Answer:
-21
Step-by-step explanation:
4(x+9) = 4x+36
4x+36 = 2x-6
-36 -36
minus 36 from both sides
4x = 2x-42
2x = -42
-42/2 = -21
x = -21
Hi there!
We are given the equation below:
[tex] \large \boxed{4(x + 9) = 2x - 6}[/tex]
1. Expand 4 in the expression.
When expand in the expression, it is like multiply everything in the expression. So when we expand 4 in x+9, it becomes 4(x)+9(4).[tex] \large{(4 \times x) + (9 \times 4) = 2x - 6} \\ \large{(4x) + (36) = 2x - 6}[/tex]
Cancel the brackets.
[tex] \large{4x + 36 = 2x - 6}[/tex]
2. Isolate x-term and solve for the variable.
Think it easy. If you want to isolate x-term then what should you do? Well simply swap sides, and change the operator/sign.[tex] \large{4x - 2x = - 6 - 36}[/tex]
Finally, combine like terms.
[tex] \large{2x = - 42}[/tex]
Then divide both sides by 2 so we can finally leave only x-term.
[tex] \large{ \frac{2x}{2} = \frac{ - 42}{2} } \\ \large \boxed{x = - 21}[/tex]
3. Check the solution if it is right or wrong.
This step is optional but if you are not confident on your answer, this step is recommended.To check the answer, we simply substitute the value of x which is -21 in the equation and see if both sides are equal or not. If both sides are equal then the answer is correct, if not then the answer is wrong. Therefore,
[tex] \large{4(x + 9) = 2x - 6 \longrightarrow 4( - 21 + 9) = 2 ( - 21) - 6} \\ \large{4( - 12) = - 42 - 6} \\ \large{ - 48 = - 48}[/tex]
Since both sides are equal when substitute in x = -21.
4. Answer
Hence, the answer for this equation is x = -21.I hope this helps and let me know if you have any doubts!
ASAP PLEASE!!The table and the relative frequency histogram show the distribution of the number of tails and three coins are tossed. Find the probability P(T=1). write your answer as a fraction.
Explanation:
P(T = 1) is the notation that means "The probability of getting exactly one tail". The table shows 3/8 in the bottom row, under the "1" in the top row. So that's why P(T = 1) = 3/8
Or it might make more sense to say P(one tail) = 3/8 so we don't have too many equal signs going on.
help me please if you can't don't touch it
Answer:
option B : 31.4 cm
Step-by-step explanation:
Given radius , r = 5cm
Circumference = [tex]2 \pi r[/tex]
= 2 x 3.14 x 5
=10 x 3.14
= 31.4 cm
Answer:
b. 31.4
Step-by-step explanation:
The radius of the circle can be plugged into C=(pi)2r. So 5x2= 10 and 10x(pi)= 31.4
PLEASE HELP
If the absolute value represents the distance from zero, can we have a negative distance?
Answer:
No, you cannot have a negative distance.
Step-by-step explanation:
No, you cannot have a negative distance.
Let's say you were asked for the absolute value of -4. How many units is -4 away from 0? The answer would be 4. There is no negative distance from 0.
Hope this helps, please mark brainliest! :)
find the value of tan 45° + sin 30°
Answer:
I think it's approximately 44°
How do you work out the total surface area of a cuboid (equation)
Answer:
A cuboid has a total of 6 rectangular sides. If you calculate the area of each of the 6 rectangular sides and add them up, you will get the surface area of the cuboid.
Surface Area of a Rectangle = Width x Height
Can someone please please please help me? I need this to be correct or else I’m gonna be grounded for the rest of the summer…
The difference between two numbers is 28. The first number is three times the other number. What are the numbers?
A. 14 and 42
B. 26 and 42
C. 14 and 14
D. 15 and 43
No links or fake answers please
Answer:
A
Step-by-step explanation:
42-14=28
Answer:
A. 42 and 14
Step-by-step explanation:
first number = x
second number = y
x - y = 28
3x - x = 28
(y is now x because it says the second number is whatever x was, but three times less)
x = 14
3(14) - (14) = the original number, 28
Calculate the unit price. Round to the nearest cent, if necessary.
0.75 lb of salami for $2.65
$4.64 per lb of salami
$2.65 per lb of salami
$3.53 per lb of salami
$1.99 lb of salami
per
Answer:
$3.53 per lb of salami
Step-by-step explanation:
0.75 lb of salami for $2.65
The price per of salami will be :
0.75 lb = $2.65
1 lb = x
Using cross multiplication :
0.75 * x = $2.65 * 1
0.75x = $2.65
Divide both sides by 0.75
0.75x / 0.75 = $2.65 / 0.75
x = $3.533
This means that :
The price per unit of salami is $3.53
Answer:
0.75 lb of salami for $2.65 is $3.53 per lb of salami.
Which system of equations is represented by the matrix below?
54 5-167
7 -4 23
O A. x+ 5y = -16
x - 4y = 23
OB. 4x + 5y = -16
7x - 4y = 23
C. 4x + 5y = -16
7x + 4y = 23
9514 1404 393
Answer:
B
Step-by-step explanation:
In order for the matrix to represent the equations, the coefficients in the equations need to match the terms in the matrix. That is only the case for choice B.
__
Details are important in math.
9. Use the Distributive Property to simplify (-5 - c)(-1).
a 5 - C
b C
c-5 + c
d 5 + C
Answer:
D. 5 + c
Step-by-step explanation:
( - 5 - c ) ( - 1 )
use distributive property ; to multiply -5 and - c by -1.
= -1 × - 5 - ( +1 ) × - c= 5 + cPlease help
A. B.C. D
A company makes plastic baseballs. They put 6 baseballs nackage. Which teple shows the values for Op, the number of baseballs in p packages? Number of packages. P 7 Tamber of baseballs. 5p42 47 52 number of cackages out of basebis 50
Answer:
Table C
Step-by-step explanation:
Given
[tex]1\ package = 6\ balls[/tex]
Required
Which table is correct
We have:
[tex]1\ package = 6\ balls[/tex]
For 7 packages, it will be:
[tex]7\ packages = 42\ balls[/tex] --- i.e. 6 * 7
For 8:
[tex]8\ packages = 48\ balls[/tex] --- i.e. 8 * 7
For p packages
[tex]f(p) = 6p[/tex]
Using the above formula, we can conclude that table (C) is correct
Somebody help me with this
Answer:
3x4 +x3+ 15x2+30x-14
Step-by-step explanation:
mary is 1 m 15 cm tall. her friend larry is 1 m 30 cm tall. who is taller and by how much?
Answer:
Mary's friend Larry is taller by 15cm.
Step-by-step explanation:
First look for the bigger number.
Then subtract the smaller number from the bigger number.
Which expression is equivalent to -6(-⅔+2x)?
O-4-12x
O-4+ 2x
O 4-12x
O 4+ 12x
Answer:
4-12x
Step-by-step explanation:
opening the brackets;
(-6×-2/3)- 12x
-2×-2 -12x
4-12x
Answer:
4 - 12x
Step-by-step explanation:
We can find an equivalent expression by distributing
-6(-⅔+2x)
Distribute by multiplying -6 times what's inside of the parenthesis ( -2/3 and 2x )
-6 * -⅔ = 4
-6 * 2x = -12x
We would be left with 4 - 12x
Which of the following phrases are expressions?
Answer:
C ,D , E just follow it . thank me later if its right
Answer:
E
Step-by-step explanation:
(10+7)(50+1)
=17×51
=867
If x = 82°, find the measures of angles 1, 2, and 3
Answer:
98
Step-by-step explanation:
x(o) + 1(o) = 180(o)
∠2° = ∠x°
∠1° = ∠3°
Answer:
angle 2 is 82 also and angle 3 and 4 is 180 - 82 = 98
9x5
pls help meeeeeeeeee
Answer:
45
hope this helps
Answer:
45
Step-by-step explanation:
9x5=45
Will mark Brainlest hellpppp
[tex]h(-3) - h( - 2) = - \frac{5}{ 8} \\ \\ [/tex]
Step-by-step explanation:
[tex]\boxed{h(x) = \frac{2 {x}^{2} - x + 1}{3x - 2}}[/tex]
[tex]h(2) = \frac{2 {(2)}^{2} - (2) + 1}{3(2) - 2} [/tex]
[tex]h(2) = \frac{2 {(4)} - 2 + 1}{6 - 2} [/tex]
[tex]h(2) = \frac{ 8 - 1}{4} [/tex]
[tex]h(2) = \frac{7}{4}[/tex]
[tex]h( - 3) = \frac{2 {( - 3)}^{2} - ( - 3) + 1}{3( - 3) - 2} \\ h( - 3) = \frac{2 (9) + 3 + 1}{ - 9- 2} \\ h( - 3) = \frac{18 + 4}{ - 11} \\ h( - 3) = \frac{22}{ - 11} \\ h(-3) = -2[/tex]
[tex]h( - 2) = \frac{2 {( - 2)}^{2} - ( - 2) + 1}{3( - 2) - 2} \\ h( - 2) = \frac{2 (4) + 2+ 1}{- 6 - 2} \\ h( - 2) = \frac{8 + 3}{- 8} \\ h( - 2) = \frac{11}{- 8} [/tex]
[tex]h(3) - h( - 2) = -2 - \frac{11}{- 8} \\ h(3) - h( - 2) =-2 + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-2}{1}+ \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16}{8} + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16+11}{8} \\ h(3) - h( - 2) = \frac{-5}{8} \\ - \frac{5}{ 8} [/tex]
25. Approximate the sample variance and standard deviation given the following frequency distribution: Class Frequency 0–9 13 10–19 7 20–29 10 30–39 9 40–49 11
Sample variance = 228.408
Standard deviation = 15.113
Step-by-step explanation:The well formatted frequency table has been attached to this response.
To calculate the sample variance and standard deviation of the given grouped data, follow these steps:
i. Find the midpoint (m) of the class interval.
This is done by adding the lower bounds and upper bounds of the class intervals and dividing the result by 2. i.e
For class 0 - 9, we have
m = (0 + 9) / 2 = 4.5
For class 10 - 19, we have
m = (10 + 19) / 2 = 14.5
For class 20 - 29, we have
m = (20 + 29) / 2 = 24.5
For class 30 - 39, we have
m = (30 + 39) / 2 = 34.5
For class 40 - 49, we have
m = (40 + 49) / 2 = 44.5
This is shown in the third column of the attached table.
ii. Find the product of each of the frequencies of the class intervals and their corresponding midpoints. i.e
For class 0 - 9, we have
frequency (f) = 13
midpoint (m) = 4.5
=> f x m = 13 x 4.5 = 58.5
For class 10 - 19, we have
frequency (f) = 7
midpoint (m) = 14.5
=> f x m = 7 x 14.5 = 101.5
For class 20 - 29, we have
frequency (f) = 10
midpoint (m) = 24.5
=> f x m = 10 x 24.5 = 245
For class 30 - 39, we have
frequency (f) = 9
midpoint (m) = 34.5
=> f x m = 9 x 34.5 = 310.5
For class 40 - 49, we have
frequency (f) = 11
midpoint (m) = 44.5
=> f x m = 11 x 44.5 = 489.5
This is shown in the fourth column of the attached table.
iii. Calculate the mean (x) of the distribution i.e
This is done by finding the sum of all the results in (ii) above and dividing the outcome by the sum of the frequencies. i.e
x = ∑(f x m) ÷ ∑f
Where;
∑(f x m) = 58.5 + 101.5 + 245 + 310.5 + 489.5 = 1205
∑f = 13 + 7 + 10 + 9 + 11 = 50
=> x = 1205 ÷ 50
=> x = 24.1
Therefore, the mean is 24.1
This is shown on the fifth column of the attached table.
iv. Calculate the deviation of the midpoints from the mean.
This is done by finding the difference between the midpoints and the mean. i.e m - x where x = mean = 24.1 and m = midpoint
For class 0 - 9, we have
midpoint (m) = 4.5
=> m - x = 4.5 - 24.1 = -19.6
For class 10 - 19, we have
midpoint (m) = 14.5
=> m - x = 14.5 - 24.1 = -9.6
For class 20 - 29, we have
midpoint (m) = 24.5
=> m - x = 24.5 - 24.1 = 0.4
For class 30 - 39, we have
midpoint (m) = 34.5
=> m - x = 34.5 - 24.1 = 10.4
For class 40 - 49, we have
midpoint (m) = 44.5
=> m - x = 44.5 - 24.1 = 20.4
This is shown on the sixth column of the attached table.
v. Find the square of each of the results in (iv) above.
This is done by finding (m-x)²
For class 0 - 9, we have
=> (m - x)² = (-19.6)² = 384.16
For class 10 - 19, we have
=> (m - x)² = (-9.6)² = 92.16
For class 20 - 29, we have
=> (m - x)² = (0.4)² = 0.16
For class 30 - 39, we have
=> (m - x)² = (10.4)² = 108.16
For class 40 - 49, we have
=> (m - x)² = (20.4)² = 416.16
This is shown on the seventh column of the attached table.
vi. Multiply each of the results in (v) above by their corresponding frequencies.
This is done by finding f(m-x)²
For class 0 - 9, we have
=> f(m - x)² = 13 x 384.16 = 4994.08
For class 10 - 19, we have
=> f(m - x)² = 7 x 92.16 = 645.12
For class 20 - 29, we have
=> f(m - x)² = 10 x 0.16 = 1.6
For class 30 - 39, we have
=> f(m - x)² = 9 x 108.16 = 973.44
For class 40 - 49, we have
=> f(m - x)² = 11 x 416.16 = 4577.76
This is shown on the eighth column of the attached table.
vi. Calculate the sample variance.
Variance σ², is calculated by using the following relation;
σ² = ∑f(m-x)² ÷ (∑f - 1)
This means the variance is found by finding the sum of the results in (vi) above and then dividing the result by one less than the sum of all the frequencies.
∑f(m-x)² = sum of the results in (vi)
∑f(m-x)² = 4994.08 + 645.12 + 1.6 + 973.44 + 4577.76 = 11192
∑f - 1 = 50 - 1 = 49 {Remember that ∑f was calculated in (iii) above}
∴ σ² = 11192 ÷ 49 = 228.408
Therefore, the variance is 228.408
vii. Calculate the standard deviation
Standard deviation σ, is calculated by using the following relation;
σ =√ [ ∑f(m-x)² ÷ (∑f - 1) ]
This is done by taking the square root of the variance calculated above.
σ = [tex]\sqrt{228.408}[/tex]
σ = 15.113
Therefore, the standard deviation is 15.113
Differentiate the function. y = (2x - 5)^2 (5 - x)?
Answer:
[tex]\displaystyle y' = -(2x - 5)(6x - 25)[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightDistributive Property
Algebra I
Terms/CoefficientsFactoringCalculus
Derivatives
Derivative Notation
Derivative of a constant is 0
Basic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹Derivative Rule [Product Rule]: [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]
Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Step-by-step explanation:
Step 1: Define
Identify
y = (2x - 5)²(5 - x)
Step 2: Differentiate
Derivative Rule [Product Rule]: [tex]\displaystyle y' = \frac{d}{dx}[(2x - 5)^2](5 - x) + (2x - 5)^2\frac{d}{dx}[(5 - x)][/tex]Chain Rule [Basic Power Rule]: [tex]\displaystyle y' = [2(2x - 5)^{2 - 1} \cdot \frac{d}{dx}[2x]](5 - x) + (2x - 5)^2\frac{d}{dx}[(5 - x)][/tex]Simplify: [tex]\displaystyle y' = [2(2x - 5) \cdot \frac{d}{dx}[2x]](5 - x) + (2x - 5)^2\frac{d}{dx}[(5 - x)][/tex]Basic Power Rule: [tex]\displaystyle y' = [2(2x - 5) \cdot 1 \cdot 2x^{1 - 1}](5 - x) + (2x - 5)^2(1 \cdot -x^{1 - 1})][/tex]Simplify: [tex]\displaystyle y' = [2(2x - 5) \cdot 2](5 - x) + (2x - 5)^2(-1)[/tex]Multiply: [tex]\displaystyle y' = 4(2x - 5)(5 - x) - (2x - 5)^2[/tex]Factor: [tex]\displaystyle y' = (2x - 5)[4(5 - x) - (2x - 5)][/tex][Distributive Property] Distribute 4: [tex]\displaystyle y' = (2x - 5)[20 - 4x - (2x - 5)][/tex][Distributive Property] Distribute negative: [tex]\displaystyle y' = (2x - 5)[20 - 4x - 2x + 5][/tex][Subtraction] Combine like terms (x): [tex]\displaystyle y' = (2x - 5)[20 - 6x + 5][/tex][Addition] Combine like terms: [tex]\displaystyle y' = (2x - 5)(25 - 6x)[/tex]Factor: [tex]\displaystyle y' = -(2x - 5)(6x - 25)[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Derivatives
Book: College Calculus 10e
Nine subtracted from four times a number is -21 what is the number?
Answer:
-3
Step-by-step explanation:
My knowledge ;D
Un recipiente cilíndrico tiene un diámetro de 160cm. y la misma altura. ¿Cuánto litros de agua puede caber?
Respuesta:
3215360 cm³
Explicación paso a paso:
Dado que :
Radio = 160/2 = 80 cm
Altura, h = 160 cm
Volumen de un cilindro = πr²h
Volumen del cilindro = π * 80² * 160
Volumen = 3215360 cm³
Helpppppppp thank u so much
Answer:
acute triangle
Step-by-step explanation:
First find the other angle
The sum of the angles is 180
x+65+60 = 180
x + 125 = 180
x = 180-125
x = 55
All three angles are different so all three side lengths are different
All the angles are less than 90 so all the angles are acute
This is an acute scalene triangle
Answer:
im is 55 so the only correct option is c
Step-by-step explanation:
hope this helps! have a great day!!
how do I solve this equation?
[tex]x + 8y = 20 \\ 2x + 4y = 4[/tex]
Answer:
Subtract x x from both sides of the equation. 8y=20−x 8 y = 20 - x. Divide each term by 8 8 and simplify.
Solve for x 2x-4y=4. 2x−4y=4 2 x - 4 y = 4. Add 4y 4 y to both sides of the equation. 2x=4+4y 2 x = 4 + 4 y. Divide each term by 2 2 and simplify.
The slope of a line is -, and the y-intercept is 10/3. What is the equation of the line written in general form?
What is the HFC of the following: 4 (x2-x+1) and 28 (x3+1)?
Your Answer is in the above image.
PLEASE HELP ME
WITH STEPS
Answer:
,(i) answer is 203,918
(ii)answer is227,306.36
HELP ME CANT FAIL!! Which parent function is represented by the graph?
A) An exponential parent function
B) Liner parent function
C)Absolute value parent function
D)Quadratic parent function
A gardener wants to plant 875 roses in the garden. Can he plant them in rows having 7 plants each without any plants left? Justify your answer. *
Answer:
Yes
Step-by-step explanation:
875 roses / 7 plants per row
875 / 7 = 125 rows, which is a whole number, meaning nothing is left over
22 hours. A
Silas ran 100 m race at a speed of 8 m/s. How long did it take him to com-
plete the race?
Answer:
100/8 = 12.5 (s)
Step-by-step explanation:
hmm bro
Answer:
[tex]{ \boxed{ \tt{formular : { \bf{ \green{time = \frac{distance}{speed} }}}}}} \\ time = \frac{100}{8} \\ { \boxed{time = 12.5 \: seconds}} \\ \\ { \underline{ \blue{ \tt{becker \: jnr}}}}[/tex]