Since this traffic flow has a jam density of 122 veh/km, the maximum flow is equal to 3,599 veh/hr.
Given the following data:
Density = 61 veh/km.Speed = 59 km/hr.Jam density = 122 veh/km.How to calculate the maximum flow.According to Greenshield Model, maximum flow is given by this formula:
[tex]q_{max}=\frac{V_f \times K_i}{4}[/tex]
Where:
[tex]V_f[/tex] is the free flow speed.[tex]K_i[/tex] is the Jam density.In order to calculate the free flow speed, we would use this formula:
[tex]V_f =2 V\\\\V_f =2\times 59\\\\V_f=118\;km/hr[/tex]
Substituting the parameters into the model, we have:
[tex]q_{max}=\frac{118 \times 122}{4}\\\\q_{max}=\frac{14396}{4}[/tex]
Max flow = 3,599 veh/hr.
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A glass of water with a mass of 0.45kg at 20∘C is to be cooled to 0∘C by dropping ice cubes at 0∘C into it. The latent heat of fusion of ice is 334kJ/kg, and the specific heat of water is 4.18kJ/kg⋅∘C. The amount of ice that needs to be added is.
By using the concept of heat transfer, we need to add 0.045kg or 45g of ice to the glass of water to cool it from 20∘C to 0∘C.
The heat lost by the water is equal to the heat gained by the ice cubes. We can use the following equation to calculate the heat transfer:
Q = m_w * c_w * ΔT + m_i * L_f
where Q is the heat transfer, m_w is the mass of water, c_w is the specific heat of water, ΔT is the temperature change (20-0 = 20∘C), m_i is the mass of ice, and L_f is the latent heat of fusion of ice.
We know the values of m_w (0.45kg), c_w (4.18kJ/kg⋅∘C), ΔT (20∘C), and L_f (334kJ/kg). We can rearrange the equation to solve for m_i:
m_i = (Q - m_w * c_w * ΔT) / L_f
Substituting the values, we get:
m_i = [(0.45kg) * (4.18kJ/kg⋅∘C) * (20∘C) - 0] / (334kJ/kg
m_i = 0.045kg
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Additional scals apply to the
of the Class I locations,
O a anterior and posterior sections
O b. distal and medial boundaries
O c conduit entrances
O d. horizontal as well as vertical boundaries
Joe maylan an employee of acme company has been sent to do some work in the highland company's main lobby. This job will take two days. Which type of pass should joe be given?
The type of Pass that Joe Maylan should be given is called; Temporary Pass
What is temporary pass?In factories or industries, there are different types of pass given to workers and visitors visit such places on a daily basis. In this case Joe maylan is going to do a job in the company for just 2 days and as such the type of pass he willl get will be a temporary pass.
It will be a temporary pass because it is a document pass issued for short-term use or due to an emergency.
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does advanced auto parts install engine air filter
Answer:
You have to do it yourself.
Explanation:
When are we going to abandon internal combustion engines?
Answer:
2035
Explanation:
Most car and truck companies say that they will completely get rid of internal combustion engines by 2035.
In python
Write an expression that executes the loop body as long as the user enters a non-negative number.
Note: If the submitted code has an infinite loop, the system will stop running the code after a few seconds and report "Program end never reached." The system doesn't print the test case that caused the reported message.
Sample outputs with inputs: 9 5 2 -1
Body
Body
Body
Done.
Answer:
inputed = input("Choose some numbers, each separated with a space: ")
chosen = list(inputed)
chosen = chosen.remove(' ')
for value in chosen:
if '-' not in value:
print(Body)
else:
print(Done)
break
Explanation:
The for loop will go through every value in the list (your numbers) and check if it is positive or negative.
You may not operate a vehicle unless all child passengers __________ are securely fastened into an approved child restraint device.
Answer:
You may not operate a vehicle unless all child passengers under the age of 16 years are either wearing a safety belt assembly or are securely fastened into an approved child restraint device.
Explanation:
A nuclear ________ reactor heats a liquid to an extremely high temperature in order to power a nuclear rocket. (7 letters)
Answer:
Thermal
Explanation:
There are seven letters in the word "thermal". High temperature would indicate the liquid needs to be at a high heat. Thermal means "heat". Therefore, the answer should be thermal.
Here's what the answer should be: A nuclear thermal reactor heats a liquid to an extremely high temperature in order to power a nuclear rocket.
I hope this helps!
-No one
About what thickness of aluminum is needed to stop a beam of (a) 2.5-MeV electrons, (b) 2.5-MeV protons, and (c) 10-MeV alpha particles?
The thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.
Thickness of the aluminum
The thickness of the aluminum can be determined using from distance of closest approach of the particle.
[tex]K.E = \frac{2KZe^2}{r}[/tex]
where;
Z is the atomic number of aluminium = 13e is charge r is distance of closest approach = thickness of aluminiumk is Coulomb's constant = 9 x 10⁹ Nm²/C²For 2.5 MeV electrons[tex]r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (1.6\times 10^{-19})^2}{2.5 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m[/tex]
For 2.5 MeV protonsSince the magnitude of charge of electron and proton is the same, at equal kinetic energy, the thickness will be same. r = 1.5 x 10⁻¹⁴ m.
For 10 MeV alpha-particlesCharge of alpah particle = 2e
[tex]r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (2 \times 1.6\times 10^{-19})^2}{10 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m[/tex]
Thus, the thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.
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A platinum resistance temperature detector has a resistance of 100.00 V at 0°C, 138.50 V at 100°C and 175.83 V at 200°C. What will be the nonlinearity error in °C at 100°C if the detector is assumed to have a linear relationship between 0 and 200°C?
Answer:
about 1.54 °C
Explanation:
The error will be the difference between the temperature interpreted from the resistance value and the actual temperature. The linear equation used to translate the resistance reading to temperature will be ...
T = (200 -0)/(175.83 -100.00)(R -100.00)
T ≈ 2.637479(R -100)
At the temperature of 100°C, the resistance value of 138.50 will be interpreted to be a temperature of ...
T = 2.637479(138.50 -100) ≈ 101.543°C
This represents an error of 1.543°C relative to the actual temperature.
Are there more pressing issues that we should be focusing on?(i.e. inflation and gas prices?)
Answer:
gas
Explanation:
As we speak gas is to high and is making it unconfortable for people to live normaly.
A conductive loop on the x-y plane is bounded by rho = 2.0 cm, rho = 6.0 cm, φ = 0º and φ = 90º. 2.0 a of current flows in the loop, going in the aφ direction on the rho = 2.0 cm arm. determine h at the origin
select one:
a. 8.4 az (a/m)
b. 4.2 ay (a/m)
c. 8.4 ax (a/m)
d. 4.2 az (a/m)
Answer:
b. 4.2 az (A/m)
Explanation:
b is the answer
A strain gauge is used to measure the strain on a vibrating beam which can vibrate up to a maximum frequency of 60 Hz. The strain gauge analog signal is converted in to a digital signal via an Analog to Digital Converter (ADC) in order to store the data on a computer hard drive. The engineer responsible for this measurement mistakenly selects a sampling frequency of 90 Hz for the ADC. (a) Determine the alias frequency due to the small sampling frequency. (b) Propose a sampling frequency that will not result into aliasing of the analog signal (make sure to provide your rationale for selecting this frequency)
The aliased frequency that is due to small sampling frequency is 675 Hz.
The proposed sampling frequency is 2f = 120
How to solve for the aliased frequencyThe signal frequency that is given in the question is 60Hz
The sampling frequency is 90Hz
a. Using Nyquist frequency,
fn = 0.5*90Hz = 45Hz
The aliased frequency = |n*fn - fs|
aliased frequency = |n*fn - fs|
We have n >= 1/Fs = 17ms
Then the aliased frequency is = 17 x 45 - 90
= 675 Hz
b) The Nyquist sampling theoremIn order to avoid aliasing the sampling frequency, this has to be at least two times the highest frequency.
Therefore Fs =
2xF = 120Hz
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What is the definition of gross axle weight rating?.
A square aluminum plate 5 mm thick and 150 mm on a side is heated while vertically suspended in quiescent air at 75°c. determine the average heat transfer coefficient for the plate when its temperature is 15°c by two methods: using results from the similarity solution to the boundary layer equations, and using results from an empirical correlation.
By using the boundary layer equation, the average heat transfer coefficient for the plate is equal to 4.87 W/m²k.
Given the following data:
Surface temperature = 15°C
Bulk temperature = 75°C
Side length of plate = 150 mm to m = 0.15 meter.
How to calculate the average heat transfer coefficient.Since we have a quiescent room air and a uniform pole surface temperature, the film temperature is given by:
[tex]T_f=\frac{T_{s} + T_{\infty} }{2} \\\\T_f=\frac{15 + 75 }{2} \\\\T_f = 45[/tex]
Film temperature = 45°C to K = 273 + 45 = 318 K.
For the coefficient of thermal expansion, we have:
[tex]\beta =\frac{1}{T_f} \\\\\beta =\frac{1}{318}[/tex]
From table A-9, the properties of air at a pressure of 1 atm and temperature of 45°C are:
Kinematic viscosity, v = [tex]1.750 \times 10^{-5}[/tex] m²/s.Thermal conductivity, k = 0.02699 W/mk.Thermal diffusivity, α = [tex]2.416 \times 10^{-5}[/tex] m²/s.Prandtl number, Pr = 0.7241.Next, we would solve for the Rayleigh number to enable us determine the heat transfer coefficient by using the boundary layer equations:
[tex]R_{aL}=\frac{g\beta \Delta T l^3}{v\alpha } \\\\R_{aL}=\frac{9.8 \;\times \;\frac{1}{318} \;\times \;(75-15) \;\times \;0.15^3 }{1.750 \times 10^{-5}\; \times \;2.416 \times 10^{-5} } \\\\R_{aL}=\frac{9.8\; \times 0.00315 \;\times \;60\; \times\; 0.003375 }{4.228 \times 10^{-10} }\\\\R_{aL}=1.48 \times 10^{7}[/tex]
Also take note, g(Pr) is given by this equation:
[tex]g(P_r)=\frac{0.75P_r}{[0.609 \;+\;1.221\sqrt{P_r}\; +\;1.238P_r]^\frac{1}{4} } \\\\g(P_r)=\frac{0.75(0.7241)}{[0.609 \;+\;1.221\sqrt{0.7241}\; +\;1.238(0.7241)]^\frac{1}{4} }\\\\g(P_r)=\frac{0.543075}{[0.609 \;+\;1.221\sqrt{0.7241}\; +\;1.238(0.7241)]^\frac{1}{4} }\\\\g(P_r)=\frac{0.543075}{[2.5444]^\frac{1}{4} }\\\\g(P_r)=\frac{0.543075}{1.2630 }[/tex]
g(Pr) = 0.430
For GrL, we have:
[tex]G_{rL}=\frac{R_{aL}}{P_r} \\\\G_{rL}=\frac{1.48 \times 10^7}{0.7241} \\\\G_{rL}=1.99 \times 10^7[/tex]
Since the Rayleigh number is less than 10⁹, the flow is laminar and the condition is given by:
[tex]N_{uL}=\frac{h_{L}L}{k} = \frac{4}{3} (\frac{G_{rL}}{4} )^\frac{1}{4} g(P_r)\\\\h_{L}=\frac{0.02699}{0.15} \times [\frac{4}{3} \times (\frac{1.99 \times 10^7}{4} )^\frac{1}{4} ]\times 0.430\\\\h_{L}= 0.1799 \times 62.9705 \times 0.430\\\\h_{L}=4.87\;W/m^2k[/tex]
Based on empirical correlation method, the average heat transfer coefficient for the plate is given by this equation:
[tex]N_{uL}=\frac{h_{L}L}{k} =0.68 + \frac{0.670 R_{aL}^\frac{1}{4}}{[1+(\frac{0.492}{P_r})^\frac{9}{16}]^\frac{4}{19} } \\\\h_{L}=\frac{0.02699}{0.15} \times ( 0.68 + \frac{0.670 (1.48 \times 10^7)^\frac{1}{4}}{[1+(\frac{0.492}{0.7241})^\frac{9}{16}]^\frac{4}{19} })\\\\h_{L}=4.87\;W/m^2k[/tex]
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What's the difference between a scale and a scale drawing?
scale is used to make a scale drawing. every scale drawing has it's sclae written for proper interpreatation
What is a scale?
A Scale is the ratio of a sketched model and the actual measuremnts while a scale drawing is a sketched model that was carefully made such that every measurement in the sketch could be represented to the site or actual mearuement through the scale with very little or no error
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To make a scale drawing, scale is used. For correct interpretation, every scale drawing has its own scale inscribed on it.
What exactly is a scale?A scale drawing is a sketched model that has been meticulously prepared so that every measurement in the sketch may be conveyed to the site or actual measurement through the scale with very little or no mistake.
A weighing apparatus or equipment with two pans of equal weight hung from its ends —usually used in the plural, either pan or tray of a balance scale.
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What should you do if you encounter a fishing boat while out in your vessel?.
Answer:
if you encounter fishing or hunting boats while you are paddling, be courteous.
Give them a wide berth.
Never run overfishing lines. Be aware that anglers may have lines out to the sides of their boat or trolling behind them.
Explanation:
How frequently should vehicle registration be renewed?
Answer:
When the renewal period comes around (with respect to the license expiry date).
Explanation:
b) Consider a large plane wall of thickness L = 0.4 m, thermal conductivity k = 1.8 W/m·K, and surface area A = 30 m2. The left side of the wall is maintained at a constant temperature of T1 = 90°C while the right side loses heat by convection to the surrounding air at
Answer:
A is correct
Explanation:
I took the test
Which organization would provide business and leadership training to a high school hospitality student?
Answer:
Future Business Leaders of America
Explanation:
What was the role of the rotors in the enigma machine?.
Answer:
Implements a reordering of the letters of the alphabet.
Explanation: GIVE ME 5 STARS AND a HEART!!! Those contacts are wired across the rotor so that each contact on the left connects to the contact on the right in some scrambled arrangement. Each rotor, therefore, implements a reordering of the letters of the alphabet, which mathematicians call a permutation.
Explain how the ideal vapour compression refrigerator cycle is an improvement upon the Carnot cycle. Use any two of the problems to explain.
what would be the output signal
of two input binary signal given
by A - 100101 and B = 110110
are applied to:
a) OR-gate
b) NAND-gate and XOR gate
U lungul 200 m. If A = 100101 and B = 110110 are applied to X-NOR gate, then the output will be :- plo (1) 101100 (2)011011 (31110111 (4) 010011 As shown in ..
List three examples of waves that can transfer energy without going through a medium
Electromagnetic waves can transfer energy without a material medium.
3 examples of elctromagnetic energy include: Radio wave, X-rays and gamma rays
What is wave?A wave is a disturbance that transfers energy from one point to another.
Electromagnetic waves are waves that does not require a material medium for the tranfer of energy
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It was a mistake that i put in under 13 of age can you put it for 27
Answer:
ill try to help you :)
Explanation:
state 5 general rules for cleat wiring
Which of the following statements about resistance is TRUE?
Resistance resists or opposes the amount of protons flowing through voltage.
Resistance allows the amount of neutrons flowing through a circuit.
Resistance resists or opposes the amount of neutrons and protons flowing through a circuit.
Resistance resists or opposes the amount of electrons flowing through a circuit.
Answer:
I think it's the no 3rd
Explanation:
hope this helps
How can we love our country? Not by words but by deeds. - Jose P. Laurel
A person can love their country by deed through the act of helping people and by volunteering in the cleaning out community.
What is this Jose P. Laurel quote about?Jose P. Laurel is known to be a man who emphasis that the love that one has for his or her country is not shown only by words but also by deed
He believe that it is not an occasional virtue people often display. He stated that people need to have unflinching determination to serve their country.
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The steel bracket is used to connect the ends of two cables. if the allowable normal stress for the steel is sallow = 30 ksi, determine the largest tensile force p that can be applied to the cables. assume the bracket is a rod having a diameter of 1.5 in.
The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb
The static equilibrium is given as:
F = P (Normal force)
Formula for moment at section
M = P(4 + 1.5/2)
= 4.75p
Solve for the cross sectional area
Area = [tex]\frac{\pi d^{2} }{4}[/tex]
d = 1.5
[tex]\frac{\pi *1.5^{2} }{4}[/tex]
= 1.767 inches²
Solve for inertia
[tex]\frac{\pi *0.75^4}{4}[/tex]
= 0.2485inches⁴
Solve for the tensile force from here
[tex]\frac{F}{A} +\frac{Mc}{I}[/tex]
30x10³ = [tex]\frac{P}{1.767} +\frac{4.75p*0.75}{0.2485} \\\\[/tex]
30000 = 14.902 p
divide through by 14.902
2013.15 = P
The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb
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Consider a homogeneous spherical piece of radioactive material of radius ro = 0.04 m that is generating heat at a constant rate of ėgen = 5 x 107 w/m3 . the heat generated is dissipated to the environment steadily. the outer surface of the sphere is maintained at a uniform temperature of 110°c and the thermal conductivity of the sphere is k = 15 w/m·k. assuming steady one-dimensional heat transfer, (a) express the differential equation and the boundary conditions for heat conduction through the sphere, (b) obtain a relation for the variation of temperature in the sphere by solving the differential equation, and (c) determine the temperature at the center of the sphere.
Answer:
Please report my answer
Explanation:
I want my account deleted