Can you please solve it

David is a salesman for a local Ford dealership. He is paid a percentage of the profit the dealership makes on each car. If the profit is under $800, the commission is 25%.

If the profit is at least $800 and less than $1,000, the commission rate is 27.5% of the profit. If the profit is $1,000 or more, the rate is 30% of the profit.

Let's find the difference between the commission paid if David sells a car for a $1,000 profit and the commission paid if he sells a car for a $799 profit. We'll begin by finding the commission paid if David sells a car for a $1,000 profit.Commission paid on a $1,000 profit=.30(1,000)=300

Therefore, if David sells a car for a $1,000 profit, his commission is $300. Let's move on to finding the commission paid if he sells a car for a $799 profit. Commission paid on a $799 profit=.25(799)=199.75Therefore, if David sells a car for a $799 profit, his commission is $199.75.The difference between these commissions is:$300-$199.75=$100.25

Therefore, the difference between the commission paid if David sells a car for a $1,000 profit and the commission paid if he sells a car for a $799 profit is $100.25.

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The limit of the Riemann sums is equal to the definite integral ∫[tex]2^3[/tex]x cos(2x) dx.

We have:

lim δ→0 ∑k=1n x_k cos(2x_k)δx_k,

where x_k = a + k(b-a)/n = 2 + k(1)/n and

δx_k = (b-a)/n = 1/n.

Notice that as δ → 0, nδ = (b-a) → 0, so we have a Riemann sum that

approaches a definite integral:

∫[tex]2^3[/tex]x cos(2x) dx.

Thus, the function f(x) = x cos(2x), and the limit of the Riemann sums is

equal to the definite integral ∫[tex]2^3[/tex]x cos(2x) dx.

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The given limit represents a Riemann sum of the function f(x) = x*cos(2x) on the interval [2, 3]. Evaluating the limit by taking the definite integral of the function over the interval gives the value of 3/2.

To evaluate the given limit of Riemann sums, we need to first identify the function f. Note that the expression inside the summation, xk cos^2(xk) delta xk, suggests that f(x) = x cos^2(x).

Next, we can rewrite the limit as a definite integral by using the definition of the integral. We have:

lim delta→0 Σk=1n xk cos^2(xk) delta xk

= ∫2^3 x cos^2(x) dx

Thus, the limit of Riemann sums is equal to the definite integral of the function f(x) = x cos^2(x) over the interval [2,3].

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Answer:

A) The estimated solution of differential equation at t=2 using Euler's method with h=0.2 is y(2) ≈ 3.4085

B) t2 = 0.2, y2 = y1 + h * f(t1, y1) = 1 + 0.1 * (0.2 * 1) = 1.02

Step-by-step explanation:

A) Using Euler's method with h=0.2, we have:

t0 = 0, y0 = 1

t1 = 0.2, y1 = y0 + h * f(t0, y0) = 1 + 0.2 * (0 * 1) = 1

t2 = 0.4, y2 = y1 + h * f(t1, y1) = 1 + 0.2 * (0.2 * 1) = 1.04

t3 = 0.6, y3 = y2 + h * f(t2, y2) = 1.04 + 0.2 * (0.6 * 1.04) = 1.1264

t4 = 0.8, y4 = y3 + h * f(t3, y3) = 1.1264 + 0.2 * (0.8 * 1.1264) = 1.2541

t5 = 1.0, y5 = y4 + h * f(t4, y4) = 1.2541 + 0.2 * (1.0 * 1.2541) = 1.4293

t6 = 1.2, y6 = y5 + h * f(t5, y5) = 1.4293 + 0.2 * (1.2 * 1.4293) = 1.6597

t7 = 1.4, y7 = y6 + h * f(t6, y6) = 1.6597 + 0.2 * (1.4 * 1.6597) = 1.9569

t8 = 1.6, y8 = y7 + h * f(t7, y7) = 1.9569 + 0.2 * (1.6 * 1.9569) = 2.3351

t9 = 1.8, y9 = y8 + h * f(t8, y8) = 2.3351 + 0.2 * (1.8 * 2.3351) = 2.8112

t10 = 2.0, y10 = y9 + h * f(t9, y9) = 2.8112 + 0.2 * (2.0 * 2.8112) = 3.4085

Therefore, the estimated solution at t=2 using Euler's method with h=0.2 is y(2) ≈ 3.4085.

B) Using Euler's method with h=0.1, we have:

t0 = 0, y0 = 1

t1 = 0.1, y1 = y0 + h * f(t0, y0) = 1 + 0.1 * (0 * 1) = 1

t2 = 0.2, y2 = y1 + h * f(t1, y1) = 1 + 0.1 * (0.2 * 1) = 1.02

t3 = 0.3, y3 = y2 + h * f(t2, y2) = 1.02 + 0.1 * (0.3 * 1.02) = 1.0506

t4 = 0.4, y4 = y3 + h * f(t3, y3) = 1.0506 +

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The values, we get ; Percentage = (0.5/2.5) x 100= 20%.Therefore, the sugar required in the recipe is 20% of the quantity usually purchased by a household.

When given a recipe, it is essential to know how to convert the recipe from the metric to the US customary system and then to a percentage. For domestic purposes, sugar is usually purchased in 2.5kg. We can calculate the sugar required in the recipe as a percentage of the amount usually purchased by the household using the following steps:

Step 1: Convert the sugar required in the recipe from grams to kilograms.

Step 2: Calculate the percentage of the sugar required in the recipe to the quantity purchased by a household, usually 2.5 kg.  Let's say the recipe requires 500g of sugar.

Step 1: We need to convert 500g to kg. We know that 1000g = 1kg, so 500g = 0.5kg.

Step 2: We can now calculate the percentage of the sugar required in the recipe as a percentage of the amount usually purchased by a household, which is 2.5kg.

We can use the following formula: Percentage = (amount of sugar required/quantity purchased by household) x 100. Substituting the values, we get; Percentage = (0.5/2.5) x 100= 20%.Therefore, the sugar required in the recipe is 20% of the quantity usually purchased by a household.

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a. The mean age (20.5 years) and standard deviation (2.6 years) you provided are considered statistics.

This is because they are calculated from a sample (all the students at a small college) rather than the entire population of college students. Statistics are numerical summaries that describe the characteristics of a sample, whereas parameters describe the characteristics of an entire population.

b. To label both numbers:
- Mean age (20.5 years): This number represents the average age of students at the small college. The mean is calculated by adding all the ages and dividing by the total number of students in the sample. It is a statistic since it is based on a sample and not the entire population of college students.

- Standard deviation (2.6 years): This number indicates the degree of variation or dispersion of the ages of students in the sample. A higher standard deviation indicates a greater spread in ages, while a lower value suggests a more consistent age range. This, too, is a statistic as it is calculated from the sample rather than the entire population.

Remember, the key distinction between statistics and parameters is that statistics describe samples, while parameters describe entire populations.

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The values of x and y such that the points (1, 6, −5), (2, 5, −3), and (x, y, 1) are collinear are x = 2 and y = 5.

To determine the values of x and y such that the points (1, 6, −5), (2, 5, −3), and (x, y, 1) are collinear, we need to check if the vectors formed by these points are parallel.

Two vectors are parallel if one is a scalar multiple of the other.

The vector from (1, 6, −5) to (2, 5, −3) is given by:

v1 = <2-1, 5-6, -3-(-5)> = <1, -1, 2>

The vector from (1, 6, −5) to (x, y, 1) is given by:

v2 = <x-1, y-6, 1-(-5)> = <x-1, y-6, 6>

If v1 and v2 are parallel, then we can write:

v2 = k*v1, for some scalar k

This gives us three equations:

x-1 = k

y-6 = -k

6 = 2k+5

Solving this system of equations, we get:

k = 1

x = 2

y = 5.

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The values of x and y such that if the points are collinear are x = 2 and y = 5.

From the question, we have the following parameters that can be used in our computation:

The points (1, 6, −5), (2, 5, −3), and (x, y, 1)

By definiton, two vectors are parallel if one is a scalar multiple of the other.

The vector from (1, 6, −5) to (2, 5, −3) is given by:

v1 = <2-1, 5-6, -3-(-5)> = <1, -1, 2>

Also, the vector from (1, 6, −5) to (x, y, 1) is given by:

v2 = <x-1, y-6, 1-(-5)> = <x-1, y-6, 6>

Since v1 and v2 are parallel, then

v2 = k * v1

So, we have the following equations

x-1 = k

y-6 = -k

6 = 2k+5

When solved for x, y and k, we have

k = 1

x = 2

y = 5.

Hence, the values of x and y are 2 and 5

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Answer:

90

42

42

48

48

Step-by-step explanation:

The diagonals of a rhombus are perpendicular.

m<1 = 90°

m<5 = 48° (alternate interior angle with 48°)

m<4 = 48° (the diagonals bisect opposite angles)

m<2 = 42° (acute angles of a right triangle are complementary)

m<3 = 42° (the diagonals bisect opposite angles)

Answer:

$25

Step-by-step explanation:

We Know

She has saved $15, which is three-fifths of the total cost of the game

How much does the game cost?

$15 = 3/5

$5 = 1/5

We Take

5 x 5 = $25

So, the cost of the game is $25.

Rounding to the nearest integer, the predicted calorie count for a cereal with 14 grams of sugar per serving is approximately 163 calories.

An integer is the number zero, a positive natural number or a negative integer with a minus sign. The negative numbers are the additive inverses of the corresponding positive numbers. In the language of mathematics,

To calculate the predicted calorie count for a cereal with 14 grams of sugar per serving using the predictive regression equation y^ = 94.639 + 4.918x, we substitute x = 14 into the equation.

y^ = 94.639 + 4.918(14)

y^ = 94.639 + 68.852

y^ ≈ 163.491

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Given the stock is purchased for $72.50 and it is expected that each day the stock will decrease by $0.05.

Let x = time (in days) and

P(x) = stock price (in $).

To find how many days it will take for the stock price to be equal to $65, we need to solve for x such that P(x) = 65.So, the equation of the stock price is

: P(x) = 72.50 - 0.05x

We have to solve the equation P(x) = 65. We have;72.50 - 0.05

x = 65

Subtract 72.50 from both sides;-0.05

x = 65 - 72.50

Simplify;-0.05

x = -7.50

Divide by -0.05 on both sides;

X = 150

Therefore, it will take 150 days for the stock price to be equal to $65

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Answer: 24.2

Step-by-step explanation: its right

The slope of the tangent line of the function f(x) = √x is 1/2√a

To determine the slope of the tangent line of the given function, we have to find the derivative of the function and take the evaluation at that point.

Given;

f(x) = √x

Using the power rule in differentiation;

[tex]f'(x) = \frac{dy}{dx} = \frac{1}{2}x^-^\frac{1}{2}[/tex]

To determine the slope of the tangent line, let's find the evaluation of the derivative at this specific point.

Assuming;

x = a

[tex]f'(a) = \frac{1}{2}a^-^\frac{1}{2}[/tex]

This implies that the slope of the tangent line to f(x) at the specific point is ;

[tex]\frac{1}{2}\sqrt{a}[/tex]

Note that since the square root function has a non-zero slope for positive values of x, the slope of the tangent line exists for all positive values of a.

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The limit can be expressed as the definite integral ∫[tex]2^3[/tex] x cos(x) dx over the interval [2, 3].

To express the given limit as a definite integral, we can first rewrite the expression inside the limit using the definition of a Riemann sum:

n cos(xi) xi δx = Σi=1n cos(xi) xi Δx

where Δx = (3 - 2)/n = 1/n is the width of each subinterval, and xi is the midpoint of the i-th subinterval [xi-1, xi].

We can then express the limit as the definite integral of the function f(x) = x cos(x) over the interval [2, 3]:

lim n→∞ Σi=1n cos(xi) xi Δx = ∫[tex]2^3[/tex] x cos(x) dx

Therefore, the limit can be expressed as the definite integral ∫[tex]2^3[/tex] x cos(x) dx over the interval [2, 3].

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To express the limit as a definite integral on the given interval [2,3], we first need to rewrite the expression using the definition of a Riemann sum. Recall that a Riemann sum is an approximation of the area under a curve using rectangular approximations.

Given the limit:

lim (n→∞) Σ [n * cos(x_i) * x_i * Δx], i=1 to n, with interval [2, 3]

We can express this limit as a definite integral by recognizing that it's a Riemann sum, which represents the sum of the areas of the rectangles under the curve of the function in the given interval. In this case, the function is f(x) = x * cos(x). The limit of the Riemann sum as n approaches infinity converges to the definite integral of the function over the interval [2, 3]. Therefore, we can write:

lim (n→∞) Σ [n * cos(x_i) * x_i * Δx] = ∫[2, 3] x * cos(x) dx

So, the limit can be expressed as the definite integral of the function x * cos(x) on the interval [2, 3].

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The median of the first 11 numbers of this set can be calculated as:(6th number + 7th number) / 2 = (21 + 22) / 2 = 21.5Therefore, the median of the first 11 numbers of the set is 21.5.

We are given that the median of a set of 22 consecutive numbers is 26.5. To find the median of the first 11 numbers of this set, we will have to find the first number of the set and add 5. So, let's find the first number of the set.

The median is the middle number of the set of 22 consecutive numbers. So, the 11th number is 26.5. Let's assume that the first number of the set is x.

Therefore, the 22nd number of the set is x + 21.Therefore, the median of the 22 consecutive numbers can be calculated as:(first number + 21st number) / 2 = 26.5(x + (x+21))/2 = 26.5Simplifying the above equation, we get:2x + 21 = 53x = 16Therefore, the first number of the set is 16. Now we can calculate the median of the first 11 numbers of this set. The first 11 numbers of this set are 16, 17, 18, ..., 24, 25, 26.5.

We can see that there are 11 numbers in this set. So, the median of the first 11 numbers of this set can be calculated as:(6th number + 7th number) / 2 = (21 + 22) / 2 = 21.5Therefore, the median of the first 11 numbers of the set is 21.5.

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The probability that the second card is a jack given that the first card was a 2 is 52/51.

To calculate the probability that the second card is a jack given that the first card was a 2, we need to consider the remaining cards in the deck after the first card is drawn.

When the first card is drawn and it is a 2, there are 51 cards remaining in the deck, out of which there are 4 jacks.

The probability of drawing a jack as the second card, given that the first card was a 2, can be calculated using conditional probability:

P(Second card is a jack | First card is a 2) = P(Second card is a jack and First card is a 2) / P(First card is a 2)

Since the first card is already known to be a 2, the probability of the second card being a jack and the first card being a 2 is simply the probability of drawing a jack from the remaining 51 cards, which is 4/51.

The probability of the first card being a 2 is simply the probability of drawing a 2 from the initial deck, which is 4/52.

P(Second card is a jack | First card is a 2) = (4/51) / (4/52)

Simplifying the expression:

P(Second card is a jack | First card is a 2) = (4/51) * (52/4)

P(Second card is a jack | First card is a 2) = 52/51

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Therefore, the formula W = Fd, where F is the force (weight) and d is the distance lifted. Plugging in our values, we get W = 48 lbs x 160 ft = 7,680 ft-lbs.

To find the work W done in pulling the rope to the top of the building, we need to calculate the weight of the rope and the distance it is being lifted. The weight of the rope is 0.8 lb/ft and the length is 60 ft, so the total weight is 48 lbs. The distance lifted is 160 ft.
The work W done in pulling the heavy rope, 60 ft long and weighing 0.8 lb/ft, to the top of a 160 ft high building can be found by calculating the weight of the rope and the distance it is being lifted. The weight of the rope is 48 lbs (0.8 lb/ft x 60 ft), and the distance lifted is 160 ft. Using the formula W = Fd, where F is the force (weight) and d is the distance lifted, we can plug in our values and find that W = 48 lbs x 160 ft = 7,680 ft-lbs.

Therefore, the formula W = Fd, where F is the force (weight) and d is the distance lifted. Plugging in our values, we get W = 48 lbs x 160 ft = 7,680 ft-lbs.

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To sketch the region in the plane consisting of points whose polar coordinates satisfy the conditions \(1 < r \leq 2\) and \(\frac{3}{4} \leq \theta \leq \frac{5}{4}\), we can visualize the region as follows:

1. Start by drawing a circle with radius 1. This represents the condition \(r > 1\).

2. Inside the circle, draw another circle with radius 2. This represents the condition \(r \leq 2\).

3. Now, mark the angle \(\theta = \frac{3}{4}\) on the circle with radius 1, and mark the angle \(\theta = \frac{5}{4}\) on the circle with radius 2.

4. Shade the region between the two angles \(\frac{3}{4}\) and \(\frac{5}{4}\) on both circles.

The resulting sketch should show a shaded annular region between the two circles, with angles \(\frac{3}{4}\) and \(\frac{5}{4}\) marked on the respective circles. This annular region represents the set of points whose polar coordinates satisfy the given conditions.

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Using the given information, the volume of the rectangular prism is 6,048 cubic units.

A rectangular prism is a three-dimensional geometric shape that has six rectangular faces, each with an identical size and form.

To compute the volume of a rectangular prism, multiply the length (L), width (W), and height (H).  

In this case, we are given:

L = 18

W = 21

H = 16

Volume = L × W × H

= 18 × 21 × 16

= 6,048 cubic units

Therefore, the volume of the rectangular prism is 6,048 cubic units.

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The original length of the reed is 45.

Given: A reed was broken off a cubit. This reed fitted 60 times along the length of the field. After restoring what was broken off, it fitted 30 times along the width. The area of the field is 525 square nindas

To find: Original length of the reedIn order to solve the problem,

let’s first define the reed length as x. It means the length broken from the reed is x-1. We know that after the broken reed is restored it fits 30 times in the width of the field.

It means;The width of the field = (x-1)/30Next, we know that before breaking the reed it fit 60 times in the length of the field. After breaking and restoring, its length is unchanged and now it fits x times in the length of the field.

Therefore;The length of the field = x/(60/ (x-1))= x (x-1) /60

Now, we can use the formula of the area of the field to calculate the original length of the reed.

Area of the field= length x widthx

(x-1) /60 × (x-1)/30

= 525 2(x-1)2

= 525 × 60x²- 2x -1785

= 0(x-45)(x+39)=0

x= 45 (as x cannot be negative)

Therefore, the original length of the reed is 45. Hence, the answer in 100 words is: The original length of the reed was 45. The width of the field is given as (x-1)/30 and the length of the field is x (x-1) /60, which is obtained by breaking and restoring the reed.

Using the area formula of the field (length × width), we get x= 45.

Thus, the original length of the reed is 45. This is how the original length of the reed can be calculated by solving the given problem.

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The expected value when a number is randomly chosen from the set (15, 22, 24, 28) is 22.25.

To calculate the expected value, we sum up the products of each number in the set and its corresponding probability, and then divide by the total number of possibilities. In this case, the probabilities are equal since each number has an equal chance of being chosen.        

The sum of the products is calculated as follows: (15 * 0.25) + (22 * 0.25) + (24 * 0.25) + (28 * 0.25) = 22.25.

The probability of choosing each number is 0.25, as there are four numbers in the set and each has an equal chance of being selected. By multiplying each number by its probability and summing the results, we obtain the expected value of 22.25. Therefore, if this process of randomly choosing a number is repeated many times, the average value over the long run would be expected to be approximately 22.25.

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There must exist an orange node in G that has both a purple neighbor and a yellow neighbor.

Suppose to the contrary that there is no orange node in G that has both a purple neighbor and a yellow neighbor. Let's consider the connected component of G containing an arbitrary vertex v. Since G is connected, this connected component contains all the vertices of G.

Since x(G) = 3, we know that this connected component contains a vertex of degree at most 2. Let's call this vertex u.

Since u has degree at most 2, it can have at most one neighbor that is colored purple and at most one neighbor that is colored yellow. Without loss of generality, assume that u has a purple neighbor but no yellow neighbor. Then, all other neighbors of u must be colored orange.

Consider the two cases:

Case 1: u has only one neighbor that is colored purple.

Then, this neighbor of u has no orange neighbor because u only has orange neighbors. Therefore, we can recolor u with the purple color, and the purple neighbor of u with the orange color. This new coloring is also a proper 3-coloring, but now u has both a purple neighbor and an orange neighbor, which contradicts our assumption.

Case 2: u has two neighbors that are colored purple.

Let's call these neighbors p and q. Since u has no yellow neighbor, both p and q must be colored orange. But then, p and q have no yellow neighbors, which contradicts the assumption that G is properly 3-colored.

Therefore, in both cases, our assumption that there is no orange node with both a purple neighbor and a yellow neighbor leads to a contradiction. Therefore, there must exist an orange node in G that has both a purple neighbor and a yellow neighbor.

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The expected value of the number of heads observed is 1, and the variance is 1/2.

When flipping two balanced coins, there are four possible outcomes: HH, HT, TH, and TT. Each of these outcomes has a probability of 1/4. Let X be the number of heads observed. Then X takes on the values 0, 1, or 2, depending on the outcome. We can use the formula for expected value and variance to find:

Expected value:

E[X] = 0(1/4) + 1(1/2) + 2(1/4) = 1

Variance:

Var(X) = E[X^2] - (E[X])^2

To find E[X^2], we need to compute the expected value of X^2. We have:

E[X^2] = 0^2(1/4) + 1^2(1/2) + 2^2(1/4) = 3/2

So, Var(X) = E[X^2] - (E[X])^2 = 3/2 - 1^2 = 1/2.

Therefore, the expected value of the number of heads observed is 1, and the variance is 1/2.

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Let's choose c = (p + q) / 2. Since p < q, it follows that (p + q) / 2 lies between f(p) and f(q). Therefore, there exists an x between p and q such that f(x) = (p + q) / 2.

To prove the proposition "if p and q are real numbers with p < q, then there exists an x in the real numbers such that p < x < q," we can use the intermediate value theorem.

Proof:

Assume p and q are real numbers with p < q.

Consider the function f(x) = x defined on the interval [p, q]. Since f(x) is a continuous function on this interval, the intermediate value theorem guarantees that for any value c between f(p) and f(q), there exists a value x between p and q such that f(x) = c.

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The final integration result is ∫1/2 dx/x^2√x^2+196 = (2/√7) + C, where C is the constant of integration.

We start by making the given substitution:

x = 14 tan(θ), dx = 14 sec^2(θ) dθ

Substituting these into the integral, we get:

∫1/2 dx/x^2√x^2+196 = ∫tan(θ) dθ/(196tan^2(θ)+196)^(1/2)

= ∫tan(θ) dθ/14(sec^2(θ))^(3/2)

= ∫sin(θ)/14 dθ/cos^3(θ)

Using the trigonometric identity 1 + tan^2(θ) = sec^2(θ), we get:

sin(θ) = 14 tan(θ)/√(196 tan^2(θ) + 196) = x/√(x^2 + 196)

Therefore, the integral becomes:

∫dx/(x^2 + 196)^(1/2) = ∫sin(θ)/14 dθ/cos^3(θ)

= ∫x/14(x^2 + 196)^(1/2) dx

Using the substitution u = x^2 + 196, du/dx = 2x, we get:

∫x/14(x^2 + 196)^(1/2) dx = (1/28) ∫du/u^(1/2)

= (1/28) (2u^(1/2)) + C

= (1/14) (x^2 + 196)^(1/2) + C

Substituting back x = 14 tan(θ), we get:

(1/14) (x^2 + 196)^(1/2) = (1/14) (196 tan^2(θ) + 196)^(1/2)

= (1/14) (196 sec^2(θ))^(1/2) = 2/√7

Therefore, the final answer is:

∫1/2 dx/x^2√x^2+196 = (2/√7) + C, where C is the constant of integration.

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The reflection of vector v=[293] in the line l that consists of all scalar multiples of the vector w=[22−1] is [-17, 192, 73].

The reflection of vector v=[293] in the line l that consists of all scalar multiples of the vector w=[22−1] is [-17, 192, 73].

To find the reflection of vector v in the line l, we need to decompose vector v into two components: one component parallel to the line l and the other component perpendicular to the line l. The component parallel to the line l is obtained by projecting v onto w, which gives us:

proj_w(v) = ((v dot w)/||w||^2) * w = (68/5) * [22,-1] = [149.6, -6.8]

The component perpendicular to the line l is obtained by subtracting the parallel component from v, which gives us:

perp_w(v) = v - proj_w(v) = [293,0,0] - [149.6, -6.8, 0] = [143.4, 6.8, 0]

The reflection of v in the line l is obtained by reversing the direction of the perpendicular component and adding it to the parallel component, which gives us:

refl_l(v) = proj_w(v) - perp_w(v) = [149.6, -6.8, 0] - [-143.4, -6.8, 0] = [-17, 192, 73]

Therefore, the reflection of vector v=[293] in the line l that consists of all scalar multiples of the vector w=[22−1] is [-17, 192, 73].

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The volume of the pill is 452.39mm³.

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

The height of the cylindrical portion is 12mm

The overall height is 18mm.

So, radius of hemisphere at any one end will be half the difference between cylindrical portion and the overall height.

The radius of the sphere is:

= (18mm - 12mm)/2

= 3mm

The volume of the capsule is :

= Volume of cylinder +2(Volume of the hemisphere)

= (πR²h) + 2[(4/6)πR³]

= (π×3²×12) + 2[(4/6)×π×3³]

= 339.292mm³ + 113.0973mm³

= 452.3893 mm³

= 452.39 mm³

Full question:

A pill has the shape of a cylinder with a hemisphere at each end. The height of the cylindrical portion is 12mm and the overall height is 18mm. Find the volume of the pill in cubic millimeters.

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Answer:

595

Step-by-step explanation:

557+38=595

rule here is to start by 453 add by 38

The rule that describes the center of the new circle after the translation is:

(x, y) → (5 + m, -8 + p)

In this rule, the original x-coordinate (5) is shifted by m units to the left, resulting in (5 + m).

The original y-coordinate (-8) is shifted p units up, resulting in (-8 + p).

These adjustments in the x and y coordinates represent the translation of the circle.

Therefore, the new center coordinates of the translated circle are (5 + m, -8 + p).

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A graph of the image of quadrilateral STUV after applying the sequence of transformations is shown in the image below.

In Mathematics, a reflection across the line y = x would interchange the x-coordinate and y-coordinate, and this can be modeled by the following transformation rule:

(x, y)                                    →              (y, x)

Ordered pair S (9, -4)    →        Ordered pair S' (-4, 9).

Ordered pair T (13, -8)    →        Ordered pair T' (-8, 13).

Ordered pair U (7, -10)    →        Ordered pair U' (-10, 7).

Ordered pair V (3, -10)    →        Ordered pair V' (-10, 3).

By translating quadrilateral S'T'U'V' 17 units right and down 1 unit, the new coordinates of the image include the following:

(x, y)               →                           (x + 17, y - 1)

S' (-4, 9)         →    (-4 + 17, 9 - 1) = S" (13, 8)  

T' (-8, 13)        →    (-8 + 17, 13 - 1) = T" (9, 12)  

U' (-10, 7)         →    (-10 + 17, 7 - 1) = U" (7, 6)  

V' (-10, 3)         →    (-10 + 17, 3 - 1) = V" (7, 2)  

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