Are humans made of matter ?

A mixture of water and acetone boils at 1.25 atm will boil at 348.15K. Given the vapor pressure of acetone (1.58 atm) and water(0.312 atm). 5.06 is the composition of the solution in terms of mole fraction of each chemical present.

Raoult's Law is a nonvolatile solute lowers the vapour pressure of the solvent.

It is expressed as:

[tex]P_{\text{soln}} = x_{\text{solvent}} P_{\text{solvent}}[/tex]

where,

[tex]P_{\text{sol}[/tex] = vapor pressure of the solution

[tex]x_{\text{solvent}}[/tex] = mole fraction of the solvent

[tex]P_{\text{solvent}}[/tex] = vapor pressure of the pure solvent

Now put the values in above expression, we get

[tex]P_{\text{soln}} = x_{\text{solvent}} P_{\text{solvent}}[/tex]

[tex]x_{\text{solvent}} = \frac{P_{\text{soln}}}{P_{\text{solvent}}}[/tex]

            [tex]= \frac{1.58}{0.312}[/tex]

            = 5.06

Thus from the above conclusion we can say that A mixture of water and acetone boils at 1.25 atm will boil at 348.15K. Given the vapor pressure of acetone (1.58 atm) and water(0.312 atm). 5.06 is the composition of the solution in terms of mole fraction of each chemical present.

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An alginic acid is bio polymer.  The two modified carbohydrate units make up the basic building block of this polymer are guluronic acid ( G) and mannuronic acid (M).

Alginic acid is a biopolymer formed from chain of polyuronic acid. Alginic acid is polysaccharide found in brown algae. Alginic acid is also known as Algin. it is linear co-polymer.

Polysaccharides  are found in the food and it is most abundant carbohydrates. It is long chains of monosachharides. Polysaccharides  is formed by glycosidic linkage or bonds .

Example of polysaccharides are cellulose , starch , glucogen.

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The liberated electron will have 10.28 eV kinetic energy.

Given that light of frequency 3.62 × [tex]10^{15}[/tex] Hz strikes a surface of copper metal with work function([tex]W_{0}[/tex]  = 4.70 eV).

The incident (photon) energy given as hf (Planck's Constant time's frequency) minus the energy that "binds" the electron to the metal (the work function) will equal the maximum kinetic energy of the emitted electron.

K.E. = hf − ϕ

Where K = Kinetic energy

h = Planck's constant = 6.62607015 × [tex]10^{-34}[/tex] J s

f = frequency = 3.62 × [tex]10^{15}[/tex] Hz

ϕ = 4.70 eV = 4.7 × 1.6 × [tex]10^{-19}[/tex] = 7.52 × [tex]10^{-19}[/tex]

K.E. = 6.62607015 × [tex]10^{-34}[/tex] × 3.62 × [tex]10^{15}[/tex] - 7.52 × [tex]10^{-19}[/tex]

       = 6.62607015 × 3.62 × [tex]10^{-19}[/tex] - 7.52 × [tex]10^{-19}[/tex]

       = 23.98 × [tex]10^{-19}[/tex] - 7.52 × [tex]10^{-19}[/tex]

K.E. = 16.46 × [tex]10^{-19}[/tex] J = 10.28 eV

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Regions in the human genome where one nucleotide has been substituted for another in at least 1% of the population are called single nucleotide polymorphism

Nucleotide can simply be defined as the basic building block of nucleic acids either RNA and DNA

Generally, nucleotides consists of a sugar molecule (either ribose in RNA or deoxyribose in DNA) attached to a phosphate group and a nitrogen-containing base.

A region is any considerable and connected part of a space or surface; specifically, a tract of land or sea of considerable but indefinite extent, a country, a district, in a broad sense, a place without special reference to location or extent but viewed as an entity for geographical, social or cultural reasons.

So therefore, regions in the human genome where one nucleotide has been substituted for another in at least 1% of the population are called single nucleotide polymorphism.

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As per Ideal gas equation, molar mass of the gas is 5.032 g/mo

We’ll begin by calculating the number of mole of the gas. This can be obtained as follow:

Volume (V) = 1.6 L

Temperature (T) = 287 K

Pressure (P) = 0.92 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =?

According to Ideal gas equation , PV = nRT

0.92 × 1.6 = n × 0.0821 × 287

1.472 = n × 23.5627

Divide by 23.5627

n = 1.176 / 23.5627

n = 0.0624 mole

Finally, we shall determine the molar mass of the gas. This can be obtained as follow:

Mass of gas = 0.314 g

Number of mole = 0.0624 mole

Mole = [tex]\frac{mass}{molar mass}[/tex]

0.0624 = [tex]\frac{0.314}{molar mass}[/tex]

Cross multiply

0.0624 × molar mass of gas = 0.314

Divide by 0.0624

Molar mass of gas =  [tex]\frac{0.314}{0.0624}[/tex]

Molar mass of gas = 5.032 g/mo

Therefore the Molar mass of gas is 5.032 g/mo

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Taking into account the definition of mole or molar fraction, the mole fraction of N₂ in the mixture is 0.79.

The molar fraction is used to express the concentration of a solute in a solution and expresses the proportion in which a substance is found with respect to the total moles of the solution, which are calculated by adding the moles of solute(s) and solvent.

The mole fraction "x" of the elements in a compound is defined as a ratio between the number of moles of each of the different elements present in the compound and the total number of moles of them:

x=number of moles of the solute÷ total number of moles

In this case, you know that:

Replacing in the definition of mole fraction:

x=2.11 moles÷ 2.67 moles

Solving:

x= 0.79

Finally, the mole fraction of N₂ in the mixture is 0.79.

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On comparing the proposed processes of ammonia synthesis by dry distillation and Haber process,

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Answer:

11.2 grams CaO

Explanation:

It appears that substance X may be calcium carbonate:  CaCO3

CaCO3 can be thermally decomposed to CO2 and CaO in the following balanced reaction:

CaCO3(s) ⇒ CaO(s) + CO2(g)     (with applied heat, 840°C)

The molar ratio between the product, CaO, and the reactant, CaCO3, is 1:1.  If we start with 1 mole CaCO3, we should produce 1 mole of CaO.

We have 20.0 grams of substance X, which we'll label CaCO3.  Calculate the moles of CaCO3 by using its molar mass of 100.1 grams/mole.

 20.0 grams/(100.1 grams/mole) = 0.1998 or 0.200 moles of CaCO3.

This should produce, with a molar ratio of 1 to 1, 0.200 moles of CaO

Convert this to grams CaO by multiply by it's molar mass of 56.1 g/mole:

(0.200 moles)*(56.1 g/mole) = 11.2 grams CaO.  Any less, then blame it on your lab partner.  But don't try taking credit if you have more than 11.2 grams.  Scraping debri off the counter into the beaker doesn't count.

The enthalpy of vaporization for Benzene is 30.8 kJ/mol. 39.42 kJ is the energy change when 100g of Benzene boils at 80.1 degrees Celsius.

The amount of enthalpy or energy that must be added to a liquid substance into gas substance is called Enthalpy of Vaporization. It is also known as Latent heat of vaporization.

To calculate the energy use this expression:

[tex]Q = n \Delta H_{\text{vapo.}[/tex]

where,

Q = Energy change

n = number of moles

[tex]\Delta H_{\text{Vapo.}}[/tex] = Molar enthalpy of vaporization

Now find the number of moles

Number of moles (n) = [tex]\frac{\text{Given Mass}}{\text{Molar mass}}[/tex]

                                   = [tex]\frac{100\ g }{78\ g/mol}[/tex]

                                   = 1.28 mol

Now put the values in above formula we get

[tex]Q = n \Delta H_{\text{vapo.}[/tex]

   = 1.28 mol × 30.8 kJ/mol

   = 39.42 kJ

Thus from the above conclusion we can say that The enthalpy of vaporization for Benzene is 30.8 kJ/mol. 39.42 kJ is the energy change when 100g of Benzene boils at 80.1 degrees Celsius.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: The enthalpy of vaporization for Benzene is 30.8 kJ/mol. What is the energy change when 100g of Benzene boils at 80.1 degrees Celsius?

Yes, Electrolysis is used as a separating method of a molten solution of their ion to extract them from the solution.

A non-spontaneous chemical reaction can be sped up using a process called electrolysis that uses direct electric current. As a step in the electrolytic cell-based separation of elements from naturally existing sources like ores, electrolysis is significant from a commercial standpoint.

The electric current used to trigger an artificial reaction Numerous elements were discovered and are still produced in today's industry by the electrolysis method, which can be used to separate a substance into its original components or elements.

Uses for electrolysis include

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The concentration of the sodium hydroxide will be 0.016 M

First, the concentration of the diluted nitric acid needs to be found.

m1 = 2.0 M,  v1 = 100 mL, v2 = 300.0 mL

m2 = 2 x 100/300 = 0.6667 M

The equation of the reaction goes thus: [tex]HNO_3 + NaOH = NaNO_3 + H_2O[/tex]

The mole ratio is 1:1.

Mole of 0.6667 M, 7.05 mL HNO3 = 0.6667 x 0.00705 = 0.0047 mol

Equivalent mole of NaOH = 0.0047 mol

Molarity of 0.0047 mol, 30.0 mL NaOH = 0.0047/0.3 = 0.016 M

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Metal that won't be oxidized:

Metal that will not be able to oxidize by any of the other metals is gold.

What causes oxidation to happen?

This chemical reaction might take place in the air or after the metal has been in contact with acids or water. The most prevalent example is corrosion of steel, which occurs when the iron molecules on the surface of steel change into iron oxides, most frequently Fe2O3 and Fe3O4.

If you've ever seen a rusted-out vehicle or corroded metal bits, you've witnessed oxidation in action.

Metals that don't oxidize:

In their native condition, noble metals like platinum or gold resist oxidation. Ruthenium, rhodium, palladium, silver, osmium, and iridium are more examples of these metals. Humans have developed a wide variety of corrosion-resistant alloys, including brass and stainless steel.

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Mass after 60 years:

2 kg of cesium-137 will remain after 60.0 years.

What is Half-life?

The duration needed for a quantity to decrease to half of its initial value is known as the half-life.

Given:

N0 = is the initial amount of cesium-137 = 8.0 Kg

N = is the amount remaining after a time =  Unknown

t =  Duration of cesium-137 decay in 8.0 Kg = 60 years

t1/2 = half-life of cesium-137 = 30.0 years

Formula = N/No = (1/2)^t/t1/2

After putting the value:

N/8= (1/2)^60/30

N/8= (1/2)^2

N/8= 1/4

4N= 8

N= 8/4

N= 2 Kg

As a result, 2 Kg of cesium-137 will be present after 60 years.

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The rate of entropy change:

The rate of entropy change of the working fluid during the heat addition process is 3 kW/K

What is the Carnot cycle?

The entropy of a system:

The rate of heat addition is expressed as,

Q = [tex]\frac{WT_{H}}{T_{H}- T_{L}}[/tex]

The entropy of a system is a measure of how disorderly a system is getting. The rate of entropy generation during heat addition is,

[tex]S_{gen} = \frac{Q}{T_{H}} = \frac{W}{T_{H} - T_{L}}[/tex]

Calculation:

Given:

[tex]T_{L}[/tex] = 400K

[tex]T_{H}[/tex] = 1600K

W = 3600 kW

Put all the values in the above equation, and we get,

[tex]S_{gen} = \frac{W}{T_{H} - T_{L}}[/tex] = [tex]\frac{3600}{1600-400}[/tex] = 3 kW/K

The rate of entropy change is 3 kW/K

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In Texas, special elections are used to ratify amendments to the Texas Constitution.

This is referred to a formal way of people voting for someone or for a type of cause.

Special elections which are held in Texas is done to ratify amendments to the constitution and is usually done by the legislature thereby making it the most appropriate choice.

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A hydrogen bond occurs between a hydrogen from one molecule and an oxygen from another molecule. Option D

The hydrogen bond is one that is responsible for association in molecules. It occurs when hydrogen is covalently bonded to a highly electronegative element such as oxygen, nitrogen or Sulphur.

Thus, a hydrogen bond occurs between a hydrogen from one molecule and an oxygen from another molecule. Option D

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Answer:

Nitrous oxide

Explanation:

Nitrous+ Oxygen (ygen becomes -ide when it is combined) = Nitrous oxide

just learnt these in school, hope this is correct

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The Old Way

If the peaks matched those of known impurities, they could use the intensities to calculate the purity of the ester.

IR-spectroscopy is perhaps the most frequently used technique in the organic chemistry labs at PSU. It is routinely used to identify products and to verify that an experiment has succeeded.

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The structure that corresponds to methylpropylether is the structure CH3 - O - C3H7 in option C.

The structure of a compound is defined as the way in which the atoms in the compound are arranged. We know that a compound is composed of atoms and these atoms are arranged in particular patterns in space. This is the stereochemistry of the molecule.

Now we know that methylpropylether is a compound that contains the methyl group and the propyl group separated by a oxygen atom as is typical of all ethers.

As such, the structure that corresponds to methylpropylether is the structure CH3 - O - C3H7 in option C.

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The property a radioisotope used for dating should have is Its half-life should be similar to the age of the fossil and is denoted as option B.

This is an element which is unstable and releases radiation to achieve its stability.

The half-life of the element used in dating should be similar to that of the fossil for easy comparisons and accuracy.

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Answer:

b, half life should be similar to the fossil

Explanation:

Answer:

0.6258 g

Explanation:

To determine the number grams of aluminum in the above reaction;

Moles of HCl

35 mL of 2.0 M HCl

2 moles of HCl is contained in 1000 mL

x moles of HCl is contained in 35 mL

[tex]x \: mol \: = \: \frac{2 \: \times \: 35}{1000} \\ = 0.07 \: moles \: [/tex]

We have 0.07 moles of HCl.

Mole ratio

6HCl(aq) + 2Al(s) --> 2AlCl3(aq) + 3H2(g)

Hence mole ratio = 6 : 2 (HCl : Al

[tex] = \frac{2}{6} \times 0.07 \\ \: = 0.0233333 \: moles[/tex]

Therefore we have 0.0233333 moles of aluminum.

Grams of Aluminum

We use the formula;

[tex]grams \: = moles \: \times \: rfm[/tex]

The RFM (Relative formula mass) of aluminum is 26.982g/mol.

Substitute values into the formula;

[tex] = 0.0233333 \: moles \: \times \: 26.982 \: \frac{g}{mol} \\ = 0.625799 \: grams[/tex]

The number of grams of aluminum required to react with HCl is 0.6258 g.

Answer:

See below

Explanation:

[tex]\rule[225]{225}{2}[/tex]

HYDROGEN: USED AS ROCKET FUEL.

CHLORINE: USED TO PURIFY WATER.

GRAPHITE: USED IN PENCILS TO WRITE.

HELIUM: USED IN BALOONS TO MAKE THEM FLOAT INTO THE AIR.

PHOSPHOROUS: USED FOR IGNITION, SUCH AS FIREWORKS.

Glaucoma Is a buildup of fluid within the eye.

The optic nerve, which is necessary for clear vision, is harmed by a group of eye conditions collectively referred to as glaucoma. This injury typically happens as a result of an excessively high amount of pressure in your eye. Glaucoma is one of the leading causes of blindness in persons over 60. Glaucoma frequently results from high intraocular pressure. Diabetes, however, can also increase your risk of developing glaucoma. We'll go into more detail about the connection between diabetes and glaucoma in this piece. We'll also talk about some preventative steps you may take to help keep your eyes healthy. Loss of side or peripheral vision: Often, this is the first glaucoma symptom.

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For Lead (II) Nitrate + Potassium Iodide → Lead (II) Iodide + Potassium                                                                                                           Nitrate , The balanced equation is [tex]Pb(NO_{3})_{2}[/tex] + 2KI ----->  [tex]PbI_{2}[/tex] + 2 [tex]KNO_{3}[/tex]

We must first convert from a word equation to a symbol equation:

Lead (II) Nitrate + Potassium Iodide → Lead (II) Iodide + Potassium

                                                                                              Nitrate

The lead (II) ion is represented as [tex]Pb^{2+}[/tex] and nitrate ion as [tex]NO_{3} ^{-}[/tex]

We need two nitrate ions per lead (II) ion,  so lead (II) nitrate is [tex]Pb(NO_{3})_{2}[/tex]

The potassium iodide is simply KI

In lead (II) iodide, the charges balance in a  1:2 ratio, so it is [tex]PbI_{2}[/tex]

And, potassium nitrate is simply [tex]KNO_{3}[/tex]

So, The symbol equation is as follows:

[tex]Pb(NO_{3})_{2}[/tex] + KI ----->  [tex]PbI_{2}[/tex] + [tex]KNO_{3}[/tex]

Now, increase the number of nitrate ions on the right hand side of the equation as:

[tex]Pb(NO_{3})_{2}[/tex] + KI ----->  [tex]PbI_{2}[/tex] + 2 [tex]KNO_{3}[/tex]

Now, balance the potassium ions on each side of the equation as:

[tex]Pb(NO_{3})_{2}[/tex] + 2KI ----->  [tex]PbI_{2}[/tex] + 2 [tex]KNO_{3}[/tex]

Hence, the balanced equation is ;

[tex]Pb(NO_{3})_{2}[/tex] + 2KI ----->  [tex]PbI_{2}[/tex] + 2 [tex]KNO_{3}[/tex]

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Propane is burned in a 1.350-kg bomb calorimeter with a specific heat of 5.82 J/g.°C. For a temperature rise of 2.87 °C, the energy released is 22.5 kJ.

It is a device that can measure heats of combustion, used in various applications such as calculating the calorific value of foods and fuels.

A sample of propane is burned in a bomb calorimeter with a mass (m) of 1.350 kg and a specific heat (c) of 5.82 J/g.°C. All the energy released by the propane is absorbed by the bomb calorimeter.

If the temperature rises by 2.87 °C (ΔT), we can calculate the energy released (Q) using the following expression.

Q = c × m × ΔT = 5.82 J/g.°C × 1,350 g × 2.87 °C × (1 kJ/1000 J)

Q =  22.5 kJ

Propane is burned in a 1.350-kg bomb calorimeter with a specific heat of 5.82 J/g.°C. For a temperature rise of 2.87 °C, the energy released is 22.5 kJ.

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Answer:

22.5 kj

Explanation:

The final concentrations of water, isopentyl acetate, isopentyl alcohol, and acetic acid obtained on using equilibrium expression are 3.4M, 3.4M, 0.6M , 4.6M

Using ICE table:-

      Acetic acid  +  Isopentyl alcohol   ------>    Isopentyl acetate +  water

I         8M                   4M                                           0                           0

C        8-x                   4-x                                          +x                          +x                      

E        8-x                   4-x                                          +x                          +x

Equilibrium constant (Keq) = 4.2

On using the equilibrium expression -

Keq = [Product] / [Reactant]

Keq = x^2 / (8-x) (4-x )

4.2  =  x^2 / 32 - 8x - 4x + x^2

    x =  3.4

Concentration of acetic acid  = 8-x = 8-3.4 = 4.6M

Concentration of isopentyl alcohol = 4-x = 4-3.4 = 0.6M

Concentration of isopentyl acetate = x = 3.4M

Concentration of water = x = 3.4M

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It is possible for two other resonance structures to be connected but results in positive formal charge which isn't suited for a very electronegative atom such as chlorine.

This is a type of diagram which depicts the bonding between atoms and lone pairs which are present in the molecule.

Adding two other resonance structures will also result in the poor overlap between the p-orbitals.

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