At t = 0, the wheel has an angular position of 2.3 rad and an angular velocity of 1.5 rad/s.
Since the wheel is rotating about a fixed axis at a constant angular acceleration of -0.40 rad/s2, we can use the equation for angular position to calculate the wheel's angular position at t = 2.0 s.
Angular position = initial angular position + (initial angular velocity × time) + (1/2 ×angular acceleration ×time²)
Angular position at t = 2.0 s = 2.3 rad + (1.5 rad/s × 2.0 s) + (1/2 ×-0.40 rad/s2 × (2.0 s)²)
Angular position at t = 2.0 s = 2.3 rad + 3.0 rad + -1.6 rad
Angular position at t = 2.0 s = 3.7 rad
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Seismic-wave velocity can change (increase or decrease) as the waves pass through different rock types.
Yes, seismic-wave velocity can change as the waves pass through different rock types.
Rocks with high porosity and permeability tend to have lower seismic-wave velocities because the pores contain fluid that can dampen the energy of the seismic waves, while rocks with high compaction and densities tend to have higher seismic-wave velocities. Additionally, changes in temperature and pressure can also affect seismic-wave velocity.
What are seismic sounders?Seismic sounders are seismic instruments that use a wide range of sound frequencies to measure the Earth's subsurface structure, composition, and its response to seismic waves generated from a source.
They are used in the exploration of oil, gas and mineral resources and for investigating earthquake and volcanic processes.
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A meter‑long wire of mass 185 g is attached to a 60. 0 Hz mechanical wave oscillator operating at 139 W. The far end of the wire is strung over a frictionless, massless pulley, and a 306 g mass is hung from it. When the oscillator is turned on, it produces a sinusoidal wave in the wire. Calculate the amplitude of oscillation of the wire. Use the value 9. 81 m/s2 for the acceleration due to gravity
The tension in the wire is 2.99986 N. The amplitude of the oscillation of the wire is approximately 0.01067 meters.
The tension (T) can be calculated using the equation:
T = m × g
T = 0.306 × 9.81
T = 2.99986 N
The linear mass density (μ) of the wire is given by the mass per unit length of the wire. It is calculated as:
μ = m(wire) ÷ L(wire)
μ = 0.185 ÷ 1
μ = 0.185 kg/m
The speed (v) of the wave on the wire can be determined using the equation:
v = √(T ÷ μ)
v = √(2.99986 ÷ 0.185 )
v = 7.351 m/s
The power (P) transmitted by the wave is related to the amplitude (A) and the speed (v) of the wave through the equation:
P = 2π² × μ × v × A² × f²
A² = P ÷ (2π² × μ × v × f²)
A² = 139 ÷ (2π² × 0.185 × 7.351 × (60.0)²)
A² = 1.138 × 10⁻⁴
A = √(1.138 × 10⁻⁴)
A = 0.01067 m
Therefore, The amplitude of the oscillation of the wire is approximately 0.01067 meters.
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A 64 g plastic ball is moving to the left at 24 m/s . How much work must be done on the ball to cause it to move to the right at 24 m/s
The ball requires a total of zero work to go to the right at 24 m/s.
Take into account the ball's kinetic energy.
Vi = -24 ms-1 for the initial velocity
Final velocity: vf = +24ms⁻¹
K = 12mvf²- 12mvi² = 12m(vf² - vi²) = 12m(242 - 242) = 0,
meaning that the ball does not undergo any effort.
As an alternative, think about the effort made to stop the ball.
W1 = ½m(0 – 24²) = 0.5 × 0.06 × –576 = –17.28J
Work required to accelerate the ball from rest to +24 milliseconds per second was W2 = 12m(242 - 0) = 0.5 0.06 576 = +17.28 J.
Therefore, the sum of the work is W = W1 + W2 = -17.28 + 17.28 = 0 J.
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Which of the following best defines the term “climate”?
A: the weather patterns that are occurring right now
B: the specific weather patterns for a local region or city
C: the temperature readings for the past 30 years or more
D:he average conditions of the atmosphere for a large region for the past 30 years or more
The statement that best defines climate is as follows: the average conditions of the atmosphere for a large region for the past 30 years or more (option D).
What is climate?Climate is the long-term manifestations of weather and other atmospheric conditions in a given area or country.
Climate is now usually represented by the statistical summary of its weather conditions during a period long enough to ensure that representative values are obtained (generally 30 years).
A description of a climate includes information on, e.g. the average temperature in different seasons, rainfall, and sunshine.
Therefore, option D correctly describes climate.
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two blocks are connected by a string of negligible mass that passes over massless pulleys
If two blocks are connected by a string of negligible mass that passes over massless pulleys, the system can be analyzed using the principles of Newton's second law and the conservation of energy.
In this scenario, the net force acting on each block is the tension in the string, which is equal in magnitude for both blocks.
Therefore, if the blocks have different masses, they will have different accelerations.
In this scenario, the mechanical energy of the system is the sum of the gravitational potential energy and the kinetic energy of the blocks. If the pulleys are massless and frictionless, then the mechanical energy of the system will be conserved.
In summary, the two blocks will move together with the same acceleration if the pulleys are massless and frictionless.
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A 30,000-kg freight car is coasting at 0.850 m/s with negligible friction under a hopper that dumps 110,000 kg of scrap metal into it. (a) What is the final velocity of the loaded freight car
The freight car which is being dumped into the metal scrap has the final velocity of 0.18 m/s.
In this problem, we use the principle of conservation of linear momentum.
Given that,
Mass of the freight car m₁ = 30,000 kg
Mass of the hopper m₂ = 110,000 kg
Velocity of the freight car u₁ = 0.85 m/s
Velocity of the hopper u₂ = 0
Let the velocity of the loaded freight car = v
We need to find out v.
m₁ u₁ + m₂ u₂ = ( m₁ + m₂) v
After putting the values into the equation above, we have,
30,000 × 0.85 + 110,000 × 0 = (30,000 + 110,000) v
140,000 v = 25500
v = 0.18 m/s
Thus, the required velocity of the loaded freight car is calculated to be 0.18 m/s.
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Please help
How does sound move from the source to the receiver? (a slinky moving back and forth)
Answer:
through a chain reaction of particle collisions in a medium.
Explanation:
Stephen has to drive 8 miles south and 3 miles east to get to work.What is his distance and displacement?
Since the displacement is a vector quantity, the distance is 11 miles while displacement is 8.5 miles
What is Displacement ?Displacement is a distance travelled in a specific direction. Distance is a scalar quantity while displacement is a vector quantity.
Given that Stephen has to drive 8 miles south and 3 miles east to get to work.
His distance will be 8 miles + 3 miles = 11 miles
While his displacement can be calculated by using Pythagoras theorem. That is,
Displacement D = √(8² + 3²)
D = √(64 + 9)
D = √73
D = 8.5 miles
Therefore, his distance is 11 miles and his displacement is 8.5 miles.
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A point particle of charge -5.40 nC is located at the origin of a Cartesian coordinate system. Determine the magnitude of the electric field due to this charge at a distance of 23.0 cm from the charge.
The magnitude of the electric field due to this charge at a distance of 23.0 cm from the charge is 918.7 N/C.
Given that,
Charge on point particle Q = -5.4 nC = -5.4 × 10⁻⁹ C
Distance from the charge r = 23 cm = 23 × 10⁻² m
The relation between distance charge and electric field is known to be,
E = 1/4πε₀ × Q/r² = 9 × 10⁹ × (-5.4 × 10⁻⁹)/(23 × 10⁻²)² = (9 × 5.4)× 10⁴/(23)² = 918.7 N/C
Thus, the magnitude of the electric field due to this charge at a distance of 23.0 cm from the charge is calculated to be 918.7 N/C.
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Assume air resistance is negligible unless otherwise stated. Calculate the displacement in m and velocity in m/s at the following times for a rock thrown straight down with an initial velocity of 14.4 m/s from the Verrazano Narrows bridge in New York City. The roadway of this bridge is 70.0 m above the water. (Enter the magnitudes.) (a) 0.500 s displacement m velocity m/s (b) 1.00 s displacement m velocity m/s (c) 1.50 s displacement m velocity m/s (d) 2.00 s displacement m velocity m/s (e) 2.50 s displacement m velocity m/s
Answer:
(a) 0.500 s displacement 70.0 m - 7.2 m velocity 7.2 m/s
(b) 1.00 s displacement 70.0 m - 28.8 m velocity -13.6 m/s
(c) 1.50 s displacement 70.0 m - 57.6 m velocity -20.4 m/s
(d) 2.00 s displacement 70.0 m - 92.8 m velocity -24.0 m/s
(e) 2.50 s displacement 70.0 m -134.4 m velocity -25.2 m/s
A 50 kg person and a 70 kg person are sitting on a bench close to each other about .5 m apart.
Estimate the magnitude of the gravitational force each exerts on the other.
Answer:
1.0 x 10-6 N.
Explanation:
The gravitational force
Fg = G m1 m2 / r2 = (6.673 x 10-11) (50 kg) (75 kg) / (0.50 m)2 = 1.0 x 10-6 N.
Define the following
a. Velocity:
b. Inertia:
c.Speed:
e Force:
f. Balanced force:
g. Net force:
h. Displacement:
Answer:
Explanation:
a.speed with direction associated
b.the ability to resist motion
c.The rate of change of position of an object
e.any influence object's motion
f.forces cancel out, create equilibrium
g.total force acting on an object
h. change in position of an object (total distance from starting point)
Ammeters that respond to the average value convert the alternating current into direct current. This value must be increased by a factor of _____ to change the average reading into the rms value for a sine wave current.
The average reading must be multiplied by a multiplier of 1.111 to become the rms value for just a sine wave flow.
Describe the wave current?Wave-current interaction in fluid dynamics is the interaction of a mean flow with surface gravity waves.After the interaction begins, both the waves as well as the average flow are impacted since the contact implies an energy exchange.
What are the tide and the wave?While the tide is a type of vertical motion of the ocean's water, waves and ocean circulation represent horizontal movements of the water.
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When a satellite is a distance d from the center of Earth, the magnitude of the gravitational force that the satellite exerts on Earth is F. What is the magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d?
plsss help
According to Newton's law of gravitation, the new gravitational force will be F/9
Newton's Law of GravitationIt states that, the force of attraction between two masses is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.
When a satellite is a distance d from the center of Earth, the magnitude of the gravitational force that the satellite exerts on Earth is F. That is,
F = GMm/d²
Where
M = mass of the earthm = mass of the satelliteG = universal gravitational constantThe magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d can be expresses as follow
f = GMm/(3d)²
f = GMm/9d²
f = GMm/d² × 1/9
Since GMm/d² = F
f = F × 1/9
f = F/9
Therefore, the magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d is F/9 Newton
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You went to move a 41 kg bookcase to a different place in the living room. If you push with a force of 65 N and the bookcase accelerates at 0. 12 m/s2 what is the coefficient of kinetic friction between the bookcase and the carpet?
If you push with a force of 65 N and the bookcase accelerates at 0. 12 m/s2. The answer to the given question is A65=41×A.A=1.2m.
Explanation of the given answer:Functions and co efficients are: Ff=μkFN F f = μ k F N
The equation for kinetic friction, where FN is the object's normal force and k is the coefficient of kinetic friction.
The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value. The formula which is fr = Fr/N serves as a representation of kinetic friction.
The primary distinction between static and kinetic friction is that kinetic friction occurs when there is relative motion between the surfaces, whereas static friction occurs when the surfaces are at rest.
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The human ear canal is about 2. 8 cm long and can be regarded as a tube open at one end and closed at the eardrum. What is the frequency around which we would expect hearing to be best when the speed of sound in air is 344. 5 m/s? (hint: find the fundamental frequency for the ear canal. )
The human ear canal is closed at one end. Thus, the fundamental frequency of the given ear canal is 3044.64Hz 3044.64 Hz .
Calculation and Explanation:Under air conduction (AC) excitation, the mean resonance frequency of the human middle ear is estimated to be between 0.8 and 1.2 kHz. The typical resonance frequency under bone conduction (BC) excitation, according to research, is higher, at 1.5–2 kHz.
It is a tube with an open end (the concha section) and a closed end (the tympanic membrane), which responds to a quarter-wave by behaving as a resonator. The resonance frequency is described by the equation F=v/4L, where "v" stands for the speed of sound and "L" for the length of the EAC.
The EAR formula should be used: EAR = (1+ i/n)n - 1. I = Stated interest rate, etc.
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What is the velocity of the particle at time t 0?
The velocity of the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
Velocity is the rate of change of velocity. At any point on a trajectory, the magnitude of the velocity is given by the rate of change of velocity in both magnitude and direction. Velocity of the body that we can consider is the increasing value of the velocity of any object at a constant rate and that of we can calculate. Hence by the primary information that we have we can formerly consider that the velocity which is acting on the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
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At an outdoor physies demonstration, a delay of 0.50 second was observed between the time sound waves left a loudspeaker and the time these sound waves reached a student through the air. If the air is at STP, how far was the student from the speaker? (1) 1.5 × 10-m (91.7 × 102 m (3) 6.6 × 10? m (4) 1.5 × 108 m
The distance that is covered by the sound is 1.66 * 10^2 m.
What is the distance?We know that sound is a mechanical wave. The implication of this is that sound woulod need to have a medium through which the sound can be able to travel. The speed of sound in the various media through which the sound travels is not the same.
We know that the speed of sound in air is 331 m/s and we have to use this in our calculations.
Distance = speed * time
Distance = 331 m/s * 0.5 s
= 1.66 * 10^2 m
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a force of 15 N is used to push a box along the floor a distance of 3 meters. find the amount of work done
Answer:
The amount of work done is 45 J.
Explanation:
We know that the force applied is 15N. The amount of displacement experienced by the box is 3 metres along the floor.
Thus, F= 15N
D= 3 metres
The formula for calculating work done is W= F×D
Thus, W=15×3
W=45J
Thus, the amount of work done is 45J.
the first artificial satellite to orbit the earth was sputnik 1, launched october 4, 1957. the mass of sputnik 1 was 83.5 kg, and its distances from the center of the earth at apogee and perigee were 7300 km and 6610 km, respectively. find the difference in gravitational potential energy for sputnik 1 as it moved from apogee to perigee
The difference in gravitational potential energy for sputnik 1 as it moved from apogee to perigee is 193 kJ.
The gravitational potential energy of an object in orbit around the Earth can be calculated using the equation:
U = -GMm/r
where U is the gravitational potential energy, G is the gravitational constant, M is the mass of the Earth, m is the mass of the object.
The difference in gravitational potential energy as the satellite moves from apogee to perigee can be found by calculating the potential energy at each point and subtracting the two values:
U(apogee) = -(6.67 x 10^-11 N*(m^2)/(kg^2)) * (5.972 x 10^24 kg) * (83.5 kg) / (7300 x 10^3 m)
U(perigee) = -(6.67 x 10^-11 N*(m^2)/(kg^2)) * (5.972 x 10^24 kg) * (83.5 kg) / (6610 x 10^3 m)
U(apogee) = -1.865 x 10^5 J
U(perigee) = -2.058 x 10^5 J
The difference in gravitational potential energy is:
= U(perigee) - U(apogee)
= -2.058 x 10^5 J - (-1.865 x 10^5 J)
= 193 x 10^3 J
So, the difference in gravitational potential energy for Sputnik 1 as it moved from apogee to perigee is 193 kJ.
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two objects gravitationally attract with a force of 36 N if the distance between the two objects centers is decreased by a factor of threee then the new force of attraction is
The new force of attraction is 324N if the distance between the centres of the two objects is reduced by a factor of 3e.
The equation for the force of gravitational attraction between two objects is: F = G*(m1*m2)/r^2 Where F is the force of attraction, G is the gravitational constant (6.67 x 10^-11 Nm^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between their centers. If the distance between the two objects' centers is decreased by a factor of three, the new force of attraction will be: F' = G*(m1*m2)/(r/3)^2The ratio of the new force of attraction to the original force of attraction is:
F'/F = (r/3)^2 If we substitute in the original force of attraction, we have:
F'/36 = (r/3)^2 = F' = 36 * (r/3)^2
As we decrease the distance by a factor of 3, the new force of attraction will increase by a factor of 9.
F' = 36*9 = 324 N
Therefore, the new force of attraction is 324 N.
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A 600 g steel block rotates on a steel table (μk = 0.6) while attached to a 1.0 m long hollow tube. Compressed air fed through the tube and ejected from a nozzle on the back of the block exerts a thrust force of 4.2 N perpendicular to the tube. The maximum tension the tube can withstand without breaking is 50 N. If the block starts from rest, how many revolutions does it make before the tube breaks?
If the block starts from rest, then revolutions that it make before the tube breaks is 0.947 rotations.
What is meant by revolution?When object turns around an internal axis, it is called a rotation. When object circles an external axis, it is called revolution.
Given mass of block = 600 g = 0.6 kg ; Radius of rotation = 1.0 m-long
Given thrust force of 4.2 N
The maximum tension is 50 N.
As thrust is perpendicular to the tube. So, tangential component of the thrust force is Ft=4.2 N and radial component Fr=0
As we know, α = F/m r
= 4.2/0.6 * 1
α = 7 rad/s²
As, m r ω²= 50 N
ω² = 50/ 0.6 * 1.0
ω = 9.128 rad/s
Ф = ω² - ω0²/2α
= (9.128² - 0)/2 * 7
Ф = 5.951 rad
As 1 Radians = 0.1592 Rotations,
5.951 rad = 0.947 rotations.
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A ball is tossed straight up from the surface of a small spherical asteroid with no atmosphere. The ball goes to a height equal to the asteroid's radius and then falls straight down toward the surface of the asteroid. What forces if any act on the ball while it is on the way up?
a. only a decreasing gravitational forces acts downward
b. only an increasing gravitational force that acts downwards.
c. only a constant gravitational force that acts downwards
d. Both a constant gravitational force that acts downwards and a decreasing force that acts upwards.
e. No forces act on the ball
'Only a decreasing gravitational force that acts downward' act on the ball while it is on the way up.
What is gravitational force?
Gravitational force is the force of attraction between two objects that have mass. It is the force of gravity that causes objects to be pulled towards each other. The strength of the force depends on the mass of the objects and the distance between them.
Since the ball is moving away from the Earth, the gravitational force between the two objects is decreasing. The ball does not experience any upward force and thus the only force acting on it is the decreasing gravitational force that acts downward.
Hence, Option A is correct.
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Write down whether quantity of potential kinetic and total energy
Potential energy is the power that a thing possesses as a result of where it is in relation to other objects.
What is Potential energy?The earth can pull you down through the force of gravity while doing work in the process, being at the top of a stairwell gives you more potential energy than standing at the bottom.
Two magnets have more potential energy when they are held apart than when they are near to one another. They will migrate near each other and begin working if you let them go.
The force acting on the two objects affects the potential energy formula. P.E. = mgh, where m is the mass in kilograms and g is the acceleration due to gravity, is the formula for gravitational force.
Therefore, Potential energy is the power that a thing possesses as a result of where it is in relation to other objects.
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The centripetal force on object M as it passes
through the rest position is approximately
Since the particle always moves in a circular motion in a direction perpendicular to the radial direction.
The work done by the centripetal force in a circular motion is therefore always zero since the dot product is always zero. A force known as the centripetal force acts on a particle when it is revolving around a specific axis or point. The circular path's center is where this force is directed. The ideal decision is (d) Therefore, the body's weight will be equal to the centripetal force when the angular acceleration reaches the same level as the acceleration caused by gravity. It should be noted that for the centripetal force to equal the weight, there must be a uniform circular motion.
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What causes diffusion in cells?
The causes diffusion in cells are, temperature, area of interaction, the size of the concentration gradient.
1) Temperature, The rate of diffusion increases as temperature rises.
2) Area of Interaction: The rate of diffusion increases as the surface area of interacting molecules increases.
3) The Size of the Concentration Gradient: The rate of diffusion is higher the greater the concentration gradient between the regions.
Higher the rate of diffusion, the more concentration between the locations. The movement is forced because of the increased pressure that the higher concentration creates. The movement of molecules from a location of higher concentration to a region of lower concentration can be used to define diffusion. The continuous motion (or kinetic energy) of atoms in matter is the primary cause of diffusion.
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anthony walks to the pizza place for lunch. he walks 1 km east then 2 km south and then 1 km east again. what distance did he cover and what was his displacement
Answer:
3 km displacement
Explanation:
I'm pretty sure that's the answer, I'm so sorry if it's not
4. A 55.0 g object connected to a spring with a force constant of 35.0 N/m oscillates on a horizontal, frictionless surface with an amplitude of 8.00 cm. a) Find the total energy of the system. 112 mJ b) Find the speed of the object when the position is 1.20 cm.
According to the given data the total energy (E) of the system is 11.2 m J.
What is an illustration of oscillation?A periodic movement between two sites is what is referred to as oscillation in this type of behavior. Examples of oscillating motion include plucking a guitar string, pendulum swinging, and pogo stick bouncing. The major distinction between oscillation, vibration, and simple harmonic motion is that oscillation is a general term for any repeating fluctuation about a central value, whereas vibration is a term used especially to describe mechanical oscillations.
Energy is given by-
E= 1/2KA²
E = 1/2 ×N/m× (8×10∧-2 m)²
E = 11.2 m J
Speed of the object-
v = ω[tex]\sqrt{A2-x2}[/tex]
v = [tex]\sqrt{K/m}[/tex] [tex]\sqrt{A2 - x2}[/tex]
v = [tex]\sqrt{35/55*10-3}[/tex] ×( (8×10-2)∧-2 - (1.20 × 10-2)∧2 )[tex]^{-1/2}[/tex]
v = 25.22 × 0.079
v = 2 m/s.
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can u pls solve this question thank u!! i having my physics paper tomorrow!!
Answer:
13.875Ω & 5Ω
Explanation:
in the first diagram:-
R = Rs + Rp + Rs'
Rp => [tex]\frac{1}{7} + \frac{1}{1} = \frac{1+7}{7} = \frac{8}{7} \\[/tex]
Rp = [tex]\frac{7}{8}[/tex] = 0.875
4 + 0.875 + 9 = 13.875Ω
in the second diagram:-
R= Rp + Rs + Rp'
Rp => 1/6 + 1/3 = 1+2/6 = 3/6 => 2
Rp' => 1/3+1/3+1/3 = 3/3 => 1
R = 2 + 2 + 1 = 5 Ω
What is the acceleration of the particle at t 0?
The acceleration of the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
Acceleration is the rate of change of velocity. At any point on a trajectory, the magnitude of the acceleration is given by the rate of change of velocity in both magnitude and direction. Acceleration of the body that we can consider is the increasing value of the velocity of any object at a constant rate and that of wee can calculate. Hence by the primary information that we have we can formerly consider that the acceleration which is acting on the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
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