Find k so that the line through (-4,1) and (k,3) is perpendicular to 8x + 13y = 26

Answers

Answer 1

The value of K so that the line passing through (-4, 1) and (k, 3) is perpendicular to 8x + 13y = 26 is solved to be

k = 68/13

How to the value of K

A linear function consists of functions where the variables has exponents of 1. the relationship is expressed in the slope intercept form as below.

y = mx + c

definition of variable to suit the problem

y = output variable

m = slope

x = input variable

c = y intercept

The given equation is rewritten in slope intercept form as follows

8x + 13y = 26

13y = 26 - 8x

y = 2 - 8/13 x

the slope is 8/13

For a perpendicular line the slope = -1/m

= -1/(8/13)

= -13/8

For a line to have a slope of -13/8, the points will be

-13/8 = (1 - 3) / (-4 - k)

cross multiplying

-13(-4 - k) = 8(1 - 3)

52 + 13k = -16

solving for k

13k = -16 - 52

13k = 68

k = 68/13

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Step-by-step explanation:

its a solution because in the graph below, 5.3 is in the shaded region. hope this helped!!

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Step-by-step explanation:

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Some biologists believe the evolution of handedness is linked to complex behaviors such as tool-use. Under this theory, handedness would be genetically passed on from parents to children. That is, left-handed parents would be more likely to have lefthanded children than right-handed parents. An alternate theory asserts that handedness should be random, with left- and right-handedness equally likely. In a recent study using a simple random sample of n  76 right-handed parents, 50 of the children born were right-handed. ( pˆ =0.658 .) Suppose handedness is a random occurrence with either hand equally likely to be dominant, implying that the probability of a right-handed offspring is p =0.50.

Required:
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b. Assuming left- and right-handed children are equally likely from right-handed parents, what is the probability of observing a sample proportion of at least p̂ =0.658 ?

Answers

Answer:

a) Since both np >= 5 and n(1-p) >= 5,  it is reasonable to approximate the sampling distribution of p^‚ using a normal distribution.

b) 0.5 = 50% probability of observing a sample proportion of at 0.658.

Step-by-step explanation:

a. Show that it is reasonable to approximate the sampling distribution of p̂ using a normal distribution.

We need that:

np >= 5

n(1-p) >= 5

Sample of 76, 50 of the children were born were right-handed.

So [tex]n = 76, p = \frac{50}{76} = 0.658[/tex]

np = 76*0.658 >= 5

n(1-p) = 76*0.342 >= 5

Since both np >= 5 and n(1-p) >= 5,  it is reasonable to approximate the sampling distribution of p^‚ using a normal distribution.

b. Assuming left- and right-handed children are equally likely from right-handed parents, what is the probability of observing a sample proportion of at least p̂ =0.658 ?

This is the mean, so 50% below and 50% above.

0.5 = 50% probability of observing a sample proportion of at 0.658.

3
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Answers

Answer:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

2308/9 = 256 7/16

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Answers

Answer:

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Step-by-step explanation:

He had 1/3 of a can.

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Answer:

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Step-by-step explanation:

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Answer:

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ill solve rest in comments

9x3+5x2=37

8-(7-5)^2+8=12

10-3+5+5x4=32

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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What is a function?

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Learn more about functions, click;

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