Draw the structures of organic compounds A and B. Indicate stereochemistry where applicable The starting material is ethyne, a carbon carbon triple bond where each carbon is bonded to a hydrogen. Step 1 is N a N H 2 followed by 1 equivalent of C H 3 C H 2 C H 2 B r to form compound A. Compound A reacts with hydrogen and lindlar's catalyst to form compound B. COmpound B reacts with H 2 O and H 3 O Plus to form a 5 carbon chain with a hydroxy substituent on carbon 2.

Answer:

c

Explanation:

dnc

Personality is the reflection of the behavioral, cognitive, and emotionalmake up of a person. The factors that are responsible for the outcome of personality are influenced by the biological and environmental factors. If the person behaves abnormally, shows anxiety, impulsiveness, emotional disturbance, not able to take decisions, and quarrelsome all these factors can be indicative of personality disorder. Learn more about personality:

Answer:muriatu acid

Explanation:

The population of weeds in an empty field would most likely be stable

It should be noted that weeds inhabiting an unattended field are expected to sustain relatively constant numbers over time due largely in part to their quick and easy reproductive capabilities.

This is complemented by their comparative resistance towards predation or disease when juxtaposed against other plant types they frequently cohabit with. Weeds can further endure hostile environmental factors better than most plants can, which adds complexity when attempting their control.

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If the Earth were to rotate from east to west (opposite to its current direction) at the same rate, the day and night cycle would be affected.

The most noticeable difference would be the direction of sunrise and sunset. With an east-to-west rotation, the Sun would rise in the west and set in the east. This reversal of the day-night cycle would affect our perception of time and require adjusting our daily routines accordingly.

Reversing the rotation would reverse the Coriolis effect as well. This change would lead to different global wind patterns and ocean currents, affecting weather systems and climate patterns worldwide.

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The molecular mass of the gas is 54 g/mol.

The Ideal gas law is the equation of state of a hypothetical ideal gas. It is a good approximation to the behaviour of many gases under many conditions, although it has several limitations. The ideal gas equation can be written as

                                  PV = nRT

where,

P = Pressure

V = Volume

T = Temperature

n = number of moles

In this equation, number of moles can be replaced by mass divided by molecular mass.

Given,

Mass = 0.695g

Volume = 293ml = 0.293L

Pressure = 807.4mmHg = 807.4/760 atm

Temperature = 22⁰C = 22 +273 = 295K

PV = nRT

(807.4 × 0.293) ÷ 760 = (0.695 × 8.314 × 295) ÷ M

M =  (0.695 × 0.0821× 295 ×760) ÷ (807.4 × 0.293)

M= 54 g/ mol

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Answer:

Br-Ag-Br

Explanation:

The wind moves from high pressure area to low pressure area because of unequal heating and cooling of Earth's land and water surfaces

The movement of air or wind from a high pressure area to a low pressure area is due to the difference in air pressure between the two regions. High-pressure areas are characterized by relatively dense and cooler air that tends to sink, while low-pressure areas have relatively warm and less dense air that rises.

These differences in air pressure arise due to the unequal heating and cooling of the Earth's land and water surfaces. For instance, regions near the equator receive more direct sunlight, and hence, the air gets heated more quickly, leading to the formation of a low-pressure area.

Conversely, regions near the poles receive less direct sunlight, and hence, the air is cooler and denser, leading to the formation of a high-pressure area. As a result, air moves from high pressure to low pressure areas, creating winds and affecting the global climate.

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The equation shown in the second option is the correct equation of oxidation and reduction.

A substance loses electrons or undergoes oxidation when it becomes more oxidized. It entails a substance's receiving oxygen, losing hydrogen, or gaining electrons from another substance.

A substance receives electrons during reduction, which also lowers its oxidation state. It entails either the addition of hydrogen to a substance, the removal of oxygen from a substance, or the acquisition of electrons from another molecule.

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The removal of hydrogen or any other electropositive element, or the addition of oxygen, is said to be the process of oxidation in classical or earlier concepts. An atom or ion gains one or more electrons during the process of reduction.

1. The oxidation half-reaction of copper is:

Cu  → Cu²⁺ + 2e⁻

The reduction half is:

Cu²⁺ + 2e⁻ → Cu

3. An anode in electrochemistry is, in its simplest form, the site of an oxidation reaction. Due to the anode's electrical potential, negative ions or anions usually react there and release electrons. After that, these electrons ascend and enter the drive circuit.

In chemistry, the cathode is referred to as the electrode where reduction takes place. In an electrochemical cell, this is typical. Here, the cathode is negative because the cell's electrical energy supply causes chemical molecules to break down.

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Answer: the answer is money

Explanation:   money=happy person.

Answer:

0.768 mol/L

Explanation:

Given, mass of CsF = 58.4 gm

Molar mass of CsF = Molar mass of Cs + Molar mass of F
= 133 u + 19 u
= 152 u

Number of moles of CsF = Mass of CsF/ Molar mass of CsF
= 58.4/152 mol

Given, volume of solution = 500 mL = 0.5 L
Molarity of solution = moles of solute/volume of solution
= (58.4/152) mol / 0.5 L
= 58.4 * 2/152 mol/L
=  0.768 mol/L

The data one must have in order to complete a titration problem is the molarity and volume of the titrant and titrand.

Titration in analytical chemistry is the determination of the concentration of some substance in a solution by slowly adding measured amounts of some other substance (normally using a burette) until a reaction is shown to be complete, for instance by the colour change of an indicator.

In titration procedure, acids and bases are commonly but not always involved. After the titration experiment, the following formula is used to calculate the molarity of the titrant:

CaVa = CbVb

Where;

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try and find a better answer or ask ur teacher please

We have 1.77 moles of sulfur in 56.8 g of sulfur.  It is a fundamental unit of measurement in the International System of Units (SI) and is defined as the amount of substance that contains the same number of entities as there are in 12 grams of carbon-12.

First, we need to use the formula:
Number of moles = Mass / Molar mass
In this case, the mass of sulfur is 56.8 g, and the molar mass of sulfur is 32.06 g/mol. Substituting these values into the formula, we get:
Number of moles = 56.8 g / 32.06 g/mol
Number of moles = 1.77 mol (rounded to two decimal places)

Therefore, we have 1.77 moles of sulfur in 56.8 g of sulfur. It is important to note that the number of moles is a measure of the amount of substance and is used extensively in chemistry calculations.The entities can be atoms, molecules, or ions, depending on the substance being measured.

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If a snail crawls 55 inches per day ,the snail will crawl approximately [tex]3.2 * 10^3 centimeters.[/tex]

To convert inches to centimeters, we need to use the conversion factor: 1 inch = 2.54 centimeters.

First, let's calculate the distance the snail crawls in inches in 23 days. We can multiply the daily distance by the number of days:

Distance in inches = 55 inches/day × 23 days = 1265 inches.

Now, to convert the distance from inches to centimeters, we multiply the distance in inches by the conversion factor:

Distance in centimeters = 1265 inches × 2.54 cm/inch = 3215.1 cm.

Rounding to the appropriate number of significant figures, the snail will crawl approximately 3215 cm or [tex]3.2 * 10^3 centimeters.[/tex] in 23 days.

Therefore, the answer is  Option 3:[tex]3.2 * 10^3 centimeters.[/tex]

This means that in 23 days, the snail will crawl approximately[tex]3.2 * 10^3 centimeters.[/tex]

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Answer:

5l NO

2

at STP

No. of molecules=

22.4

5

mol=

22.4

5

×N

A

molecules

A) 5ℊ of H

2

(g)

No. of moles=

2

5

mol=

2

5

×N

A

molecules

B) 5l of CH

4

(g)

No. of moles of CH

4

=

22.4

5

mol=

22.4

5

N

A

molecules

C) 5 mol of O

2

=5N

A

O

2

molecules

D) 5×10

23

molecules of CO

2

(g)

Molecules of 5l NO

2

(g) at STP=5l of CH

4

(g) molecules at STP

Therefore, option B is correct.

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The phase changes are;

Fusion- Exothermic

Sublimation  - Exothermic

Condensation - Endothermic

Vaporization - Exothermic

Freezing - Endothermic

When a substance changes from one phase or state of matter to another, this is referred to as a phase change. The solid, liquid, and gas states are the three fundamental types of matter. A substance's physical characteristics, including shape, volume, and density, might alter when it goes through a phase shift.

Temperature and pressure variations are the primary causes of phase shifts. The particular conditions necessary for a phase change to take place vary depending on the substance. As phase shifts affect the behavior, properties, and uses of diverse materials

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a) There are approximately 1.75 grams of sulfuric acid in the sample.

b)The % error for this experiment is 66.67%.

The percent error for this experiment is approximately 66.67%.To find the number of grams of sulfuric acid in the sample, we can use the stoichiometry of the balanced chemical equation between sulfuric acid (H2SO4) and potassium hydroxide (KOH).

a.The balanced equation is:H2SO4 + 2KOH → K2SO4 + 2H2O

From the equation, we can see that one mole of sulfuric acid reacts with two moles of potassium hydroxide. Therefore, we need to determine the number of moles of potassium hydroxide used in the titration.

Volume of potassium hydroxide solution used = 142.5 mL = 0.1425 L

Moles of potassium hydroxide used = Molarity × Volume (in liters) = 0.25 M × 0.1425 L = 0.0356 moles

Since the ratio between sulfuric acid and potassium hydroxide is 1:2, the number of moles of sulfuric acid in the sample is half of the moles of potassium hydroxide used:

Moles of sulfuric acid = 0.0356 moles / 2 = 0.0178 moles

To convert moles to grams, we can use the molar mass of sulfuric acid, which is approximately 98.09 g/mol:

Mass of sulfuric acid = Moles × Molar mass = 0.0178 moles × 98.09 g/mol ≈ 1.75 grams

b. To calculate the percent error, we need to compare the experimental value (grams of sulfuric acid calculated in part a) with the expected value based on the labeled concentration.

Expected mass of sulfuric acid = Mass of sample × Percentage by mass = 35.0 g × 0.03 = 1.05 grams

Percent error = (|Experimental value - Expected value| / Expected value) × 100

Percent error = (|1.75 g - 1.05 g| / 1.05 g) × 100 ≈ 66.67%

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The pOH of a solution can be calculated using the formula: pOH = -log[OH-]. To find the [OH-] concentration when the pOH is 7, we need to convert the pOH value to the OH- concentration.

Starting with pOH = 7, we can rearrange the equation to find [OH-]. Taking the antilog of both sides, we get 10^(-pOH) = 10^(-7). This simplifies to [OH-] = 10^(-7) or 0.0000001 M.

Therefore, the [OH-] concentration in the solution with a pOH of 7 is 0.0000001 M or 1 x 10^(-7) M.

It's worth noting that the pOH and pH of a solution are related by the equation: pH + pOH = 14. In this case, if the pOH is 7, the pH of the solution would be 14 - 7 = 7.

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7.24 moles of NaOH can produce 3.62 moles of Na3AlO3.

To determine the number of moles of Na₃AlO₃ formed from 7.24 moles of NaOH, we need to consider the balanced chemical equation for the reaction. The reaction between NaOH and Al₂(SO₄)₃ produces Na₃AlO₃ and H₂O.

The balanced chemical equation is:

6 NaOH + Al₂(SO₄)₃ → 3 Na₃AlO₃ + 3 H₂O

From the equation, we can see that 6 moles of NaOH react to produce 3 moles of Na₃AlO₃. This means that the mole ratio of NaOH to Na₃AlO₃ is 6:3, which simplifies to 2:1.

Therefore, if we have 7.24 moles of NaOH, we can calculate the moles of Na₃AlO₃ formed by dividing the number of moles of NaOH by 2:

7.24 moles NaOH / 2 = 3.62 moles Na₃AlO₃

Thus, 7.24 moles of NaOH can produce 3.62 moles of Na₃AlO₃ according to the balanced chemical equation.

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The molarity of the NaOH is  0.25 M

The total volume of the NaOH used is 3.8 mL

Total volume of the HCl used is 9.5 mL

Total volume of HCl = Final burette reading - Initial burette reading

= 25 mL - 15.5 mL = 9.5 mL

Total volume of NaOH used = 8.80 mL - 5.00 mL = 3.8 mL

Number of moles of the HCl = 9.5/1000 * 0.1 M

= 0.00095 moles

Since the reaction is 1:1

molarity of the NaOH = Number of moles /Volume

=  0.00095 moles * 1000/3.8

= 0.25 M

This is the molarity of the NaOH that is involved.

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The four major bond types are ionic bonds, covalent bonds, metallic bonds, and hydrogen bonds. It influences boiling and melting points, solubility, and the structure and function of complex molecules like proteins and DNA.

Each bond type has distinct properties:Ionic Bonds: Ionic bonds form between ions of opposite charges. They have high melting and boiling points and are typically formed between metals and nonmetals. Ionic compounds are held together by strong electrostatic attractions, resulting in solid crystalline structures. They are often soluble in water and conduct electricity when dissolved or molten.

Covalent Bonds: Covalent bonds involve the sharing of electrons between atoms. They can be polar or nonpolar, depending on the electronegativity difference between the atoms. Covalent compounds have varying melting and boiling points, but they are generally lower than those of ionic compounds. They can exist as gases, liquids, or solids, and their properties depend on factors like molecular size and intermolecular forces.

Metallic Bonds: Metallic bonds occur in metals, where valence electrons are delocalized and form a "sea" of mobile electrons. Metallic compounds have high thermal and electrical conductivity due to the free movement of electrons. They are malleable and ductile, allowing metals to be shaped into various forms. Metallic bonds result in metallic luster and varying melting points depending on the metal's properties.

Hydrogen Bonds: Hydrogen bonds form between hydrogen atoms and highly electronegative atoms like oxygen, nitrogen, or fluorine. They are relatively weak compared to ionic or covalent bonds. Hydrogen bonding plays a crucial role in the properties of substances such as water and biological molecules.

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Without specific details about Gita's model, it is difficult to determine whether her sister can use it to correctly describe the patterns of the seasons on Earth.

In order to evaluate Gita's model and determine whether her sister can use it to correctly describe the patterns of the seasons on Earth, we need more specific information about the details and accuracy of the model. However, without that information, we can discuss some general aspects to consider when evaluating a model.

Firstly, a model should be based on accurate and relevant data. Gita's model should incorporate scientific data about Earth's axial tilt, its orbit around the sun, and how these factors contribute to the changing seasons. It should also consider other factors that influence seasons, such as the distribution of landmasses, ocean currents, and atmospheric circulation patterns.

Secondly, the model should be logically consistent and able to explain observed phenomena. Gita's model should be able to explain why different parts of the Earth experience different seasons at the same time, why the duration and intensity of seasons vary at different latitudes, and how the position of the sun relative to Earth affects seasonal changes.

Additionally, the model should be able to make accurate predictions and align with empirical evidence. Gita's sister should be able to compare the model's predictions with actual observations of seasonal patterns on Earth and assess how well they match.

It is important to note that accurately describing the patterns of seasons on Earth requires a complex understanding of various interconnected factors. It is unlikely that a simple or incomplete model would be able to fully capture all the intricacies of Earth's seasonal variations. Therefore, Gita's model would need to be comprehensive and supported by scientific knowledge in order for her sister to rely on it for an accurate description of the seasons.

In conclusion, without specific details about Gita's model, it is difficult to determine whether her sister can use it to correctly describe the patterns of the seasons on Earth. It would depend on the accuracy, relevance, logical consistency, and predictive capabilities of the model, as well as its alignment with empirical evidence and scientific understanding of Earth's seasonal variations.

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The final temperature must be approximately 248 K for the pressure to remain constant. B is correct option.

We can use the combined gas law to solve this problem, which states that: (P1V1)/T1 = (P2V2)/T2

where P1 and V1 are the initial pressure and volume, respectively, T1 is the initial temperature, P2 and V2 are the final pressure and volume, respectively, and T2 is the final temperature.

We know that the initial volume V1 is 0.250 L and the final volume V2 is 0.285 L. The pressure P is constant, so we can set P1 = P2. The initial temperature T1 is 10°C, which is equivalent to 283 K (10°C + 273 = 283 K). Substituting these values into the combined gas law and solving for T2, we get: (P1V1)/T1 = (P2V2)/T2

(P1V1) = (P2V2)(T1/T2)

T2 = (P2V2)(T1)/(P1V1)

T2 = (P1V1)(T2)/(P2V2)

T2 = (283 K × 0.250 L)/(0.285 L)

T2 = 248 K.

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The electric force increases by a factor of 16 when the distance is reduced by a factor of 4, hence option A is correct.

The nucleus and electrons are drawn to one another by the electric force. The void created by a positive or negative charge is referred to as an electric field, since it generates a field there.

The electric force is inversely linked to the square of the separation distance and directly connected to the product of the charges. It would be possible to treble the force by doubling both charges.

Reduce one particle's charge by a factor of 4, to increase the electric force between two charged particles by a factor of 16.

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Answer:  9.78 X 10^223 atoms NaCl

Explanation:

Solve using Stoichiometry.

94 g NaCl X (1mole NaCl/58 gNaCl) X (6.02 X 10^23 atoms NaCl/1mole NaCl) = 9.78 X 10^23 atoms NaCl

The mass percent of the sodium chloride in the saline solution is approximately 1.33%. The molar concentration of the saline solution is approximately 0.229 M.

To determine the mass percent and molar concentration of the saline solution, we need to analyze the mass of the sodium chloride residue and the initial mass of the sample.

Mass percent:

The mass percent is calculated by dividing the mass of the sodium chloride residue by the initial mass of the sample and then multiplying by 100%.

Mass percent = (Mass of NaCl / Initial mass of sample) × 100%

Mass of NaCl = 0.669 g

Initial mass of sample = 50.320 g

Mass percent = (0.669 g / 50.320 g) × 100% ≈ 1.33%

The mass percent of the sodium chloride in the saline solution is approximately 1.33%.

Molar concentration:

To calculate the molar concentration of the saline solution, we need to determine the number of moles of sodium chloride and the volume of the solution.

Moles of NaCl = Mass of NaCl / Molar mass of NaCl

The molar mass of NaCl is 58.44 g/mol.

Moles of NaCl = 0.669 g / 58.44 g/mol ≈ 0.01144 mol

Since the volume of the sample is given as 50.0 mL, we need to convert it to liters.

Volume of solution = 50.0 mL = 50.0 mL × (1 L / 1000 mL) = 0.0500 L

Now we can calculate the molar concentration (Molarity) using the formula:

Molarity (M) = Moles of solute / Volume of solution (in liters)

Molarity = 0.01144 mol / 0.0500 L ≈ 0.229 M

The molar concentration of the saline solution is approximately 0.229 M.

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The total pressure of the gases in the container is 1.000 atm at RTP.

To calculate the total pressure of the gases in the container, we need to use the ideal gas law, which states:

PV = nRT

where P is the pressure of the gas, V is the volume of the container, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.

At RTP (standard temperature and pressure), the temperature is 273 K and the pressure is 1 atm. The volume of the container is not given, but since it is rigid, we can assume it is constant.

To find the total pressure, we need to first calculate the partial pressures of each gas using the mole fraction of each gas. The mole fraction is the fraction of the total moles of gas that are made up of each gas.

Let's assume that we have 100 moles of gas in the container. Then, we have:

20.0 moles of helium (20.0% of 100 moles)

20.0 moles of neon (20.0% of 100 moles)

60.0 moles of argon (60.0% of 100 moles)

The total moles of gas is then:

n = 20.0 moles + 20.0 moles + 60.0 moles = 100 moles

The mole fraction of helium is:

X(He) = n(He) / n = 20.0 moles / 100 moles = 0.200

The mole fraction of neon is:

X(Ne) = n(Ne) / n = 20.0 moles / 100 moles = 0.200

The mole fraction of argon is:

X(Ar) = n(Ar) / n = 60.0 moles / 100 moles = 0.600

The partial pressure of helium is:

P(He) = X(He) * P(total) = 0.200 * 1 atm = 0.200 atm

The partial pressure of neon is:

P(Ne) = X(Ne) * P(total) = 0.200 * 1 atm = 0.200 atm

The partial pressure of argon is:

P(Ar) = X(Ar) * P(total) = 0.600 * 1 atm = 0.600 atm

The total pressure is the sum of the partial pressures:

P(total) = P(He) + P(Ne) + P(Ar) = 0.200 atm + 0.200 atm + 0.600 atm = 1.000 atm

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Answer:

An electrical charge is created when electrons are transferred to or removed from an object.

Explanation:

Because electrons have a negative charge, when they are added to an object, it becomes negatively charged. When electrons are removed from an object, it becomes positively charged.