Find the measures of all the angles in the rhombus shown below.
31
1
5
2
4
3

Answer:

A=x-3

B=X-14

C=X-10

Answer:

part 1: $532.95. Part 2: 16

Step-by-step explanation:

Part 1: 15 * 15.35 = 230.25

30 * 10.09 = 302.70

230.25 + 302.70 = $532.95

Part 2: R = letters in the word desk

there are 4 letters in the word Desk

[tex]2^{R}[/tex] = [tex]2^{4}[/tex] = 2 * 2 * 2 * 2 = 4 * 4 = 16 subsets

Answer:

Area = 160 cm²

Perimeter = 55.31 cm

Step-by-step explanation:

Applying,

Area of the figure = area of the rectangle- area of the triangle

A = lw+bh/2............... Equation 1

From the question,

Given: l = 16 cm, w = 12 cm, h = 8cm, b = 8 cm

Substitute these values into equation 1

A = (16×12)-(8×8/2)

A = 192-32

A = 160 cm²

Perimeter P = /BC/+/CD/+/DE/+/EF/+/FG/+/GA/

Applying pythagoras theorem to get /FG/

FG² = GE²+EF²

FG² = 8²+8²

FG² = 64+64

FG² = 128

FG = √128

FG = 11.31 cm

Therefore,

P = 16+12+4+8+11.31+4

P = 55.31 cm

Answer:

24.6

Step-by-step explanation:

take 72 degree as reference angle

using tan rule

tan 72 = opposite / adjacent

3.07 = x/8

3.07 * 8 = x

24.56 = x

24.6 = x

Answer:

The two column proof is presented as follows;

Statement  [tex]{}[/tex]                            Reason

ΔSCW ≅ ΔTUW [tex]{}[/tex]                    Given

[tex]\overline {SV}[/tex] ≅ [tex]\overline {TU}[/tex] [tex]{}[/tex]                               CPCTC

[tex]\overline {SW}[/tex] ≅ [tex]\overline {TW}[/tex]  [tex]{}[/tex]                            CPCTC

[tex]\overline {WV}[/tex] ≅ [tex]\overline {UW}[/tex] [tex]{}[/tex]                            CPCTC

∠SVW ≅ ∠TUW  [tex]{}[/tex]                   CPCTC

SU = SW + UV [tex]{}[/tex]                       Additive property of Length

TU = TW + VW [tex]{}[/tex]                       Additive property of Length

SU = TW + VW [tex]{}[/tex]                       Substitution

SU = TV [tex]{}[/tex]                        [tex]{}[/tex]          Transitive property

ΔSTV ≅ ΔTSU  [tex]{}[/tex]                       SAS

∠TSV ≅ ∠STU [tex]{}[/tex]                        CPCTC

Step-by-step explanation:

The two column proof is presented as follows;

Statement  [tex]{}[/tex]                            Reason

ΔSCW ≅ ΔTUW [tex]{}[/tex]  Given

[tex]\overline {SV}[/tex] ≅ [tex]\overline {TU}[/tex] [tex]{}[/tex]            Congruent Parts of Congruent Triangles are Congruent

[tex]\overline {SW}[/tex] ≅ [tex]\overline {TW}[/tex]  [tex]{}[/tex]         Congruent Parts of Congruent Triangles are Congruent                  

[tex]\overline {UV}[/tex] ≅ [tex]\overline {VW}[/tex] [tex]{}[/tex]         Congruent Parts of Congruent Triangles are Congruent                  

∠SVW ≅ ∠TUW  [tex]{}[/tex]Congruent Parts of Congruent Triangles are Congruent                  

SU = SW + UV [tex]{}[/tex]    Additive property of Length

TU = TW + VW [tex]{}[/tex]   Additive property of Length

SU = TW + VW [tex]{}[/tex]    Substitution

SU = TV [tex]{}[/tex]              Transitive property

ΔSTV ≅ ΔTSU  [tex]{}[/tex]   Side-Angle-Side rule of congruency

∠TSV ≅ ∠STU [tex]{}[/tex]     Congruent Parts of Congruent Triangles are Congruent                  

Answer:

total= 98

Step-by-step explanation:

so the way to do this is to find the total surface area of the white bench and then subtract the interfacing portion for the support, and then total surface area of support and also subract the area of the interface with the white as well as the ground

bench top area

area of long side *number of sides + area of end *number of ends

(9*2)*4+(2*2)*2= 72+8=80

interface area is area of long side of red portion

5*2=10

support area is same as bench top for rationale

(5*2)*4+(2*2)=40+8=44

total surface area = area of white + area of red - 2* interface area - bottom of red that interfaces with the ground

total = 80+48-2*10-(5*2)

total = 128-20-10

total= 98

Answer:

CP = ₹ 700

Step-by-step explanation:

Let the cost price be 'x'

SP = [tex](\frac{100+Profit}{100})*CP[/tex]

   [tex]= \frac{100+10}{100}*x\\\\=\frac{110}{100}*x\\\\= \frac{11}{10}x[/tex]

If it had been sold are 10% loss, then

SP = [tex](\frac{100-loss}{100})*CP[/tex]

     [tex]=\frac{100-10}{100}*x\\\\=\frac{90}{100}*x\\\\=\frac{9}{10}x[/tex]

Difference in both the selling price =  140

[tex]\frac{11}{10}x-\frac{9}{10}x=140\\\\\\\frac{2}{10}x=140\\\\\frac{1}{5}x=140\\\\ x = 140*5\\x = 700[/tex]

Answer:

A

Step-by-step explanation:

The line is parallel to y axis, so the equation is x = 5

Given:

Two points are A(6,1) and B(9,4).

To find:

The equation of the line that passes through the given points.

Solution:

If a line passes through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], then the equation of the line is:

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

It is given that the line passes through the two points A(6,1) and B(9,4). So, the equation of the line is:

[tex]y-1=\dfrac{4-1}{9-6}(x-6)[/tex]

[tex]y-1=\dfrac{3}{3}(x-6)[/tex]

[tex]y-1=1(x-6)[/tex]

[tex]y-1=x-6[/tex]

Adding 1 on both sides, we get

[tex]y-1+1=x-6+1[/tex]

[tex]y=x-5[/tex]

Therefore, the equation of the line is [tex]y=x-5[/tex].

Answer:

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!;;;;!!!!!!!!!!!

The required equation of graph f(x) is y = -x²-3.

A parabola is a U-shaped plane curve where any point is at an equal distance from a fixed point (known as the focus) and from a fixed straight line which is known as the directrix.

here, we have,

Given that,

The graph of f(x), resembles the graph of G(x) =x^2 .

We have to find,

Which of the following could be the equation of  f(x).

According to the question,

Function, G(X) = x^2 ,

The graph in the given question figure. It is a parabola with vertex at (0,0).

By the graph predict that Sign of  x^2 is positive, that is why the parabola opens up.

General equation of parabola is given by,

y = a(x-h)^2 + k

Where, a = 1, and vertex (h, k) is (0,0).

The graph of F(x) unknown function opens down ,

Sign of x^2 as negative. and the vertex is at (0,-3)

To find the equation of function f(x),

Putting the values of a and vertex coordinates,

y = a(x-h)^2 + k

The equation of parabola become:

y = -x²-3.

(solving we get)

Hence, The required equation of f(x) is y = -x²-3.

For more information about Parabola click the link given below.

brainly.com/question/4074088

#SPJ7

The image of the diagram is missing, so i have attached it.

Answer:

a = 30°

Step-by-step explanation:

From the diagram attached, we can see that the 2 angles a and 5a are interior supplementary angles.

The sum of interior supplementary angles is 180°

Thus;

5a + a = 180

6a = 180

a = 180/6

a = 30°

Answer:

Domain:  all real numbers

Step-by-step explanation:

The domain is the values that x can take

X can be any real number

Domain:  all real numbers

Answer:

A. 120

Step-by-step explanation:

600÷60=10

10×12=120

Hope this helps! :)

Answer:

Step-by-step explanation:

set the equation for the area equal to the equation of the perimeter.

Then solve for x

-----------------------------

Figure a

area = perimeter

3x = 2(x + 3)

Distribute

3x = 2x + 6

subtract 2x from both sides

x = 6

perimeter

p = 2(x + 6)

p = 2(3 + 63)

p = 18

Area

a = 3x

a = 3*6

a = 18

----------------------------

Use the same method on the remaining figures

Answer:

TRUE

Step-by-step explanation:

Answer:

true i think

Step-by-step explanation:

Answer:

q ≥ 5/7

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

-6q + 7 ≤ 8q - 3

Step 2: Solve for q

Here we see that any number q greater than or equal to 5/7 would work as a solution to the inequality.

Answer:

q ≥ [tex]\frac{5}{7}[/tex]

Step-by-step explanation:

Given

- 6q + 7 ≤ 8q - 3 ( add 6q to both sides )

7 ≤ 14q - 3 ( add 3 to both sides )

10 ≤ 14q ( divide both sides by 2 )

5 ≤ 7q ( divide both sides by 7 )

[tex]\frac{5}{7}[/tex] ≤ q , then

q ≥ [tex]\frac{5}{7}[/tex]

Answer:

l

Step-by-step explanation:

Answer:

2103 bags

Step-by-step explanation:

8412/4=2103

Answer:

[tex]A^{I}[/tex]= (7, -1)

Step-by-step explanation:

Rotation is a method of rigid transformation in which a point is moved about a reference point through a stated angle. The rotation could be clockwise or counterclockwise so as to produce the image of the initial object.

In the polar coordinate given, the coordinate of A is given as;

A = (3, 3)

On rotating point A about point C counterclockwise for [tex]270^{o}[/tex], an image [tex]A^{I}[/tex] would be produced.  

But [tex]A^{I}[/tex] would have a coordinate;

[tex]A^{I}[/tex]= (7, -1)

The image of A produced is [tex]A^{I}[/tex] (7, -1).

Answer:

b

Step-by-step explanation:

Answer: B <S

Step-by-step explanation:

Answer:

pretty sure its 40cm

Step-by-step explanation:

hope this helps :)

Answer:

36cm

Step-by-step explanation:

Tan(14/12)=angle of ONP

Tan(42/X)=angle of LNM

singe those angels are the same;

Tan(14/12)=Tan(42/X)

14/12=42/X

14*X=42*12

X=(42*12)/14

X=36

Answer:

true

Step-by-step explanation:

[tex]dahil \: alam \: ko \: \: masagutan \: ko \: mayn[/tex]

Answer:

x = 1.817

Step-by-step explanation:

[tex]x^3 = 6\\\sqrt[3]{x} = \sqrt[3]{6} \\x = 1.817[/tex]

Answer:

m = 9, n = 2

Step-by-step explanation:

Find [tex]f^{-1}[/tex] (x) by letting y = f(x) and rearranging making x the subject, that is

y = mx + n ( subtract n from both sides )

y - n = mx ( divide both sides by m )

[tex]\frac{y-n}{m}[/tex] = x

Change y back into terms of x with x = [tex]f^{-1}[/tex] (x) , then

[tex]f^{-1}[/tex] (x) = [tex]\frac{x-n}{m}[/tex]

Given [tex]f^{-1}[/tex] (x) = g(x) , then

[tex]\frac{x-n}{m}[/tex] = [tex]\frac{x-2}{9}[/tex]

By comparison of the 2 sides

m = 9 and n = 2

Answer:

Area = 42.43 square cm

Step-by-step explanation:

Using Heron's Formula :

 [tex]Area = \sqrt{s\times (s-a) \times (s-b) \times(s -c)} \ , \ where \ s \ =\ \frac{a+ b+ c}{2}[/tex]

Find Area :

[tex]s = \frac{11 + 9 + 10 }{2} = \frac{30}{2} = 15[/tex]

[tex]Area = \sqrt{15 \times ( 15 - 11 ) \times { (15 - 9 ) \times ( 15 -10)}\\\\[/tex]

      [tex]= \sqrt{15 \times 4 \times 6 \times 5}\\\\=\sqrt{1800}[/tex]

      [tex]= 42 . 43 \ cm^2[/tex]

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

[tex]\huge\underline{\sf{\red{Problem:}}}[/tex]

[tex]\huge\underline{\sf{\red{Choices:}}}[/tex]

[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]

[tex] \quad \quad \underline{ \boxed{\sf{ \red{ B.)\: {y | y = –9, –3, 0, 5, 7} }} }}[/tex]

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

#CarryOnLearning

[tex]\sf{\red{✍︎ C.Rose❀}}[/tex]