Find the coordinates of the vertices of the figure after the given transformation: T<0,7>

Answer:

y= 5x/7 -27/7

if they are parallel there gradient is the same

m1=m2

y-y1=m(x-x1)

plug in the gradient and points E

y-(-3)=5/7( x-4)

y= 5/7(x) -20/7 +3

final answer

y= 5/7(x) +1/7

Answer:

[tex](f/g)(4)=8[/tex]

Interpretation: 4 elephants traveled at a speed of 8 miles per hour

Step-by-step explanation:

Given

[tex]f(x) = 4x + 8[/tex]

[tex]g(x) = x -1[/tex]

Required

[tex](f/g)(4)[/tex]

This is calculated as:

[tex](f/g)(4)=\frac{f(4)}{g(4)}[/tex]

We have:

[tex]f(x) = 4x + 8[/tex]

[tex]f(4) = 4 * 4 + 8 =24[/tex]

[tex]g(x) = x -1[/tex]

[tex]g(4) = 4 - 1 = 3[/tex]

So:

[tex](f/g)(4)=\frac{f(4)}{g(4)}[/tex]

[tex](f/g)(4)=\frac{24}{3}[/tex]

[tex](f/g)(4)=8[/tex]

Answer:

Answer:C) 8; The elephants’ rate in miles per hour

Step-by-step explanation:

First write the question as an equation that can be solved to give you a numerical answer.

[f(4)=4(4)+8] / [g(4)=(4)-1]

Then solve the equation.

24/3=8

Finally use background information to give you the context.

Since the problem gives you the function for distance and the function for time then it can be concluded that the context will be the elephants’ rate in miles per hour

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

55/11=5

Answer:

SSS

Step-by-step explanation:

Same Sides Subtract

The congruence theorem that can be used to prove that ΔBDA ≅ ΔBDC is: D. SSS

The SSS Congruence Theorem is a theorem that proves that if one triangle has three sides that are congruent to the three corresponding sides of a another triangle, both triangles are congruent.

Thus, ΔBDA and ΔBDC both have three pairs of congruent corresponding sides, namely:

Therefore, the congruence theorem that can be used to prove that ΔBDA ≅ ΔBDC is: D. SSS

Learn more about the SSS Congruence Theorem on:

https://brainly.com/question/25425647

Answer:

Rs 8160

Step-by-step explanation:

Principal = Rs 6000

Time = 3 years

Rate = 12%

Simple Interest = ?

Amount = ?

Simple Interest = PTR/100

=6000*3*12/100

=216000/100

=2160

Amount = principal + Interest

=Rs 6000 + Rs 2160

=Rs 8160

Step-by-step explanation:

Principal = Rs. 6000

Time = 3yrs 8months = 3⅔ yrs.

Rate = 12% pa.

SI = ?

Amount = ?

SI = PRT/100 = (6000×12×11)/(100×3) = 2640

Amount = SI+P = 2640+6000 = Rs. 8640

hope this helps you.

Answer:

y = |x - (-2)| -3

Step-by-step explanation:

Answer:

You would do the change in y over the change in x.  

That means you subtract your y values and that's the numerator.  Subtract your x values and that is your denominator.  Then simplify.

(4 - 4)

______

(-2 - 2)

Step-by-step explanation:

Answer: y=4

Step-by-step explanation:

4 is the y-intercept. The slope is 0

Answer:

its D

Step-by-step explanation:

Answer:

its probably D your welcome

Answer:

x=57°

Step-by-step explanation:

the sum of the measures of the angles of a triangle add up to 180°.

it is given that there is a 33°, and a right angle which is 90°.

to find x:

x=180°-(90°+33°)

x=180°-123°

x=57°

Answer:

180° - 33° - 90° = 57°

x = 57°

Answer:

P(AUB)'=2/15

Step-by-step explanation:

According to the Question,

So, P(B)=1-P(B') ⇒ P(B)=1-(1/3) ⇔ P(B)=2/3

P(A∩B)=3/5 × 2/3 ⇒ P(A∩B)=2/5

Thus, P(AUB)= 3/5 + 2/3 - 2/5

P(AUB)=1/5 + 2/3

P(AUB)=(3+10)/15 ⇔P(AUB)=13/15

Answer:

RST is not an equilateral

Step-by-step explanation:

Given

[tex]R = (-2,-2)[/tex]

[tex]S = (1,4)[/tex]

[tex]T = (4,5)[/tex]

Required

Prove or disprove the triangle is equilateral

To do this, we simply calculate the distance between each vertex using:

[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex]

So, we have:

[tex]RS = \sqrt{(-2 - 1)^2 + (-2 - 4)^2}[/tex]

[tex]RS = \sqrt{45}[/tex]

[tex]ST = \sqrt{(1 - 4)^2 + (4 - 5)^2}[/tex]

[tex]ST = \sqrt{10}[/tex]

[tex]RS \ne ST[/tex] means the triangle is not an equilateral

Answer:

D

Step-by-step explanation:

Given

5 - [tex]\sqrt{c+5}[/tex] = 1 ( subtract 5 from both sides )

- [tex]\sqrt{c+5}[/tex] = - 4 ( multiply both sides by - 1 )

[tex]\sqrt{c+5}[/tex] = 4 ( square both sides )

c + 5 = 4² = 16 ( subtract 5 from both sides )

c = 11

The value of c is 11 when n = 5.To find the value of c in the equation [tex]n - \sqrt(c + 5) = 1[/tex] when n = 5, you can simply substitute n with 5 and then solve for c.

Given equation: [tex]n - \sqrt(c + 5) = 1[/tex]

Now, replace n with 5:

[tex]5 - \sqrt(c + 5) = 1[/tex]

Next, isolate the square root term by moving the constant term to the other side:

[tex]sqrt(c + 5) = 5 - 1\\sqrt(c + 5) = 4\\[/tex]

Now, square both sides of the equation to eliminate the square root:

[tex](c + 5) = 4^2\\c + 5 = 16[/tex]

Finally, isolate c:

c = 16 - 5

c = 11

So, the value of c is 11 when n = 5.

To know more about equation:

https://brainly.com/question/10724260

#SPJ2

[tex] \huge \mathrm{ \underline{Ànswér : }}[/tex]

let's solve for " x "

[tex]➢ \: \: 4(6x - 9.5) = 46[/tex]

[tex]➢ \: \: 6x - 9.5 = \dfrac{46}{4} [/tex]

[tex]➢ \: \: 6x - 9.5 = 11.5[/tex]

[tex]➢ \: \: 6x = 11.5 + 9.5[/tex]

[tex]➢ \: \: 6x = 21[/tex]

[tex]➢ \: \: x = \dfrac{21}{6} [/tex]

[tex]➢ \: \: x = 3.5[/tex]

[tex] \mathrm{✌TeeNForeveR✌}[/tex]

Answer:

y = -1/2x - 3 1/2    exact fractions

y = -0.5x - 3.5     exact decimals

Step-by-step explanation:

From the two points indicated on the graph

rise goes from -4  to -5 = -1

run goes from 1 to 3 = 2

m = slope = rise/run = -1/2

slope intercept form is

y = mx+b

to find "b" use either point

using (1, -4)

-4 = (-1/2)(1) + b

-4 = -1/2 + b

Add 1/2 to both sides

-3 1/2 = b

The equation is

y = -1/2x - 3 1/2     exact fractions

y = -0.5x - 3.5     exact decimals

Answer:

measure of arc QR = 28.8°

Step-by-step explanation:

Full circle = 100% = 360°

Measure of arc QR = percentage covered by arc QR / 100 × 360

arc QR covers 8%

Therefore:

measure of arc QR = 8/100 × 360°

measure of arc QR = 0.08 × 360°

measure of arc QR = 28.8°

Answer:

8x² + 8

Step-by-step explanation:

Given

(x² + 3)² - (x² - 1)² ← expand factors using FOIL

= [tex]x^{4}[/tex] + 6x² + 9 - ([tex]x^{4}[/tex] - 2x² + 1) ← distribute by - 1

= [tex]x^{4}[/tex] + 6x² + 9 - [tex]x^{4}[/tex] + 2x² - 1 ← collect like terms

= 8x² + 8

Answer:

t = 16

Step-by-step explanation:

Hope this helped :]

Now,

10/5t - 75 = 12/6

10*6 = 12 (5t - 75)

60 = 60t - 900

60 + 900 = 60t

960 = 60t

t = 960/60

t = 16

I hope it's help you...

Mark me as brainliest...

Answer:

yes

because the descent of the ball is 32m per second

Step-by-step explanation:

To determine if the relationship is proportional, determine the descent of the ball per second

after 2 seconds = 64 / 2 = 32

after3 seconds = 96/3 = 32

after 4 seconds = 128 / 4 = 32

the relationship is proportional

Answer:

A. 4

Step-by-step explanation:

HG = 6,

PO = 8

HG = ½(PO + MN) => Trapezoid Mid-segment Theorem

Plug in the values into the equation

6 = ½(8 + MN)

Multiply both sides by 2

2*6 = 8 + MN

12 = 8 + MN

12 - 8 = 8 + MN - 8 => Subtraction Property of Equality

4 = MN

MN = 4

Answer:

i think it is 4 because it is lowering by 2 from  po-8 to  hg-6. my answer: mn-4

Step-by-step explanation:

Answer:

the nun I think so

actually it may be wrong ☺️

Answer:

2 grams

Step-by-step explanation:

a = 145 * (1/2)⁶

a = 2.265625

Rounded

2 grams

Answer:

5000

Step-by-step explanation:

100/52=?

?x2600=5000

Answer:

x=5000

Step-by-step explanation:

100%=5000

branliest

Answer:

4.5

Step-by-step explanation:

The Interesecting Secants Theorem states that when two secant lines intersect each other outside a circle, the products of their segments are equal. A secant is a straight line that cuts a curve in two or more points, so this definitely applies here, as both AB and CB interesect the circle twice.

Using this theorem, we can say that 6*3=4*x, so 18=4*x and x=4.5

Answer:

The answer is - 25

If it is correct then make it brainlist

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\large\textsf{8(-3) + (-1)}[/tex]

[tex]\large\textsf{= 8(-3) - 1}[/tex]

[tex]\large\textsf{8(-3) = \boxed{\large\textsf{\bf -24}}}[/tex]

[tex]\large\textsf{-24 - 1}[/tex]

[tex]\large\textsf{= \underline{\bf -25}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: \huge \bf -25}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

C. The temperature increase went down because it became cooler as the sun went down for the night

Step-by-step explanation:

It is natural to have high temperatures when the sun is up, and as dusk begin to set, the temperature of a place drops. L

Going by the above stated fact, to explain the hours after the peak increase in temperature, it is plausible to conclude that as the sun went down, it became cooler for the night. That's why we have the lowest temperature displayed on the graph between 10 PM to 11:59 PM.

Answer:

Negative 80 x + 28 y minus 56

4 (negative 20 x + 7 y minus 14)

Answer:

Range: 0.07

Median: 0.145

Mode: none

Step-by-step explanation:

Range: largest #- smallest #

Median: middle number (when numbers are in order least to greatest) or when two are middle number you add them, and divide by two

Mode: most occurring number(s) (if there aren't any, no mode)—but if there are multiples such as 2 zeros and 2 ones then 0 and 1 would be the mode

Answer:

See below

Step-by-step explanation:

For a right triangle, there are relationships between the sides and the angles of the triangle:

[tex]sin\theta=\frac{opposite}{hypotenuse}[/tex]

[tex]cos\theta=\frac{adjacent}{hypotenuse}[/tex]

[tex]tan\theta=\frac{opposite}{adjacent}[/tex]

I would study the attached image for a better understanding.

Answer:

ok kdkdkddkkdkdkkfkffk

Answer:

37

Explanation:

3 + 3 + 3 + 3 + 3 + 3 + 3 + 4 + 4 + 4 + 4

if my answer did help mark me as brainlist :D

Given:

The function is:

[tex]f(x)=2x^2-14x+10[/tex]

The function g(x), the image of f(x) after a [tex]r_{y=x}[/tex] (reflection over the line y=x).

To find:

The function g(x).

Solution:

We have,

[tex]f(x)=2x^2-14x+10[/tex]

Substitute [tex]f(x)=y[/tex] in the given function.

[tex]y=2x^2-14x+10[/tex]

The function g(x), the image of f(x) after a [tex]r_{y=x}[/tex] (reflection over the line y=x). So, interchange x and y.

[tex]x=2y^2-14y+10[/tex]

Now, we need to find the value of y.

[tex]x=2(y^2-7y+5)[/tex]

[tex]\dfrac{x}{2}=y^2-7y+5[/tex]             [Divide both sides by 2]

[tex]\dfrac{x}{2}-5=y^2-7y[/tex]             [Subtract 5 from both sides]

Add both sides half of square of coefficient of y, i.e. [tex](\dfrac{-7}{2})^2[/tex], to make it perfect square.

[tex]\dfrac{x}{2}-5+(\dfrac{-7}{2})^2=y^2-7y+(\dfrac{-7}{2})^2[/tex]

[tex]\dfrac{x}{2}-5+\dfrac{49}{4}=y^2-7y+(\dfrac{7}{2})^2[/tex]

[tex]\dfrac{x}{2}-5+\dfrac{49}{4}=\left(y-\dfrac{7}{2}\right)^2[/tex]          [tex][\because (a-b)^2=a^2-2ab+b^2][/tex]

[tex]\dfrac{x}{2}+\dfrac{49-20}{4}=\left(y-\dfrac{7}{2}\right)^2[/tex]

Taking square root on both sides, we get

[tex]\pm\sqrt{\dfrac{x}{2}+\dfrac{29}{4}}=y-\dfrac{7}{2}[/tex]

[tex]\dfrac{7}{2}\pm\sqrt{\dfrac{2x+29}{4}}=y[/tex]

[tex]\dfrac{7}{2}\pm\dfrac{\sqrt{2x+29}}{2}=y[/tex]

[tex]\dfrac{7\pm \sqrt{2x+29}}{2}=y[/tex]

Substituting [tex]y=g(x)[/tex], we get

[tex]\dfrac{7\pm \sqrt{2x+29}}{2}=g(x)[/tex]

Therefore, the required function is [tex]g(x)=\dfrac{7\pm \sqrt{2x+29}}{2}[/tex].