Find a function for the graph below.
a. f(t) = 3 cos 41
b. ft) = 8 sin 3t
fit) = 3 sin 41
d. (t) = 3 cos 6

Step-by-step explanation:

it clearly says (and also shows it by specifying 4cm × 4cm side lengths) : a square base.

so, all net diagrams not having a square in the middle (but a rectangle or a triangle) are out.

and in fact, all 3 that have a square in the middle, are valid nets that would fold up to the pyramid : the 2nd, 4th and 6th.

Answer:

point A is the answers for the question

Step-by-step explanation:

please mark me as brainlest

Question :-

Answer :-

Explanation :-

As per the provided information in the given question, we have been given that the Area of Triangle is 48 cm² . It's Height is given as 6 cm . And, we have been asked to calculate the Base of Triangle .

For calculating the Base of Triangle , we will use the Formula :-

[tex] \bigstar \: \: \: \boxed{ \sf{ \: Area \: _{Triangle} \: = \: \frac{1}{2} \: \times \: B \: \times \: H \: }} [/tex]

Where ,

Therefore , by Substituting the given values in the above Formula :-

[tex] \dag \: \: \: \sf { Area \: _{Triangle} \: = \: \dfrac{1}{2} \: \times \: Base \: \times \: Height } [/tex]

[tex] \longmapsto \: \: \: \sf {48 \: = \: \dfrac {1}{2} \: \times \: Base \: \times \: 6 } [/tex]

[tex] \longmapsto \: \: \: \sf {48 \: \times \: 2 \: = \: 1 \: \times \: Base \: \times \: 6} [/tex]

[tex] \longmapsto \: \: \: \sf {96 \: = \: 1 \: \times \: Base \: \times \: 6} [/tex]

[tex] \longmapsto \: \: \: \sf {96 \: = \: 6 \: \times \: Base } [/tex]

[tex] \longmapsto \: \: \: \sf {Base \: = \: \dfrac {96}{6} } [/tex]

[tex] \longmapsto \: \: \: \textbf {\textsf {Base \: = \: 16 \: cm}} [/tex]

Hence :-

[tex] \underline {\rule {180pt} {4pt}} [/tex]

A triangle has an area of 48 square centimetres. The height of the triangle is 6 centimetres. What is the base of the triangle ?

[tex] \blue{\boxed{Area \: of \: triangle = \frac{1}{2} \times b \times h}}[/tex]

Where ,

In this question the concept belongs to the areas of two dimensional shapes i.e. how we can find length , breadth or height with the help of given area .

[tex] \longmapsto \: 48 = \frac{1}{2} \times b \times 6[/tex]

Now , transposing 2 to left hand side :

[tex] \longmapsto \: 48 \times 2 = 1 \times b \times 6[/tex]

Now , multiplying 48 with 2 and multiplying b with 1 and 6 :

[tex] \longmapsto \: 96 = 6b[/tex]

Now , transposing 6 to left hand side :

[tex] \longmapsto \: \cancel\frac{96}{6} = b[/tex]

Now , by cancelling them we get :

[tex] \longmapsto \: \red{ \boxed{ \sf{b = 16 \: cm}}}[/tex]

We know that area of triangle is equal to 48 cm². So :

[tex] \rightarrow \: \frac{1}{ \cancel2} \times \cancel{16} \times 6 = 48[/tex]

Now , by cancelling 16 with 2 we get :

[tex] \rightarrow \: 8 \times 6 = 48[/tex]

So , by multiplying we get :

[tex] \rightarrow \: 48 = 48[/tex]

That means :

[tex] \rightarrow \: L.H.S = R.H.S[/tex]

Answer:

mean

Step-by-step explanation:

The mean will decrease, in an option of mean, mode, median and range:)

Answer:

perimeter=21 area=12

Step-by-step explanation:

perimeter- 5+6+10=21

area- b x h x 1/2

6x4/2

24/2

12

Answer: 64 inches

Step-by-step explanation:

Answer:

1152°

Step-by-step explanation:

interior angles of polygon = (n - 2) x 180, where n is the number of sides.

Decagon has 10 sides. 10 - 2 = 8 and 8 x 180 = 1440

Since there are 10 angles, Each angle a= 1440 / 10, which equals 144.

Finally, multiply 144 by 8 and you get 1152°

The Pythagorean theorem is the idea that the sum of the two legs which are both squared is equal to the hypotenuse's length squared.

     *look at the image I attached for a better explanation

By looking at the picture, we are missing the leg's length, and by using the Pythagorean theorem, we get the equation

    [tex]?^2+5^2 = 13^2\\?^2 + 25 = 169\\?^2 = 144\\? = 12[/tex]

Thus the missing side length is 12 cm

Hope that helps!

Answer:

Graphs pairs of numerical data, with one variable on each axis, to look for a relationship between them

Step-by-step explanation:

The scatter diagram graphs pairs of numerical data, with one variable on each axis, to look for a relationship between them. If the variables are correlated, the points will fall along a line or curve. The better the correlation, the tighter the points will hug the line.

Answer:

Step-by-step explanation:

The largest number of groups they can be split into and have the same number of boys and girls on each team is 6 groups

Given:

Number of girls = 12

Number of boys = 16

Find the highest common factor of 12 and 16

12 = 1, 2, 4

18 = 1, 2,4

The highest common factor of 12 and 16 is 4

Number of girls in each group = 12/4

= 3 girls

Number of boy in each group = 18/4

= 4.5 boys=5

Therefore, the group can be split into 4 groups to have 3 girls and 5 boys in each group

Answer:

A) 9 and 15.

Step-by-step explanation:

First, let's see what each number's factor is:

A)

9 : 1, 3 & 9

15 : 1, 3, 5 & 15

B)

6 : 1, 2, 3 & 6

10 : 1, 2, 5 & 10

C)

8 : 1, 2, 4 & 8

12 : 1, 2, 3, 4, 6 & 12

Therefore, The number 3 is a common factor of A) 9 and 15.

___

Answer:

the answer without rounding is 147 but with its 100

Step-by-step explanation:

firsts you add up both sides of the triangle and then you subtract by 180 and now that you your answer but you had to round AN anyting above 150 you would have to run to 200 but you had one 47 so it's 100

Answer:

20 and 13

Step-by-step explanation:

If one list is 'a' and the other one is 'b' then

a-b = 7 and a+b = 33

a-b+a+b = 7+33

2a = 40

a = 20

Now, 20 - b = 7

-b = -13

b = 13

Answer:

True I'm pretty sure. Just check to be sure.

Step-by-step explanation:

Answer:

Label ELabel E

Step-by-step explanation:

Label ELabel ELabel k

Answer:

D

Step by step explanation:

[tex]x^3 \cdot \sqrt[3]{x}\\\\=x^3 \cdot x^{\tfrac 13}\\\\=x^{3+ \tfrac 13}\\\\=x^{\tfrac{10}3}[/tex]

Step-by-step explanation:

each pack 15 pencil

n* 15= 15n

Answer:

the quotient of 18 and 3 is 6

Step-by-step explanation:

do the inverse and get 6x3=18

Answer:

86.5

Step-by-step explanation:

Length of the string forms the hypotenuse AC of right angle triangle ABC.

C is the kite. A is the hand of the person (or, one end of the string). CB is the perpendicular

(height of the kite) from C on the ground. BC is the horizontal.

Sin 60° CB/AC = √3/2

height = 1.73/2 AC = 0.865 * 100 m = 86.5 m

Answer:

The first x=4       y=8

Step-by-step explanation:

2x-5 = y-5

x+1 = y-3

  Multiply the second by -2(to eliminate x)

  2x-5 =y-5

 -2x-2= -2y+6

      ADD BOTH

-7 = -y+1

y=8

            PLUG y

x+1 =y-3

x+1 =8-3

x+1=5

x=4

Answer:

11.9

Step-by-step explanation:

Making sure your calculator is in degree mode, we have:

[tex] \cos(32) = \frac{x}{14} [/tex]

[tex]x = 14 \cos(32) = 11.9[/tex]

Answer:

Question 3

Given expression:

[tex]\sf \left(\dfrac{-8}{9} \times \dfrac{1}{-5}\right)+\left(\dfrac{-8}{9} \times \dfrac{-7}{11}\right)[/tex]

Both parentheses share a common term.

To factor out a common term: ab + ac = a(b + c)

[tex]\textsf{Factor out the common term }\dfrac{-8}{9}[/tex]

[tex]\sf \implies\dfrac{-8}{9} \times \left(\dfrac{1}{-5}+\dfrac{-7}{11}\right)[/tex]

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Question 4

To calculate the amount of money Rajni had to begin with, sum the three amounts she spent:

[tex]\sf \implies total=10\frac14+25\frac34+16\frac12[/tex]

As [tex]\sf a\frac{b}{c}=a+\frac{b}{c}[/tex], then:

[tex]\sf \implies 10+\frac14+25+\frac34+16+\frac12[/tex]

Collect and sum the whole numbers:

[tex]\sf \implies (10+25+16)+\frac14+\frac34+\frac12[/tex]

[tex]\sf \implies 51+\frac14+\frac34+\frac12[/tex]

As  [tex]\sf \frac14+\frac34=\frac44=1[/tex], then

[tex]\sf \implies 51+1+\frac12[/tex]

[tex]\sf \implies 52+\frac12[/tex]

[tex]\sf \implies 52\frac12[/tex]

The cost to buy the flooring for Raul's bedroom is $364.65.

A scale drawing is a reduced form in terms of dimensions of an original image / building / object

Actual length of the bedroom = 4 x 3.25 = 13 feet

Actual length of the bedroom = 4 x 2.75 = 11 feet

Area = 143 square feet

Cost = 143 x 2.55 = $364.65

To learn more about scale drawings, please check: https://brainly.com/question/26388230

The car on a Ferris wheel with a radius of 20 feet. travels a distance of 125.6 feet.

In order to determine the distance that the car has travelled, we will use the formula for calculating the circumference of a circle.

C = 2πr

where

r = radius

Therefore,

r is the radius of the fairy wheel

r = 20 ft

C = 2 × 3.14 × 20

C = 40 × 3.14

C = 125.6 ft

This shows that the car on a Ferris wheel with a radius of 20 feet. travels a distance of 125.6 feet

learn more on circumference here: https://brainly.com/question/23385261

The length of the wire is the perimeter of the wire

The radius of the circle is 1.59 meters

The length of the wire is given as:

L  = 20m

When cut into two pieces, we have:

The circumference of the circle is calculated using:

C = 2πr

So, we have:

2πr = 10

Make r the subject

r = 10/2π

Evaluate the quotient

r = 1.59

Hence, the radius of the circle is 1.59 meters

Read more about radius at:

https://brainly.com/question/9554871

The weight of the third heaviest among the four dogs is 2 kg.

An equation is an expression that shows the relationship between two or more numbers and variables.

The 4 dogs weight is 60 kg with each dog weight been different. The second heaviest dog weighs 28 kg.

Let the heaviest dog be 29 kg, the third heaviest be 2 kg and the fourth be 1 kg.

29 + 28 + 2 + 1 = 60 kg

The weight of the third heaviest among the four dogs is 2 kg.

Find out more on equation at: https://brainly.com/question/2972832

YES IS THE ANSWER BECAUSE X=9

AND 11+3=87

Answer:

⠀

Step-by-step explanation:

⠀

We know,

[tex]{\longrightarrow \qquad \boldsymbol{\pmb{Area_{(semicircle)} = \dfrac{1}{2}( \pi {r}^{2} ) }}}[/tex]

⠀

Where,

⠀

Now, Substituting the values in the formula :

⠀

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it \dfrac{1}{2} \times 3.14 \times ({8})^{2} }}}[/tex]

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it \dfrac{1}{ \cancel2} \times 3.14 \times \cancel{64} }}}[/tex]

⠀

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it {1} \times 3.14 \times 32 }}}[/tex]

⠀

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it {1} \times 100.48 }}}[/tex]

⠀

[tex]{\longrightarrow \qquad \boldsymbol{ \pmb{Area_{(semicircle)} \approx \it 100.48 }}}[/tex]

⠀

Therefore,

Answer:

100.48 cm² ( option 2 )

Step-by-step explanation:

Given:-

To find:-

Solution:-

Area of semi-circle :-

[tex] \frac{1}{2} \pi \: r {}^{2} [/tex]

1/2 × 3.14 × 8²

[tex]100.48 \: cm {}^{2} [/tex]