During a chemical reaction, an iron atom became the ion Fe2+. What happened to the iron atom?

Answer:

i think C  is the answer

Explanation:

The change in average annual temperatures on earth will be due to "photosynthesis by plants and algae".

Photosynthesis can be defined as a process in which plants, as well as other organisms, as well as other organisms, utilize to transform sunlight into chemical energy which can then be released to power the organism's activities using cellular respiration.

Plants seem to be mostly photosynthetic eukaryotes belonging to the plantae kingdom.

Therefore, photosynthesis cannot change in average annual temperature on Earth.

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Answer: The mass of sample that remained is 0.127 mg

Explanation:

The integrated rate law equation for first-order kinetics:

[tex]k=\frac{2.303}{t}\log \frac{a}{a-x}[/tex] ......(1)

Given values:

a = initial concentration of reactant = 0.500 mg

a - x = concentration of reactant left after time 't' = ?mg

t = time period = 28 s

k = rate constant = [tex]0.049s^{-1}[/tex]

Putting values in equation 1:

[tex]0.049s^{-1}=\frac{2.303}{28s}\log (\frac{0.500}{(a-x)})\\\\\log (\frac{0.500}{(a-x)})=\frac{0.049\times 28}{2.303}\\\\\frac{0.500}{a-x}=10^{0.5957}\\\\frac{0.500}{a-x}=3.94\\\\a-x=\frac{0.500}{3.942}=0.127mg[/tex]

Hence, the mass of sample that remained is 0.127 mg

Answer:

See explanation and image attached

Explanation:

Nitrogen trichloride NCl3 contains one nitrogen and three chlorine atoms. Each chlorine atom has three lone pairs of electrons while nitrogen has one lone pair of electrons.

The molecule geometry of the molecule is trigonal pyramidal while it's electron domain geometry is tetrahedral. Nitrogen is the central atom and is found in sp3 hybridization.

There is no formal charge on the molecule.

Answer:

sim eu também preciso desta respota

An ether and alkene are formed as by products in the reaction which is a electrophilic addition reaction.

An addition reaction known as an electrophilic addition reaction occurs when a chemical molecule having a double or triple bond has one of its bonds broken and two new bonds are formed. The interconversion of C=C and CC into a variety of significant functional groups, such as alkyl halides and alcohols, is made possible via the key.

The following describes the general mechanism: Hydrogen bromide produces an electrophile, H+, which attacks the double bond to create a carbocation. The production of ions is dominated by secondary carbocation because it is more stable than primary carbocation.

Thus, an ether and alkene are formed as by products in the reaction which is a electrophilic addition reaction.

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Answer:

d

Explanation:

nCl2 = 0,1 -> nRCI = 0,2

M muéi = R + 35,5 = 14,9/0,2

-> R = 39: R la K

Answer:

d

Explanation:

nCl2 = 0,1 -> nRCI = 0,2

M muéi = R + 35,5 = 14,9 / 0,2

-> R = 39: R la K

Answer:

Số gam muối ăn cần là 76:42,7%=177,986 g

Explanation:

Answer:

0.2 M

Explanation:

Step 1: Given data

There are different ways to express the concentration of a solution. We will calculate molarity, which is one of the most used.

Step 2: Calculate the moles of sucrose

The molar mass of sucrose is 342.3 g/mol.

15 g × 1 mol/342.3 g = 0.044 mol

Step 3: Calculate the molarity of the solution

Molarity is equal to the moles of solute divided by the liters of solution.

M = 0.044 mol/0.2 L = 0.2 M

Answer:

Mixture of a Strong Acid and a Strong Base

On mixing a strong acid and strong base neutralization (pH = 7) takes place. The resulting solution may be an acid or base depending on the Concentration. Say, N1, V1 is the strength and volume of the strong acid and N2, V2 is the strength and volume of the strong base

Explanation:

Most introductory chemistry books will teach that the reaction between an acid and a base is called neutralization, and the products formed are water and a salt

Answer:

The answer is "5.4".

Explanation:

[tex]BoH + HCL =BCL +H_2o \\\\At eq \\\\N_1V_1=N_2V_2 \\\\v_2=20 \ ml\\\\[BCL]=\frac{20 \times 0.08}{20+20}=0.04\\\\pH = \frac{1}{2} [pkw - pk_b - \log e]\\\\pk_b = 2 pH - Pkw + \Log C\\\\pK_b=5.4[/tex]

Answer:

A:Itasca

A:ItascaB:Hubbard

A:ItascaB:HubbardC:Douglas

A:ItascaB:HubbardC:DouglasD:Grand Marais

E:Two harbors

F:Duluth

Answer:

Duluth, Twin Harbors and Grand Marais because they are on the coast of the lake.

Explanation:

Answer:

Water forms more hydrogen bonds than HF

Explanation:

The answer to this question goes back to the idea of hydrogen bonding. Hydrogen bonding occurs when hydrogen is bonded to a highly electronegative atom such as fluorine or oxygen.

However, in HF, there are three lone pairs of electrons on fluorine atom and one hydrogen atom bonded to fluorine.

In H2O, there are two lone pairs of electrons on oxygen atom and two hydrogen atoms bonded to oxygen. This simply means that water can form four hydrogen bonds while HF only forms two hydrogen bonds.

This implies that H2O molecules possess more hydrogen bonding than HF molecules. Hence, the molar enthalpy of vaporization for liquid hydrogen fluoride is lesser than that for water.

Answer:

b . uranium, It is not a renewable resource.

Answer:

The solubility of the gaseous solute decreases

Explanation:

As we know, pressure decreases with altitude. This means that, at higher altitudes, the pressure is much lower than it is at sea level.

The solubility of a gas increases with increase in pressure and decreases with decrease in pressure.

Hence, in Denver, Colorado where the elevation is about 5,280 feet above sea level, a gaseous solute is less soluble than it is at sea level due to the lower pressure at such high altitude.

The question is incomplete, the complete question is:

When 177. g of alanine [tex](C_3H_7NO_2)[/tex] are dissolved in 800.0 g of a certain mystery liquid X, the freezing point of the solution is [tex]5.9^oC[/tex] lower than the freezing point of pure X. On the other hand, when 177.0 g of potassium bromide are dissolved in the same mass of X, the freezing point of the solution is [tex]7.2^oC[/tex] lower than the freezing point of pure X. Calculate the van't Hoff factor for potassium bromide in X.

Answer: The van't Hoff factor for potassium bromide in X is 1.63

Explanation:

Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.

The expression for the calculation of depression in freezing point is:

[tex]\Delta T_f=i\times K_f\times m[/tex]

OR

[tex]\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}[/tex] ......(1)

[tex]\Delta T_f=5.9^oC[/tex]

i = Vant Hoff factor = 1 (for non-electrolytes)

[tex]K_f[/tex] = freezing point depression constant

[tex]m_{solute}[/tex] = Given mass of solute (alanine) = 177. g

[tex]M_{solute}[/tex] = Molar mass of solute (alanine) = 89 g/mol

[tex]w_{solvent}[/tex] = Mass of solvent = 800.0 g

Putting values in equation 1, we get:

[tex]5.9=1\times K_f\times \frac{177\times 1000}{89\times 800}\\\\K_f=\frac{5.9\times 89\times 800}{1\times 177\times 1000}\\\\K_f=2.37^oC/m[/tex]

[tex]\Delta T_f=7.2^oC[/tex]

i = Vant Hoff factor = ?

[tex]K_f[/tex] = freezing point depression constant = [tex]2.37^oC/m[/tex]

[tex]m_{solute}[/tex] = Given mass of solute (KBr) = 177. g

[tex]M_{solute}[/tex] = Molar mass of solute (KBr) = 119 g/mol

[tex]w_{solvent}[/tex] = Mass of solvent = 800.0 g

Putting values in equation 1, we get:

[tex]7.2=i\times 2.37\times \frac{177\times 1000}{119\times 800}\\\\i=\frac{7.2\times 119\times 800}{2.37\times 177\times 1000}\\\\i=1.63[/tex]

Hence, the van't Hoff factor for potassium bromide in X is 1.63

Answer:

1. B

2. A

3. C

Explanation:

1. Boyle's law is one of the gas laws that states that the pressure of a gas is inversely proportional to its volume at a constant temperature. PV = K. Hence, this gas law compares the properties of the pressure (P) and the volume (V)

2. Avogadro's law states that the volume of a gas is directly proportional to the number of molecules of that gas, at a constant temperature and pressure. K = Vn. Hence, this gas law compares the properties of the number of moles (n) and the volume (V).

3. Gay-Lussac's law states that the pressure of a gas is directly proportional with the temperature of the gas at a constant volume. K = PT. Hence, this law compares the properties of the pressure (P) and the temperature (T)

The properties compared by Boyle's law are pressure and volume, Avogadro's law is volume and moles, and Gay-Lussac's law is pressure and temperature.

The ideal gas has the absence of interatomic collisions and follows the ideal gas equation.

The ideal gas law at constant pressure and temperature is termed Boyle's and Gay Lussac's law. The laws can be given as:

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Answer:

mwlooy kagabi jal

64 JAHA VI PHÂN KAY

Answer:

The same number of each atom are on both sides of the equation.

The Law of conservation of mass states that matter is neither destroyed nor created in a chemical reaction. Therefore, the mass of the reactants will be equal to the mass of the products in a chemical reaction. According to the law matter is neither created nor destroyed in a chemical reaction.

Answer: here you go

Explanation:

Physical properties of the substances in a mixture are different, so this allows the substances to be separated. Think about the example of a mixture of salt water.

Answer:

Mixtures can be classified on the basis of particle size into three different types: solutions, suspensions, and colloids. The components of a mixture retain their own physical properties. These properties can be used to separate the components by filtering, boiling, or other physical processes.

Explanation:

Explanation:

can u post a picture of the question ?

Answer:

electrovalent

NaCl

Lithium Carbonate

ammonium phosphate

aluminium floride

potassium hydride

covalent

methane

benzene

carbon iv oxide

hydro flouride

hydro chloride

Answer: The molarity of NaCl solution is 0.0489 M

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

[tex]\text{Molarity of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}[/tex] .....(1)

We are given:

Given mass of NaCl = 0.8 g

Molar mass of NaCl = 58.44 g/mol

Volume of the solution = 280 mL

Putting values in equation 1, we get:

[tex]\text{Molarity of solution}=\frac{0.8\times 1000}{58.44\times 280}\\\\\text{Molarity of solution}=0.0489M[/tex]

Hence, the molarity of NaCl solution is 0.0489 M

Answer:

Give the IUPAC name for the following alkyl group, and classify it as primary, secondary, or tertiary.

CH3(CH2)9CH2

Explanation:

In the given alkyl group there are eleven carbon atoms.

So, the alkyl group name is:

n-undecyl.

Pimary carbon is the one which is attached only one other carbon atom,group.

Secondary carbon is the one which is attached to two carbons.

Thertiary carbon is the one which is attached to three other carbons.

In the given alkyl group,

the primary,secondary alkyl groups are shown below:

There is no tertiary carbon atom in the given molecule.

Answer: The value of [tex][H_{3}O^{+}][/tex] is 0.0012 M and [tex][OH^{-}][/tex] is [tex]1.02 \times 10^{-14}[/tex].

Explanation:

pH is the negative logarithm of concentration of hydrogen ion.

It is given that pH is 2.89. So, the value of concentration of hydrogen ions is calculated as follows.

[tex]pH = - log [H^{+}]\\2.89 = - log [H^{+}]\\conc. H^{+} = 0.0012 M[/tex]

The relation between pH and pOH value is as follows.

pH + pOH = 14

0.0012 + pOH = 14

pOH = 14 - 0.0012 = 13.99

Now, pOH is the negative logarithm of concentration of hydroxide ions.

Hence, [tex][OH^{-}][/tex] is calculated as follows.

[tex]pOH = - log [OH^{-}]\\13.99 = - log [OH^{-}]\\conc. OH^{-} = 1.02 \times 10^{-14} M[/tex]

Thus, we can conclude that the value of [tex][H_{3}O^{+}][/tex] is 0.0012 M and [tex][OH^{-}][/tex] is [tex]1.02 \times 10^{-14}[/tex].

Answer:

A solution contains 100mM NaCl, 20mM CaCl2, and 20mM urea. We would say this solution is hypotonic compared to a 300 mOsM solution and hypotonic compared to a cell with 300 mOsM (non-penetrating solutes) interior.

Explanation:

The osmolarity is calculated from the molar concentration of the active particles in the solution. We have a solution that is composed of NaCl, CaCl₂ and urea.

When they are dissolved in water, they dissociate into particles as follows:

NaCl → Na⁺ + Cl⁻  (2 particles per compound)

CaCl₂ → Ca²⁺ + 2 Cl⁻ (3 particles per compound)

urea: not dissociation (1 particle per compound)

Then, we have to calculate the osmolarity of the solution. We multiply the molarity of each compound by the number of particles produced by the compound in water:

Osm = (100 mM NaCl x 2) + (20 mM CaCl₂ x 3) + (20 mM urea x 1) = 280 mOsm

Compared with 300 mOsm, 280 mOsm has a lower osmolarity, so it is a hypotonic solution.

To compare with a cell's osmolarity, we have to consider only the non-penetrating solutes. Urea is considered a penetrating solute for mammalian cells. So, the osmolarity of non-penetrating solutes (NaCl  and CaCl₂) is calculated as:

Osm (non-penetrating solutes) = (100 mM NaCl x 2) + (20 mM CaCl₂ x 3) = 260 mOsm

Therefore, we have:

Compared to 300 mOsm solution ⇒ 280 mOsm solution is a hypotonic solution

Compared to a cell with 300 mOsm ⇒ 260 mOsm solution is hypotonic

Answer:

Explanation:

Answer:

1x10^-6

Explanation:

Answer:

Kf = 0.389.

Explanation:

Hello there!

In this case, it turns out possible for us to solve this problem by firstly writing the equilibrium chemical equation and equilibrium expression for the formation of this complex:

[tex]B+C\rightleftharpoons BC\\\\Kf=\frac{[BC]}{[B][C]}[/tex]

Thus, we firstly calculate the concentrations at equilibrium, knowing that the reaction extent in this case is 0.00500mol (same as the formed moles of BC):

[tex][B]=[C]=\frac{0.0350L*1.00mol/L-0.00500mol}{0.0700L} =0.429M[/tex]

[tex][BC]=\frac{0.00500mol}{0.0700L} =0.0714M[/tex]

And finally, the equilibrium constant:

[tex]Kf=\frac{0.0714}{[0.429][0.429]}\\\\Kf=0.389[/tex]

Regards!