Four identical lab carts each have a mass of 200 kg. different masses are added to the carts and the velocities are measured. all carts move to the right. an illustration with four carts labeled cart a, cart b, cart c, and cart d. cart b has a 20 kilogram mass in it, cart c has a 40 kilogram mass in it, and cart d has a 60 kilogram mass in it. there are labels under each cart. under cart a is v = 4.8 meters per second, under cart b is v = 4.0meters per second, under cart c is v = 3.8 meters per second, and under cart d is v = 3.5 meters per second. which cart has the greatest momentum? cart a cart b cart c cart d

The riddle is solved by knowing that there is only one person left in the garden and that is you.

We are told that there were a total of 34 people in the yard. We do not know if these people are in the garden or somewhere around the yard. The next information we have is that a total of 30 persons were killed.

Since you killed them in the garden, the others may still be lurking somewhere in the yard thus there is only one person left in the garden and that is you.

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The area of Piston A is 13.88 in^2

What is a hydraulic system?

The hydraulic system functions by using pressurized fluid.  The power of liquid fuel in hydraulics is significant and as a result, they are commonly used in heavy equipment.

Hydraulic system simply means a mechanical function that operates through the force of liquid pressure.

Here

A hydraulic system contains 3 pistons.

Pressure, P = 1440 psi

for piston A:

Area, A= 0.625 in^2

Force, F = 20,000 lb

We know that,

Force = Pressure x Area

F = P x A

Area ( piston A) = F / P

A = 20,000 / 1440

A = 13.88 in^2

Hence,

The area of Piston A is 13.88 in^2

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The tangential speed of a lug nut on a wheel of a car will be 4.68 m/s

Given:

Distance of lug nut = 0.114 m

wheel is rotating at speed = 6.53 rev/sec

To Find:

tangential speed of a lug nut

Solution: Tangential velocity is the linear speed of any object moving along a circular path. A point on the outside edge of a turntable moves a greater distance in one complete rotation than a point near to the center

Vr = r.ω

(0114 m)(41.03 rad/s) = Vr

Vr = 4.68 m/s

Hence, tangential speed of lug nut on wheel of car is 4.68 m/s

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The electric field due to the nucleus at the location of the electron is 4.101 × 10¹² N/C.

Given:

Distance between the electron and nucleus, r = 26.5 × 10⁻¹² m

Charge on an electron, Q = 1.6 × 10⁻¹⁹ C

Calculation:

We know that the Helium atom (He²⁺) has an atomic number Z = 2  and an atomic mass number A = 2 ( 2 protons + 2 neutrons). Thus the charge of a helium atom can be calculated as:

Q' = +2e = 2(+1.6 × 10⁻¹⁹ C) = 3.2 × 10⁻¹⁹ C

We know that the electric field on charge Q due to the nucleus is given as:

E = kQ' / r²

where E is the electric field

           k is Coulomb's force constant

           Q' is a  charge ona  Helium atom

           r is the separation distance between the electron and nucleus

Applying values in the above equation we get:

E = (9×10⁹ Nm²/C²) (3.2 × 10⁻¹⁹ C) / (26.5 × 10⁻¹² m)²

  = 4.101 × 10¹² N/C

Thus, the electric field on electrons due to the Helium nucleus is of magnitude 4.101 × 10¹² N/C.

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The actual distance of Regulus from Earth is 23.81 parsecs.

Given:

Parallax of Regulus, p = 0.042 arc seconds

Calculation:

When an observer changes their position, an apparent change in the object's position takes place. This change can be calculated using the angle ( or semi-angle) made by the observer and object i.e. the angle made between the two lines of observation from the object to the observer.

Thus from the relation of parallax of a celestial body we get:

S = 1/ tan p ≈ 1 / p

where S is the actual distance between the object and the observer

            p is the parallax angle observed

Here for Regulus, we get:

S = 1 / p

  = 1 / (0.042)                                     [ 1 parsecs = 1 arcseconds ]

  = 23.81 parsecs

We know that,

1 parsecs = 3.26 light-years = 206,000 AU

Converting the actual distance into light years we get:

23.81 parsecs = 23.81 × (3.26 light yrs) = 77.658 light-years

Therefore, the actual distance of Regulus from Earth is 23.81 parsecs which is 77.658 in light years.

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The rarest type of stars is those that are more than 50 solar masses.

How are stars categorized?

Stars are categorized on the basis of mass, spectral behavior, and temperature.

There are 7 spectral types of stars:

Thus, the rarest type of stars are the O-type stars that have more than 50 times the solar mass of the sun.

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The SI unit of current is the ampere, which is defined as the flow of charge in units of coulomb over a period of time measured in seconds.

Electrical charge carriers, often electrons or atoms deficient in electrons, travel as current. The capital letter I is a typical way to represent the current. The ampere, denoted by the letter A, is the common unit. An ampere is a unit of measure of the rate of electron flow or current in an electrical conductor. One coulomb of electrical charge (6.24 x 1018 charge carriers) traveling by a given place in one second is represented by one ampere of current.

Conventional current, also known as Franklin current, is thought by physicists to flow from relatively positive points to comparatively negative locations. The most prevalent charge carriers, electrons, are negatively charged. From somewhat negative to relatively good points, they move.

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There will be no reaction force acting on the object

Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

The motion of a free falling object can be described by Newton's second law of motion,

Force (F) = mass * acceleration

a = F / m

The net external force is just the weight of the object (F = W).

Substituting into the second law equation gives:

a = W / m = m * g / m = g .

The acceleration (change of velocity) of the object then becomes the gravitational acceleration.

On freely falling body their is no normal acting on that object

hence , there will be no reaction force acting on the object

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The angular speeds of the wheels is 1,647.28 rad/min

angular velocity is the speed at which the angle between two bodies changes as an item rotates or revolves around an axis.

The diameter of a bicycle, d = 20inches

Radius, r = 10 inches

The bicycle is travelling at 16 mi/h.

We need to find the angular speed of the wheels in rad/min.

We know that,

1 mi/h = 0.0166667 mi/min

It means,

16 mi/h = 0.26 mi/min

Also,

10 inch = 0.0001578356 miles

The angular speeds of the wheels is given by :

v = rω

ω = v/r

ω = 0.26/0.0001578356

ω = 1,647.28 rad/min

So, the angular speeds of the wheels is 1,647.28 rad/min

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The forces listed are considered fundamental forces (2) gravitational (4) strong nuclear (6) electroweak.

Fundamental force, also called fundamental interaction, in physics, is any of the four primary forces—gravitational, electromagnetic, sturdy, and weak—that govern how gadgets or particles interact and how certain particles decay. All of the regarded forces of nature may be traced to those essential forces.

Now, physicists say they have discovered viable symptoms of a fifth essential force of nature. The findings come from studies performed at a laboratory near Chicago. The four fundamental forces govern how all of the objects and particles inside the Universe engage with each other.

The strong nuclear pressure pulled definitely and negatively charged quarks collectively to form undoubtedly charged protons and neutrally charged neutrons. The strong nuclear force also binds protons and neutrons within the nucleus of atoms. The weak nuclear force enabled complicated atoms to form through nuclear fusion.

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If the strength of a magnetic field at B is three units the strength of the magnetic field at A, means that point B has three times more turns as compared to point A.

We can increase the strength of the magnetic field by increasing the number of turns which increases the strength of the current flow.

So we can conclude that point B has three times more turns as compared to point A.

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By speeding up the process of doing work, power production may be enhanced. The following statement is true.

Description:

Work is completed at a rate determined by power. It is the ratio of work to time. It may be calculated mathematically using the next equation.

                                Power = Work / Time

                                 or, P = W / T

If the amount of effort/work increases and the amount of time decreases, power will grow. To complete a task in a short amount of time, a lot of force is used.

Therefore it is concluded that the questioned statement is true.

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0.07  is the magnitude of the magnetic field at a distance of 2d from the wire

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Answer: Hydrostatic equilibrium in the Sun means that pressure balances the weight of overlying layers.

Explanation: To find the answer, we have to know more about the Hydrostatic equilibrium in sun.

Thus, we can conclude that, the Hydrostatic equilibrium in the Sun means that pressure balances the weight of overlying layers.

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Through 57 revolutions the tub rotate while it is in motion.

What is angular speed?

Angular speed is defined as the rate of change of angular displacement, It is a scalar measurement of rotating object.

It is expressed as follows:  ω = θ / t.

Here,

Initially tub is at rest so,

ω(i) = 0 rev/s

ω(f) = 6 rev/s

time taken, t = 8 second

Now the total number of revolutions,

N = t * ( ω(i)+ ω(f) ) / 2

N1 = 8* ( 0+6 ) / 2

N1 = 24 rev

Now, when the lid is opened it's safety switch is off due to which it is uniformly decelerated and comes to rest in 11 s

N2 = 11* ( 0+6 ) / 2

N1 = 33 rev

So,

Total number of revolutions:

N = N1 + N2

N = 24 + 33

N = 57 revolutions

Thus,

Through 57 revolutions the tub rotate while it is in motion.

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Hudson Bay is the  restricted basin that has the coolest temperatures

Hudson Bay is a restricted basin which  remains frozen or is dominated by ice over the summer solstice and through- out much of the high-sun season. This basin experiences a harsh continental climate.

The average annual temperature in almost the entire bay is around 0 °C (32 °F) or below. In the extreme northeast, winter temperatures average as low as −29 °C or −20.2 °F. The region of this basin has very low year-round average temperatures.

This basin starts freezing up by early November, and the northern part of the basin is typically entirely iced over by the end of the month.

correct answer is Hudson bay

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The maximum height above the point of release it rises is 8.82 m

The force exerted by a spring on objects attached to its ends is proportional to the spring's change in length away from its equilibrium length.

F(spring) = k*x

here,

mass, m=0.240 kg

vertical spring constant, k = 5050 N/m

compression, x=0.090 m

When the spring is compressed, the spring potential energy is:

E = (k*x^2) / 2

substituting the values,

E = 5050* 0.090^2 / s

E = 20.91 J

This energy would be converted to kinetic, so the mass gains speed, which is then converted to gravitational potential energy once the mass reaches its highest point

E(p) = m*g*h

where, h is the maximum height

E(p) = E

m*g*h = 20.91

h = 20.91 / ( 9.8 * 0.248 )

h = 8.82 m

hence

The maximum height above the point of release is 8.82 m

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The value of the coefficient  is μ=0.18.

Find the value of this coefficient.​

The particles are in equilibrium, meaning the net force on them is zero.

Thus, repulsion due to their charge = friction due to the table.

As the equilibrium is limiting, friction reaches its maximum value.

[tex]\frac{kQ^{2} }{r^{2} }[/tex]=μmg

[tex]k=9*10^{9} Nm^{2} C^{-2}[/tex]The electrostatic constant [tex]Q=10^{-7} C[/tex]  is the charge, and r=0.1m is the distance between the charges.

[tex]\frac{(9*10^{2})(10^{-7})^{2} }{(0.1)^{2} }[/tex]=μ*[tex](5*10^{-3})(10)[/tex]

Therefore, The answer is μ=0.18.

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Answer:

The requried number of outer-orbital electrons in an atom of Na is 1, P is 5, Br is 7, I is 7, Te is 6, and Sr is 2.

An orbital is a region of space around the nucleus of an atom where there is a high probability of finding an electron. The electrons in an atom are arranged in specific energy levels or shells, and each shell contains one or more subshells, which in turn contain one or more orbitals.

Here,
To determine the number of outer-orbital electrons in an atom, we need to look at the position of the element in the periodic table. The number of outer-orbital electrons is equal to the group number of the element for groups 1, 2, and 13 to 18. For groups 3 to 12, we need to subtract the group number from 10.

a) Na is in group 1, so it has 1 outer-orbital electron.

b) P is in group 15, so it has 5 outer-orbital electrons.

c) Br is in group 17, so it has 7 outer-orbital electrons.

d) I is in group 17, so it has 7 outer-orbital electrons.

e) Te is in group 16, so it has 6 outer-orbital electrons.

f) Sr is in group 2, so it has 2 outer-orbital electrons.

Therefore, the number of outer-orbital electrons in an atom of Na is 1, P is 5, Br is 7, I is 7, Te is 6, and Sr is 2.

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Galaxy X contains more total mass within 25,000 light-years of its center than Galaxy Y.

A light-year, a significant unit of length used to express astronomical distances, is roughly 9.46 trillion kilometers, or 5.88 trillion miles. A light-year is the distance that light travels in a vacuum in one Julian year, according to the International Astronomical Union. The name "light-year" is occasionally misunderstood as a unit of time since it contains the time measurement word "year". When expressing distances to stars and other distances on a galactic scale, the light-year is most frequently employed, especially in non-specialized situations and popular science publications. The parsec, which comes from astrometry and is the distance at which one astronomical unit subtends an angle of one second of arc, is the unit that is most frequently used in professional astronomy.

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True

In place of photographic plates or films, charge coupled devices, or CCDs, are sensitive photon detectors that can be employed in telescopes to create images. CCDs were created in the late 1960s and are now found in various devices, including digital cameras and photocopiers.

CCDs are more light-efficient, catch a greater proportion of incoming photons, can store and transfer digital data, and don't require development like film does. They respond linearly and capture up to 80% of the light that strikes them.

I understand the question you are looking for is this:

One of the primary advantages of CCDs over photographic plates is the former's high efficiency in detecting light. True or false.

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Answer: The end point of a spring oscillates with a period of 2.0 s when a block with mass m is attached to it. When this mass is increased by 2.0 kg, the period is found to be 3.0 s.  Then the mass m is 0.625kg.

Explanation: To find the answer, we need to know more about the simple harmonic motion.

                                          [tex]T=2\pi \sqrt{\frac{m}{k} }[/tex]

               [tex]T_1=2s\\m_1=m\\m_2=m+2kg\\T_2=3s[/tex]

              [tex]T_1=2\pi \sqrt{\frac{m}{k} } \\T_2=2\pi \sqrt{\frac{m+2}{k} } \\\frac{T_1}{T_2} =\sqrt{\frac{m}{m+2} }\\\frac{2}{3} =\sqrt{\frac{m}{m+2} }\\\\[/tex]

               [tex]m=\frac{5}{8} =0.625kg[/tex]

Thus, we can conclude that, the mass m will be 0.625kg.

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The new magnitude of the force of attraction will be 6 times the original force of attraction

F = Gm₁m₂ / r²

F₁ = Gm₁m₂ / r²

F = Gm₁m₂ / r²

F₂ = G × 2m₁ × 3m₂ / r²

F₂ = 6Gm₁m₂ / r²

But

F₁ = Gm₁m₂ / r²

Therefore

F₂ = 6Gm₁m₂ / r²

F₂ = 6F₁

Thus, the new magnitude of the force of attraction will be 6 times the original force of attraction

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Gate-control theory

According to the Gate Control Theory of Pain, the spinal cord has a system that allows pain signals to be amplified in the brain before being processed at the spinal cord itself, or attenuated there. 

The mechanism that allows or prevents the passage of pain signals is known as the gate. The gate may be open or it may be closed, one of two possibilities: 

The administration of a non-noxious (soothing or light rubbing) stimulus can help engage the gate control mechanism and alleviate pain in those who are exposed to painful (noxious) stimuli.

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The angle that the stuck ball makes with the direction of motion and the velocity of both the billiard balls are 65°, 2.6 m/s and 5.5m/s respectively.

To find the answer, we need to know about the linear momentum and angle made in elastic 2 dimensional collision.

           0= m×v×sin25°-m×u×sin65°

            v×sin25°=u×sin65°

            v= 2.1u

                6= 2.1u× cos25° +u×cos65°

                  = 2.33u

Thus, we can conclude that the angle that the stuck ball makes with the direction of motion and the velocity of both the billiard balls are 65°, 2.6 m/s and 5.5m/s respectively.

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V = 0.9375 m3 is minimum volume .

Given,

            1000 kg/m3 = density of water

             920 kg/m3 = density of ice

BF = Woman Weight + Slab Weight

Pvg = 75 + Pvg

V = 75 kg / (1000 - 920)

V = 75 / 80

V = 0.9375 m3

Therefore, V = 0.9375 m3 is minimum volume .

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The magnitude of the average friction force on the box is 400 N

What is energy conservation?

It is the principle by which the total energy remains constant in a system that is not subject to external influence.

It states that energy can neither be created nor be destroyed, It may be transformed from one form to another.

Here,

length of the plane, d = 4 m

height of the plane, h = 2 m

work done total, w = 3200 J

kinetic energy on top, KE = 0

Potential energy on top,

PE = weight x height

PE = 800 *2

PE = 1600 J

Now,

Total work done = KE + PE + W (friction)

W (friction) = 3200 - 1600

W (friction)  = 1600 J

W (friction) = F (friction) x d

F (friction) = 1600 / 4

F (friction) = 400 N

Hence,

The magnitude of the average friction force on the box is 400 N

option A is correct

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Hydrogen, the element that is by far the most prevalent in the universe, exhibits radio emissions with a wavelength of 21 centimetres.

This makes it practical for using radio waves to explore space objects. An object in space emits radio waves that are more noticeable the more hydrogen it has.

The majority of a disk-shaped galaxy's mass is located on the galactic plane. The galactic poles are shown by directions that are perpendicular to the galactic plane.

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Answer:

Fe

Explanation:

Dựa vào dãy hoạt động hóa học của kim loại