**Answer:**

4166.6667m/s

**Explanation:**

The hour equals 3600 secound, and Km equals to 1000 meter.

**Answer:**

15000000

**Explanation:**

formula multiply the lenght value by 1000

The half-life of radium-226 is 1590 years. (a) A sample of radium-226 has a mass of 100 mg. Find a formula for the mass of the sample that remains after t years. (b) Find the mass after 1000 years correct to the nearest milligram. (c) When will the mass be reduced to 40 mg? SOLUTION (a) Let m(t) be the mass of radium-226 (in milligrams) that remains after t years. Then dm/dt = km and m(0) = 100, so this theorem gives m(t) = m(0)ekt = ekt. In order to determine the value of k, we use the fact that m(1590) = 1 2 . Thus e1590k = so e1590k = and 1590k = ln 1 2 = − ln(2) k = . Therefore m(t) = . We could use the fact that eln(2) = 2 to write the expression for m(t) in the alternative form m(t) = . (b) The mass after 1000 years is as follows. (Round your final answer to the nearest milligram.) m(1000) = ≈ mg

**Answer:**

See explanation

**Explanation:**

a) Formula for the mass of the sample that remains after t years = N= Noe^-kt

Where;

N = mass at time t years

No = mass at time t= 0

k = decay constant

t = time taken

So,

N = 100e^-kt

b) First,

t1/2 = -ln(1/2)/k

t1/2 = 0.693/k

t1/2 = half life of radium-226 =1590 years

1590 = 0.693/k

k = 0.693/1590

k = 4.36 * 10^-4

So,

N= 100e^-(4.36 * 10^-4 * 1000)

N= 65 mg

c) From

N = 100e^-kt

40 = 100e^-(4.36 * 10^-4t)

40/100 = e^-(4.36 * 10^-4t)

0.4 = e^-(4.36 * 10^-4t)

ln(0.4) = ln(e^-(4.36 * 10^-4t))

-0.9163 = -4.36 * 10^-4t

t = 0.9163/4.36 * 10^-4

t = 2102 years

An 5kg object is released from rest near the surface of a planet. The vertical position of the object as a function of time is shown in the graph. All frictional forces are considered to be negligible. What is the closest approximation of the weight of the object.

a) 300N

b) 30N

c) 5N

d) 150N

**Answer:**

**The correct option is b: 30 N.**

**Explanation:**

First, we need to find the acceleration due to gravity (a):

[tex] y_{f} - y_{0} = v_{o}t - \frac{1}{2}a(\Delta t)^{2} [/tex] (1)

Where:

[tex]y_{f}[/tex]: is the final vertical position (obtained from the graph)

[tex]y_{0}[/tex]: is the initial vertical position (obtained from the graph)

v₀: is the initial speed = 0 (it is released from rest)

Δt: is the variation of time (from the graph)

From the graph, we can take the following values of height and time:

t₀ = 0 s → [tex]t_{f}[/tex] = 5 s

y₀ = 300 m → [tex]y_{f}[/tex] = 225 m

Now, by entering the above values into equation (1) and solving for "a" we have:

[tex] a = 2\frac{y_{0} - y_{f}}{(t_{f} - t_{0})^{2}} = 2\frac{300 m - 225 m}{(5 s - 0)^{2}} = 6 m/s^{2} [/tex]

Finally, the weight of the object is:

[tex] W = ma = 5 kg*6 m/s^{2} = 30 N [/tex]

**Therefore, the correct option is b: 30 N.**

I hope it helps you!

How to calculate this operation? m=10kg and L=2500J/kg? What is the Energy?

I hope you will give me the correct answer because the last answer was too rude. His known by SOD!

**Answer:**

25000J

**Explanation:**

**Formula**** ****:**** ****Q**** ****=**** ****m****×****c****×****Δt**

**Q****=****Heat**** ****energy**** **

**m****=**** ****mass**

**c****=****specific**** ****heat**** ****capacity**

**ΔT**** ****=**** ****change**** ****in**** ****temperature****.**** **

**Q****=****M**** ****x**** ****C**** ****for**** ****this**** ****question****.**** **

Specific heat capacity = 2500 J/Kg

Mass = 10kg

2500 x 10 = 25000 J

(What is the weight of a 50 kg woman at the top of Jupiter's

atmosphere, where g = 24.8 N/kg? Give your answer in both

newtons and pounds.

**Answer:**

**The correct answer is - 1240 newtons; 278.763 lbs.**

**Explanation:**

Neuroticism, psychoticism, and extraversion are the three dominant personality traits according to

A. Paul Costa

B. Hans Eysenck

C. Gordon Allport

D. Robert McCrae

**The answer is b I just took the test**

**Neuroticism**, psychoticism, and **extraversion **are the three **dominant **personality traits **according **to Hans **Eysenck.**

**Eysenck's **theory of personality is **based **on three logical **attributes **namely:

**a) Introversion vs. extroversion **– **Extroversion **leads to sociable life , while introversion causes **need **of being alone and **limited **interactions

**b) Neuroticism vs. stability **– Neuroticism leads to **anxiousness **and an overactive sympathetic **nervous **system while stability leads to emotional **stability**.

**c) Nsychoticism vs. socialization**. - psychoticism leads to **independent **thinking, and **hostility**. While socialization leads to co-**operative **and conventional behaviour.

Therefore **Neuroticism**, psychoticism, and **extraversion **are the three **dominant **personality traits **according **to Hans **Eysenck.**

To know more about **Hans Eysenck's theory** follow

https://brainly.com/question/11912668

#SPJ2

name and explain two sleeping disorders

insomnia and night terrors

TRUE OR FALSE

2. Somnambulism is a psychologically induced altered state of consciousness.

3. Unconscious information processing occurs simultaneously on many parallel

tracks.

4. Your subconscious mind is just the "tip of the iceberg" according to psychologists

like Sigmund Freud.

answers: true true false

An open pipe is 1.42 m long

What fundamental frequency

does it produce?

(Speed of sound = 343 m/s)

(Unit = Hz)

**Answer:**

the fundamental frequency produced by the open pipe is **120.78 Hz**

**Explanation:**

Given;

length of the open pipe, L = 1.42 m

speed of sound in air, v = 343 m/s

The length of the open pipe for the fundamental frequency is equivalent to half of wavelength;

[tex]L = \frac{\lambda}{2} \\\\\lambda = 2L[/tex]

The fundamental frequency produced by the open pipe is calculated as;

[tex]f_o = \frac{v}{\lambda} \\\\f_o = \frac{v}{2L} \\\\f_o = \frac{343}{2 \times 1.42} \\\\f_o = 120.78 \ Hz[/tex]

Therefore, the fundamental frequency produced by the open pipe is **120.78 Hz**

Consider a large truck carrying a heavy load, such as steel beams. A significant hazard for the driver is that the load may slide forward, crushing the cab, if the truck stops suddenly in an accident or even in braking. Assume, for example, that a 10 000-kg load sits on the flatbed of a 20 000-kg truck moving at 12.0 m/s. Assume that the load is not tied down to the truck, but has a coefficient of friction of 0.500 with the flatbed of the truck.

A) Calculate the minimum stopping distance for which the load will not slide forward relative to the truck.

B) Is any piece of data unnecessary for the solution?

a) mass of the load.

b) mass of the truck.

c) velocity.

d) coefficient of static friction.

e) all are necessary.

**Answer:**

**A)**

the minimum stopping distance for which the load will not slide forward relative to the truck is **14 m**

**B)**

data that were not necessary to the solution are;

**a) mass of truck** and** b) mass of load**

**Explanation:**

Given that;

mass of load [tex]m_{LS}[/tex] = 10000 kg

mass of flat bed [tex]m_{FB}[/tex] = 20000 kg

initial speed of truck [tex]v_{0}[/tex] = 12 m/s

coefficient of friction between the load sits and flat bed μs = 0.5

A) the minimum stopping distance for which the load will not slide forward relative to the truck.

Now, using the expression

Fs,max = μs [tex]F_{N}[/tex] -------------let this be equation 1

where [tex]F_{N}[/tex] = normal force = mg

so

Fs,max = μs mg

ma[tex]_{max}[/tex] = μs mg

divide through by mass

a[tex]_{max}[/tex] = μs g ---------- let this be equation 2

in equation 2, we substitute in our values

a[tex]_{max}[/tex] = 0.5 × 9.8 m/s²

a[tex]_{max}[/tex] = 4.9 m/s²

now, from the third equation of motion

v² = u² + 2as

[tex]v_{f}[/tex]² = [tex]v_{0}[/tex]² + 2aΔx

where [tex]v_{f}[/tex] is final velocity ( 0 m/s )

a is acceleration( - 4.9 m/s² )

so we substitute

(0)² = (12 m/s)² + 2(- 4.9 m/s² )Δx

0 = 144 m²/s² - 9.8 m/s²Δx

9.8 m/s²Δx = 144 m²/s²

Δx = 144 m²/s² / 9.8 m/s²

Δx = **14 m**

Therefore, the minimum stopping distance for which the load will not slide forward relative to the truck is **14 m**

B) data that were not necessary to the solution are;

**a) mass of truck** and** b) mass of load**

What does the Preamble to the Constitution set out as the goals for the government? Which branches of

government address each of the goals of the Preamble specifically?

**Answer:**

Six purposes of government: to form a more perfect union; establish justice; insure domestic tranquility; provide for the common defense; promote the general welfare; secure the blessings of liberty now and in the future.

**Explanation:**

To determine the coefficient of static friction between two materials, an engineer places a small sample of one material on a horizontal disk whose surface is made of the other material and then rotates the disk from rest with a constant angular acceleration of 0.4 rad/s2. If she determines that the small sample slips on the disk after 9.903 s, what is the coefficient of friction

This question is incomplete, the missing image is uploaded along this answer.

**Answer:**

the coefficient of friction is **0.32**

**Explanation:**

Given the data in the question;

we make use of kinematic equation of motion;

ω = ω₀ + ∝t

we substitute

ω = ( 0 rad/s ) + ( 0.4 rad/s² )( 9.903 s )

ω = 3.9612 rad/s

The centripetal force acting on the sample is;

Fc = mrω²

from the image; r = 200 mm = 0.2 m

so we substitute

Fc = m(0.2 m ) ( 3.9612 rad/s )²

Fc = (3.13822 m/s²)m

we know that the frictional force between the two materials should be providing the necessary centripetal force to rotate the sample object;

f = Fc

μN = Fc

μmg = (3.13822 m/s²)m

μ = (3.13822 m/s²)m / mg

μ = (3.13822 m/s²) / g

acceleration due to gravity g = 9.8 m/s²

so

μ = (3.13822 m/s²) / 9.8 m/s²

μ = **0.32**

Therefore, the coefficient of friction is **0.32**

Explain what happens to the movement, energy and arrangement of particles during the process

of distillation.

**Answer:**

Distillation separates a liquid from a solution. For example, water can be separated from salty water by simple distillation. This method works because the water evaporates from the solution, but is then cooled and condensed into a separate container. The salt does not evaporate and so it stays behind.

What is the name of the theory describing how the lithosphere is broken into segments, or plates, which "float" on the asthenosphere, and associates the interactions between these plates with earthquakes and volcanic activity and the formation of mid-ocean ridges, trenches, mountains, and chains of volcanic islands?

A. Conservation of Matter

B. Big Bang Theory

C. Plate Tectonics

D. Theory of Evolution

**Answer:**

**C. Plate Tectonics**

**Explanation:**

The theory of plate tectonics is when the lithosphere is separated into plates. These plates move over or float over the asthenosphere. The movement of these plates cause earthquakes and can interact with the volcanic activity.

A child balancing while standing on a chair is demonstrating which type of energy?

A. Potential energy,

B. Nuclear energy,

C. Electrostatic energy,

**Answer:**

Potential Energy

**Explanation:**

A. Potential energy

A 10 kg object moving to the left collides with and sticks to a 3 kg object moving to the right. Which of the following is true of the motion of the combined objects immediately after the collision?

**Answer:**

"Cannot be determined," if that's an answer choice. It depends on the velocities of both objects, since momentum=mass*velocity.

**Explanation:**

Question 1 of 10

Which object has the most gravitational potential energy?

A. A 8 kg book at a height of 2 m

B. An 8 kg book at a height of 3 m

C. An 5 kg book at a height of 3 m

D. A5 kg book at a height of 2 m

SUBMIT

**Answer:**

B = An 8 kg book at a height of 3 m

I think the answer is B

a rugby player passes the ball 5.34 m across the field, where it is caught at the same height as it left his hand. at what angle was the ball thrown if its initial speed was 7.7 m/s, assuming that the smaller of the two possible angles was used

**Answer:**

[tex]31.035^{\circ}[/tex]

**Explanation:**

x = Displacement in x direction = 5.34 m

t = Time taken to travel the displacement

y = Displacement in y direction = 0

u = Initial velocity of ball = 7.7 m/s

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

Displacement in x direction is given by

[tex]x=u\cos\theta t\\\Rightarrow t=\dfrac{5.34}{7.7 \cos\theta}[/tex]

Displacement in y direction is given by

[tex]y=u\sin\theta t-\dfrac{1}{2}gt^2\\\Rightarrow 0=7.7\sin\theta \dfrac{5.34}{7.7\cos\theta}-\dfrac{1}{2}\times 9.81 (\dfrac{5.34}{7.7\cos\theta})^2\\\Rightarrow 0=7.7\sin\theta-4.905\times \dfrac{5.34}{7.7\cos\theta}\\\Rightarrow 0=7.7^2\sin\theta \cos\theta-4.905\times 5.34\\\Rightarrow 0=7.7^2\dfrac{\sin2\theta}{2}-4.905\times 5.34\\\Rightarrow 0=7.7^2\sin2\theta-4.905\times5.34\times 2\\\Rightarrow \sin2\theta=\dfrac{4.905\times 5.34\times 2}{7.7^2}\\\Rightarrow 2\theta=\sin^{-1}\dfrac{4.905\times 5.34\times 2}{7.7^2}[/tex]

[tex]\Rightarrow \theta=\dfrac{62.07}{2}\\\Rightarrow \theta=31.035^{\circ}[/tex]

**The angle at which the ball was thrown is [tex]31.035^{\circ}[/tex].**

How does the amplitude of the wave change as you get farther from the speaker?

Answer:

The amplitude decreases

Explanation:

From the inverse square law, we know that;

I ∝ 1/d²

Where;

I is intensity

d is distance

Also, we know that;

A² ∝ I

Where A is amplitude

Thus, we can say that;

A ∝ 1/d²

Thus, amplitude is inversely proportional to the distance.

So the larger the distance, the lesser the amplitude and the lesser the distance, the higher the amplitude.

Thus, as you move farther from the speaker the distance increases and therefore the amplitude decreases

A 20g bullet moving at 200m/s hits a bag of sand and comes to rest in 0.011s, calculate the momentum of the bullet just before hitting the bag

**Answer:**

momentum = mass * velocity ... kg•m/s

acceleration = v / t = 200 m/s / 11 ms ... m/s^2

force = mass * acceleration = .02 kg * (200 m/s / 11 ms) N

**Explanation:**

A 7.80 g bullet has a speed of 620 m/s when it hits a target, causing the target to move 6.30 cm in the direction of the bullet's velocity before stopping. (a) Use work and energy considerations to find the average force (in N) that stops the bullet. (Enter the magnitude.) N (b) Assuming the force is constant, determine how much time elapses (in s) between the moment the bullet strikes the target and the moment it stops moving. s

**Answer:**

[tex]23796.19\ \text{N}[/tex]

[tex]0.0002032\ \text{s}[/tex]

**Explanation:**

F = Force

s = Displacement = 6.3 cm

m = Mass of bullet = 7.8 g

v = Velocity of bullet = 620 m/s

t = Time taken

Work done is given by

[tex]W=Fs[/tex]

Kinetic energy is given by

[tex]K=\dfrac{1}{2}mv^2[/tex]

Using work energy considerations we get

[tex]Fs=\dfrac{1}{2}mv^2\\\Rightarrow F=\dfrac{1}{2s}mv^2\\\Rightarrow F=\dfrac{1}{2\times 0.063}\times 7.8\times 10^{-3}\times 620^2\\\Rightarrow F=23796.19\ \text{N}[/tex]

**The average force that stops the bullet is [tex]23796.19\ \text{N}[/tex].**

Force is given by

[tex]F=m\dfrac{v-u}{t}\\\Rightarrow t=m\dfrac{v-u}{F}\\\Rightarrow t=7.8\times 10^{-3}\times \dfrac{620}{23796.19}\\\Rightarrow t=0.0002032\ \text{s}[/tex]

**The time taken to stop the bullet is [tex]0.0002032\ \text{s}[/tex].**

A ray of light is incident on a plane mirror at an angle of 30 degree state the angle of reflection?

**Answer:**

30°

**Explanation:**

*The law of reflection states that when a ray of light reflects off a surface, the angle of incidence is equal to the angle of reflection.*

∠i = ∠r

so as ∠i = 30°

∠r will also be 30°

HELP - What are some good topics to add to a Pipeline presentation? So yes, a presentation about pipelines, like for example in the US. Have any ideas??

Talk about the jobs that pipeline construction provides to citizens and wether or not it’s effects are ultimately eco-friendly

HELP PLEASE

60 POINTS

HAVE A GREAT REST OF YOUR DAY PEOPLE :>

**Answer:**

The sun and the stars

**Explanation:**

I hope this helps!

**Answer:**

Northstar & North Pole

**Explanation:**

yyggggggggggggggg

A turtle crawls at 4.32 m/s to cover the short 3.84 m distance to his food bowl. How long does it take?

Speed=Distance/Time. so you need to do distance/speed to get time. 3.84/4.32= .88888888889 seconds to get to his food bowl

What did you learn about from the NASA's perseverance Rover land on Mars project?

NASA's Mars Pathfinder mission, launched in 1996, put the first free-moving rover—called Sojourner—on the planet. ... Together, these missions have shown scientists that Mars is an active planet that is rich in the ingredients needed for life as we know it—water, organic carbon, and an energy source

Which task would be impossible without radio waves ?

**Answer:**

*checking your e-mail on your computer using a coffee's shop WiFi. *No need radio waves for this.

**Explanation:**

Because you are only checking it, nothing else.

Yup exactly what the other person said ! ^^i was gonna say the same

Using the American Engineering system of units (AES), a) Calculate the weight of a 170.5 lbm person on the surface of the earth, where the local acceleration due to gravity is 32.174 ft/s2 . Report your answer in pound-force, lbf. b) What would be the weight of a 170.5 lbm astronaut on the moon, where the local acceleration due to gravity is 5.32 ft/s2 . Report your answer in pound-force, lbf.

**Answer:**

**a) **the weight of the person is **170.5 lbf**

**b) **weight of the astronaut on the moon is **28.2 lbf**

**Explanation:**

Given the data in the question;

a)

we know that;

weight on the surface of the earth = m[tex]g_{earth[/tex]

given that m = 170.5 lbm and g = 32.174 ft/s²

we substitute

weight on the surface of the earth = 170.5 lbm × 32.174 ft/s²

= 5485.667 lbm-ft/s²

1 lbf = 32.174 lbm-ft/s²

so

weight on the surface of the earth = (5485.667 / 32.174) lbf

weight on the surface of the earth = **170.5 lbf**

Therefore, the weight of the person is **170.5 lbf**

b)

given that;

weight on the surface of the earth = m[tex]g_{moon[/tex]

m = 170.5 lbm and g = 5.32 ft/s²

weight on the surface of the earth = 170.5 lbm × 5.32 ft/s²

= 907.06 lbm-ft/s²

1 lbf = 32.174 lbm.ft/s²

weight on the surface of the earth = ( 907.06 / 32.174 ) lbf

weight on the surface of the earth = **28.2 lbf**

Therefore, weight of the astronaut on the moon is **28.2 lbf**

g We have studied diffraction from a single slit, where light is sent through a thin opening. A similar phenomena occurs when light bends around a thin object, like a human hair. Here the width of the hair plays the role of the width of the single slit. Measurements found that when a beam of light of wavelength 632.8 nm was shone on a single strand of hair, the first dark fringe on either side of the central bright spot were 5.22 cm apart. If the screen is 1.25 meters away, how thick was this strand of hair?

**Answer:**

[tex]3.031\times 10^{-5}\ \text{m}[/tex]

**Explanation:**

[tex]y[/tex] = Distance between central maxima and first minimum

m = Order = 1

d = Thickness of hair

[tex]\lambda[/tex] = Wavelength = 632.8 nm

L = Distance between light source and screen = 1.25 m

Width of central maximum is given by

[tex]2y=5.22\times 10^{-2}\\\Rightarrow y=\dfrac{5.22\times 10^{-2}}{2}\\\Rightarrow y=0.0261\ \text{m}[/tex]

Distance between central maxima and first minimum is given by

[tex]y=L\tan\theta_{min}\\\Rightarrow \tan\theta_{min}=\dfrac{y}{L}\\\Rightarrow \tan\theta_{min}=\dfrac{0.0261}{1.25}\\\Rightarrow \theta_{min}=\tan^{-1}0.02088\\\Rightarrow \theta_{min}=1.1962^{\circ}[/tex]

Since [tex]\theta[/tex] is small [tex]\tan\theta_{min}=\sin\theta_{min}[/tex]

[tex]\sin\theta_{min}=\dfrac{m\lambda}{d}\\\Rightarrow d=\dfrac{m\lambda}{\sin\theta}\\\Rightarrow d=\dfrac{1\times 632.8\times 10^{-9}}{\sin1.1962^{\circ}}\\\Rightarrow d=3.031\times 10^{-5}\ \text{m}[/tex]

**The strand of hair is **[tex]3.031\times 10^{-5}\ \text{m}[/tex]** thick.**

cosmic Microwave Background radiation is one piece of supporting evidence for the Big Band Theory. Are these microwaves at the longer or shorter end of the spectrum?

are they long or short?

**Answer:**

it is long.

**Explanation:**

I know the answer but I don't know how to explain it

As a sports car travels along a level stretch of road with constant speed, most of the power developed by the engine is used to compensate for the energy transformations due to friction forces exerted on the sports car by the air and the road. If the power developed by the engine is 0.824 hp, calculate the total friction force acting on the sports car (in N) when it is moving at a speed of 30 m/s. One horsepower equals 746 W.

Answer:

20.49 N

Explanation:

From the question given above, the following data were obtained:

Power (P) = 0.824 hp

Velocity (v) = 30 m/s

1 h = 746 W

Force (F) =?

Next, we shall convert 0.824 hp to Watts (W). This can be obtained as follow:

1 h = 746 W

Therefore,

0.824 hp = 0.824 hp × 746 W / 1 h

0.824 hp = 614.704 W

Finally, we shall determine the force as follow:

Power (P) = 614.704 W

Velocity (v) = 30 m/s

Force (F) =?

P = F × v

614.704 = F × 30

Divide both side by 30

F = 614.704 / 30

F = 20.49 N

Which two events caused this culture found in Latin America?A. Columbian Exchange and Mexican Revolution B. Cuban Revolution and Brazilian Uprising C. Columbian Exchange and Triangular TradeD. Cuban Revolution and the Age Exploration
The framers of the Texas Constitution showed the strongest commitment to popular sovereignty in-
Can someone answer my question please
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geometry, god bless u 2
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