The speed depends on the gravitational force acting on the object in the rolling motion of the object that is acting on it at a continuous moment rate. the speed increases at a constant rate.
Rolling motion of any object occurs when the object starts sliding in a different methods from the other objects such as when the objects starts to roll from the ramp or any other sloppy surface and it rolls down due to the gravitational force and with many other forces such as the rolling tangential force. many forces are acting on the object at the same moment and we are just seeing the gravitational force which is playing a major portion. Hence by this information we can consider that the ball accelerates at a constant rate as it moves down the slope because of the constant gravitational force acting on it in a major portion and the rolling tangential force on the object is acting in the smaller form.
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A pulse can be described as a single wave disturbance that moves through a medium. Consider a pulse that is defined at time t=0. 00s by the equation y(x)=6. 00m3x2+2. 00m2 centered around x=0. 00m. The pulse moves with a velocity of v=3. 00m/s in the positive x-direction. (a) What is the amplitude of the pulse? (b) What is the equation of the pulse as a function of position and time? (c) Where is the pulse centered at time t=5. 00s?
The amplitude of the pulse is 3 m, the equation of the pulse as a function of position and time is y(x) = 6/{(x - 3t)² + 2} m and the pulse is 15 m centred at time t = 5. 00s.
y(x) = 6/(x² + 2)
v = 3 m/s
The amplitude(A) of the pulse:
When x= 0, Then y = A
Put x= 0
y(x) = 6/(x² + 2)
y(0) = 6/(0² + 2)
y = A = 3 m
Distance travel in time t
x = vt
x = 3 t
y(x) = 6/{(x - 3t)² + 2}
The distance covered by the pulse in the time 5 s
D = v t
D = 3 x 5
D = 15 m
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If the work done to move a toy car by a force of 20N is 60J how far did the car move?
Answer: Distance = 60 J / 20 N = 3 meters. So the car moved a distance of 3 meters.
Explanation: To determine how far the car moved, you need to know how long the force was applied. The equation for work is work = force * distance, so if you know the force and the work, you can solve for the distance. In this case, you know that the force applied was 20 N and the work done was 60 J, so you can calculate the distance by rearranging the equation to solve for distance: distance = work/force. Plugging in the values, you get distance = 60 J / 20 N = 3 meters. So the car moved a distance of 3 meters.
Important Formulas:
[tex]w=Fd[/tex]
work(measured in joules) = force(measured in newtons) * distance(measured in meters)
__________________________________________________________
Given:
[tex]w=60J[/tex]
[tex]F=20N[/tex]
[tex]d=?[/tex]
__________________________________________________________
Rearranging formula to make distance the subject:
[tex]w=Fd[/tex]
[tex]\dfrac{w}{F} =\dfrac{Fd}{F}[/tex]
[tex]d=\dfrac{w}{F}[/tex]
__________________________________________________________
Finding distance:
[tex]d=\dfrac{w}{F}[/tex]
[tex]d=\dfrac{60}{20}[/tex]
__________________________________________________________
[tex]\fbox{d = 3 meters}[/tex]
If the current carried by a conductor is doubled, how are each of the following affected?
(a) The charge carrier density- ____ (b) The current density____ (c) The electron drift velocity ____
(d) The average time interval between collision____ is halved. is quartered. is unchanged
doubles
triples
quadruples.
(a) The charge carrier density doubles,(b) The current density doubles, (c) The electron drift velocity doubles, (d) The average time interval between collision halved.
I = nq[tex]v_{d}[/tex]A
where n is the charge/volume
I is the current.
q is the charge per carrier
[tex]v_{d}[/tex] is the drift velocity of the charge carriers
A is the cross-sectional area of current flow
Here,
a) The charge carrier density (n) doubles if I doubles.
b) The charge carrier density (J = I/A is the current density). If I doubles, J doubles.
c) The electron drift velocity ([tex]v_{d}[/tex]) doubles if I doubles.
d) The average time interval between collisions depends inversely on [tex]v_{d}[/tex]. If I doubles, [tex]v_{d}[/tex] doubles, so the average time between collisions is halved.
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o, the point at which we lose awareness of the intervals and begin to see apparent motion seems to kick in at around ________ frames per second. 16 - 20
The point at which we lose awareness of the intervals and begin to see apparent motion seems to kick in at around 8 - 12 frames per second.
What is frames per second?The frequency (rate) at which consecutive images (frames) are captured or displayed is known as frame rate and is expressed in frames per second (FPS). The phrase is equally applicable to motion capture devices, computer graphics, and film and video cameras.
Frame frequency, also known as frame rate, is measured in hertz. Frame rate in electronic camera specifications may refer to the highest possible rate, whereas in practise, other settings (like exposure time), may reduce the frequency to a lower number.
Individual differences exist in both the type and properties of the visual stimulus as well as the temporal sensitivity and resolution of human vision. The human visual system can process 10–12 images per second, each of which is perceived individually; higher rates are interpreted as motion.
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Which would be eaier to carry --- a chool bag with a broad trap for a chool bag with a very thin trap?
Jutify your anwer
A school bag with a broad strap would be easier to carry when compared with a school bag with thin strap.
Bags are used to carry loads. There are bags with two straps and bags with one strap. Bags with one strap spread lesser area for carrying whereas bags with two straps spread more area.
The school bags with broad straps are easier to handle. This is due to the reason that the load of the bag is distributed over larger area, thereby decreasing the pressure on the shoulders. The pressure provided by smaller straps is higher ans causes irritation.
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What is the equation for torque used for lever arm and F for force?
The required equation for torque used for lever arm r and F for force is given as τ = |r| |F| sinθ.
A simple way to calculate the magnitude of the torque is to first determine the lever arm and then multiply by the times of applied force.
The lever arm is described as the perpendicular distance from axis of rotation to the line of action of force.
The equation used to calculate torque is , τ = r × F = |r| |F| sinθ
where,
r is the magnitude of lever arm
F is the magnitude of force vector
θ is the angle between lever arm and force vectors
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Two objects with negative charges of 6.2 nC each are separated by 0.3 m. What is the size and direction of theforce between the two charges?
A negatively charged object is one that has more electrons than protons.
What is the negative charge?A negative charge is present when an object has more electrons than protons. An atom has a positive charge when there are more protons than electrons in it. The charges of protons are positive while those of electrons are negative. The coulomb is used to measure charge (C).
The opposite of a charge's attraction is the opposite of its repellency. Therefore, a positive charge attracts a negative charge, whereas two negative charges repel one another. Along the boundary between the two charges, attraction or repulsion occurs.
Along the line that connects the centres of the two objects, the force is applied in that direction. Coulomb's law results in a negative value if the two charges have opposing signs. As a result, the force separating the particles is an attractive force.Coulomb's law produces a favourable outcome if the two charges have the same signs.
Therefore, the answer is 12.4 c positive.
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Two objects with negative charges of 6.2 nC (Coulomb) each are separated by 0.3 m. the size and direction of the force between the two charges is 3.8387038*10^12 N and toward left.
What is Coulomb?In the International System of Units, the unit of electric charge is the coulomb. It is equivalent to 5 1027/801088317 elementary charges in the current version of the SI, as well as the electric charge given by a 1 ampere continuous current in 1 second, e.Solution:
Given :
Two objects with negative charges of 6.2 nC (nano coulomb ) each.
Separation= 0.3 m.
We will use the following Coulomb’s Law.
F = k*|q1| |q2|/r2 ∵ where k = 8.9876 × 109 N·m2
Putting the values, we get
F = 8.9876 × 109*|6.2| |6.2|/0.3^2
F=3.8387038*10^12 N
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calculate the kinetic energy of a 50 kg object that is moving at a speed of 12 m/s
Hello there!
Answer:
3600 J
Explanation:
[tex]E = \frac{mv^2}{2}[/tex]
So m = 50 kg and v = 12 m/s then
[tex]E = \frac{50 * 12^2}{2} J = 3600 J[/tex]
Mass = 50 kg
Velocity = 12 m/s
FindThe kinetic energy of an object.
SolutionThe formula that is used to find the kinetic energy of an object is given by :
[tex]K = \frac{1}{2}mv^{2} \\K = \frac{1}{2} X 50 X 12^{2} \\K = \frac{1}{2} X 50 X 144[/tex]
Answer= 3, 600 JHow do you calculate torque of a shaft?
Divide the radius by the shear stress and the polar moment of inertia to find the shaft torque.
A device that measures shaft torque records the degree to which a shaft will twist in the presence of a specific amount of force. A shaft will twist less than one with a torque of 3 degrees than one with a torque of 5 degrees, and so on.
Does torque equate to rotation?The rotating equivalent of force is torque. So an object will rotate with an angular acceleration in response to a net torque. A torque must be described about the rotational axis since every rotational motion has an axis of rotation. A torque is an applied force that rotates an object about its axis.
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A small rectangular object of unknown material is examined in the laboratory. Iron filings and a compass needle are not attracted to the object. The object is suspended from a light string and is free to swing but does not align itself with Earth’s magnetic field. A strong magnetic field is switched on perpendicular to the long axis of the object. The object changes its orientation so that it partially aligns with the magnetic field. After the field is switched off, the object and string eventually return to their original orientation. Once again, it is observed that iron filings and a compass needle are not attracted to the object. The object most likely is exhibiting the property of
The object is likely exhibiting the property of diamagnetism.
A small rectangular object of unknown material is examined in the laboratory. Iron filings and a compass needle are not attracted to the object. The object is suspended from a light string and is free to swing but does not align itself with Earth’s magnetic field. A strong magnetic field is switched on perpendicular to the long axis of the object. The object changes its orientation so that it partially aligns with the magnetic field. After the field is switched off, the object and string eventually return to their original orientation. Once again, it is observed that iron filings and a compass needle are not attracted to the object. The object most likely is exhibiting the property of Diamagnetism.
Diamagnetism is a type of magnetism that is exhibited by all materials, and it is the weakest type. It results in a repulsive force between the material and an external magnetic field. This repulsion is what caused the object to partially align with the magnetic field when it was switched on.
The lack of attraction between the iron filings and the compass needle indicates that the object is not ferromagnetic or paramagnetic, which are both stronger types of magnetism. When the magnetic field was switched off, the repulsive force between the object and the field was no longer present, allowing the object and the string to return to their original orientation.
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What does the second law of thermodynamics tell us about?
Explanation:
The Second Law of Thermodynamics states that the state of entropy of the entire universe, as an isolated system, will always increase over time. The second law also states that the changes in the entropy in the universe can never be negative.
Draw the phasor for the emf = (170 V) cos ((2pi*60 Hz)t) at t = 60 ms. Tail at the origin.
Answer:
9798687564=-=-=97858
Explanation:oy 8gyf86 r = 76y
Two ropes are tied to a steel ring, and a student holds the free end of each rope. The students then pull on the ropes in a tug-of-war. If the forces exerted by the students are unbalanced, what happens to the ring ?
A. The ring remains at rest.
B. The ring moves at a constant velocity.
C. The ring accelerates in the direction of the net unbalanced force.
D. The ring accelerates in the direction opposite the net unbalanced force.
The ring accelerates in the direction of the net unbalanced force. Thus option C is the correct answer.
According to Newton's second law of motion, the net force acting on an object is equal to the mass of the object multiplied by its acceleration. If the forces exerted by the two students in the tug-of-war are unbalanced, there will be a net force acting on the steel ring.
The direction of this net force will be in the direction of the stronger force. As a result, the ring will accelerate in the direction of the net unbalanced force. This means that the ring will begin to move, and its velocity will change as long as the net force is applied.
Since the steel ring is accelerating, it can no longer be at rest, and it will not move at a constant velocity. The ring will move in the direction of the stronger force until the forces exerted by the students are balanced again.
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A rope of length L is attached to a support at point C. A person of mass m, sits on a ledge at position Aholding the other end of the rope so that its horizontal and taut, as shown above. The person then dropsoff the ledge and swings down the rope toward position B on the lower ledge where an object withmass m₂ is at rest. At position B the person grabs hold of the object and simultaneously lets go of therope. The person and object then land together in the lake at point D, which is a vertical distance Lbelow position B. Air resistance and mass of the rope are negligible. Derive expressions for each of thefollowing in terms of m₁, m₂, L, and g.
Insignificant are air resistance and rope mass. Point C on a support is where a rope of length L is fastened.
What is meant by mass?As a measure of inertia, which is a characteristic of all matter, mass is used in physics. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force. The change caused by an applied force is proportional to the mass of the body.The amount of matter that makes up any object or body is best referred to as its mass. All of the objects we perceive have mass. There is mass in objects like tables, chairs, beds, footballs, glasses, and even air. As a result, every object has a mass, which determines whether it is light or heavy.The amount of matter in a thing is measured by its mass.To learn more about mass refer to:
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A typical spectrophotometer has a path length (the distance light travels through a sample) of 1 cm. Light travels at approximately 3.0 x 108 m/s in vacuum. How long does it take (in ns) for light to travel 1.0 cm
The time taken is 3.33 ns for light to travel 1.0 cm in a spectrophotometer.
What is time?
Time is defined as a scalar quantity that describes the progression of events in the universe. It is often considered to be the fourth dimension of spacetime, along with the three dimensions of space. Time is closely related to the concepts of causality, or the relationship between cause and effect, and is considered to be a fundamental aspect of the physical universe.
The distance light travels in 1 cm is equal to 1 cm x 10^-2 m. To find out how long it takes for light to travel this distance, we can use the formula:
time = distance / speed
Where distance is the distance light travels (1.0 cm x 10^-2 m), and speed is the speed of light in vacuum (3.0 x 108 m/s).
time = (1.0 cm x 10^-2 m) / (3.0 x 108 m/s)
time = 3.33 x 10^-10 s
To convert this time to nanoseconds (ns), we can multiply the time in seconds by 1 billion (10^9):
time = 3.33 x 10^-10 s x 10^9 ns/s
time = 3.33 ns
Therefore, the time taken is approximately 3.33 ns for light to travel 1.0 cm in a spectrophotometer.
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Describe how you would find absolute pressure in a car tire if you had a barometer and a tire pump with an air
pressure gauge
The absolute pressure in a car tire can found by following method:
Pressure is the force per unit area applied toward a course perpendicular to the outer layer of an item. To keep it precise, it is an amount of force following up on a unit area. The SI unit for pressure is measured in Pascals (Pa). Other non-SI units are bar and PSI. There are two types of references to quantify pressure,
Gauge Pressure
Absolute Pressure
The most well-known pressure reference is Gauge Pressure which is connoted by a ‘g’ after the pressure unit, for example, 33 psi g. It is the pressure relative to barometric or atmospheric pressure; it is positive for pressures above atmospheric pressure and negative for pressures that are below atmospheric pressure. An Absolute pressure estimation is one that is alluded to as a perfect or an ideal vacuum. The best illustration of an absolute referenced pressure is the calculation of Barometric pressure. To deliver an absolute pressure sensor, one strategy is for a maker to seal a high vacuum behind the detecting diaphragm.Formula of Absolute pressure is given by:
p(a) = p(g) + p(atm)
Where ,
p(a) is absolute pressure,
p(g) is gauge pressure and
P(atm) is atmospheric pressure
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A dedicated PV system circuit breaker, suitable for backfeed and positioned at the opposite end of the bus from the ______, is a requirement of NEC 705.12(B).
A dedicated PV system circuit breaker, suitable for backfeed and positioned at the opposite end of the bus from the main circuit breaker, is a requirement of NEC 705.12(B).
What is a circuit's straightforward definition?A completed circular conduit through which electricity flows is known as a circuit in electronics. A simple circuit includes a current provider, conductors, and a load. The term "circuit" can broadly be used to describe any ongoing path via which electricity, information, or a signal might go.
Why are circuits essential?A channel for the transfer of electric current is known as an electric circuit. Electric energy is transferred to components that transform it into various types of energy that can perform work, such as supplying power to light, appliances, and other devices, when electrical current flows across a circuit.
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A bicyclist maintains a constant velocity of
4. 0 m/s for a distance of 480 m. How long does it take the bicyclist to travel this distance?
A8s
B 120s C 476s D 1920s
The bicyclist will need to ride for a total time of 120 seconds in order to cover 480 meters of distance at a constant velocity of 4.0 meters per second.
In this scenario, we are provided with:
The distance of the ride is 480 meters.
The velocity is four meters per second
In order to calculate the time, we can use the following formula:
Time = Distance : Velocity
= 480 meters : 4.0 meters per second
= 120 seconds
Therefore, the amount of time a cyclist needs to travel would be 120 seconds.
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Taylor's car broke down and he exerted a force of 8,000 newtons trying to push it before giving up and calling the tow truck. How much work did he accomplish
He accomplished no job. When Taylor's car broke down, he attempted to push it with 8,000 newtons of force before giving up and calling a tow truck.
The amount that indicates how many times a machine multiplies a force is known as what?The mechanical advantage is how many times a machine can multiply the force of the effort. The mechanical advantage of the machine increases when the effort force is exerted across a bigger distance.
Please describe force multiplier machines and provide two instances.Force multipliers are tools that lessen the force required to move an object. Force multipliers come in handy when lifting heavy objects or performing other actions that call for a lot of force.
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To protect yourself from being electrocuted by contact with overhead power lines, you should always assume overhead lines are energized and keep yourself and equipment and at least ________ away from power lines up to 50KV
Keep equipment and yourself at least 10 feet away from power lines carrying high voltage up to 50KV.
Which of the following components of PPE can guard against electrocution?Safety glasses, face shields, hard hats, insulated boots, rubber gloves with leather protectors, insulating sleeves, and fire clothing are among the personal protective equipment (PPE) that must be worn when working near power lines depending on the job task. This lowers the risk of electrocution.
Which power line safety precautions are recommended?Assume that overhead electricity wires are active and keep a minimum of 10 feet away from them. When operating close to power lines, de-energize and ground them. When working close to electricity lines, use fiberglass or wood ladders that are non-conductive.
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Glands that excrete salt in the mangroves are examples of
Glands that excrete salt in the mangroves are examples of adaptions.
What is adaptions?The meaning of adaptation implies how a species changes its body and behaviour to better suit its natural environment. There are an estimated 8.7 million species currently living on earth. They are found across a wide and diverse natural environment, ranging from frozen and desolate Arctics to the sweltering sands of the Sahara.The natural environment is an ever-changing feature of planet earth. The process of adaptation ensures that the species which adapts the most, survive.Read on to explore plant and animal adaptations across the wide ranges of landscapes.In biology, adaptation has three related meanings. Firstly, it is the dynamic evolutionary process of natural selection that fits organisms to their environment, enhancing their evolutionary fitness. Secondly, it is a state reached by the population during that process.
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10 points!
Which measuring tool should be used to measure the length of a marble track?
graduated cylinder
spring scale
metric ruler
stopwatch
Answer:
metric ruler
Explanation:
it counts legnth
Why is copper wire a better conductor of electricity than carbon fiber? (1 point)
A) Carbon (C) does not have any valence electrons.
B) Copper (Cu) is a metal, and only metals can conduct electricity.
C) The electrons in copper (Cu) are loosely bound to the nucleus.
D) Copper (Cu) has no loose electrons.
The copper wire a better conductor of electricity than carbon fiber because copper (Cu) is a metal, and only metals can conduct electricity option - B is correct answer.
Why does copper behave better as an electrical conductor?A metal has greater electrical conductivity the lower its resistivity level. And copper wire is an excellent electrical conductor because it has a low level of resistivity. Incredibly flexible is another quality of copper.
Carbon fiber still does not conduct electricity as well as metal, even after being treated with other materials. Though still about 100 times faster than carbon fiber treated with good electricity conductors, metals like silver, aluminum, and copper are particularly good at conducting electricity.
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Answer:
1. The electrons in copper (Cu) are loosely bound to the nucleus. (C.)
2. An electrical current that flows in one direction (D.)
3. aluminum (Al) (D.)
4. Opposite charges attract one another. (D.)
5. Atoms with a nearly empty valence shell make good conductors. (C.)
Explanation:
I did the Connections Academy test (Conductors and Insulators Quick Check)
How do you calculate sound intensity level?
Sound intensity level (SIL) is measured in decibels (dB).
What is sound?
Sound is a type of energy created by the vibration of particles in a medium, such as air, that can be heard when it reaches a person or animal's ear. Sound can travel through solids, liquids, and gases, and can have different pitches and volumes.
Sound intensity level is defined as the ratio of the sound pressure to a reference pressure level. It is calculated using the following equation: SIL (dB) = 10 log10 (I/I_0), where I is the sound intensity and I_0 is the reference sound intensity equal to 10^−12 W/m^2.
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Position Collisions
Scenario 1: Fatima and Alberta are playing catch. Fatima is standing at
the door, while Alberta is standing 8m away to the right. Fatima throws a
paper ball to the right with a speed of 2.4m/s. Alberta realizes that she is
to far away and runs to the left at 0.6m/s. When and where will Alberta meet
the paper ball?
Answer:
t = (x_ball + 8 ) / 0.6
Explanation:
To solve this problem, we can use the equations of motion for the paper ball and Alberta, and then set them equal to each other to find the time and position where they will meet.
The equation of motion for the paper ball is:
x = x0 + v0t + (1/2)at^2
where x is the position of the paper ball, x0 is the initial position (the door), v0 is the initial velocity (2.4 m/s to the right), t is the time, and a is the acceleration (which is 0 for a thrown ball).
The equation of motion for Alberta is:
x = x0 + v0t + (1/2)at^2
where x is the position of Alberta, x0 is the initial position (8 m to the right), v0 is the initial velocity (-0.6 m/s to the left), t is the time, and a is the acceleration (which is 0 for a person running).
If we set these two equations equal to each other, we get:
x_ball = x_alberta
x0 + v0t + (1/2)at^2 = x0 + v0t + (1/2)at^2
This simplifies to:
x_ball = x_alberta
Then we know that both x_ball and x_Alberta are the same point in space (where Alberta met the paper ball)
Now to find time, we need to use one of the original equation for time t. Using equation of motion for Alberta,
x_Alberta = x0 + v0t
So, t = (x_Alberta - x0) / v0
t = (x_ball - 8 ) / (-0.6) = (x_ball + 8 ) / 0.6
The negative sign of velocity of Alberta tells that she is running towards left whereas ball is thrown towards right.
So we can find time and position where Alberta will meet the paper ball by plugging in the specific distance (x_ball) and known values for x0, v0 and acceleration.
How do the overload and progression principles work together for strength training?
If you are exercising with a specific goal in mind, such as improved strength or cardio fitness. Exercise training's guiding principles include overload, recuperation, progression, reversibility, and specificity.
Your muscles will remain challenged and you'll get stronger if you change or advance your workouts.
To get the most out of any training programme, you must follow certain rules. You won't benefit much from your workouts if you don't adhere to these rules. Exercise training's guiding principles include overload, recuperation, progression, reversibility, and specificity. The concept of specificity is especially important if your exercise programme is designed to help you achieve a particular goal, like increased strength or improved aerobic fitness.
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When the displacement in SHM is two-thirds the amplitude xm, what fraction of the total energy is kinetic energy
The displacement in SHM is 2/3 of amplitude and the fraction of total kinetic energy is Ek = 5/9.
Let’s derive the equations needed from the first principle. The displacement for SHM with amplitude A and angular speed is:
s = A sin(ωt) ---- (1)
Differentiate the displacement to get the velocity:
v = s′ = A ωcos(ωt)
So for a mass m, the kinetic energy is:
Ek = 1/2 mv²
Ek = 1/2 m × (Aωcos(ωt) )² ---- (2)
At time t = 0 the displacement s = 0 and so all the energy is kinetic. Therefore the total energy is:
E (total) = 1/2m ×( Aωcos(0) )²
E (total) = 1/2m × (Aω)² ---- (3)
We can rephrase the kinetic energy in terms of the total energy by comparing (2) and (3):
Ek = E (total) cos²(ωt)
Using the identity cos² (x) + sin² (x) = 1, we can rewrite this equation as:
Ek = E total (1 − sin²) (ωt)) ---- (4)
Additionally, we are aware that potential energy U = E(total) Ek, so
U = E (total) − E (total) (1 − sin²(ωt) )
U = E (total) sin²(ωt) ---- (5)
Now in this question, we’re given that s = 2/3 A, so from our displacement formula (1) we have:
s = Asin (ωt) = 2/3 A
This is what we get for the kinetic energy when we insert it into equation (4):
Ek = E (total)(1 − (2/3)²)
Ek = 5/9 (E (total) )
Hence, the displacement in SHM is 2/3 of the amplitude, and the fraction of total kinetic energy is Ek = 5/9.
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The distance from the acoustic center of the source to the point at which the intensity of the direct sound equals that of the reverberant field describes
Critical distance is defined as the distance between the acoustic center of the source and the point at which the intensity of the direct sound equals that of the reverberant field.
The distance from a sound source when the direct energy (energy radiated straight from the source) equals the reverberant energy (radiated from walls, floor, and ceiling) is called critical distance. It can be said as the critical distance is the distance between the microphone and the sound source at which the level of room reverberation is equal to the level of the direct sound. Critical distance is considered an important factor in positioning loudspeakers and microphones.
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A thermodynamic system undergoes a process in which its internal energy decreases by 500 joules. at the same time, 220 joules of work is done on the system. what is the amount of heat transferred to or from the system?
a. 280 joules
b. 720 joules
c. -280 joules
d. -720 joules
e. 0 joules
The amount of heat transferred from the system is -720j, hence option d is the proper response. It passes through a process where its internal energy drops by 500 joules in a thermodynamic system.
The system receives 220 joules of work at the same time. A thermodynamic system's internal energy is the energy that it contains, excluding the energies that are determined by how it interacts with its environment, such as the system's overall kinetic energy of motion and its overall potential energy with regard to external force fields. The definition of heat in thermodynamics is the kind of energy that crosses a thermodynamic system's boundary.
U = Q+W
Q = U - W Q = -500 -220 = -720J
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Two spherical objects have masses of 8,000 kg and 5.0 kg. Their centers are separated by a distance of 1.5 m. Find the gravitational attraction between them.
The gravitational force of attraction between them is 3.56 * 10⁻⁴ N
What is Gravitational attraction?F = G*M1M2/d²,
where G = 6.67 * 10⁻¹¹ Nm²Kg⁻²,
M1 = 8000Kg and M2 = 1500 Kg,
F = 6.67 * 10⁻¹¹ * 8000 * 1500 / (1.5)² F = 3.56 * 10⁻⁴ N
The gravitational force of attraction between them is 3.56 * 10⁻⁴ N.
The universal gravitational law of Newton. According to this law, every body in the universe is attracted to every other body with a force that is inversely proportional to the square of the distance between them and proportional to the product of their masses.
Therefore, The gravitational force of attraction between them is 3.56 * 10⁻⁴ N.
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