Determine
i. the total capacitance for the circuit
ii. the total charge stored in the circuit
iii. the charge stored in C9 (3μF)​

Determinei. The Total Capacitance For The Circuitii. The Total Charge Stored In The Circuit Iii. The

Answers

Answer 1

(i) The total capacitance for the circuit is 5 μF.

(ii) The total charge stored in the circuit is 1 x 10⁻⁴ C.

(iii) The charge stored in 3μF capacitor is  6 x 10⁻⁶ C.

Total capacitance of the circuit

The total capacitance of the circuit is determined by reolving the series capacitors separate and parallel capacitors separate as well.

C1 and C2 are in series

[tex]\frac{1}{C_{12}} = \frac{1}{C_1 } + \frac{1}{C_2} \\\\\frac{1}{C_{12}} = \frac{1}{4 } + \frac{1}{4} \\\\\frac{1}{C_{12}} = \frac{1}{2} \\\\C_{12} = 2 \ \mu F[/tex]

C1 and C2 are parallel to C3

[tex]C_{123} = C_{12} + C_3\\\\C_{123} = 2\ \mu F + 2\ \mu F \\\\C_{123} = 4 \ \mu F[/tex]

C(123) is series to C5 and C6

[tex]\frac{1}{C_{t} } = \frac{1}{C_{123}} + \frac{1}{C_5} + \frac{1}{C_6} \\\\\frac{1}{C_{t} } = \frac{1}{4} + \frac{1}{6} + \frac{1}{6} \\\\\frac{1}{C_{t} } = \frac{12}{24} \\\\\frac{1}{C_{t} } = \frac{1}{2} \\\\C_t = 2 \ \mu F[/tex]

C7 and C8 are in series

[tex]\frac{1}{C_{78}} = \frac{1}{6} + \frac{1}{6} \\\\\frac{1}{C_{78}} = \frac{2}{6} \\\\\frac{1}{C_{78}} =\frac{1}{3} \\\\C_{78} = 3 \ \mu F[/tex]

Total capaciatnce of the circuit

Ct + C(78) = 2 μF + 3 μF = 5 μF

Total charge stored in the circuit

The total charge stored in the capacitor is calculated as follows;

Q = CV

Q = (5 x 10⁻⁶) x (20)

Q = 1 x 10⁻⁴ C

Charge stored in 3μF capacitor

Q =  (3 x 10⁻⁶) x (20)

Q = 6 x 10⁻⁶ C

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Related Questions

A ball is dropped off of a building and falls past a window that is 2.2m long. If it takes .28s for the ball to cross the window what is the distance from the top of the building to the top of the window?

Answers

Answer:

oh what do you believe this one

How does the gravitational force between two objects change if the distance between the objects doubles?
a)
The force decreases by a factor of 4.
b)
The force decreases by a factor of 2.
c)
The force increases by a factor of 4.
d)
The force increases by a factor of 2.

Answers

if the distance between the objects is doubled the force is reduced by a factor of 4

Whats is gravitational force?

Gravitational force is the force of attraction between objects in the universe.

f = G * m1 * m2 / r^2

f = gravitational force

G = gravitational constant

m1 = mass of object 1

m2 = mass of object 2

r = distance between the objects

From the formular, the gravitational force and the distance is an inverse relationship so increasing the distance by a factor results to reduction of the force by the square of the factor. hence doubling the distance which is distance mutiplied by 2 will lead to reduction of the force by 2^2 = 4

Therefore: The force decreases by a factor of 4.

hope it helps

A crate of oranges is shoved across a grocery store floor with a force of 100 N for a distance of 1 meter. The crate travels an additional 1 meter after the shove and stops just short of the display. You can conclude: the magnitude of work done by frictional forces on the crate is 100 J the magnitude of work done by the applied force on the crate is 100 J the magnitude of the force of friction on the crate is 50 N all of the above conclusions are correct none of the above conclusions are correct

Answers

The statements that are true are;

the magnitude of work done by frictional forces on the crate is 100 Jthe magnitude of work done by the applied force on the crate is 100 JWhat is work done?

Work is said to be done when te force applied travels a distance in the direction of the force. Now we can see that when the force is applied by shoving the crate, work is done, an additional work is done by friction to bring the crate to a stop.

Hence, the following are true;

the magnitude of work done by frictional forces on the crate is 100 Jthe magnitude of work done by the applied force on the crate is 100 J

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16. The energy absorbed in 10minutes by an electrical heater is 1.5 MJ. The supply voltage is 240 V. calculate: a) The current drawn b) The quantity of electricity in Coulombs taken in 5 minutes c) The energy absorbed in 100 hours.

Answers

Answer:

If by 1.5 MJ you mean 1.5E6 Joules then

W = P t    = power X time

W / t = P   power

P = 1.5E6 J / 600 sec = 2500 J / s

P = I V

a) I = 2500 J/s / (240 J/c) = 10.4 C / sec  = 10.4 amps

b) Q = I t = 10.4 C / sec * 300 sec = 3120 Coulombs

c)  E = P * t = 2500 J / sec * 100 hr * 3600 sec / hr = 9.0E8 Joules

Water of mass, m at 100 ℃ is added to 0.50 kg of water at 20 ℃ in a lagged calorimeter of thermal capacity 105 JK −1 . If the specific heat capacity of water is 4200 kg −1K −1 and the final temperature of the mixture is 70℃, determine the value of m.

Answers

The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg

Determine the value of m

Applying the principle of energy conservation

Heat lost by the hot body = heat absorbed by the cold water + calorimeter

= m * 4200 * ( 100 - 70  ) = 0.50 * 4200 * ( 70 -20 ) + 105 * ( 70 -20 )

= m * 126000 = 110250

therefore ;

m = 110250 / 126000

  = 0.875 kg

Hence we can conclude that The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg

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Calculate The pressure produced by a force of 392 N acting on an area of 8.0 m^2

Answers

Answer:

Explanation:

500-0.05=499.95

500-100+5=405

100+100=10000

Two bodies of specific heats S1 and S2 having the same heat capacities are combined to form a single composite body. What is the specific heat of the composite body?​

Answers

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Heat capacity of body 1 :

[tex]\qquad \sf  \dashrightarrow \:m_1s_1[/tex]

Heat capacity of body 2 :

[tex]\qquad \sf  \dashrightarrow \:m_2s_2[/tex]

it's given that, the the head capacities of both the objects are equal. I.e

[tex]\qquad \sf  \dashrightarrow \:m_1s_1 = m_2s_2[/tex]

[tex]\qquad \sf  \dashrightarrow \:m_1 = \dfrac{m_2s_2}{s_1} [/tex]

Now, consider specific heat of composite body be s'

According to given relation :

[tex]\qquad \sf  \dashrightarrow \:(m_1 + m_2) s' = m_1s_1 + m_2s_2[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ m_1s_1 + m_2s_2}{m_1 + m_2}[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ m_2s_2+ m_2s_2}{ \frac{m_2s_2}{s_1} + m_2 }[/tex]

[ since, [tex] m_2s_2 = m_1s_1 [/tex] ]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2m_2s_2}{ m_2(\frac{s_2}{s_1} + 1)}[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2 \cancel{m_2}s_2}{ \cancel{m_2}(\frac{s_2}{s_1} + 1)}[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2 s_2}{ (\frac{s_2 + s_1}{s_1} )}[/tex]

[tex]\qquad \sf  \dashrightarrow \: s' = \dfrac{2s_1s_2}{s_1 + s_2} [/tex]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

Differences between fundamental and derived quantities​

Answers

Answer:

Fundamental quantities are quantities that were created to measure a object/substance which are the basis on which derived quantities are formed, where as derived quantities are created by extracting variables from the fundamental quantities.

If a car takes 3500j of total energy to make 1200j of useful energy, how energy efficient is it

Answers

Answer: 34%

Explanation: eff = (Eout/Ein) *100(for % form)

1200/3500 * 100 = 34%

While cruising on the high sea at speed of v = 22 km/hr, a cargo ship suddenly encounters a problem with its propeller shaft leading to the main engine being shut down. This causes the vessel to slow down to 12 km/hr over the next 14 minutes. Assuming that its deceleration profile is following a correlation of as a = -0.85ct², where c is the acceleration constant for any time t, determine; i) The magnitude for constant c from the two boundary limits of deceleration profile given above, and ii) Plot against the timescale for same interval above, a total distance covered by the vessel as it's slowing down from 22 km/hr to 12 km/hr. Also plot the speed profile for the vessel during that 14 minutes' span.​

Answers

Answer:

how can you support to leprosy victims?

Explain the differences between horticulture and agriculture.

Answers

Hello There

[tex] \tt{Difference \: Between \: \underline\red {Horticulture} \: And \: \underline\green{Agriculture}}[/tex]

[tex] \text{\underline\red {Horticulture}}[/tex]

The Cultivation of Fruits, Vegetables and Flowers for domestic and international markets are called Horticulture.

[tex] \text{\underline\green{Agriculture}}[/tex]

It is science, art and occupation of cultivating the soil, producing crops and livestock. It is systematic and controlled use of living organisms and the environment to improve the human condition.

Hope This Helps

Which term describes living things?

A) We shiver when we get cold.
B) Moss on the side of the tree is active even though it looks still.
C) Human kidneys produce urine.
D) A rabbit gets nutrients from a carrot.

Answers

Answer:                                                                                    

Explanation:

                                                                                                         

"A ball with a mass of 0.1 kg is rolling at a velocity of 5 m/s. What is its
momentum?" What Given is the 5 in this problem? *
mass
velocity
acceleration
momentum

Answers

Answer:

velocity

Explanation:

because the si unit of mass is kg, velocity is m/s, acceleration is m/S2 , moment is kgm2/s . so 5 is given as velocity.

Parallel field lines evenly spaced and all pointing left labeled B. There is a point with a vector down labeled v. There is a circle next to the point labeled F. Use the right-hand rule for magnetic force to determine the charge on the moving particle. This is a charge.

Answers

By using the right-hand rule for magnetic force to determine the charge on the moving particle, it's a negative charge.

What is magnetic force?

It should be noted that the magnetic force simply means the attraction or repulsion that arises between electrically charged particles.

The right-hand rule for magnetic force states that to determine the direction of the magnetic force, one should point the right thumb in the direction of the velocity.

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Answer:

Particle q1 has a charge of 2.7 μC and a velocity of 773 m/s. If it experiences a magnetic force of 5.75 × 10–3 N, what is the strength of the magnetic field?

✔ 2.8

T

In the same magnetic field, particle q2 has a charge of 42.0 μC and a velocity of 1.21 × 103 m/s. What is the magnitude of the magnetic force exerted on particle 2?

✔ 0.12

N

Explanation:

Hope this helps

When people are interested in changing their personalities, they are usually most interested in
a.more turbulent less feeling
b.more judging less extroverted
c.more neurotic less assertive
d. More extroverted less neaurotic

Answers

When people are interested in changing their personalities, they are usually most interested in more neurotic less assertive.

What is personality?

Personality makes up an individual, they are the features or characteristics that forms an individual.

Each individual is made of distinctive character which makes one of different from other.

Therefore, when people are interested in changing their personalities, they are usually most interested in more neurotic less assertive

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what are the three gases our atmosphere is mainly composed of

Answers

Answer:

the three gases our atmosphere is mainly composed of are nitrogen oxygen and carbon

In absence of friction, to bring an object to rest
a. a force must act in the same direction of its direction of motion
b. a force may not be necessary
C. the object will come to rest by itself
d. a force must act in the opposite direction of its direction of motion

Answers

"An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force”

(This is not an awnser this is just some information hope it’s helpful)
D. without friction it won’t stop on its own. it needs a force acting in the opposite direction

If an object accelerates from rest, with a constant acceleration of
10 m/s2, what will its velocity be after 2 s?

Answers

Answer: 20 m/s

Explanation:

Acceleration = change in velocity / time → 10 m/s^2 = final velocity - 0 (original velocity) / 2s → final velocity = 20 m/s

What is the solution of this? ​

Answers

Answer:

1.2 is the correct answer due to the graph

Explanation:

math teacher

The answer is the third one 0.8s

Two people work together to move a heavy box. One person pulls the box with a force of 200 Newtons. The other person pushes the box with a force of 150 newtons. The force of friction on the box is 400 newtons. Which of the following BEST describes what will happen to the box and people?
A. The person pushing the box will move the box towards the person pulling it.
B. The box will accelerate in the direction of the frictional force.
C. Both people will accelerate in the direction of friction, but the box will remain stationary.
D. Neither the box nor people will move.

Answers

Answer:

D. Neither the box nor people will move.

Explanation:

We are given three forces that are present on the box and friction is the result of someone trying to move the box. The net force of the people pulling/pushing is barely 50 Newtons which doesn't compare with the frictional force of 400 Newtons, you will need to surpass a net force of 400 Newtons in order for the box to START moving.

A tire on a car is rolling smoothly. Its center of mass is moving at 18 m/s. How fast is the top of the tire moving in m/s

Answers

For a tire on a car is rolling smoothly and It's center of mass is moving at 18 m/s, the speed of the top of the tire is mathematically given as

Vtop=36m/s

What is the speed of the top of the tire?

Generally, the equation for the relationship between the top and the core is mathematically given as

Vtop=2*(vcore)

Threrefore

Vtop=2*18

Vtop=36m/s

In conclusion, the speed of the top

Vtop=36m/s

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define key terms related to the muscular, skeletal, and nervous systems

Answers

Answer:

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Write any two differences between series combination and parallel combination of cells.

Answers

Answer:

Your answer is attached above

Hope it helps

TC

have a great time

A student uses a motion detector to study the kinematics of a block suspended on a vertical spring that obeys Hooke’s law. The student pulls the block a distance y from equilibrium, releases it from rest, and records the speed v of the block as it passes the equilibrium position. The student repeats this process several times for different values of y. Which variables should be plotted on the horizontal and vertical axes to yield a linear graph?

Answers

When the speed of the block is plotted on the vertical axis and displacement of the block plotted on the horizontal axis, a linear graph will be obtained showing the inverse relationship between the speed of the block and the displacement of the block.

Hooke's law

Hooke's law states that force or load applied to elastic material is directly proportional to the extension produced in the material. This law can be written as;

F = kx

where;

F is the applied forcek is spring constantx is extension of the materialVelocity of the block

The speed of the block increases with decreasing displacement of the bock. This is because the kinetic energy of the block is maximum at zero displacement and minimum at maximum displacement of the block.

Thus, when the speed of the block is plotted on the vertical axis and displacement of the block plotted on the horizontal axis, a linear graph will be obtained showing the inverse relationship between the speed of the block and the displacement of the block.

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enumerate two ways that you practice to control manage noise pollution

1.

2.



please answer it correctly i really need it
nonsense-report

Answers

1. Sound insulation at construction sides.
2. Using silencers in automobiles and replacing old noisy machines with new quitter machines or using lubricants

The hot exhaust from a rocket travels in one direction, and the rocket travels in the opposite direction. This is an example of?
A. Equal and opposite forces.
B. Friction.
C. Balanced forces.
D. Inertia.

Answers

Answer:

Explanation:

The hot exhaust from a rocket travels in one direction, and the rocket travels in the opposite direction. This is an example of?

A. Equal and opposite forces.

B. Friction.

C. Balanced forces.

D. Inertia.

What must be the charge of a particle having E = 81 N/C at 49 mm from the said particle? Express in Coulombs. Use k = 9.0 x 109 kg⋅m3⋅s−2⋅C−2​

Answers

[tex]\text{Given that,}\\\\\text{Electric field strength,}~ E = 81 ~NC^{-1} \\ \\ \text{Distance,}~ d= 49mm = 49 \times 10^{-3} ~m\\ \\\text{Coulomb's constant,}~ k = 9\times 10^9 ~Nm^2 C^{-2}\\\\ \\E= k\dfrac{q}{d^2} \\\\\implies q=\dfrac{Ed^2}{k} = \dfrac{81 \times \left(49 \times 10^{-3}\right)^2}{9\times 10^9} = 2.1609\times 10^{-11} ~C\\\\\\\text{The charge of the particle is}~2.1609\times 10^{-11} ~C[/tex]

Two identical spheres, A and B, carry charges of
+6 microcoulombs and -2 microcoulombs,
respectively. If these spheres touch, what will be
the resulting charge on sphere A?

Answers

The resulting charge in sphere A from the two given different charges is determined as +2 μC.

Resulting of the two speheres

The resulting charge of the two spheres is determined by suming the two individual charges together as shown below;

Resulting charge = +6 μC - 2 μC

Resulting charge = +4 μC

Charge in sphere A

The resulting charge will be distributed uniformly between the two spheres and charge in sphere A and B will be equal.

Charge in sphere A = charge in sphere B = ¹/₂ x +4 μC = + 2 μC

Thus, the resulting charge in sphere A from the two given different charges is determined as +2 μC.

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Express this as y=mx + c
1.
[tex] \frac{1}{y} = \alpha ( {x - 6)}^{ - b} [/tex]

Answers

Answer:

let alpha be y,

1/2=y(x-6)^(-b)

1/2=y(1/x-6)

1/2=y/x-6

x-6=2y

x-6/2=y

(1/2)x-(6/2)=y

y=(1/2)x-3

Three-Dimensional Thinking
2. Aiden collected canned goods for a neighborhood service project. He
pulled a plastic wagon behind him to put the items in. From the time
Aiden began until he finished collecting, the mass of the wagon tripled.
The walk back to Aiden's house was downhill and the speed of the
wagon tripled. What happened to the kinetic energy when the mass
tripled? What happened to the kinetic energy when the speed tripled?
A
When the speed tripled, the kinetic energy increased by a factor of 3.
B
When the mass tripled, the kinetic energy increased by a factor of 3.
When the mass tripled, the kinetic energy increased by a factor of 3.
When the speed tripled, the kinetic energy increased by a factor of 9.
When the mass tripled, the kinetic energy increased by a factor of 9
When the speed tripled, the kinetic energy increased by a factor of 3.
When the mass tripled, the kinetic energy increased by a factor of 9.
When the speed tripled, the kinetic energy increased by a factor of 9.
с
D

Answers

Answer:

A.

Explanation: both triple by 3

Answer: B

Explanation: It is because the formula for this eq is KE=V^2. In the eq, it says that the mass is triple meaning the KE also must have tripled. For the speed, since it has a formula then you just have 3^2 which is 9.

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