Draw the structural formula of (E)-1,2-dibromo-3-isopropyl-2-hexene

Answers

Answer 1

The structural formula of (E)-1,2-dibromo-3-isopropyl-2-hexene is attached below.

Do functional groups include isopropyl groups?

In organic chemistry, isopropyl is an alternative name for propane, an alkyl functional group with three carbons.

From the name of the compound (E)-1,2-dibromo-3-isopropyl-2-hexene, hex- means the parent hydrocarbon chain has 6 carbon atoms and

-ene means this hydrocarbon has one double bond. It is present in between 2nd and 3rd carbons. 2 Bromine atoms are presented at 1st and 2nd carbons. One isopropyl group is presented at 3rd carbon of the parent chain. In this compound, the isopropyl group and bromine atom are in opposite sides of the double bond so the configuration of double bond is E.

Thus, the structural formula of (E)-1,2-dibromo-3-isopropyl-2-hexene is attached below.

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Draw The Structural Formula Of (E)-1,2-dibromo-3-isopropyl-2-hexene

Related Questions

a 3.211 g sample of gypsum a hydrated salt of magnesuim sulfate, MgSO4.XH2OIS HEATED IN A CRUCIBLE UNTIL A CONSTANT MASS IS REACHED . THE MASS OF THE ANHYDROUS MgSO4 IS 2.539g
a) calculate the percentage by the mass of water in the hydrated MgSO4.xH2O
b) calculate the moles , the amount of H2O released during heating and the amount (in moles) of the anhydrates MgSO4 remaining after heating
c) calculate the value of x in MgSO4.xH2O/ This is the empirical formula of the hydrated magnesium sulfate

Answers

From the calculation, the compound is MgSO4.2H2O.

What is a hydrated salt?

A hydrated salt is a salt that contains molecules of the water of crystallization.

a) Percentage of the water of crystallization = 3.211 g - 2.539g/ 3.211 g * 100/1 = 21%

b) Number of moles of water of crystallization = 3.211 g - 2.539g/ 18 g/mol =

0.037 moles

c) Number of moles of anhydrous salt = 2.539g/120 g/mol = 0.021 moles

Number of moles of hydrated salt = 3.211 g/120 + 18x

Hence;

0.021 = 3.211 /120 + 18x

0.021(120 + 18x) = 3.211

2.52 + 0.378x = 3.211

0.378x = 3.211 - 2.52

x = 3.211 - 2.52/ 0.378

x = 2

Hence the compound is MgSO4.2H2O

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The molar heat of fusion of gold is 12.550 kJ mol–1. At its melting point, how much mass of melted gold must solidify to release 235.0 kJ of energy?

Answers

The mass of melted gold to release the energy would be 3, 688. 8 Kg

How to determine the mass

We have quantity of energy is;

Q = n × HF

n = number of moles

HF = heat of fusion

Let's find number of moles

235.0 = n × 12.550

number of moles = [tex]\frac{235}{12. 550}[/tex] = 18. 725 moles

Note that molar mass of Gold is 197g/ mol

Number of moles = mass/ molar mass

Mass = number of moles × molar mass

Mass = 18. 725 × 197

Mass = 3, 688. 8 Kg

Thus, the mass of melted gold to release the energy would be 3, 688. 8 Kg

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what is the type of chemical reaction that vinegar, baking soda, and dish soap have?

Reaction 1: Two reactions are occurring:
sodium bicarbonate + acetic acid  sodium acetate + carbonic acid
carbonic acid  carbon dioxide + water
Add a teaspoon of dish soap to a cup of vinegar and mix well. Add a table spoon of baking soda to the vinegar soap mixture.

What are the two reactions that occur? I only noticed one and that was when I added baking soda.

what is the type of chemical reaction that vinegar, baking soda, and dish soap have (Combustion, decomposition, etc.) and what is the balanced chemical equation of this reaction?

Answers

Answer:

Explanation:

The reaction between baking soda (sodium bicarbonate) and vinegar (dilute acetic acid) generates carbon dioxide gas, which is used in chemical volcanoes and other projects.

if 14.0 g of aluminium reacts with excess sulfuric acid to produce 75.26 g of aluminium sulfate, what is the percent yield?

Answers

Taking into account definition of percent yield, the percent yield for the reaction is 84.88%.

Reaction stoichiometry

In first place, the balanced reaction is:

2 Al + 3 H₂SO₄ → Al₂(SO₄)₃ + 3 H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Al: 2 moles H₂SO₄: 3 molesAl₂(SO₄)₃. 1 moleH₂: 3 moles

The molar mass of the compounds is:

Al: 27 g/moleH₂SO₄: 98 g/moleAl₂(SO₄)₃: 342 g/moleH₂: 2 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Al: 2 moles ×27 g/mole= 54 gramsH₂SO₄: 3 moles ×98 g/mole= 294 gramsAl₂(SO₄)₃: 1 mole ×342 g/mole= 342 gramsH₂: 3 moles ×2 g/mole= 6 grams

Mass of aluminium sulfate formed

The following rule of three can be applied: if by reaction stoichiometry 54 grams of aluminium form 342 grams of aluminium sulfate, 14 grams of aluminium form how much mass of aluminium sulfate?

[tex]mass of aluminium sulfate=\frac{14 grams of aluminium x342 grams of aluminium sulfate}{54 grams of aluminium}[/tex]

mass of aluminium sulfate= 88.67 grams

Then, 88.67 grams of aluminium sulfate can be produced if 14.0 g of aluminium reacts with excess sulfuric acid.

Percent yield

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

[tex]percent yield=\frac{actual yield}{theorical yield} x100[/tex]

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

Percent yield for the reaction in this case

In this case, you know:

actual yield= 75.26 gramstheorical yield= 88.67 grams

Replacing in the definition of percent yields:

[tex]percent yield=\frac{75.26 grams}{88.67 grams} x100[/tex]

Solving:

percent yield= 84.88%

Finally, the percent yield for the reaction is 84.88%.

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A drop of water with a mass of 0.48 g is vaporized at 100 ∘C and condenses on the surface of a 55- g block of aluminum that is initially at 25 ∘C . If the heat released during condensation goes only toward heating the metal, what is the final temperature in Celsius of the metal block? (The specific heat capacity of aluminum is 0.903 J/(g⋅∘C ).)
Express the temperature in Celsius to two significant figures.

Answers

The final temperature in Celsius of the metal block is 49°C.

How to find the number of moles ?

Moles water = [tex]\frac{\text{Given mass}}{\text{Molar Mass}}[/tex]

= [tex]\frac{0.48\ g}{18\ \text{g/mol}}[/tex]

= 0.0266 moles

Heat lost by water = 0.0266 mol x 44.0 kJ/mol

= 1.17 kJ

= 1170 J [1 kJ = 1000 J]

Heat lost = Heat gained

Heat gained by aluminum = 1170 J

1170 = 55 x 0.903 (T - 25) = 49.7 T - 1242

1170 + 1242 = 49.7 T

T = 48.5°C (49°C at two significant figures)

Thus from the above conclusion we can say that The final temperature in Celsius of the metal block is 49°C.

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Determine the mass of CO2 produced when 51.2 g of CaO is reacted with 50.0 g of C according to the unbalanced chemical equation:

CaO (s) + C (s) ---> CaC2 (s) + CO2 (g)

Hint: You will need to balance the equation first.

Answers

The mass of CO2 produced will be 8.01 grams

Stoichiometric problem

The balanced equation of the reaction is written as:

[tex]2CaO (s) + 5C (s) --- > 2CaC_2 (s) + CO_2 (g)[/tex]

The mole ratio of CaO and C is 2:5 from the balanced equation.

Mole of 51.2 g CaO = mass/molar mass = 51.2/56 = 0.91 moles

Mole of 50.0 g C = 50/12 = 4.17 moles

From the mole ratio, 0.91 mole CaO will require 5/2 x 0.91 = 2.28 moles C.

This means 4.17 moles carbon is excessive. In other words, C is the limiting reagent.

The mole ratio of C and CO2 is 5:1. Thus, the equivalent mole of CO2 that will be produced from 0.91 moles C will be:

0.91/5 = 0.182 moles.

Mass of 0.182 moles CO2 = mole x molar mass = 0.182 x 44 = 8.01 grams

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A glass container was initially charged with
3.00 moles of a gas sample at 3.75 atm and
21.7 °C. Some of the gas was released as the
temperature was increased to 28.1 °C, so the
final pressure in the container was reduced to
0.998 atm. How many moles of the gas
sample are present at the end?
Answer in mol

Answers

The number of moles of the gas sample present at the end is 0.78 moles.

Number of moles of the gas

PV = nRT

V = nRT/P

At a constant volume, V;

n₁RT₁/P₁ = n₂RT₂/P₂

n₁T₁/P₁ = n₂T₂/P₂

n₂ = (n₁T₁P₂)/(P₁T₂)

where;

T₁ is initial temperature = 21.7⁰C = 294.7 KT₂ is final temperature = 28.1⁰C = 301.1 K

n₂ = (3 x 294.7 x 0.998)/(3.75 x 301.1)

n₂ = 0.78 moles

Thus, the number of moles of the gas sample present at the end is 0.78 moles.

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What classifies a substance as an element?
What classifies a substance as a compound?

Actually, answer what the question is asking and give a short answer. No copying and pasting.

Answers

The difference between an element and a compound is that an element is a substance made of same type of atoms, whereas a compound is made of different elements in definite proportions.Examples of elements include iron, copper, hydrogen and oxygen. Examples of compounds include water (H2O) and salt (Sodium Chloride - NaCl).

what is the cation of Al2(SO4)3

Answers

Answer:

Al has a 3+ charge, and SO4 has a 2- charge. So, it takes 3 of the SO4 anions to balance 2 of the Al cations. So, you get Al2(SO4)3

Identify the parts of the equation by dragging each label below to the correct arrow on the diagram. Drag the items on the left to the correct location on the right.

Answers

The missing labels are:

CuCO₃(s), H₂SO₄(aq): reactants. +: plus sign. CuSO₄(aq), H₂O(l), CO₂(g): products. (s): solid.(aq): aqueous.(l): liquid.(g): gaseous.

What is a chemical equation?

It is a way to represent a chemical reaction.

Let's consider the following chemical equation.

CuCO₃(s) + H₂SO₄(aq) → CuSO₄(aq) + H₂O(l) + CO₂(g)

The missing labels are:

CuCO₃(s), H₂SO₄(aq): reactants. They are on the left side of the equation.+: plus sign. It separates substances.CuSO₄(aq), H₂O(l), CO₂(g): products. They are on the right side of the equation.(s): solid.(aq): aqueous.(l): liquid.(g): gaseous.

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which element is trigonal pyramidal molecular shape ? a) NF3. b) BCL3 c) COCL2 d) CLO3- e) BRF3

Answers

Answer:

A.) NF₃

D.) ClO₃⁻

Explanation:

To determine the molecular shape of the molecules, you need to:

1.) Calculate the total valence electrons in the molecule

-----> The sum of the element's valence electrons

2.) Draw the Lewis structure

What state of matter is Polaris, the north star?

A. Plasma
B. Liquid
C. Light
D. Gas

Answers

The state of matter of Polaris, the north star is gas.

What are stars made of?

Stars are made up of a mixture of hot gases.

The mixture consists of helium and hydrogen. Hydrogen burns into helium to give starts a shining appearance when observed from a far distance.

Thus, the state of matter of all stars, including the north star, is gas.

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GIVING BRAINLIEST!!!!!!!!! (and the rest of my points)
The Himalayan balsam plant makes seeds in pods and releases them when it is ready, while the Surinam toad absorbs its eggs into its own back until they are ready to come out. How are the adaptations of the balsam and the toad similar?

A. They are behaviors that allow the plant and the animal to reproduce through shorter life cycles.
B. They are behaviors that protect the plant and the animal from predators.
C. They are life cycle differences that protect the offspring and help them to survive.
D. They are physical characteristics that allow the offspring to survive in cold weather conditions.

Answers

They are life cycle differences that protect the offspring and help them to survive. The correct option is C.

Life cycle adaption

Some organisms have life cycle features that ensure that their population is perpetuated in subsequent generations.

Such features include ensuring that propagules are only released when they are mature and making sure that eggs are hatched and offspring become viable before they are allowed to move to the environment.

These actions will make sure that the propagules of offspring have what it takes to survive in their new environment.

In other words, these life cycle features are embedded in the genome of organisms as a way to survive the environment.

Thus, the features of the Himalayan balsam plant and that of the Surinam toad are more or less targeted toward the same thing - the survival of their offspring.

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Answer: Option (C) is correct, They are life cycle differences that protect the offspring and help them to survive.

Explanation: Hope it helps!

Good luck!!!

How many moles of dissolved sodium hydroxide are in 25.0mL of a 6.00 M sodium hydroxide solution?

Answers

0.025L multiply 6mol/L =0.15 mol

ALab Data
78°F
Verify your volume measurement
You have not titrated to the endpoint
Did you report your data to the correct number of
significant figures?
Standardized NaOH (M) 0.4171
Initial volume of buret (mL) 0.50
Volume of vinegar (mL) 10.00
Observations
solution increased.
Final volume of buret (mL)
Volume of NaOH (mL)
Molarity of acetic acid (M)

Answers

The correct number of significant figures are,

Final volume of burette is 38.86ml

Volume of NaOH is 38.36ml

Given data:

Initial volume of burette V(I)= 0.50ml

Molarity of NaOH is M1 = 0.4171M

Volume of Vinegar V2 = 10.00ml

Molarity of acetic acid M2= 1.6M

Final volume of burette V(f)= ?

volume of NaOH V1 = V(f) - V(I) = ?

Determining the moles of acetic acid (CH3COOH)

Molarity = moles of solute / volume of solution

Molarity of acetic acid = moles of CH3C00H / Volume of vinegar

1.6 = moles of CH3C00H / 10.00

moles of CH3C00H = 1.6 * 10.00

Moles of CH3COOH is 16.00mols

Determining the moles of Sodium Hydroxide (NaOH)

In a volumetric titration the amount of Standard solution (titrant) used in the titration is stoichiometrically equivalent to amount of unknown solution (analyte) used for the titration at the endpoint.

Hence,

Moles of NaOH = Moles of CH3COOH

Moles of NaOH is 16.00mols

Determining the volume of Sodium Hydroxide (NaOH)

Molarity of NaOH = moles of NaOH / Volume of NaOH

0.4171 = 16.00 / V(f)-V(I)

0.4171 = 16.00 / V(f)- 0.50

V(f) = ( 16 / 0.4171 ) + 0.50

V(f) = 38.86 ml

Final volume of NaOH V(f) is 38.86ml

Volume of NaOH V1 = 38.86 - 0.50

Volume of NaOH is 38.36ml

DISCLAIMER: Question is incomplete

Initial volume of burette = 0.50ml

Molarity of NaOH = 0.4171M

Volume of Vinegar = 10.00ml

Molarity of acetic acid = 1.6M

Final volume of burette = ?

volume of NaOH = ?

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Look at Table 4 in the procedure portion of the experiment. Calculate the pH you would expect each of the buffer solutions (A, B, C, D, and E) to be using the Henderson-Hasselbalch equation, assuming that the solutions of acetic acid and sodium acetate are equimolar.

Answers

The pH of the buffer solutions as determined using the Henderson–Hasselbalch equation are:

A. pH = 4.75B. pH = 4.05C. pH = 3.75D. pH = 5.75E. pH = 5.45

What is the pH of the solutions?

The pH of a buffer is determined using the Henderson–Hasselbalch equation shown below:

pH = pKₐ + log([A⁻]/[HA])

A. Volume of acetic acid = 5 mL; Volume of sodium acetate = 5 mL; pka of acetic acid = 4.75