2. A carpenter wants to cut a wood board that is feet long
d on
5
into pieces that are feet long. How many whole pieces
can be cut from the board? How much wood is left over
16

2. A Carpenter Wants To Cut A Wood Board That Is Feet Longd On5into Pieces That Are Feet Long. How Many

Answers

Answer 1

Answer:

2 whole pieces

5/24 feet left

Step-by-step explanation:

divide 5/6 by 5/16 = 2 2/3 pieces

so there are 2 whole pieces and 2/3 small piece.

The 2/3 small short equals to 5/16 x 2/3 = 5/24 ft


Related Questions

If triangle LMN ~ triangle PON, what is MN?


Answers

Answer:

pretty sure its 40cm

Step-by-step explanation:

hope this helps :)

Answer:

36cm

Step-by-step explanation:

Tan(14/12)=angle of ONP

Tan(42/X)=angle of LNM

singe those angels are the same;

Tan(14/12)=Tan(42/X)

14/12=42/X

14*X=42*12

X=(42*12)/14

X=36

If 1=3

2=3

3=5

4=4

5=4

Then, 6=?

Answers

9514 1404 393

Answer:

  3

Step-by-step explanation:

For "a = b" it appears that the intention is b = f(a). It appears that f(a) is the number of letters in the spelling of 'a'.

  "One" has 3 letters

  "Two" has 3 letters

  "Three" has 5 letters

  "Four" has 4 letters

  "Five" has 4 letters

  "Six" has 3 letters

so, 6 = 3.

_____

Additional comment

This appears to be a non-standard use of the equal sign, in which it has no relation to the usual meaning of "equals." Using standard symbols with non-standard meanings should generally be avoided, unless the intended meaning is explained.

Write and solve a real-world problem that involves finding the volume of a rectangular or triangular prism

Answers

Answer:

l

Step-by-step explanation:

Leona has a large bag of apples. There are 180 apples in the bag. She uses 14of the apples to make some juice. She uses 20% of the apples to make some pies. How many apples are left?

Answers

Answer:

132.8 are left enjoy

a trader sold an article at 10% profit if he had sold it at 10% loss,it would yield RS 140 less than the previous selling price.find the cost price of the article.​

Answers

Answer:

CP = ₹ 700

Step-by-step explanation:

Let the cost price be 'x'

SP = [tex](\frac{100+Profit}{100})*CP[/tex]

   [tex]= \frac{100+10}{100}*x\\\\=\frac{110}{100}*x\\\\= \frac{11}{10}x[/tex]

If it had been sold are 10% loss, then

SP = [tex](\frac{100-loss}{100})*CP[/tex]

     [tex]=\frac{100-10}{100}*x\\\\=\frac{90}{100}*x\\\\=\frac{9}{10}x[/tex]

Difference in both the selling price =  140

[tex]\frac{11}{10}x-\frac{9}{10}x=140\\\\\\\frac{2}{10}x=140\\\\\frac{1}{5}x=140\\\\ x = 140*5\\x = 700[/tex]

Please help me out this is hard .

Answers

Answer:

24.6

Step-by-step explanation:

take 72 degree as reference angle

using tan rule

tan 72 = opposite / adjacent

3.07 = x/8

3.07 * 8 = x

24.56 = x

24.6 = x

Write the equation of the line that passes through points A(6,1) and B(9,4)? simple answers

Answers

Given:

Two points are A(6,1) and B(9,4).

To find:

The equation of the line that passes through the given points.

Solution:

If a line passes through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], then the equation of the line is:

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

It is given that the line passes through the two points A(6,1) and B(9,4). So, the equation of the line is:

[tex]y-1=\dfrac{4-1}{9-6}(x-6)[/tex]

[tex]y-1=\dfrac{3}{3}(x-6)[/tex]

[tex]y-1=1(x-6)[/tex]

[tex]y-1=x-6[/tex]

Adding 1 on both sides, we get

[tex]y-1+1=x-6+1[/tex]

[tex]y=x-5[/tex]

Therefore, the equation of the line is [tex]y=x-5[/tex].

the girls heights in inches are as follows:62,70,60,63,66,what is their average height?​

Answers

Answer:

Average height = 64.2 inches

Step-by-step explanation:

[tex]Average = \frac{sum \ of \ the \ values }{number \ of\ value}[/tex]

            [tex]=\frac{62 + 70 + 60 + 63 + 66}{5}\\\\=\frac{321}{5}\\\\=64.2 \ inches[/tex]

The average of the given heights is 64.2 inches

What is an average?

An average of a list of data is the expression of the central value of a set of data. It is defined as the ratio of summation of all the data to the number of units present in the list.

According to the given problem,

Given data = { 62, 70, 60, 63, 66 }

Sum of the given heights = ( 62 + 70 + 60 + 63 + 66 )

                                          = 321

Average = [tex]\frac{321}{5}[/tex]

              = 64.2 inches

Hence, we can conclude, the average of the given data is 64.2 inches.

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Pls I beg someone to finish ALL of this :(. I’ve stayed up all night to do this but I couldn’t figure all of them out. Pls pls pls!!! ill mark you brainliest n I can give you a thank you such as 5 Stars in return. Please take your time and I hope you all have a amazing day!

Answers

Answer:

Question 1: 75 minutes

Question 2: 4:07

Question 3: 30 minutes

Question 4: 8:35

Step-by-step explanation:

An hour is sixty minutes; that's the key to solving these questions.

The time basketball was played is 75 minutes or 1 hour 15 minutes

The time I get home is at 4:07

The cook was cooked for 30 minutes.

The cheerleading was over at 8:35.

What is unit conversion?

It is the conversion of one unit to another unit with its standard conversion.

We have,

Trey and Na Asia played basketball from 10:30 - 11:45.

From 10 to 11 we have 60 minutes.

= 60 minutes - 30 minutes [10:30] + 45 minutes [ 11:45]

= 105 minutes - 30 minutes

= 75 minutes

The time basketball was played.

= 75 minutes

= 1 hour 15 minutes

I left school at 3:15 on the bus. I got home 52 minutes later.

1 hour = 52 minutes

= 3:15 + 52 minutes

= 3  + 15 minutes + 52 minutes

= 3 + 67 minutes

= 3 + 1 hour +  7 minutes

= 4:07

The time I get home is at 4:07

Antavious makes Macaroni and cheese. He begins making it at 6:35 and finished at 7:05.

= 6:35 to 7:05

From 6 to 7 we have 60 minutes.

So,

= 60 minutes - 35 minutes [6:35] + 5 minutes [7:05]

=  65 minutes - 35 minutes

= 30 minutes

The cook was cooked for 30 minutes.

Makhiya and Madison went to cheerleading at 7:15. It was over 1 hour and 20 minutes later.

= 7:15 + 1 hour + 20 minutes

= 7 + 15 minutes + 1 hour + 20 minutes

= 8 + 35 minutes

= 8:35

The cheerleading was over at 8:35.

Thus,

The time basketball was played is 75 minutes or 1 hour 15 minutes

The time I get home is at 4:07

The cook was cooked for 30 minutes.

The cheerleading was over at 8:35.

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Question 2 Multiple Choice Worth 5 points)
(02.04 LC)
Determine the equation of the line shown in the graph

Answer choices
X= 5
y = 0
x = 0
y = 5

Answers

Answer:

A

Step-by-step explanation:

The line is parallel to y axis, so the equation is x = 5

Davis's Snacks will make 8,412 ounces of corn chips next year. The company plans to put the chips into 4-ounce bags. How many bags will the company be able to fill next year?

Answers

Answer:

2103 bags

Step-by-step explanation:

8412/4=2103

Help I’m stuck!!!! Solve the equation below for x. Enter your answer as a fraction in lowes
terms, using the slash mark (/) as the fraction bar. 4/21 + 2/9
X=

Answers

Answer:

26/63

Step-by-step explanation:

Try to make the denominators equal so that you can add them:

4(3)/21(3)= 12/63

2(7)/9(7)= 14/63

And now you add, which will give you:

12/63 + 14/63= 26/63

The variable 100 POINTS!!!!

What is the value of 2 + (-2/3) ^2 ÷1/3 ?

16

3 1/3

-2

0

Answers

Answer:

second option is correct

3 1/3 is the right answer ( thats what i used for mine)

The length of the rectangle, in feet, is represented by (5x + 4). Find the perimeter of the rectangle.

Answers

2(5x+4)= 10x+8 ,

I might be wrong but tried my best so best of wishes!

Please solve with explanation.

Answers

Answer:

Area = 160 cm²

Perimeter = 55.31 cm

Step-by-step explanation:

Applying,

Area of the figure = area of the rectangle- area of the triangle

A = lw+bh/2............... Equation 1

From the question,

Given: l = 16 cm, w = 12 cm, h = 8cm, b = 8 cm

Substitute these values into equation 1

A = (16×12)-(8×8/2)

A = 192-32

A = 160 cm²

Perimeter P = /BC/+/CD/+/DE/+/EF/+/FG/+/GA/

Applying pythagoras theorem to get /FG/

FG² = GE²+EF²

FG² = 8²+8²

FG² = 64+64

FG² = 128

FG = √128

FG = 11.31 cm

Therefore,

P = 16+12+4+8+11.31+4

P = 55.31 cm

Question 24 of 25 The graph of F(x) shown below resembles the graph of G(X) = x2, but it has been changed somewhat. Which of the following could be the equation of F(x)? G(X) = x2 Fx) = ?​

Answers

Answer:

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!;;;;!!!!!!!!!!!

The required equation of graph f(x) is y = -x²-3.

What is parabola?

A parabola is a U-shaped plane curve where any point is at an equal distance from a fixed point (known as the focus) and from a fixed straight line which is known as the directrix.

here, we have,

Given that,

The graph of f(x), resembles the graph of G(x) =x^2 .

We have to find,

Which of the following could be the equation of  f(x).

According to the question,

Function, G(X) = x^2 ,

The graph in the given question figure. It is a parabola with vertex at (0,0).

By the graph predict that Sign of  x^2 is positive, that is why the parabola opens up.

General equation of parabola is given by,

y = a(x-h)^2 + k

Where, a = 1, and vertex (h, k) is (0,0).

The graph of F(x) unknown function opens down ,

Sign of x^2 as negative. and the vertex is at (0,-3)

To find the equation of function f(x),

Putting the values of a and vertex coordinates,

y = a(x-h)^2 + k

The equation of parabola become:

y = -x²-3.

(solving we get)

Hence, The required equation of f(x) is y = -x²-3.

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Someone started fishing at 15.30 am after fishing for 2hours 15 min he rested for half an hour he then continued until 11am how long did he fish?

Answers

Answer:

7 Hours

Step-by-step explanation:

According to the Question,

Given, Someone started fishing at 3:30 am after fishing for 2hours 15min. he rested for half an hour(30min). Thus,  Now The Clock is Rotating to 3:30 am + 2hour 15 min. + 30 min. = 6:15 am .

He then continued doing Fishing until 11 am. As a result, he fished for 4 h 45 min. more after resting.

So the Total Time he Spends Fishing is 4 hour 45 min. + 2 hours 15 min.

7 hours  

3n^5 ÷ 6n^3, using properties of exponents

Answers

Answer:

Step-by-step explanation:

[tex]\frac{a^{m}}{a^{n}}=a^{m-n}\\\\\frac{3n^{5}}{6n^{3}}=\frac{3}{6}*n^{5-3}\\\\=\frac{1}{2}n^{2}[/tex]

Answer:

[tex]\frac{n^{2} }{2}[/tex]

Step-by-step explanation:

Rewrite the division as a fraction.

[tex]\frac{3n^{5} }{6n^{3} }[/tex]

Cancel the common factor of 3 and 6.

[tex]\frac{3(n^{5}) }{6n^{3} }[/tex]

[tex]\frac{n^{5} }{2n^{3} }[/tex]

Cancel the common factor

[tex]\frac{n^{2} }{2}[/tex]

Hope this helps!

If you need more help with questions like these please reach out to me!

In the diagram below, ΔABC≅ΔSTR. Complete the statement ∠A≅

A. ∠C
B. ∠S
C. ∠T
D. ∠R

Answers

Answer:

b

Step-by-step explanation:

Answer: B <S

Step-by-step explanation:

what is the domain of the function represented by the graph

Answers

Answer:

Domain:  all real numbers

Step-by-step explanation:

The domain is the values that x can take

X can be any real number

Domain:  all real numbers

Complete the proof that

Answers

Answer:

The two column proof is presented as follows;

Statement  [tex]{}[/tex]                            Reason

ΔSCW ≅ ΔTUW [tex]{}[/tex]                    Given

[tex]\overline {SV}[/tex] ≅ [tex]\overline {TU}[/tex] [tex]{}[/tex]                               CPCTC

[tex]\overline {SW}[/tex] ≅ [tex]\overline {TW}[/tex]  [tex]{}[/tex]                            CPCTC

[tex]\overline {WV}[/tex] ≅ [tex]\overline {UW}[/tex] [tex]{}[/tex]                            CPCTC

∠SVW ≅ ∠TUW  [tex]{}[/tex]                   CPCTC

SU = SW + UV [tex]{}[/tex]                       Additive property of Length

TU = TW + VW [tex]{}[/tex]                       Additive property of Length

SU = TW + VW [tex]{}[/tex]                       Substitution

SU = TV [tex]{}[/tex]                        [tex]{}[/tex]          Transitive property

ΔSTV ≅ ΔTSU  [tex]{}[/tex]                       SAS

∠TSV ≅ ∠STU [tex]{}[/tex]                        CPCTC

Step-by-step explanation:

The two column proof is presented as follows;

Statement  [tex]{}[/tex]                            Reason

ΔSCW ≅ ΔTUW [tex]{}[/tex]  Given

[tex]\overline {SV}[/tex] ≅ [tex]\overline {TU}[/tex] [tex]{}[/tex]            Congruent Parts of Congruent Triangles are Congruent

[tex]\overline {SW}[/tex] ≅ [tex]\overline {TW}[/tex]  [tex]{}[/tex]         Congruent Parts of Congruent Triangles are Congruent                  

[tex]\overline {UV}[/tex] ≅ [tex]\overline {VW}[/tex] [tex]{}[/tex]         Congruent Parts of Congruent Triangles are Congruent                  

∠SVW ≅ ∠TUW  [tex]{}[/tex]Congruent Parts of Congruent Triangles are Congruent                  

SU = SW + UV [tex]{}[/tex]    Additive property of Length

TU = TW + VW [tex]{}[/tex]   Additive property of Length

SU = TW + VW [tex]{}[/tex]    Substitution

SU = TV [tex]{}[/tex]              Transitive property

ΔSTV ≅ ΔTSU  [tex]{}[/tex]   Side-Angle-Side rule of congruency

∠TSV ≅ ∠STU [tex]{}[/tex]     Congruent Parts of Congruent Triangles are Congruent                  

Solve the following inequality for qq. Write your answer in simplest form. -6q+7≤8q-3

Answers

Answer:

q ≥ 5/7

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right  

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

-6q + 7 ≤ 8q - 3

Step 2: Solve for q

[Subtraction Property of Equality] Subtract 8q on both sides:                      -14q + 7 ≤ -3[Subtraction Property of Equality] Subtract 7 on both sides:                        -14q ≤ -10[Division Property of Equality] Divide -14 on both sides:                               q ≥ 5/7

Here we see that any number q greater than or equal to 5/7 would work as a solution to the inequality.

Answer:

q ≥ [tex]\frac{5}{7}[/tex]

Step-by-step explanation:

Given

- 6q + 7 ≤ 8q - 3 ( add 6q to both sides )

7 ≤ 14q - 3 ( add 3 to both sides )

10 ≤ 14q ( divide both sides by 2 )

5 ≤ 7q ( divide both sides by 7 )

[tex]\frac{5}{7}[/tex] ≤ q , then

q ≥ [tex]\frac{5}{7}[/tex]

Can someone answer this plz

Answers

Answer:

[tex]A^{I}[/tex]= (7, -1)

Step-by-step explanation:

Rotation is a method of rigid transformation in which a point is moved about a reference point through a stated angle. The rotation could be clockwise or counterclockwise so as to produce the image of the initial object.

In the polar coordinate given, the coordinate of A is given as;

A = (3, 3)

On rotating point A about point C counterclockwise for [tex]270^{o}[/tex], an image [tex]A^{I}[/tex] would be produced.  

But [tex]A^{I}[/tex] would have a coordinate;

[tex]A^{I}[/tex]= (7, -1)

The image of A produced is [tex]A^{I}[/tex] (7, -1).

Can someone please answer these 2 questions​

Answers

Answer:

part 1: $532.95. Part 2: 16

Step-by-step explanation:

Part 1: 15 * 15.35 = 230.25

30 * 10.09 = 302.70

230.25 + 302.70 = $532.95

Part 2: R = letters in the word desk

there are 4 letters in the word Desk

[tex]2^{R}[/tex] = [tex]2^{4}[/tex] = 2 * 2 * 2 * 2 = 4 * 4 = 16 subsets

How many miles did it cruise?

Answers

The 120 is the correct one A

Answer:

A. 120

Step-by-step explanation:

600÷60=10

10×12=120

Hope this helps! :)

solve for the missing sidebof the triangle shown in the figure​

Answers

Answer:

∠B = 74°

a ≈ 14.5 inches

c ≈ 11.4 inches

Step-by-step explanation:

The given parameters of triangle ΔABC are;

∠A = 62.2°, ∠C = 43.8° and side [tex]\overline{AB}[/tex] = b = 15.8 in

By sine rule, we have;

[tex]\dfrac{a}{sin(\angle A)} = \dfrac{b}{sin(\angle B)} = \dfrac{c}{sin(\angle C)}[/tex]

[tex]a = {sin(\angle A)} \times \dfrac{b}{sin(\angle B)}[/tex]

By angle sum property, we have;

∠B = 180° - (∠A + ∠C)

∴ ∠B = 180° - (62.2° + 43.8°) = 74°

∠B = 74°

[tex]\therefore {a} = {sin(62.2^{\circ})} \times \dfrac{15.8}{sin(74^{\circ})} \approx 14.5[/tex]

a ≈ 14.5 in.

[tex]c = {sin(\angle C)} \times \dfrac{b}{sin(\angle B)}[/tex]

[tex]\therefore {c} = {sin(43.8^{\circ})} \times \dfrac{15.8}{sin(74^{\circ})} \approx 11.4[/tex]

c ≈ 11.4 in.

What is the mode
of 2, 8, 16, 4,
12, 9, 2?

Answers

the mode is 2
this is because 2 appears twice while the rest of the numbers only appear once.

The mode is the highest frequency data among the given data set is 2.

What is the mode?

The value that appears most frequently in a data set is called the mode. One mode, several modes, or none at all may be present in a set of data.

Mode is the highest frequency of any number among data

For example 2,3,5,5,6,5,9,8,5,1

Here mode will be 5 because it has a frequency of 4 remaining all have a lower frequency than 5.

Given the data set is

2, 8, 16, 4, 12, 9, 2

2 has frequency = 2

And remaining all have a frequency as 1

Since 2 has the highest frequency so it will be mode.

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Please help i dont remember how to do this

Answers

just add 5 5 and 10 10 to get yo answers
i will work

if 6.2a=0.0143 then what is a?​

Answers

6.2a = 0.0143

=> a = 0.0143/6.2

=> a = 0.0023......

The perpendicular room is 4m long, 3m wide and 2.5m high. They tiled and painted the interior walls of the room. How many square meters of tiles should be used? Answer only

Answers

Answer:

12m²

Step-by-step explanation:

are the files to be used only for the floor, or also for the walls ? ceiling ?

if it is only for the floor, then the height of the room is irrelevant.

perpendicular clearly stands here for rectangular.

so, the good of the room is a rectangle of 4m length and 3m width.

the area of a rectangle is length×width.

area = 4×3 = 12m²

so, 12m² of tiles will be needed (in reality there would be at least 10% to 20% added for bad tiles, wrong cuts, ...).

if walls need to be included, then you will have to add the areas of 4 more rectangles of length×height.

which would be 2 times 3×2.5 = 7.5m² and 2 times 4×2.5 = 10m².

so, the total area incl. walls would be

12 + 7.5 + 7.5 + 10 + 10 = 47m²

if the ceiling has to be included too, then you need to add the area of another rectangle of the same size as the floor.

so, that total would then be

47 + 12 = 59m².

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