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The binomial expansion of the [tex](x-4)^5[/tex] is  [tex]x^5+20x^4+160x^3+640x^2+1280x+1024[/tex]

According to the statement

we have given that a equation and we have to expand it by use of the binomial theorem.

So, For this purpose we know that the

A binomial theorem, statement that for any positive integer n, the nth power of the sum of two numbers a and b may be expressed as the sum of n + 1 terms of the form.

And the general formula is

[tex](x+y)^n= ^nC_0x^ny^0+^nC_1x^(n-1)y^1+^nC_2x^(n-2)y^2+...+^nC_nx^0y^n[/tex]

And we have to solve it with the given equation (x-4)^5.

Then

[tex](x-4)^5=x^5+20x^4+(20)/(2)x^3(4^2)+(60)/(6)x^2(4)^3+(120)/(24)x^1(4)^4+(120)/(120)x^0(4)^5[/tex]

Now after solving the equation become

[tex](x-4)^5=x^5+20x^4+160x^3+640x^2+1280x+1024[/tex]

So, The after expanding the given statement with the binomial theorem the result output is

[tex](x-4)^5=x^5+20x^4+160x^3+640x^2+1280x+1024[/tex]

So, The binomial expansion of the [tex](x-4)^5[/tex] is  [tex]x^5+20x^4+160x^3+640x^2+1280x+1024[/tex]

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With annual compounding, the number of years for 1000 to become 1400 is 6.7 years

With continous compounding, the number of years for 1000 to become 1400 is 1.35 years

With annual compounding, the formula that would be used is:

(In FV / PV) / r

Where:

(In 1400 / 1000) / 0.05 = 6.7 years

With continous compounding, the formula that would be used is:

(In 1400 / 1000) / (In e^r)

Where r = interest rate

((In 1400 / 1000) / (In e^0.05) = 1.35 years

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Answer:

10

Step-by-step explanation:

g(x) = 3(10-x^2)-8=>30-3x^2-8=>-3x^2+22

then substitute -2 in x

-3(-2)^2+22

-3(4)+22=-12+22=10

The equivalent expression of [tex]\sqrt x + 11 = 15[/tex] is [tex]\sqrt x = 15 - 11[/tex]

The complete question is in the attached image

The expression is given as:

[tex]\sqrt x + 11 = 15[/tex]

Subtract 11 from both sides of the equation

[tex]\sqrt x + 11 - 11= 15 - 11[/tex]

This gives

[tex]\sqrt x = 15 - 11[/tex]

Hence, the equivalent expression of [tex]\sqrt x + 11 = 15[/tex] is [tex]\sqrt x = 15 - 11[/tex]

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The quadratic equation of the data is y = 7x^2 + 13x + 3

The table of values is given as:

X 0 -1 -2.

y 3 -3 -5​

When the above values are added to the graphing calculator, we have the following summary

a = 7

b = 13

c = 3

A quadratic equation is represented as:

y = ax^2 + bx + c

So, we have:

y = 7x^2 + 13x + 3

Hence, the quadratic equation of the data is y = 7x^2 + 13x + 3

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Answer:

see explanation

Step-by-step explanation:

to evaluate f(a) substitute x = a into f(x)

f(a) = 5a + 4

---------------------

2f(a) = 2(5a + 4) = 10a + 8

-----------------------

to evaluate f(2a) substitute x = 2a into f(x)

5(a + 2) + 4 = 5a + 10 + 4 = 5a + 14

--------------------------

f(a) + f(2) ← substitute x = 2 into f(x)

= 5a + 4 + 5(2) + 4 = 5a + 4 + 10 + 4  = 5a + 18

Answer:

D. 4

Step-by-step explanation:

[tex]\sqrt{2-\left( 4\right)^{2} } =\sqrt{2-16} =\sqrt{-12}[/tex]

since ,√(-12) is not a real number

Then

The function f is not defined for x = 4

Answer:

D. 4

Step-by-step explanation:

thank you for your help 4 was the correct answer took the test and got it right

Answer:

Multiply the top equation by -3 and the bottom equation by 2

Step-by-step explanation:

Given system of equations:

[tex]\begin{cases}4x-2y=7\\3x-3y=15 \end{cases}[/tex]

To solve the given system of equations by addition, make one of the variables in both equations sum to zero.  To do this, the chosen variable must have the same coefficient, but it should be negative in one equation and positive in the other, so that when the two equations are added together, the variable is eliminated.

To eliminate the variable y:

Multiply the top equation by -3 to make the coefficient of the y variable 6:

[tex]\implies -3(4x-2y=7) \implies -12x+6y=-21[/tex]

Multiply the bottom equation by 2 to make the coefficient of the y variable -6:

[tex]\implies 2(3x-3y=15) \implies 6x-6y=30[/tex]

Add the two equations together to eliminate y:

[tex]\begin{array}{l r r}& -12x+6y= &-21\\+ & 6x-6y= & 30\\\cline{1-3}& -6x\phantom{))))))} = & 9\end{array}[/tex]

Solve for x:

[tex]\implies -6x=9[/tex]

[tex]\implies x=-\dfrac{9}{6}=-\dfrac{3}{2}[/tex]

Substitute the found value of x into one of the equations and solve for y:

[tex]\implies 3\left(-\dfrac{3}{2}\right)-3y=15[/tex]

[tex]\implies -\dfrac{9}{2}-3y=15[/tex]

[tex]\implies -3y=\dfrac{39}{2}[/tex]

[tex]\implies y=-\dfrac{39}{2 \cdot 3}[/tex]

[tex]\implies y=-\dfrac{13}{2}[/tex]

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Answer:

$4.50

Step-by-step explanation:

Okay so, first add both.

50+40 is 90, then multiply 90 by the tax percent which is

90x5%=4.5

If expression then,

x=money that they have to pay.

5%(50+40)=x    (the original)

btw there's already a question like this :

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Answer:

  (6, 1)

Step-by-step explanation:

The formula for dividing segment AB into parts in the ratio M:N is ...

  P = (M·B +N·A)/(M+N)

Using the above formula with the given values, we have ...

  P = (3(12, 3) +2(-3, -2))/5 = (36 -6, 9 -4)/5 = (30, 5)/5

  P = (6, 1)

The point P that divides segment AB into parts in the proportion 3:2 is ...

  P = (6, 1)

Using the Factor Theorem to find the equation of the parabola, we have that:

[tex]a + b + c = -\frac{48}{7}[/tex]

The Factor Theorem states that a polynomial function with roots [tex]x_1, x_2, \codts, x_n[/tex] is given by:

[tex]f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)[/tex]

In which a is the leading coefficient.

In this problem, we have a horizontal parabola, defined as follows:

[tex]f(y) = a(y - y_1)(y - y_2)[/tex].

The roots are [tex]y_1 = -1, y_2 = -7[/tex], hence:

f(y) = a(y + 1)(y + 7)

f(y) = a(y² + 8y + 7).

The x-intercept is of x = -3, hence f(0) = -3, so:

[tex]-3 = 7a[/tex]

[tex]a = -\frac{3}{7}[/tex]

Then the equation is:

[tex]x = -\frac{3}{7}y^2 - \frac{24}{7}x - 3[/tex]

Then the sum of the coefficients is:

[tex]a + b + c = -\frac{3}{7} - \frac{24}{7} - \frac{21}{7} = -\frac{48}{7}[/tex]

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Answer:

Hello!

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

The first part of this is to represent the center.

It sits at (1,-1), so the left hand part of the equation is

(x - 1)^2 + (y + 1) = r^2

That means the answer has to be either B or C. D gets knocked out of the running because of the minus sign in the middle. D does not give a circle.

B is wrong because the y value should be plus. So the answer is C. Notice because the question is multiple choice you don't need to solve for r since all answers give r^2 = 36

Answer:

yo-yo cost 2.50 dollar because if we divide 15 and 6 the answer will be 2.50

Answer:

In question 20

B) the triangles are not similar

Step-by-step explanation:

u can see that 1 triangle length is 14 and other 49 and one triangle breath is 8 and other 28 so how they are same

Answer:

IN question 19

what is your question I can't understand

Answer:

a.1

b.10

c.120

Step-by-step explanation: don't know that last one

We can see that a and b are parallel, and c and e are parallel, so the correct option is E.

On the diagram, we can see that the angles in the third quadrant of the intersections between a and c, and the intersections between b and c,  are the same angle.

Then, lines a and b must be parallel.

For the intersections with line d, we can see that this time the angle is on the fourth quadrant, so c and d are not parallel.

Finally, for line e, we can see that the known angle is on the first quadrant.

Notice that the angle on the first quadrant will be equal to the angle on the third quadrant.

So for the intersections of a and e, and b and e, on the third quadrant we have the known angle (the same one as in the intersections of a and c, and a and b).

Then c and e are parallel.

Then A and C are true.

Thus, the correct option is E.

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The number of stone pavers needed to go round the patio is 3.

The first step is to determine the perimeter of the concrete patio.

Perimeter : 12 + 12 + 14 = 38 feet

Number of stone pavers needed to go round the patio : perimeter of the patio / length of each stone paver

38 / 14 = 3

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Answer:

1 - p

Step-by-step explanation:

1 - p

The measure of the length DC to nearest tenth is 24.1 units

In order to determine the measure of DC from the figure shown, we will use the pythagoras theorem

Determine the measure of BC

BC² = 22² - 15²

BC² = 259

BC = 16.09

Determine the measure of DC

DC² = 259 + 28²
DC = √583

DC = 24.1 units

Hence the measure of the length DC to nearest tenth is 24.1 units

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Answer:

40 3/8

Step-by-step explanation:

You can just multiple it on calculator, which 1/8 is 0.125 so convert 40.375 to 40 3/8

By the way, there's already answer to this question.

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Answer:

0

Step-by-step explanation:

By the remainder theorem, this is the same as finding f(-1/2), which is equal to 0.

Answer:

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1jwjqhwhwjmnbhokmbhiknb

Answer:

Yes. {(-12, 8), (-15, 8), (-5, 8)} is function because there is no overlap in the x values.

The monthly payment for option 1 is $1755.144 and option 2 is $2088.97, total amount for option 1 is $631851.84 and option 2 is $376014.6, and on comparing option 2 will be better option.

Given that for $200,000 loan Option 1 is a 30-year loan at an APR of 10% Option 2 is a 15-year loan at an APR of 9.5%.

A concept that implies that the future value of money will be lower than its present value due to several factors such as inflation is known as TVM(time of value money).

Monthly Payments

Option 1

Loan Amount = $200,000

Number of payments = 30×12 = 360

Monthly interest rate = 10%/12 = 0.008333333

Monthly payment = Loan amount (1+ monthly interest rate)ⁿ×monthly interest rate/[(1+monthly interest rate)ⁿ- 1]

Monthly payment=200,000×(1+0.008333333)³⁶⁰×(0.008333333)/[(1+0.008333333)³⁶⁰-1]

Monthly payment=33062.328/18.83739

Monthly payment=$1755.144

Option 2

Loan Amount = $200,000

Number of payments = 15 x 12=180

Monthly interest rate = 9.5%/12=0.00792

Monthly payment = 200,000(1+0.00792)¹⁸⁰(0.00792)/[(1+0.00792)¹⁸⁰-1]

Monthly payment=6553.096/3.137

Monthly payment=$2088.97

Total Payments

Option 1

As we've found out the monthly payments, we now need to multiply it by the number of months.

$1755.144×360 = $631851.84

Option 2

$2088.97×180 = $376014.6

Conclusion

Option 2 will always be the better option economically as it saves $255837.24 ($631851.84 - $376014.6) in total payments.

Hence, For $200,000 loan Option 1 a 30-year loan at an APR of 10% Option 2 a 15-year loan at an APR of 9.5% is the monthly payment for option 1 is $1755.144 and option 2 is $2088.97, total amount for option 1 is $631851.84 and option 2 is $376014.6, and on comparing option 2 will be the better option.

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The x-coordinates of the vertices of the hyperbola are 11 and -11

The hyperbola is given as:

[tex]\frac{x^2}{121} - \frac{y^2}{49} = 1[/tex]

A hyperbola is represented as:

[tex]\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1[/tex]

Where the coordinate of the vertex is:

Vertex = (±a, 0)

By comparing the above equations, we have:

[tex]a^2= 121[/tex]

Take the square of both sides

a = 11

Substitute 11 for a in Vertex = (±a, 0)

Vertex = (±11, 0)

Hence, the x-coordinates of the vertices of the hyperbola are 11 and -11

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Answer:

- 6(6 - 2x)²

Step-by-step explanation:

using the chain rule

[tex]\frac{dy}{dx}[/tex] = [tex]\frac{dy}{du}[/tex] × [tex]\frac{du}{dx}[/tex]

let y = (6 - 2x)³

let u = 6 - 2x , then y = u³

[tex]\frac{du}{dx}[/tex] = - 2 and [tex]\frac{dy}{du}[/tex] = 3u²

then

[tex]\frac{dy}{dx}[/tex] = 3u² × - 2 = - 6(6 - 2x)²

The equivalent expression to [tex]\mathbf{(\dfrac{r}{s})(6)= \dfrac{17}{13}}[/tex]

Equivalent expressions are similar expressions that may have different forms but when a value is replaced with the variables in the same form provides the same answer.

From the information given, If:

Then the fractional form can be an expression as:

[tex]\mathbf{(\dfrac{r}{s})(x)= \dfrac{3x-1}{2x+1}}[/tex]

where;

[tex]\mathbf{(\dfrac{r}{s})(6)= \dfrac{3(6)-1}{2(6)+1}}[/tex]

[tex]\mathbf{(\dfrac{r}{s})(6)= \dfrac{18-1}{12+1}}[/tex]

[tex]\mathbf{(\dfrac{r}{s})(6)= \dfrac{17}{13}}[/tex]

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The answer is: 2(m+1)

First combine like terms.
we do 6m-4m which is 2m
2m+2=?

Second we factor. We notice that both terms have 2.
2(m+1)

by distributive law, the 2 is distributed to m and 1.