For each value of u, determine whether it is a solution to 6u-1< −19. u Is it a solution? Yes or No 5 −4 −3 8

a = 2, b = -18, c = 40

[tex]Given:\ Polynomial\ f(x)=ax^2+bx+c\ has\ zoroes\ 4\ aud\ 5[/tex]

[tex]and\ f(-1)=60[/tex]

[tex]Tofind:\ a,\ b,\ c[/tex]

[tex]Solution:\ As\ 4\ and\ 5\ are\ zeroes\ so\ f(4)=f(5)=0[/tex]

[tex]f(4)=a(4)^2+b(4)+c=0\Rightarrow16a+4b+c=0-(1)[/tex]

[tex]f(5)=a(5)^2+b(5)+c=0\Rightarrow25a+5b+c=0[/tex]

[tex]f(-1)=a(-1)^2+b(-1)+c=60\Rightarrowa-b+c=60-(3)[/tex]

[tex]subtracting\ (1)\ from\ (2)[/tex]

[tex]25a+5b+c-(16a+4b+c)=0\Rightarrow9a+b=0\Rightarrowb=-9a[/tex]

[tex]subtracting\ (3)\ from(2):[/tex]

[tex]25a+5b+c-(a-b+c)=0-60\Rightarrow24a+6b=-60[/tex]

[tex]putting\ b=-9a[/tex]

[tex]24a+6(-9a)=-60\Rightarrow24a-54a=-60\Rightarrow-30a=-60[/tex]

[tex]a=\frac{-60}{-30}=2[/tex] [tex]\Rightarrow[/tex] [tex]a=2[/tex]

[tex]b=-9a=-9\times2=-18[/tex]

[tex]c=-a+b\neq60=-2-18+60=-20+60=40[/tex]

I hope this helps you

:)

Answer:

8

Step-by-step explanation:

A=πr^2

64π=πr^2

since answer is in terms of pi, ignore the pi.

sqrt(64)=8

Answer:

Side A is 4

Step-by-step explanation:

Answer:

A.4

Step-by-step explanation:

a = √(c² - b²)

a= √(5² -3b²)=4

Answer:

Answer:

Step-by-step explanation:

Refer to the definition of a function. I'll just give you a layman's definition to be concise.

For something to be a function, there needs to be exactly 1 output for every input. You cannot have a case where you input 1 value, and get 2 or more values as an output.

In math we call all the possible input values the domain, and we call all the possible output values the range.

Let's take a look at each situation on your worksheet.

1. Is a function. This is because only one arrow stems from each input value. There are cases where the different input values give the same output, sure, but each input returns 1 discrete thing, not an array of things.

(Think of it this way, if i had a machine that could answer any question I had with yes, no or maybe. I wouldn't want the machine to give me "yes and maybe" or "yes and no" as the result when I ask it a question. That doesn't make sense and I would think the machine is broken. What could happen, is that I ask the machine different questions, and for those different questions, it gave me the same answer, like "yes" and "yes" respectively. in that case, it would be acceptable, because it isn't contradicting itself for any individual question.)

2. Not a function. There are 2 different output values for b.

(Refer back to my machine analogy. The "machine" in this question is contradicting itself. I gave the machine one input, and the machine is telling me, "it's this and actually it's this other thing too")

3. Is a function for the same reasons as 1.

4. Isn't a function.

(It's basically telling you, the machine reads -6 as -4, but it also reads -6 as 0, and also 2. And it also tells you the machine reads -4 as -3, but it also reads it as 8. Again, the machine should only read 1 input in 1 way and not contradict itself. )

Answer:

c. 2x.

Step-by-step explanation:

16x2 - 14x

Common factor of 16 and 14 =  2'

for x2 and x it is x,

Answer: 2x.

Answer:

he correct answer is D. 12 adult tickets, 4 child ticket

Step-by-step explanation:

=======================================================

Perpendicular lines have slopes that are opposite reciprocals.

This means we take a number, flop it over, and change its sign.

In this case, we take [tex]\boxed{-3}[/tex], change its sign:

[tex]\boxed{3}[/tex]

3 can also be written as

[tex]\boxed{\frac{3}{1} }[/tex]

Now the numerator & denominator switch places:

[tex]\boxed{\frac{1}{3}}[/tex]

So that's the slope of the new line.

Now, let's write the equation in point-slope form:-

[tex]\bigstar{\underline{\boxed{\pmb{y-y_1=m(x-1)}}}[/tex]

Where

y₁  is the y-coordinate of the point (in this case, y₁ = 3)

m = slope (1/3)

x₁= the x-coordinate of the point (in this case, it's -2)

Plug in the values:-

[tex]\bigstar{\boxed{\pmb{y-3=\frac{1}{3}(x-(-2)}}[/tex]

[tex]\bigstar{\boxed{\pmb{y-3=\frac{1}{3}(x+2)} }\longleftarrow\sf{Point-Slope~Formula:)}}[/tex]

===============================================

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)

The value of the hypotenuse y will be equal to y = 2.8 inches.

The volume of the prism is equal to the product of the area of its base and the height of the prism.

[tex]\rm V=Area \ of\ triangular \ base\times Height \ of \ prism[/tex]

The volume oif the prism is =4 cubic inches

Height of the prism = x inches

Base of the right angle isosceles triangle will be =x inches

The hypotenuse is given = y

Now

[tex]\rm V=\dfrac{1}{2}\times Base\times Height \times height \ of \ prism[/tex]

[tex]V=\dfrac{1}{2} \times x \times x \times x[/tex]

[tex]x^3=8[/tex]

[tex]x=2[/tex]

Now by pythagorus theorem

[tex]y^2=h^2+b^2[/tex]

[tex]y^2=x^2+x^2[/tex]

[tex]y^2=2x^2=2\times 2^2[/tex]

[tex]y=2\sqrt{2}=2.82[/tex]

Thus the value of the hypotenuse y will be equal to y = 2.8 inches.

To know more about Volume of prism follow

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Answer:

2.8 INCHES

Step-by-step explanation:

Answer:

y = x - 5

Step-by-step explanation:

Line A

Equation

Step-by-step explanation:

percentage of green marbles=

(total green marbles÷ total marbles )×100

The length of arc of the given circle, to the nearest hundreth, is: 2.41 units.

Length of arc = ∅/360 × 2πr, where the radius of the circle is r, and the reference angle is ∅.

We are given the following:

Radius (r) = 3 units

Reference angle (∅) = 46°

Plug in the values into the length of arc formula:

Length of arc = 46/360 × 2π(3)

Length of arc = 2.41 units.

Therefore, the length of arc of the given circle, to the nearest hundreth, is: 2.41 units.

Learn more about length of arc on:

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Answer:

60 cm

Step-by-step explanation:

The perimeter of a polygon means adding up all the side lengths.

In this case, we need to add up 13, 12, 8, 8, and 19

Adding all of these gets us 60

Answer:

58.58

Step-by-step explanation:

[tex] \frac{1}{2} \times 10 \times 3 \\ 5 \times 3 = 15.....(1)[/tex]

[tex] \frac{1}{2} \times 10 \times 10 \\ 5 \times 10 = 50...(2)[/tex]

Add one and two :- 15+ 50 = 65

Answer: 10.62 irrational

Step-by-step explanation: You can divide 69.15 by 5.25 which equals 74.4 then divide by 7 which equals 10.62

Let that be x

[tex]\\ \rm\rightarrowtail tan\theta=\dfrac{Perpendicular}{Base}[/tex]

[tex]\\ \rm\rightarrowtail tan20=\dfrac{x}{10}[/tex]

[tex]\\ \rm\rightarrowtail 0.364=\dfrac{x}{10}[/tex]

[tex]\\ \rm\rightarrowtail x=10(0.364)[/tex]

[tex]\\ \rm\rightarrowtail x=3.64mi[/tex]

Answer:

[tex]\displaystyle 4\:mi.[/tex]

Step-by-step explanation:

[tex]\displaystyle \frac{10}{h} = cot\:20 \hookrightarrow 10 = hcot\:20 \hookrightarrow \frac{10}{cot\:20} = h; 3,6397023427... \\ \\ \boxed{4 \approx h}[/tex]

OR

[tex]\displaystyle \frac{h}{10} = tan\:20 \hookrightarrow 10tan\:20 = h; 3,6397023427... \\ \\ \boxed{4 \approx h}[/tex]

I am joyous to assist you at any time.

Answer:

Step-by-step explanation:

Isolate the term of x and y from one side of the equation.

3x+y=8 and 6x+2y=10

x=8-y/3

Solve.

Rewrite the problem down.

6*8-y/3+2y=10

Then, solve.

16=10

Therefore, the final answer is no solution.

I hope this helps you! Let me know if my answer is wrong or not.

Answer:

h = 24 cm

Step-by-step explanation:

Let [tex]x[/tex] = height of ΔCBD

Let [tex]h[/tex] = height of ΔABE

As ΔABE ~ ΔCBD then AE : CD = [tex]h[/tex] : [tex]x[/tex]

Given:

[tex]\implies 20 : 10 = h : x[/tex]

[tex]\implies \dfrac{20}{10}=\dfrac{h}{x}[/tex]

Cross multiply:

[tex]\implies 20x=10h[/tex]

Simplify:

[tex]\implies 2x=h[/tex]

As we are told that [tex]x+h=36 \ \sf cm[/tex]

[tex]\implies h=36-x[/tex]

Equate the two equations for [tex]h[/tex] and solve for [tex]x[/tex]:

[tex]\implies 2x=36-x[/tex]

[tex]\implies 3x=36[/tex]

[tex]\implies x=12[/tex]

Since [tex]h=2x[/tex] then

[tex]\implies h=2 \cdot 12[/tex]

[tex]\implies h=24 \ \sf cm[/tex]

Answer:

The graph of g is translated down 5 units from the graph of f and stretched horizontally

Step-by-step explanation:

was correct on test :)

pls brainliest XD

.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.

Answer:

Monica has 1 more card than Joey

Step-by-step explanation:

its simple math

Answer:

(n/4)-1

Step-by-step explanation:

Answer:

256x^8

Step-by-step explanation:

Hope this helped

Maybe mark brainiest?

Answer:

The coordinate of the image of a point is (2, +3) under the translation (x , y) → (x - 2),( y + 3). Find the coordinate of the preimage.

We are just looking for x and y and we know (2, +3) → (x - 2, y + 3)

2 = x - 2

x = 4

-3 = y + 3

y = -6

(x , y) = (4, -6)

How to find a 

Answer:

8

Step-by-step explanation:

first multiple 12 by 12 then divide by 18 then you'll get 2 times 4 and that's how you get 8.

Answer:

5x/1/2 = 1x



answer  1.12 <3


hope it helps


use brainly<3

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

Answer:

Step-by-step explanation:

Anything going from lower left to upper right is a positive slope.

The lines are not easily seen. My best estimate is that one point is (2,5)

Use the two points you are sure of.

(0,-1) and (1,2)

Givens

Formula

m = (y2 - y1)/(x2 - x1)

Solution

m = (2 - - 1) / (1 - 0)

m = 3/1

m = 3

Answer:

Choice a 10 cm

Step-by-step explanation:

Volume of a sphere; 4/3 x 3.14(r^3)

Since we dont know the radius aka r, we can put in the different values until we get what we are looking for :)

!!!used an online calculator for this!!!

Choice a: 4188.79

Choice b: 50965.01

Choice c: 38792.39

Choice d: 5575.2

Since none of the answers are coming out as 4846.59, I would go with the closest one, choice a.

I really hope this helps!!

Please rate!!

Have a wonderful day!!

The average squared distance between the points is their variance

The average squared distance is 8/3

The given parameters are:

R={(x,y): 0<=x<=2, 0<=y<=2}

The point = (2,2).

f(x,y) = (x-2)² + (y-2)²

The squared distance is calculated as:

D² = f(x,y) = (x-2)² + (y-2)²

Where the area (A) is:

A = xy

Substitute the maximum values of x and y in A = xy

A = 2 * 2

A = 4

The minimum values of x and y are 0.

So, the limits for the integrals are 0 to 2

The integral becomes

[tex]D\² = \int \int (x-2)\² + (y-2)\² dx dy[/tex]

Expand

[tex]D\² = \int \int x\² -4x + 4 + (y-2)\² dx dy[/tex]

Evaluate the inner integral with respect to x from 0 to 2

[tex]D\² = \int \frac 13x^3 -2x^2 + 4x + x(y-2)\² |\limits^2_0 dy[/tex]

Expand

[tex]D\² = \int [\frac 13(2)^3 -2(2)^2 + 4(2) + (2)(y-2)\²] dy[/tex]

Simplify

[tex]D\² = \int \frac 83 + (2)(y-2)\² dy[/tex]

Expand

[tex]D\² = \int \frac 83 + 2y^2-8y + 8 \ dy[/tex]

Evaluate the integral with respect to y from 0 to 2

[tex]D\² = [\frac 83y + \frac 23y^3- 4y^2 + 8y ]|\limits^2_0[/tex]

Expand

[tex]D\² = \frac 83*2 + \frac 23*2^3- 4*2^2 + 8*2[/tex]

D² = 32/3

The average squared distance (AD²) is calculated as:

AD² = D²/A

So, we have:

AD² = 32/3 [tex]\div[/tex] 4

Evaluate the quotient

AD² = 32/12

Simplify

AD² = 8/3

Hence, the average squared distance is 8/3

Read more about average distance or variance at:

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The average squared distance between the points of R = {(x,y): 0<=x<= h, 0<=y<=k } is 8/3.

How do determine the average squared distance?

From the given parameters R = {(x,y): 0<=x<= h, 0<=y<=k }

The squared distance from point (h, k) is calculated as

D² = f(x,y) = (x-2)² + (y-2)²

Where the area (A) will be

A = xy

Substitute the maximum values of x and y

A = 2 × 2 = 4

The minimum values of x and y are 0.

So, The integral becomes

[tex]D^{2} = \int \int(x-2)^2 +(y-2)^2 dx dy\\\\D^{2} = \int \int\limits^2_0 (x)^2 -4x + 4+(y-2)^2 dx dy\\\\D^{2} = \int1/3(x)^3-2x^{2} +4x + 4+x(y-2)^2 dy\\\\D^{2} = \int8/3+2y^{2} -8y +8 dy[/tex]

[tex]D^2 = {8/3y +2/3y^2 -4y^2+8y[/tex]

By expanding we get,

D^2 = 32/3

The average squared distance (AD²) is calculated as:

AD² = D²/A

AD² = 32/3  4

AD² = 32/12

AD² = 8/3

Hence, the average squared distance is 8/3

Read more about average distance;

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2×+3y=6

-8×-3y=12

-6×=18

×=18/-6

×=-3

——————

2×+3y=6

2(3)+3y=6

6+3y=6

3y=6-6

3y=0

Y=0/3

Y=0

——————

×=3

Y=0

————

2×+3y=6

2(3)+3(0)=6

6=6