At which point on the image to the right would the ball have the greatest velocity if it moved from A to G.

please help me out.

A


B


C


D


E


F


G

Answer:

 Em₀ = U = m g h ,  Em_{f} = K = ½ m v²

Explanation:

When a car is on a ramp it has a certain amount of mechanical energy. At the highest point of the ramp the mechanical energy is fully potential given by

          Em₀ = U = m g h

As part of this energy descends down the ramp, part of this energy is transformed into kinetic energy and has one part of each, even though the sum remains the initial energy

            Em = K + U = ½ m v² + mg y

        y <h

when it reaches the bottom of the ramp it has no height therefore there is no potential energy, all of it has been transformed into kinetic energy

          Em_{f} = K = ½ m v²

This energy transformation is in the case that the friction force is zero.

If there is a friction force, it performs work against the low car, it is reflected in an increase in the internal energy (temperature) of the car. In this case the energy in the lower part is less than the initial one by a factor

         [tex]W_{nc}[/tex] = - fr L

therefore the numeraire values ​​of the velocity are lower, due to the energy lost by friction.

Answer:

1. p = 562.3 kg*m/s

2. F = 142.7 N

Explanation:

1. The linear impulse (p) is given by:

[tex] p = mv [/tex]

Where:

m: is the passenger's mass = 73.7 kg

v: is the speed = 7.63 m/s

[tex] p = mv = 73.7 kg*7.63 m/s = 562.3 kg*m/s [/tex]

Hence, the magnitude of the linear impulse experienced by a passenger is 562.3 kg*m/s.

2. The average force can be calculated using the following equation:

[tex] F = \frac{m(v_{f} - v_{0})}{t} = \frac{73.7 kg(7.63 m/s - 0)}{3.94 s} = 142.7 N [/tex]  

Therefore, the average force experienced by the passenger is 142.7 N.

I hope it helps you!

Answer:

I would guess its leaves

Answer:

Leaves

Explanation:

Answer:

A landfill is a carefully designed structure built into or on top of the ground, in which trash is separated from the area around it. Why are landfills important? Landfills contain garbage and serve to prevent contamination between the waste and the surrounding environment, especially groundwater.

Explanation:

Answer: A landfill is a carefully designed structure built into or on top of the ground, in which trash is separated from the area around it. Why are landfills important? Landfills contain garbage and serve to prevent contamination between the waste and the surrounding environment, especially groundwater.

Explanation: Google lol

Answer:

D: gas and plasma

Explanation:

1. Ohm's law shows the relationship between:

Formula: voltage = current x resistance

2. The negative charge on the hairbrush will induce a positive charge on your hair. As a result, your hair is going to be attracted to the hairbrush (and repelled by other strands of hair.)

3. V = IR, so if the resistance of the current increases, and the voltage of the current stays the same, there is as a result, going to be less current.

Best of Regards!

Answer:

Δt = 1.1 s

Explanation:

Given information:

H= 50.0 m

g= 9.8 m/s²

   [tex]H = \frac{1}{2} * g* t^{2}[/tex]

Solving for t, we get:

t₁= 3.2 s

We can find the final velocity for the object when it hits the ground, using the following expression:

[tex]v_{f}^{2} - v_{o}^{2} = 2*g*H[/tex]

Solving for vf, we get:

vf = 33.9 m/s

Applying the definition of acceleration, being this acceleration the one due to gravity (g), we can write the following equation:

[tex]v_{f} = v_{o} + g*t[/tex]

(Assuming the downward direction to be positive).

Solving for t, we get:

t₂ = 2.1 s

So the difference in time when both objects hit the ground, it's simply

Δt = t₂ - t₁ = 3.2 s - 2.1 s = 1.1 s

Answer: D

Experiment 1 has a confounding variable related to the mass of the rockets. Any variation in mass may cause a discrepancy in the distance traveled.

This is the answer to the question because:

The answer has to be the option D. Hope this helps you!

Answer:

We are given:

displacement (s) = 130 m

acceleration (a) = -5 m/s²

final velocity (v) = 0 m/s      [the cars 'stops' in 130 m]

initial velocity (u) = u m/s

Solving for initial velocity:

From the third equation of motion:

v² - u² = 2as

replacing the variables

(0)² - (u)² = 2(-5)(130)

-u² = -1300

u² = 1300

u = √1300

u = 36 m/s

Answer: a

Explanation:

The ocean near the equator gets the most sunlight throughout the year, therefore the correct option is A.

The Equator is an imaginary line passing through the middle of a globe. It is equidistant from the North Pole and the South Pole, Its is a horizontal line residing at 0 degrees latitude.

Because of the revolving position of the earth in the solar system, The ocean near the equator gets the most sunlight throughout the year, therefore the correct option is A.

Learn more about the equator from here

https://brainly.com/question/24203207

#SPJ5

Answer:

Situational Interview

Explanation:

A situational interview is about as close to the real job as it gets. During this type of interview, candidates may be presented with a visual or audio simulation of a scenario and asked to respond to it. They are asked to analyze a problem and profer suggestions on how they would handle it.

If the candidate has solved similar problems in the past, it will come to the fore.

If they haven't then the best outcome is that it will tell the interviewers how well the candidate is able to solve similar problems.

An example of a Situational Interview question is this:

How would you handle an angry customer who for no justifiable reason has decided to create a problematic scene to disrupt the business?

Because Situational Interviews are about behavioral responses (present, past, and future), they are powerful tools in determining or predicting future job performance. An interviewing technique that is developed using this methodology is called the S.T.A.R.

This is an acronym for Situation, Task, Action, Result.

Situation: the candidate is asked to present a challenging situation that occurred recently. This tests what the candidate sees as a challenging situation.

Task: The candidate based on the situation is asked to identify what they need to do to remedy the problem. This tells the interviewer(s) whether or not the candidate can think up a solution for the problem.

Action: Here they define the actual steps taken to resolve the problem

Result: The candidate against the above is required to give the result gotten

Action and Result tell the interviewer the quality of the candidate's ability to follow through and achieve the intended results. This also judges the quality of execution in terms of cost and time. The candidate with the lowest cost and time and the highest quality of outcome is considered the best.

Cheers

Answer:

  2.5 m/s²

Explanation:

a = ∆v/∆t = (15 m/s)/(6 s) = (15/6) m/s² = 2.5 m/s²

Answer:

B 5.0 A .

Explanation:

Hello.

In this case, since we know the charge (1200 C), time (4 min =240 s) and resistance (10Ω) which is actually not needed here, we compute the current as follows:

[tex]I=\frac{Q}{t}[/tex]

Then, for the given data, we obtain:

[tex]I=\frac{1200C}{4min}*\frac{1min}{60s}\\\\I=5A[/tex]

Therefore, answer is B 5.0 A .

Best regards!

Answer:

  b-the velocity of the object will remain the same

Explanation:

Forces from opposite sides cancel each other, so there is no net force on the box that would affect its motion. The velocity of the box will remain unchanged.

__

(The box may be crushed, but it will continue in the same direction at the same speed.)

Answer:

b the velocity of the object will remain the same

Explanation:

use your brain:)

Answer:

5

Explanation:

Bextra in bf x vi d sj by

Answer:

The correct option is  B

Explanation:

From the question we are told that

   The mass of the pile is  M

   The  height is  H  =  4 y

    The vertical distance achieve during the first lift is  [tex]h_1  =  3 y[/tex]

     The time taken is  [tex]t_1 =  4T [/tex]

    The vertical distance achieve during the second lift is  [tex]h_2  =  y[/tex]

     The time taken is [tex] t_2 =  T [/tex]

Generally the velocity of the crane during the first lift is  

      [tex]v _1 =  \frac{h_1}{t_1 }[/tex]

=>    [tex]v _1 =  \frac{3 y}{4T }[/tex]    

Generally the velocity of the crane during the second  lift is    

      [tex]v _2 =  \frac{h_2}{t_2 }[/tex]

=>    [tex]v _2 =  \frac{ y}{T}[/tex]  

Generally the power generated by  the crane during the first lift is    

    [tex]P_1 =  F_1 *  v_1[/tex]

Here [tex]F_1[/tex] is the weight of the brick which is mathematically represented as

      [tex]F_1 =  M  * g [/tex] , g is the acceleration due to gravity

 So

       [tex]P_1 =  Mg  *  \frac{3y}{4T}[/tex]

Generally the power generated by  the crane during the first lift is    

    [tex]P_1 =  F_2 *  v_2[/tex]

Here [tex]F_2[/tex] is the weight of the brick which is mathematically represented as

      [tex]F_2 =  M  * g [/tex] , g is the acceleration due to gravity

 So

       [tex]P_1 =  Mg  *  \frac{y}{T}[/tex]

The ratio of the first power generated to the second power is  

       [tex]\frac{P_1}{P_2} =  \frac{Mg  *  \frac{3y}{4T} }{ Mg  *  \frac{y}{T} }[/tex]

=>    [tex]\frac{P_1}{P_2}  =  \frac{3}{4}[/tex]

=>   [tex]P_2 = \frac{4}{3} P_1[/tex]

Answer:

According to the University of Iowa, the average length of a stride is 5ft.

Now, the total distance of the marathon is:

26mi and 385yd.

Let's transform that distance into ft.

1mi = 5280ft

Then:

26mi = 26*5280ft = 137,280ft

1yd = 3ft

then:

385yd = 385*3ft = 1,155ft.

Then the total distance of the marathon, in ft, is:

D = 137,280ft + 1,155ft = 138,435 ft.

Now the average number of strides needed will be equal to the quotient between the total distance of the marathon and the distance traveled in each stride.

N = 138,435ft/5ft = 27,687.

Answer:

Sigmund Freud

Explanation:

Answer:

Wilhelm Wundt

Answer:

a) FB = 260 [N]

b) FT = 230 [N]

Explanation:

In order to solve this problem we must use a static analysis, since Globe does not move. For a better understanding in solving this problem, a free body diagram with the forces acting on the globe is attached.

The buoyant force acts upward as it causes the balloon to tend to float, the weight of the balloon tends to lower the balloon and the downward tension force does not allow the balloon to float

The buoyant force is defined by the following equation:

FB = Ro*V*g

where:

FB = Buoyant force [N]

Ro = density of the air = 1.3 [kg/m^3]

V = volume of the balloon = 20 [m^3]

g = gravity acceleration = 10 [m/s^2]

FB = 1.3*20*10 = 260 [N]

Now we do a sum of forces equal to zero in the y-axis

FB - 30 - FT = 0

260 - 30 = FT

FT = 230 [N]

Answer:

2 and 8

Explanation:

please mark me brainiest I would really appreciate it.

Answer:

Uniformly accelerated rectilinear motion (MRUA), also known as uniformly varied rectilinear motion (MRUV), is one in which a mobile moves along a straight path being subjected to a constant acceleration.

Explanation:

Answer:With gravity, two things with mass will want to move toward each other. However, we humans don't feel our gravity pulling on another person because it's not very big, but we do all feel the pull of Earth's gravity all the time - we're not all floating in the air, because that would be happening without Earth's gravity!

Explanation:

Answer:

Cornea

Explanation:

Cornea protects outer layer of the eye.

Answer:

The value  is [tex]  \mu  = 0.72  [/tex]

Explanation:

From the question we are told that

   The mass of the first car is  [tex]m_1  =  1870\ kg[/tex]

    the initial  speed of the car  is  [tex]u  =  13.5 \  m/s[/tex]

    The  mass of the second car is  [tex]m_2 =  2970\  kg[/tex]

    The distance move by both cars is  s =  1.93  m

Generally from the law of momentum conservation

    [tex]m_1 * u_1 + m_2 *  u_2  =  (m_1 + m_2 ) *  v_f[/tex]

Here [tex]u_2  =  0[/tex] because the second car is at rest

and  [tex]v_f[/tex] is the final  velocity of the the two car

So

    [tex]1870*  13.5+ 0=  ( 1870 + 2970 ) *  v_f[/tex]      

=> [tex]v_f  =  5.22\  m/s[/tex]

Generally from kinematic equation

    [tex]v_f^2 = u_2^2  +  2as[/tex]

here a is the deceleration

So

    [tex]5.22^2 = 0  +  2 *a  *  1.93[/tex]

=> [tex]a =  7.06 \  m/s^2 [/tex]

Generally the frictional  force is equal to the force propelling the car , this can be mathematically represented as

   [tex]F_f  =  F[/tex]

Here  F is mathematically represented as

[tex]F =  (m_1 + m_2) *  a[/tex]

[tex]F =  (1870 + 2970) *  7.06 [/tex]    

[tex]F =34170.4 \ N[/tex]  

and

[tex]F_f  =  \mu *  (m_1 + m_2 ) *  g[/tex]

[tex]F_f  =  47432 * \mu [/tex]

So

[tex]  47432 * \mu   = 34170.4  [/tex]

=> [tex]  47432 * \mu   = 34170.4  [/tex]

=> [tex]  \mu  = 0.72  [/tex]