("Coin value: " + penny.getValue()); // calls getValue method of Coin using penny object to get the coin value stored in value field    

   System.out.println("Coin weight: " +penny.getWeight()); }} // calls getWeight method of Coin using penny object to get the coin weight stored in weight field    

The value of coinName is set to Penny, that of value is set to 1 and that of weight is set to 0.003 using mutator method and then the accessor methods to access these values and prinln() to display these accessed values on output screen. Hence the output of the entire program is:

Coin name: Penny                                                                                                                                Coin value: 1                                                                                                                                   Coin weight: 0.003

The screenshot of the program along with its output is attached.

Answer:

Here is the Python program:

d = {5:3, 4:1, 12:2}

val_of_max = d[max(d.keys())]

print(val_of_max)

Explanation:

The program works as follows:

So we have a dictionary named d which is not empty and has the following key-value pairs:

5:3

4:1

12:2

where 5 , 4 and 12 are the keys and 3, 1 and 2 are the values

As we can see that the largest key is 12. So in order to find the largest key we use max() method which returns the largest key in the dictionary and we also use keys() which returns a view object i.e. the key of dictionary. So

max(d.keys()) as a whole gives 12

Next d[max(d.keys())]  returns the corresponding value of this largest key. The corresponding value is 2 so this entire statement gives 2.

val_of_max = d[max(d.keys())] Thus this complete statement gives 2 and assigns to the val_of_max variable.

Next print(val_of_max) displays 2 on the output screen.

The screenshot of program along with its output is attached.

def something(string1, string2):

return True if string2 in string1 else False

This would be the most concise way of writing this function.

Corrected Question

Write a program that reads in 15 numbers in sorted order from the user (i.e. the user enters them in order) and stores them in a 1D array of size 15. Next, prompt the user for a number to search for in the array (i.e. the "target"). Then, print the array. Next, search the array using a linear search – find the target element and printing out the target and its index as well as the entire array

Answer:

The solution is given in the explanation section

See detailed explanation of each step given as comments

Explanation:

import java.util.*;

class Main {

 public static void main(String[] args) {

   //Create the array of 15 elements

   int [] array = new int [15];

   //Create an object of the scanner class to receive user input

   Scanner in = new Scanner(System.in);

   //Prompt user to enter the values in sorted order

   //Using a for loop

   for (int i =0; i<array.length; i++){

         System.out.println("Enter the next element: In SORTED order please!");

         array[i] = in.nextInt();

   }

   System.out.println("All Fifteen element have been entered");

   // Ask the user for an element to be searched for

   //A target element

   System.out.println("Which element do you want to search for in the array");

   //Create the target element

   int target = in.nextInt();

   //Use a for loop to sequentially check each element in the array

   for(int i = 0; i<array.length; i++){

     if(array[i]==target){

       System.out.println(target+" is found at index "+i +" of the array");

     }

   }

       // Printout the entire array

   System.out.println(Arrays.toString(array));

 }

}

Answer:

The solution is provided in the explanation section.

Detailed explanation is provided using comments within the code

Explanation:

import java.util.*;

public class Main {

//The Bubble sort method

public static void bb_Sort(int[] arr) {  

   int n = 10; //Length of array  

   int temp = 0; // create a temporal variable  

   for(int i=0; i < n; i++){  

         for(int j=1; j < (n-i); j++){  

           if(arr[j-1] > arr[j]){  

               // The bubble sort algorithm swaps elements  

               temp = arr[j-1];  

               arr[j-1] = arr[j];  

               arr[j] = temp;  

             }  

         }            

         }  

        }

 public static void main(String[] args) {

   //declaring the array of integers

   int [] array = new int[10];

   //Prompt user to add elements into the array

   Scanner in = new Scanner(System.in);

   //Use for loop to receive all 10 elements

   for(int i = 0; i<array.length; i++){

     System.out.println("Enter the next array Element");

     array[i] = in.nextInt();

   }

   //Print the array elements before bubble sort

   System.out.println("The Array before bubble sort");

   System.out.println(Arrays.toString(array));

   //Call bubble sort method

   bb_Sort(array);  

   System.out.println("Array After Bubble Sort");  

   System.out.println(Arrays.toString(array));

 }

}

Answer:

a. I think the Aluminum will conduct heat better.

b. I think the Fiberglass will insulate heat better.

Fiberglass is used to insulate most everyday items, so I can be sure that fiberglass can be the best insulator, as for aluminum it conducts heat like you wouldn't believe.

Note: Your answer doesn't have to be right, they just want you to make a prediction about your answer, that means it's alright to guess, also know I didn't guess I am just telling you that you didn't have to ask this question. <3

Answer:

To use cout statements, you must include the iostream file in your program.

Answer:

WHAT DO YOU MEAN

Explanation:

THIS IS FOR QUESTIONS ONLY !!!!

Answer:

def __str__(self):

       return ('Year: %d, VIN: %s' %(self.year_made, self.car_vin))

Explanation:

Here you go! This should do it.

The program gives an implementation of the car record class which displays the model year and registration number of a car. The program written in python 3 goes thus :

class CarRecord :

#initialize a class named carRecord

def __init__(self):

#define the init method of the class

self.year_made = 0

#year car was made is initialized to 0 (integer)

self.car_vin = ' '

#vehicle registration is an empty string

def __str__(self):

#define an str method

return f"Year:{self.year_made}, VIN:{self.car_vin}"

#returns formatted display of the year and VIN number

my_car = CarRecord()

#creates an instance of the carRecord class

my_car.year_made = int(input())

#prompts user for the model year of the car

my_car.car_vin = input()

#prompts user for the model Vin number

print(my_car)

# display the details

A sample run of the program is given

Learn more :https://brainly.com/question/20504501

Answer:

The answer is "The last memory addresses used by a specific program is 2CF0".

Explanation:

For this specific problem, we assume that only a memory storage allocation like Array data structure is needed, as well as any allocation only needs one memory cell since it focuses on the structure and type of data used.  

So, first, we will transform the provided memory address for better comprehension from Hexadecimal into decimal.  

[tex]\to \bold{(2C8D)_{16} = (11405)_{10}}[/tex]

Now 11405 is the first memory cell's address. With all of this number, it can add 99, resulting in the final decimal memory address.  

[tex]=11405 + 99\\\\= 11504[/tex]

[tex]\bold{(11504)_{10} = (2CF0)_{16}}.[/tex]

Answer:

Throughout the interpretation section elsewhere here, the explanation of the problem is summarized.

Explanation:

Answer:A 404 error is often returned when pages have been moved or deleted. ... 404 errors should not be confused with DNS errors, which appear when the given URL refers to a server name that does not exist. A 404 error indicates that the server itself was found, but that the server was not able to retrieve the requested page.

Explanation: Hope this helps

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

              //print the header

              System.out.println("**************************************");

              System.out.println("*                                    *");

              System.out.println("*                                    *");

              System.out.println("*   Gas-N-Clean Service Station      *");

              System.out.println("*                                    *");

              System.out.println("*   March 2, 2004                    *");

              System.out.println("*                                    *");

              System.out.println("**************************************");

               //set the constant values for gasoline

               final double REGULAR_GASOLINE = 2.89;

               final double PLUS_GASOLINE = 3.09;

               final double SUPER_GASOLINE = 3.39;

              // initialize the variables as 0

              double gasolinePrice = 0, gasolineCost = 0, carWashCost = 0, totalCost = 0;

               Scanner input = new Scanner(System.in);

               //ask the user to enter the gallons, gas type and car wash choice

               System.out.print("Enter number of gallons ");

               double gasolinePurchase = input.nextDouble();

               System.out.print("Enter gas type (R, P, S, or N) ");

               char gasType = input.next().charAt(0);

               System.out.print("Enter Y or N for car wash ");

               char carWashChoice = input.next().charAt(0);

               //check the gas type. Depending on the choice set the gasolinePrice from the corresponding constant value

              if(gasType == 'R')

                  gasolinePrice = REGULAR_GASOLINE;

              else if(gasType == 'P')

                  gasolinePrice = PLUS_GASOLINE;

              else if(gasType == 'S')

                  gasolinePrice = SUPER_GASOLINE;

                //calculate the gasolineCost

                gasolineCost = gasolinePurchase * gasolinePrice;

               //check the carWashChoice. If it is yes and gasolineCost is greater than 10, set the carWashCost as 1.25. Otherwise, set the carWashCost as 3.00

               if(carWashChoice == 'Y'){    

                   if(gasolineCost >= 10)

                       carWashCost = 1.25;

                   else

                       carWashCost = 3.00;

               }

              //calculate the total cost, add gasolineCost and carWashCost

              totalCost = gasolineCost + carWashCost;

               //print the values in required format

              System.out.println("Amount Gasoline purchases " + gasolinePurchase);

              System.out.println("Gallons Price per gallons $ " + gasolinePrice);

              System.out.printf("Total gasoline cost $ %.2f\n", gasolineCost);

              System.out.println("Car wash cost $ " + carWashCost);

              System.out.printf("Total due $ %.2f\n", totalCost);

               System.out.println("Thank you for stopping\nPlease come again \nRemember to buckle up and drive safely");

}  

}

Explanation:

*The code is in Java.

Please see the comments in the code for explanation

Answer:

Ill do this in C# and Java

Explanation:

C#:

public static void Main(string[] args)

       {

           string input = Console.ReadLine();

               switch (input)

               {

                   case "A1":

                       Console.WriteLine("Footwear:");

                       Console.WriteLine("Shoes");

                       break;

                   case "B1":

                       Console.WriteLine("Tops:");

                       Console.WriteLine("Jackets");

                       break;

                   case "C1":

                       Console.WriteLine("Pants:");

                       Console.WriteLine("Trousers");

                       break;

                   case "A2":

                       Console.WriteLine("Footwear:");

                       Console.WriteLine("Trainers");

                       break;

                   case "B2":

                       Console.WriteLine("Tops:");

                       Console.WriteLine("TShirts");

                       break;

                   case "C2":

                       Console.WriteLine("Pants:");

                       Console.WriteLine("Shorts");

                       break;

                   default:

                       Console.WriteLine("Incorrect Input");

                       break;

               }

       }

Java:

public static void main(String[] args)

   {

       Scanner myObj = new Scanner(System.in);  // Create a Scanner object

       String input = myObj.nextLine();

       {

           switch (input)

               {

                   case "A1":

                       System.out.println("Footwear:");

                       System.out.println("Shoes");

                       break;

                   case "B1":

                       System.out.println("Tops:");

                       System.out.println("Jackets");

                       break;

                   case "C1":

                       System.out.println("Pants:");

                       System.out.println("Trousers");

                       break;

                   case "A2":

                       System.out.println("Footwear:");

                       System.out.println("Trainers");

                       break;

                   case "B2":

                       System.out.println("Tops:");

                       System.out.println("TShirts");

                       break;

                   case "C2":

                       System.out.println("Pants:");

                       System.out.println("Shorts");

                       break;

                   default:

                       System.out.println("Incorrect Input");

                       break;

               }

       }

In python:

for i in range(56, 71):

   print(i, end=" ")

Answer:

for n in range(56,71):

   print(n, end=" ")

Explanation:

Explanation:

question a) answer:

At the moment when it sends the package, then it has a waiting time for the acknowledgement from the receiver, however, the time will be split in two when the frameset size becomes two, meaning that two packages have been sent together, causing the receiver to acknowledge only one package.

question b) answer:

The timeout is equal to two times.

In cases when the frame size is 3, the frame will be lost since the timeout turns to be 2 times. Because the sender has to wait for the acknowledgement, therefore it will send other of the parcels.

Answer:

Open your python console and execute the following .py code

Explanation:

Code bellow:

#include <iostream>

#include <iomanip>

#include <string>

using namespace std;

void inputInfo(string*, int*, int);

double mathAvr(int*, int);

void printInfo(string*, int*, int, double);

int main()

{

   double avg;  

   int n;  

   string *names;  

   int *scores;  

   char ch;

   do

   {

       cout << "\n contestants quantity: ";

       cin >> n;

       names = new string[n];

       scores = new int[n];

       inputInfo(names, scores, n);

       avg = mathAvr(scores, n);

       printInfo(names, scores, n, avg);

       delete [] names;

       delete [] scores;

       cout << "\n again? (Y/N): ";

       cin >> ch;

   }while(ch=='Y' || ch=='y');

   cout << "\n\n";

   return 0;

}

void inputInfo(string *names, int *scores, int n)

{

   int i;

   for(i=0; i<n; i++)

   {

       cout << "\n\n Name of the participant: ";

       cin >> *(names+i);

       do

       {

           cout << "\n score " << *(names+i) << " (0-100): ";

           cin >> *(scores+i);

       }while(*(scores+i) < 0 || *(scores+i) > 100);

   }

}

double mathAvr(int *scores, int n)

{

   int i, sum=0;

   double avg;

   for(i=0; i<n; i++)

   {

       sum += *(scores+i);

   }

   avg = sum / (double)n;

   return avg;

}

void printInfo(string *names, int *scores, int n, double avg)

{

   int i;

   cout << "\n\n " << left << setw(20) << "Participant name" << left << setw(6) << "Score" << " \n";

   for(i=0; i<n; i++)

   {

       cout << "\n " << left << setw(20) << *(names+i) << left << setw(6) << *(scores+i);

   }

   cout << fixed << setprecision(2);

   cout << "\n\n Average: " << avg << " \n\n";

}

Answer:

Written in Python

inp = int(input("Length: "))

num = []

num.append(inp)

for i in range(1,inp+1):

    userinp = int(input("Input: "))

    num.append(userinp)

smallest = num[1]

for i in range(1,len(num)):

    if smallest > num[i]:

         smallest = num[i]

for i in range(1,len(num)):

    num[i] = num[i] - smallest

for i in range(1,len(num)):

    print(num[i],end=' ')

Explanation:

I've added the full program as an attachment where I used comments as explanation

Answer: it’s E btw

Explanation:

Answer:

It is A and D

Explanation:

Hope this helps. :)

Answer:

110101 = 53

Hope this helps :)

To help us solve this problem, I've created a simple python program.

print(int("110101", 2))

The program prints 53 to the console.

If you search python ide online and paste that code into the ide and then replace the binary in between the quotes, you can find the value of any binary number you want.

Answer:

The answer to this question is given below in the explanation section.

Explanation:

This question is about mapping correct terms with their number in the given picture. The correct matching of Column A and Column B is given below

Column A                               Column B

Horizontal axis                        3

Legend                                    4

Vertical axis                             2

Chart Data                               1

Answer:

human performance plan

Explanation:

(for odyssey users)

Answer:

See solution below

See comments for explanations

Explanation:

import java.util.*;

class Main {

 public static void main(String[] args) {

   //PrompT the User to enter a String

   System.out.println("Enter a sentence or phrase: ");

   //Receiving the string entered with the Scanner Object

   Scanner input = new Scanner (System.in);

   String string_input = input.nextLine();

   //Print out string entered by user

   System.out.println("You entered: "+string_input);

   //Call the first method (GetNumOfCharacters)

   System.out.println("Number of characters: "+ GetNumOfCharacters(string_input));

   //Call the second method (OutputWithoutWhitespace)

   System.out.println("String with no whitespace: "+OutputWithoutWhitespace(string_input));

   }

 //Create the method GetNumOfCharacters

   public static int GetNumOfCharacters (String word) {

   //Variable to hold number of characters

   int noOfCharactersCount = 0;

   //Use a for loop to iterate the entire string

   for(int i = 0; i< word.length(); i++){

     //Increase th number of characters each time

     noOfCharactersCount++;

   }

   return noOfCharactersCount;

 }

 //Creating the OutputWithoutWhitespace() method

 //This method will remove all tabs and spaces from the original string

 public static String OutputWithoutWhitespace(String word){

   //Use the replaceAll all method of strings to replace all whitespaces

   String stringWithoutWhiteSpace = word.replaceAll(" ","");

   return stringWithoutWhiteSpace;

 }

}

Answer:

The Program written in C is as follows:

#include <stdio.h>

int main() {

   int num1, num2, num3, smallest;

   printf("Enter any three numbers: ");

   scanf("%d", &num1);    scanf("%d", &num2);    scanf("%d", &num3);

   if(num1 <= num2 && num1 <= num3) {

       smallest = num1;

   }

   else if(num2 <= num1 && num2 <= num3) {

       smallest = num2;

   }

   else {

       smallest = num3;

   }

   printf("Smallest: ");

   printf("%d", num3);

   return 0;

}

Explanation:

This line declares necessary variables

int num1, num2, num3, smallest;

This line prompts user for input of three numbers

   printf("Enter any three numbers: ");

This lines get input for the three numbers

   scanf("%d", &num1);    scanf("%d", &num2);    scanf("%d", &num3);

The following if/else statements determine the smallest of num1, num2 and num3 and assigns to variable smallest, afterwards

   if(num1 <= num2 && num1 <= num3) {

       smallest = num1;

   }

   else if(num2 <= num1 && num2 <= num3) {

       smallest = num2;

   }

   else {

       smallest = num3;

   }

The next two lines print the smallest value

   printf("Smallest: ");

   printf("%d", num3);

Answer:

Written in Python

import random

tryagain = 1

while tryagain == 1:

guess = int(input("Enter your guess number between 1 and 6: "))

num = random.randint(1,7)

if guess == num:

print("Your guess is correct")

else:

print("Wow, the dice number is "+str(num))

tryagain = int(input("Do you want to dice it up again:Enter 1 and if not enter 0: "))

Explanation:

I've added the full source code as an image attachment where I used comments to explain difficult lines

This is python code.

In python, you are supposed to put a colon at the end of while loops. This code does not have a colon after the while loop, therefore, you need to add a colon to the end of the statement.

The error to be fixed in the while loop is to add a colon at the end of the while statements.

x = 1

while (x<26)

     print(x)

     x = x + 1

This is the right code;

x = 1

while(x < 26):

   print(x)

   x = x + 1

The actual code , the while statement is missing a colon at the end of it.

The code is written in python. In python while or for loops statements always ends with a colon.

In the error code, there was no colon at the end of the while loop.

The right codes which I have written will print the value 1 to 25.

learn more on python loop here: https://brainly.com/question/19129298?referrer=searchResults

Answer:

a pop-up box

Explanation:

A voice command, mouse clicks, or keyboard strokes is the user doing something. But a pop-up box is not. I realize that a popup box could contain a user input, but the box itself is not any sort of user input. It's the opposite.

Answer:

Sentence: Jack or Peggy Zale must fix quickly the fax.

Correct: Either Jack or Peggy Zale must quickly fix the fax.

There are 2 errors in these sentence construction. In stating two persons as an option we must use the word "either" to indicate that you only have two choose from the two of them. The word "

Explanation:

The correct sentence would be "either Jake or Peggy Zale must quickly fix the fax".

In the question construction, there is a conjunction and misarrangement error.

In conclusion, the word " "either Jake or Peggy Zale must quickly fix the fax" is correct

Read more about conjunction

brainly.com/question/8094735

Answer:

The corrected program is:

import java.util.Scanner;

public class LabProgram{

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int qtr, dime, nickel, penny;

double dollars;

System.out.print("Quarters: ");

qtr =scnr.nextInt();

System.out.print("Dimes: ");

dime = scnr.nextInt();

System.out.print("Nickel: ");

nickel = scnr.nextInt();

System.out.print("Penny: ");

penny = scnr.nextInt();

dollars = qtr * 0.25 + dime * 0.1 + nickel * 0.05 + penny * 0.01;

System.out.printf("Amount: $%.2f\n", dollars);

System.out.print((dollars * 100)+" cents");

}

}

Explanation:

I've added the full program as an attachment where I used comments as explanation

Answer:

729. is answer...........

Answer:

729

Explanation: