calculate the electrical potential at a point P a distance of 1 m from either two to charge of +10 micro coulomb and -5 micro coulomb which are 10 cm apart calculate also the potential energy of a +2 micro coulomb charge placed at a point p​

Answers

Answer 1

Answer:

a)  V = 45 10³ V, b) U = 4.59 J

Explanation:

a) The electric potential for a series of point charges is

         V = k ∑ [tex]\frac{q_i}{r_i}[/tex]

in this case point P is at a distance of 1 m from each charge, so the point is located perpendicular to the charges at its midpoint

 

         V = k ( [tex]\frac{q_1}{r} + \frac{q_2}{r}[/tex])

         V = 9 10⁹ (10 - 5/ 1) 10⁻⁶

         V = 45 10³ V

b) the potential energy is

           U = k (  [tex]\frac{q_1q}{r} + \frac{q_2q}{r} + \frac{q_1q_2}{r_2}[/tex] )

where r = 1m and r₂ is the distance between the two charges r₂ = 0.10 m

           U = 9 10⁹ (10 2 / 1 - 5 2/1 - 10 5 /0.10) 10⁻¹²

           U = 9 10⁻³  510

           U = 4.59 J


Related Questions

A 92-kg man climbs into a car with worn out shock absorbers, and this causes the car to drop down 4.5 cm. As he drives along he hits a bump, which starts the car oscillating at an angular frequency of 4.52 rad/s. What is the mass of the car ?A) 890 kg
B) 1900 kg
C) 920 kg
D) 990 kg
E) 760 kg

Answers

Answer:

the mass of the car is 890 kg

Explanation:

Given;

mass of the man, m = 92 kg

displacement of the car's spring, x = 4.5 cm = 0.045 m

acceleration due to gravity, g = 9.8 m/s²

The spring constant of the car,

f = kx

where;

f is the weight of the man on the car = mg

mg = kx

k = mg/x

k = (92 x 9.8) / 0.045

k = 20,035.56 N/m

The angular speed of car, ω, when the is inside is given as 4.52 rad/s

The total mass of the car and the man is calculated as;

[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega^2 = \frac{k}{m} \\\\m = \frac{k}{\omega^2} = \frac{20,035.56}{(4.52)^2} = 980.7 \ kg[/tex]

The mass of the car alone = 980.7 kg - 92 kg

                                            = 888.7 kg

                                             ≅ 890 kg

Therefore, the mass of the car is 890 kg

Una persona en la tierra tiene una masa de 70[kg]. Calcule: a) Su fuerza peso en la tierra. b) Su fuerza peso en la luna (considere que la aceleración gravitatoria en la luna es de 1.62 [m/s²]) *

Answers

Answer:

a. El peso = 686 Newton

b. El peso = 113.4 Newton

Explanation:

Dados los siguientes datos;

Masa = 70 kg

Aceleración debida a la gravedad en la luna = 1,62 m/s² una.

a. Para encontrar la fuerza-peso en la Tierra;

Sabemos que la aceleración debida a la gravedad es igual a 9,8 m/s² en el planeta Tierra.

El peso se puede definir como la fuerza que actúa sobre un cuerpo o un objeto como resultado de la gravedad.

Matemáticamente, el peso de un objeto viene dado por la fórmula;

[tex] Peso = mg [/tex]

Dónde;

m es la masa del objeto.

g es la aceleración debida a la gravedad.

Substituting into the formula, we have;

El peso = 70 * 9.8

El peso = 686 Newton

b. To find weight on moon;

Weight = mass * acceleration due to gravity on moon

Weight = 70 * 1.62

Weight = 113.4 Newton

a 50kg skater on level ice, has built up her speed to 30km/h. how far will she coast before sliding friction dissipates her energy?​

Answers

Answer:

belpw

Explanation:

The distance prior to the sliding friction dispersing her energy would be:

- The distance will remain unaffected by the sliding friction i.e. 354m

As we know, When Sliding friction dissolves her energy, leading her Kinetic Energy to turn 0 on coming to the state of rest. So,

[tex]1/2 mv^2 - 1/2 mu^2 = -W[/tex]            (∵ Work in -ve denotes it is done opposite to friction)

Given that,

m(mass) [tex]= 50 kg[/tex]

v(velocity) [tex]= 30 km/hr[/tex] or [tex]8.33 m/s[/tex]

The coefficient of Kinetic Friction [tex]= 0.01[/tex]

g(gravitational force) [tex]= 9.8 m/s^2[/tex]

Initial Velocity(u) [tex]= 30[/tex] × [tex]1000/3600 m/s[/tex]

[tex]= 8.33 m/s[/tex]

Now by employing the provided values,

[tex]F =[/tex] μ[tex]mg[/tex]

[tex]= (0.01) (50) (9.8)[/tex]

[tex]= 4.9[/tex]

[tex]F = 4.9 N[/tex]

By using the above expression, we will find the distance;

[tex]1/2 mv^2 - 1/2 mu^2 = -W[/tex]

⇒ [tex]1/2 (50) (0)^2 - 1/2 (50) (8.33)^2 = -4.9(S)[/tex]

⇒ [tex]1734.7225 = 4.9S[/tex]

⇒ [tex]S = 1734.7225/4.9[/tex]

[tex]S = 354 m[/tex]

Because [tex]1/2 mv^2 - 1/2 mu^2 = -W[/tex]  [tex]= -[/tex] μmgS

⇒ [tex]S = (u^2 - v^2)[/tex]/2μ[tex]g[/tex]

Thus, the distance will remain unaffected by the sliding friction i.e. 354m

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Prepare a stock available at home following the procedure you learned in this lesson. Have a picture of the finished product and a narration on how you do it​

Answers

Answer:

NO, 1. is stocks

2. is also stocks

bouquit GARNI IS NUMBER 3

NUMBER 4 IS ACID PRODUCTS

number 5 is brown stock

Explanation:

stocks are bones

A 5.0-kg solid cylinder of radius 0.25 mis free to rotate about an axle that runs along the cylinders length and passes through its center. A thread wrapped around the cylinder is weighed down by a mass of 2.0 kg so as to unwrap and make the cylinder rotate as this mass falls. Ignore any friction in the axle. If there is no slippage between the thread and the cylinder, and the cylinder starts from rest (a) Calculate the velocity of the block after it has fallen a distance of 2.0m. Give your answer in m.s (b) Calculate the total work done by the rope on the cylinder after the block has fallen a distance of 2.0 m. Give your answer in Joule. ​

Answers

Answer:

157n is the correct answer

On a day when the speed of sound is 345 m/s, a 440 Hz tuning fork causes a tube closed at one end to vibrate in the second harmonic. How long is the tube?​

Answers

Answer:

Length = 3.136 meters

Explanation:

Given the following data;

Speed = 345 m/s

Frequency = 440 Hz

To find how long is the tube;

First of all, we would determine the wavelength;

Wavelength = speed/frequency

Wavelength = 345/440

Wavelength = 0.784 m

Next, we would determine how long is the tube using the formula;

[tex] Length = \frac {2n - 1}{4} * wavelength [/tex]

Substituting into the formula, we have;

[tex] Length = \frac {2*1 - 1}{4} * 0.784 [/tex]

[tex] Length = \frac {2 - 1}{4} * 0.784 [/tex]

[tex] Length = \frac {1}{4} * 0.784 [/tex]

Length = 3.136 meters

A pitcher throws a curveball that reaches the catcher in 0.61 s. The ball curves because it is spinning at an average angular velocity of 350 rev/min (assumed constant) on its way to the catcher's mitt. What is the angular displacement of the baseball (in radians) as it travels from the pitcher to the catcher

Answers

Answer:

22.36 rad

Explanation:

Applying,

ω = θ/t.............. Equation 1

Where ω  = angular velocity, θ = angular displacement of the baseball, t = time

make θ the subject of the equation

θ = ωt............... Equation 2

From the question,

Given: ω = 350 rev/min = 350(0.10472) = 36.652 rad/s, t = 0.61 s

Substitute these values into equation 1

θ = 0.61(36.652)

θ = 22.36 rad

Hence the angular displacement of the baseball is  22.36 rad

A swift blow with the hand can break a pine board. As the hand hits the board, the kinetic energy of the hand is transformed into elastic potential energy of the bending board; if the board bends far enough, it breaks. Applying a force to the center of a particular pine board deflects the center of the board by a distance that increases in proportion to the force. Ultimately the board breaks at an applied force of 870 N and a deflection of 1.4 cm.
a. To break the board with a blow from the hand, how fast must the hand be moving? Use 0.50 kg for the mass of the hand.
b. If the hand is moving this fast and comes to rest in a distance of 1.2 cm, what is the average force on the hand?

Answers

Answer:

A. The hand must move with a velocity of 6.98 m/s to break the board.

B. Average force on the hand = 1025 N

Explanation:

A.To determine the speed the hand must move with to break the board, the force workdone in breaking the board is found first.

Workdone = force × distance

Minimum force required = 870 N;

Distance moved by board/Deflection in order to break = 1.4 cm = 0.014 M

Workd done = 870 N × 0.014 m = 12.18 Nm or 12.18 J

This work done = Kinetic energy of the hand

Kinetic energy = mv²/2 ; where m is mass and v is velocity

Mass of hand = 0.50 Kg, velocity = ?, K.E. = 12.18 J

v² = 2 KE/m

v = √2KE/m

v = √(2 × 12.18/0.50)

v = 6.98 m/s

Therefore, the hand must move with a velocity of 6.98 m/s to break the board.

B. Average force on the hand

This can be determined using the equation of motion, v² = u² + 2as to find acceleration, since force = mass × acceleration

From the equation of motion, a = v² - u²/2s

At rest, v = 0, u = 6.98, s = 1.2 cm = 0.012 m

a = 0² - 6.98²/ 2 × 0.012

a = -2030 m/s²

Force = 2030 m/s² × 0. 50 kg = 1015 N

Therefore, Average force on the hand = 1025 N

advantages of 2 pulley system​

Answers

Answer:

Using multiple pulleys decreases the amount of force necessary to move an object by increasing the amount of rope used to raise the object. The mechanical advantage (MA) of a pulley system is equal to the number of ropes supporting the movable load.

An elevator lifts a mass=200kg a distance of 20m in 15s. What power does the elevator motor produce? *
A) 20000J
B) 20000W
C) 2666W
D) 600000W
show your work please

Answers

Answer:

C. 2666W

Explanation:

m =200kg

h =20m

t =15s

g =10ms^-2

p = mgt/t

=200×20×10/15

=40,000/15

=2666.6

≈2666W

.Use Newton's third law to describe the forces that are exerted by the falling egg and the ground. Explain how the use of the straws in the design affects the forces

Answers

Answer:

Newton's third law states that for every action, there is an equal and opposite reaction. That means when you exert a force on an object, the object exerts a force back on you. ... Using shock-absorbing materials can help reduce the amount of force exchanged between the ground and the egg.

Explanation:

I hope it helps you

When one of the tall straws hits the ground, the energy is transferred to the center of the pyramid and then to the egg, but as the middle straw is connected to the outer surface of the egg, energy enters trying to make the egg rotate. This is governed by Newton's third law.

What is Newton's third law?

If an object exerts a force on another object, then another object must exert a force of equal magnitude and opposite direction back on first object.

What are examples of Newton's third law?

Examples of Newton's third law are:

A swimmer moves forward by pushing off the side of pool. This way, the wall pushes in opposite direction and giving acceleration.

Another example is rockets move forward by expelling gas backward at high velocity. This means the rocket exerts a large backward force on the gas in the rocket combustion chamber, and the gas therefore exerts a large reaction force forward on the rocket. This reaction force is called thrust.

Helicopters similarly create lift by pushing air down, thereby experiencing an upward reaction force. Birds and airplanes also fly by exerting force on air in a direction opposite to that of whatever force they need. For example, the wings of a bird force air downward and backward in order to get lift and forward motion.

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Two stars that are in the same constellation:

Answers

Answer:

A binary star is a star system consisting of two stars orbiting around their common barycenter.

❣️(◍Jess bregoli◍)❣️

#keep learning

A student solving a physics problem to find the unknown has applied physics principles and obtained the expression: μkmgcosθ=mgsinθ−ma, where g=9.80meter/second2, a=3.60meter/second2, θ=27.0∘, and m is not given. Which of the following represents a simplified expression for μk?A student solving a physics problem to find the unknown has applied physics principles and obtained the expression: , where , , , and is not given. Which of the following represents a simplified expression for ?tanθ− agTo avoid making mistakes, the expression should not be simplified until the numerical values are substituted.gsinθ−agcosθThe single equation has two unknowns and cannot be solved with the information given.

Answers

Solution :

Given expression :

[tex]$\mu_k$[/tex]mgcosθ = mgsinθ − ma

Here, g = 9.8 [tex]m/s^2[/tex] , a = 3.60 [tex]m/s^2[/tex] , θ = 27°

Therefore,

[tex]$\mu_k mg \cos \theta = mg \sin \theta - ma$[/tex]

[tex]$\mu_k mg \cos \theta = m(g \sin \theta - a)$[/tex]

[tex]$\mu_k g \cos \theta = (g \sin \theta - a)$[/tex]

[tex]$\mu_k =\frac{(g \sin \theta-a)}{g \cos \theta}$[/tex]

Mow calculating the coefficient of kinetic friction as follows :

[tex]$\mu_k=\frac{g \sin \theta-a}{g \cos \theta}$[/tex]

[tex]$\mu_k=\frac{9.8 \times \sin 27^\circ-3.60}{9.8 \times \cos 27^\circ}$[/tex]

[tex]$\mu_k=0.097$[/tex]

Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the electric field strength between them, if the potential 8.00 cm from the zero volt plate

Answers

Complete Question

Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the electric field strength between them, if the potential 8.00 cm from the zero volt plate(and 2.00 cm from the other) is 450 V?

Answer:

[tex]V'=562.5v[/tex]

Explanation:

From the question we are told that:

Separation distance [tex]d=10cm[/tex]

Voltage at 8cm [tex]V_8=450v[/tex]

Generally the equation for Voltage is mathematically given by

[tex]|V|=|E.d|[/tex]

Where

E=electric field

Therefore

At [tex]d=0.8[/tex]

 [tex](450-0)V=E*(0.08m)[/tex]

 [tex]E=\frac{450}{0.08}[/tex]

 [tex]E=5625v/m[/tex]

Therefore

 At [tex]d=10[/tex]

 [tex]V'=Ed[/tex]

 [tex]V'=5625*0.1m[/tex]

 [tex]V'=562.5v[/tex]

QUESTION 24
2 point
A man travels 40 km eastwards, then 40 km to the south before finally travelling
10 km west. At the end of his journey the magnitude of his displacement is

Answers

-30. 40 east on timeline, 40 down, then 10 over right

Mary applies a force of 73 N to push a box with an acceleration of 0.48 m/s^2. When she increases the pushing force to 84 N, the box's acceleration changes to 0.64 m/s^2. There is a constant friction force present between the floor and the box.

Required:
a. What is the mass of the box?
b. What is the coefficient of kinetic friction between the floor and the box?

Answers

Answer: [tex]68.75\ kg, 0.06[/tex]

Explanation:

Mary applies a force of 73 N to create an acceleration of [tex]0.48\ m/s^2[/tex]

When She increases force to 84 N, it creates an acceleration of [tex]0.64\ m/s^2[/tex]

Friction opposes the motion of box

[tex]\Rightarrow 73-f=m\times 0.48\quad \ldots(i)\\\Rightarrow 84-f=m\times 0.64\quad \ldots(ii)[/tex]

Subtract (i) from (ii)

[tex]\Rightarrow 11=m(0.64-0.48)\\\Rightarrow m=68.75\ kg[/tex]

Therefore friction is

[tex]\Rightarrow f=73-68.75\times 0.48\\\Rightarrow f=73-33\\\Rightarrow f=40\ N[/tex]

Here, friction is kinetic friction which is given by

[tex]\Rightarrow f=\mu_kmg\\\Rightarrow 40=\mu_k 68.75\times 9.8\\\Rightarrow \mu_k=0.061[/tex]

The fact that we can define electric potential energy means that:
A) the electric force is nonconservative
B) the electric force is conservative
C) the work done on a charged particle depends on the path it takes
D) there is a point where the electric potential energy is exactly zero
E) it takes work for the electric force to move from some point a to some other point b and back again

Answers

Answer: I'd go with Option B if you're allowed to pick One Option Only.

Option A is wrong. Electric Forces arent Non - Conservative. They're Conservative forces.

Option B: We Can Only Define Potential Energies for conservative Forces/fields✅

Option C is wrong. Since the Electric Force is Conservative... It doesn't depend on the path taken.

Option D... There's a Point where the electric Potential Energy is Zero but the separation Distance Would be large.

E is wrong because the Workdone around a closed path is Zero.

The electric potential energy results from the conservative Coulomb forces.

What is electric potential energy?

The electric potential energy is the potential energy that results due to the conservative Coulomb forces and is always associated with the set of two charged particles.

Any object can have electric potential energy by two key elements first is its own charge and the second is its position with respect to the other charged particle.

The electric potential energy-containing only one point charge will be zero. Because there are no other sources of electrostatic force against which an external agent must do work in moving the point charge from infinity to its final position.

Thus the electric potential energy results from the conservative Coulomb forces.

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A 0.277 kg bat is flying 4.25 m/s.
It then doubles its velocity.
How much KE did it gain?

Answers

Answer:

7.51

Explanation:

The mass of the bat is given to us as:

m = 0.277  kg

,

and its initial velocity is:

v

i  = 4.25  m/s

 

When the velocity is doubled, the new value becomes:

v f = 4.25 m/s × 2 = 8.5   m/s

.

The formula for kinetic energy is:

K

=

1

2

m

v

2

.

The change in kinetic energy is:

Δ K = 1 /2( m ) ( v2 f − v 2 i ) = 1 2 ( 0.277)

10-2.5=7.5J

7.51  J

.

The bat gained 7.51 joules.

What is the y component of a vector that is 673 m at -38o?

Answers

Answer:

D_y = 414.38m

Explanation:

D_y = D*sin(x)

D_y = 673m*sin(38°)

D_y = 414.38m

A ceramic tile measuring 50 cm x50cm has been designed to bear a pressure of 40 N/in . Will it with stand a force of 5 N?

Answers

Answer:

The ceramic tile will stand the force of 5 N.

Explanation:

Step 1: Calculate the area (A) of the ceramic tile

We will use the formula for the area of a square.

A = 50 cm × 50 cm = 2500 cm²

Step 2: Convert "A" to in²

We will use the conversion factor 1 in² = 6.45 cm².

2500 cm² × 1 in²/6.45 cm² = 3.9 × 10² in²

Step 3: Calculate the pressure (P) exerted by a force (F) of 5 N

We will use the following expression.

P = F/A

P = 5 N / 3.9 × 10² in² = 0.013 N/in²

Since the pressure exerted would be less than the maximum pressure resisted (40 N/in²), the ceramic tile will stand the force of 5 N.

A supernova is a large explosion that takes place at the end of a star's life cycle. Although supernovas only burn for a short amount of time, they can tell scientists a lot about the universe. Scientists use electromagnetic waves to detect supernovas. Why are electromagnetic waves used instead of sound waves?
A. Electromagnetic waves are created by physical vibrations.
B. Electromagnetic waves travel slower than sound waves.
C. Electromagnetic waves can travel in vacuums.
D. Electromagnetic waves cannot be absorbed.

Answers

I’m pretty sure it’s c

Electromagnetic waves can travel in vacuums.

To find the correct statement among all the options, we need to know more about the electromagnetic wave.

What is electromagnetic wave?Electromagnetic wave is a transeverse wave in which both the electric field and magnetic field travel simultaneously.The electric field and magnetic field are perpendicular to each other and perpendicular to the direction of prapagation of the EM wave.How is the electromagnetic wave created?

Electromagnetic wave is created from the oscillation of any charge particles like electron, proton, ions etc. .

What is the speed of electromagnetic waves?The speed of electromagnetic wave in vacuums is maximum that is 3×10⁸ m/s. (Speed of EM wave is much more than that of sound (340m/s)).In any other medium, its speed changes and it depends on the refractive index of that medium.How is the electromagnetic wave affected by medium?In any medium, the electromagnetic wave is absorbed to some extent except ideal vacuum. Also in vacuum in space, it's absorbed; because the vacuum in space is not completely vacuum since it contains few molecules per cubic kilometers.However, the electromagnetic wave can travel in any medium even in vacuum while the sound wave can travel only in particle medium.

Thus we conclude that scientists use electromagnetic waves to detect supernovas because electromagnetic waves can travel in vacuums.

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HELP ME PLSSSS!!!!!!!
Which statement describes why the viscosity of olive oil is higher than that of
rubbing alcohol?
A. The molecules that make up olive oil are longer than those that
make up alcohol, so they have more resistance to sliding past one
another.
B. The molecules that make up olive oil repel one another, while the
molecules that make up alcohol are attracted to one another.
C. The molecules that make up olive oil are shorter than those that
make up alcohol, so they have more resistance to sliding past one
another.
D. The molecules that make up olive oil are attracted to one another,
while the molecules that make up alcohol repel one another.

Answers

Answer:B

Explanation: The answer explains it

The molecules that make up olive oil are longer than those that make up alcohol, so they have more resistance to sliding past one another. The correct answer is option A.

This higher resistance to flow leads to a higher viscosity in olive oil compared to rubbing alcohol. Viscosity is a measure of a fluid's resistance to flow, and longer molecules in olive oil result in stronger intermolecular forces and entanglements. In contrast, rubbing alcohol has shorter and less complex molecules, which allow them to move more freely and exhibit lower viscosity. The molecular structure and intermolecular forces play a crucial role in determining the viscosity of liquids, making olive oil more viscous than rubbing alcohol. Option A is correct.

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define force and types of force​

Answers

Answer:

Force is the strength or weight of things that depends on movement. The types of forces are conteact force, spring force, applied force, air resistance force, normal force, frictional force, tension force, and non-contact force.

What is the direction of a vector with an x component of -12 m and a y component of -15 m?

Answers

Answer:

[tex]51.34^{\circ}[/tex]

Explanation:

Given that,

x component of a vector = -12 m

The y component of a vector = -15 m

We need to find the direction of a vector. The direction of a vector is given by :

[tex]\tan\theta=\dfrac{y}{x}[/tex]

Put all the values,

[tex]\tan\theta=\dfrac{-15}{-12}\\\\\theta=\tan^{-1}(\dfrac{-15}{-12})\\\\\theta=51.34^{\circ}[/tex]

So, the direction of vector is [tex]51.34^{\circ}[/tex] to x component.

Mỗi giây có 2,1.1018 ion+
2 và 1,8.1018
electron chạy qua tiết diện đèn ống.
Đường kính tiết diện của đèn ống là 2,0
cm. Mật độ dòng điện trung bình qua
đèn là bao nhiêu

Answers

A I seen it on the quiz

There are only two charged particles in a particular region. Particle 1 carries a charge of 3q and is located on the negative x-axis a distance d from the origin. Particle 2 carries a charge of -2q and is located on the positive x-axis a distance d from the origin.

Required:
Where is it possible to have the net field caused by these two charges equal to zero?

Answers

Answer:

The net field will be the sum of the fields created by each charge.

where the charge Q in a position r' is given by:

E(r) = k*Q/(r - r')^2

Where k is a constant, and r is the point where we are calculating the electric field.

Then for the charge 3q, in the position r₁ = (-d, 0, 0) the electric field will be:

E₁(r) = k*3q/(r - r₁)^2

While for the other charge of -2q in the position r₂ = (d, 0, 0)

The electric field is:

E₂(r) = -k*2*q/(r - r₂)^2

Then the net field at the point r is:

E(r) = E₁(r) + E₂(r) = k*3q/(r - r₁)^2 + -k*2*q/(r - r₂)^2

E(r) = k*q*( 3/(r - r₁)^2 - 2/(r - r₂)^2)

Then if the we want to find the points r = (x, y, z) such that:

E(r) = 0 = k*q*( 3/(r - r₁)^2 - -k*2*q/(r - r₂)^2)

Then we must have:

0 = ( 3/(r - r₁)^2 - 2/(r - r₂)^2)

Also remember that the distance between two points:

(x, y, z) and (x', y', z') is given by:

D = √( (x - x')^2 + (y - y)^2 + (z -z')^2)

Then we can rewrite:

r - r₁ = √( (x - (-d))^2 + (y - 0 )^2 + (z -0)^2)

       = √( (x + d))^2 + y^2 + z^2)

and

r - r₂ =  √( (x - d)^2 + (y - 0 )^2 + (z -0)^2)

       = √( (x - d))^2 + y^2 + z^2)

Replacing that in our equation we get:

0 = ( 3/(√( (x + d))^2 + y^2 + z^2))^2 - -k*2*q/(√( (x - d))^2 + y^2 + z^2))^2)

0 = (3/((x + d))^2 + y^2 + z^2) - 2/ (x - d))^2 + y^2 + z^2)

We want to find the values of x, y, z such that the above equation is true.

2/ (x - d))^2 + y^2 + z^2) = (3/((x + d))^2 + y^2 + z^2)

2*[((x + d))^2 + y^2 + z^2] = 3*[(x - d))^2 + y^2 + z^2]

2*(x + d)^2  + 2*y^2 + 2*z^2 = 3*(x - d)^2 + 3*y^2 + 3*z^2

2*(x + d)^2 - 3*(x - d)^2 =  3*y^2 + 3*z^2 -  2*y^2 - 2*z^2

2*(x + d)^2 - 3*(x - d)^2  = y^2 + z^2

2*x^2 + 2*2*x*d + 2*d^2 -  3*x^2 + 3*2*x*d - 3*d^2 = y^2 + z^2

-x^2 + 10*x*d - d^2 = y^2 + z^2

we can rewrite this as:

- ( x^2 - 10*x*d + d^2) =  y^2 + z^2

now we can add and subtract 24*d^2 inside the parenthesis to get

- ( x^2 - 10*x*d + d^2 + 24*d^2 - 24*d^2) =  y^2 + z^2

-( x^2 - 2*x*(5d) + 25d^2 - 24d^2) = y^2 + z^2

-(x^2 - 2*x*(5d) + (5*d)^2) + 24d^2 = y^2 + z^2

The thing inside the parenthesis is a perfect square:

-(x - 5d)^2 + 24d^2 = y^2 + z^2

we can rewrite this as:

24d^2 = y^2 + z^2 + (x - 5d)^2

This equation gives us the points (x, y, z) such that the electric field is zero.

Where we need to replace two of these values to find the other, for example, if y = z = 0

24d^2 = (x - 5d)^2

√(24d^2)  = x - 5d

√24*d = x - 5d

√24*d + 5d = x

so in the point (√24*d + 5d, 0, 0) the net field is zero.

the oscillation of pendulum is ...... motion​

Answers

Answer:

A simple pendulum consists of a ball (point-mass) m hanging from a (massless) string of length L and fixed at a pivot point P. When displaced to an initial angle and released, the pendulum will swing back and forth with periodic motion.

equations of kinematics new dimensions

Answers

Answer:

Δx Displacement

t Time interval

v0  Initial velocity

v  Final velocity

a  Constant acceleration

Explanation:

I dont know if this helps because these are kinda like, examples... hope it helps tho :)

A man pulls his dog (m=20kg) on a sled with a force of 100N at a 60° angle from the horizontal. What is the horizontal component of the force?

A) 100N

B) 196N

C) 50N

D) 86N

show your work please

Answers

Answer:

the horizontal component of the force is 50 N

Explanation:

Given;

force applied by the man, F = 100 N

angle of inclination of the force, θ = 60⁰

mass of the dog, m = 20 kg

The horizontal component of the force is calculated as;

[tex]F_x = F\times cos(\theta)\\\\F_x = 100 \ N \times cos(60^0)\\\\F_x = 100\ N \times 0.5\\\\F_x = 50 \ N[/tex]

Therefore, the horizontal component of the force is 50 N

We say that evaporation is a cooling process. (a) What cools and what warms? We say that condensation is a warming process. (b) What warms and what cools?

Answers

Answer:

a liquid warms gas cools

b solid piece warms and liquid cools

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