A student scores in a history class are listed 45 52 65 68 68 70 77 78 78 81 85 96 100 which of the following histogram correctly represent the data

If the quantity of big macs demanded falls from 2.0 million to 1.6 million as the price of whoppers falls from $1.40 to $.80, the cross-price elasticity of demand for big macs is 0.4.

Cross-price elasticity quantifies how responsive a product's demand is to changes in a related product price. Some products on the market frequently have connections to one another.

This could imply that the demand for a product can be favourably or negatively impacted by a product's price change. The cross elasticity of demand, also known as the cross-price elasticity of demand, in economics quantifies the relationship between the percentage change in the quantity of a commodity sought and the percentage change in the price of another good, ceteris paribus. The cost of milk is one such example. People might switch to 2% milk if full milk prices rise. Similar to how whole milk gets more popular as 2% milk prices go up.

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Answer:

13

Step-by-step explanation:

first multiply then divide and subtract

The trigonometry ratios have their values to be

The complete question is added as an attachment

From the question, we have the following parameters that can be used in our computation:

Hypotenuse = 10

Adjacent = 5

Opposite = 5√3

Using the above as a guide, we have the following:

sin(x) = Opposite/Hypotenuse

cos(x) = Adjacent/Hypotenuse

tan(x) = Opposite/Adjacent

Using the above as a guide, we have the following:

sin(x) = 5√3/10 = √3/2

cos(x) = 5/10 = 0.5

tan(x) = 5√3/5 = √3

The above are the values of the trigonometry ratios based on the attached figure

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The average distance from the mean is 0.09.

The mean is also known as the average and is calculated by adding up all the values in the set and then dividing the sum by the total number of values.

So, for the given set of data: 24.49, 24.68, 24.77, 24.83, 24.73, the mean would be calculated as follows:

Mean = (24.49 + 24.68 + 24.77 + 24.83 + 24.73) / 5

= 24.70

It tells us what the typical value is within the data set. In this case, the mean value of the data set is 24.70.

Next, let's find the median of the set of data. The median is the middle value of a data set when it is arranged in numerical order. In this case, the data set is already arranged in numerical order, so we can easily find the median.

The median value of the data set is the middle value, which is 24.77.

Now, we will calculate the deviation from the mean for each data point within the set. The deviation from the mean tells us how far each value is from the mean value. This is calculated by subtracting the mean from each value in the set.

Deviation from the mean for each data point:

-0.21, -0.02, 0.07, 0.13, 0.03

As you can see, some values are above the mean, and some are below the mean. The deviation from the mean can be used to determine how spread out the data is from the mean value.

Finally, we will calculate the mean deviation for the set. The mean deviation is the average of the absolute values of the deviation from the mean.

Mean deviation = (|(-0.21)| + |(-0.02)| + |0.07| + |0.13| + |0.03|) / 5

= 0.09

The mean deviation tells us the average distance from the mean value.

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Answer:

P(t) = 30t + 4820

In 2009, the moose population will be 5,330 according to the model.

Step-by-step explanation:

4970 - 4820 = 150

150 / 5 = 30

P(t) = 30t + 4820

30 x 17 = 510

510 + 4820 = 5330

For a number 345,600 which is expressed as 2ᵃ × 3ᵇ × 5ᶜ, ae integers a, b and c. Then the value of the product abc is equals to the 54.

We have, a number 345,600, which can be expressed as 2ᵃ × 3ᵇ × 5ᶜ. That is it can be written as 345,600 = 2ᵃ × 3ᵇ × 5ᶜ, which is prime factorazation of number. To determine the value of a , b , c, we have to do prime factorization of number 345,600. Prime factorzation of a number contains all prime factors of a number. So,

345600 = 3456×100 = 576× 6 × 100

= 24² × 2×3 × 10² = ( 2×2×2×3)² × 2× 3×(2× 5)²

= 2⁶ × 3² × 2× 3×2²× 5²

345,600 = 2⁹ × 3³ × 5²

but 345,600 = 2ᵃ × 3ᵇ × 5ᶜ,

=> 2ᵃ × 3ᵇ × 5ᶜ = 2⁹ × 3³ × 5²

On comparing the powers of 2, 3, and 5 in above equation, we get a = 9 , b = 3 , c = 2.

Therefore, the value of product of a, b, and c

= abc = 9×3×2 = 54

Hence, the value of product is 54.

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Complete question:

The number 345,600 can be expressed as 2ᵃ × 3ᵇ × 5ᶜ for integers a, b and c. What is the value of the product abc?

Answer:

CrabSVR

BRscrV

ScarbRV

VRbScCr

Step-by-step explanation:

I can suggest that some of these words might be memorable because they are short and have a combination of consonants and vowels that make them sound unique and catchy. For example, "ScrubVR" has a rhythmic and playful sound to it, while "BRscrV" has a more abbreviated and tech-like feel to it. Ultimately, what makes a word memorable is highly subjective and varies from person to person.

Answer: he right

Step-by-step explanation:

Answer: 85 miles left

Step-by-step explanation:

65 miles x 7 hours = 455 miles

540 miles - 455 miles = 85 miles

Answer:

45

Step-by-step explanation:

Y = forty percent of blank to make 18

18 = 40/100 x Y

Y = 18 x 100/40

Y = 18 x 100 divided by 40

Y = 45

The result of the function is h = 1 is equal to -2

Linear equations are equations that has a leading degree of 1.

Given the linear equation f(h) = h - 3

We need to determine the resulting value when h is equal to 1

f(1) = 1 - 3

f(1) = -2

Hence the value of the function given if the value of h is 1 is -2

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The right answer, based on the provided assertion, is (C) R(x) = 2.6³ˣ⁻⁸.

Mathematical expressions consist of at least two integers or factors, a minimum of one math procedure, and a sentence. It's possible to multiply, divide, add, or remove with this mathematical procedure. An expression's form is as follows: Expression: (Math Operator, Number/Variable, Math Operator)

To find the ratio of the population of the second germ to the population of the first germ, we can divide the function for the population of the second germ by the function for the population of the first germ. That is:

R(x) = B(x) / A(x)

Plugging in the given functions, we get:

R(x) = (x+1) / (1.3)ˣ⁺⁹

To simplify this expression, we can use the properties of exponents and rewrite it as:

R(x) = 2.6ˣ⁻⁸

Therefore, the function that best represents the ratio of the population of the second germ to the population of the first germ is R(x) = 2.6ˣ⁻⁸

So, the correct option is (C) R(x) = (2.6)³ˣ⁻⁸.

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Answer:

The roots are -2 and 4

Step-by-step explanation:

Using the graph, we can estimate the roots of the equation by seeing where it crosses the x axis.

It appears to cross the x axis at -2 and 4.

The roots are -2 and 4

The sailboat mast casts a shadow 45 meters long and a nearby marble column that is 8 meters tall casts a shadow 15 meters long, then the height of the sailboat mast is 24 meters.

We can use proportions to solve this problem. Let's let h be the height of the sailboat mast, then we have:

h/45 = 8/15

Cross-multiplying, we get:

15h = 8 * 45

Simplifying, we get:

15h = 360

Dividing by 15, we get:

h = 24

Therefore, the height of the sailboat mast is 24 meters. This means that the sailboat mast is 3 times as tall as the marble column, since its shadow is 3 times as long.

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For a particle in a 2D box with impenetrable walls, the time-independent Schrödinger equation can be simplified to equation 3, which is a separable differential equation.

Using the Separation of Variables approach, the 2D wavefunction can be expressed as the product of two independent 1D components, given by equation 4.

The resulting differential equations in equations 5 and 6 have the same form as those found for the particle in a 1D box and their solutions are given by equations 8 and 9. The total energy of the particle is given by equation 7.

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The answer for the angle cos (5π/3) is 1/2.

We know that in the polar coordinate system,

x = r cosθ ;  y = r sinθ

Since, we are approximating using a unit circle, therefore, r = 1

As we can see in the graph of unit circle, we take the angle in radians anti-clockwise as 5π/3.

As we want the value of cos(5π/3), we look for the x coordinate.

We get this from the end point of the angle that we have drawn on the unit circle in anti-clockwise motion.

The x co-ordinate is 1/2, hence we get the value of cos(5π/3) as 1/2.

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(a) The equation of the secant line connecting (1, f(1)) and (0.9, f(0.9)) is y = -x + 2.1.

(b) The slope of the tangent line to f at x is f'(x) = -cos(x), and the equation of the tangent line at (x, f(x)) is y = -cos(x)*x + sin(x) + cos(x)*x.

In contrast to the tangent line, which meets a curve just once and has the same slope as the curve at that point, the secant line is a straight line that connects two locations on a curve. In this task, we are required to determine the equations of the secant and tangent lines at various places given a function f(x).

Using the two provided locations, we determine the slope of the secant line in section (a), which is equal to the difference between the y- and x-coordinates. The equation of the line is therefore written using the point-slope form, and it is y = -x + 2.1.

In part (b), we use the definition of the derivative to find the slope of the tangent line at a given point x. We then use the point-slope form of a line to write the equation of the tangent line, which has the same slope as the derivative and passes through the point (x, f(x)). In this case, the slope of the tangent line is -cos(x), and the equation of the tangent line is

y = -cos(x)*x + sin(x) + cos(x)*x.

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Answer: Your welcome!

Step-by-step explanation:

O 1.7278

El porcentaje de error del 16.1% se refiere a la raíz de la ecuación f(x) = x - (√5x - e^x), comenzando en xo = 0.5. Utilizando el método de iteración del punto fijo, se obtiene que la raíz de esta ecuación es 1.7278.

Answer:

Step-by-step explanation:

Para encontrar la raíz de la ecuación f(x) = x - (√(5x) - e^x) con un porcentaje de error del 16.1%, podemos utilizar el método de iteración de punto fijo con la siguiente fórmula:

x1 = f(x0) + x0

Donde x0 es el valor inicial, f(x) es la función y x1 es el siguiente valor de la raíz aproximada.

Primero, evaluamos la función en x0 = 0.5:

f(0.5) = 0.5 - (√(5*0.5) - e^0.5) = -0.2749

Luego, usamos la fórmula para encontrar el siguiente valor:

x1 = f(0.5) + 0.5 = 0.2251

Continuamos iterando hasta que el porcentaje de error sea menor o igual al 16.1%. Podemos calcular el porcentaje de error relativo por iteración con la siguiente fórmula:

Error relativo (%) = |(x_nuevo - x_viejo) / x_nuevo| * 100%

donde x_nuevo es el valor actual de la raíz aproximada y x_viejo es el valor anterior de la raíz aproximada.

Después de algunas iteraciones, encontramos que la respuesta que tiene un porcentaje de error del 16.1% es 1.7351.

We need a sample size of at least 397 in order to be 95% confident that the sample mean is within 20 minutes of the true mean.

To calculate the sample size needed, we need to use the formula:

n = (zα/2σ/E)2

where zα/2 is the critical value associated with the desired confidence level (in this case 95%), σ is the standard deviation (3.2 hours in this case), and E is the margin of error (20 minutes in this case).

Thus, n = (1.96*3.2/20)2, which simplifies to 397.

E = 20

σ = 3.2

n = (1.96*3.2/20)2

Therefore, we need a sample size of at least 397 in order to be 95% confident that the sample mean is within 20 minutes of the true mean.

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Answer: She saved 90 dollars.

To solve this we must find amount of 600 that makes 15 percent.

15 % of 600 is 90. This means that Jennifer saved up 90 dollars

I hope that this helps & Good Luck <3 !!!

Answer: Your welcome!

Step-by-step explanation:

Your minimum payment would be $135 ($4500 x 0.03 = $135).

Your interest for 1 month would be $99 ($4500 x 0.22 = $990 x 0.1 = $99).

Your new balance would be $4634 ($4500 + $99 - $135 = $4664).

In this example, process A completed its final quantum in q4, process B completed its final quantum in q4, and process C completed its final quantum in q4.

To determine which queue each process is in when it begins its final quantum, we need to know the length of time each process has been running and how many times it has already used each queue's quantum. Without that information, we cannot determine which queue a process will be in at a specific point in time. However, we can provide an example of how a process might move between the queues over time.

Let's consider the following three processes:

Process A - CPU burst time = 100s

Process B - CPU burst time = 30s

Process C - CPU burst time = 50s

Assume that all three processes arrive at the scheduler at the same time and are added to q1, the highest priority queue.

When the scheduler begins, it will select the first process in q1, which is process A. Since q1 has a quantum of 5s, process A will run for 5s before it is preempted and placed at the back of q2.

The next process in q1 is B. B will also run for 5s before being preempted and placed at the back of q2.

Next, the scheduler will select process C from q1. C will run for 5s before being preempted and placed at the back of q2.

Now the scheduler has completed one round-robin cycle through q1, and all the processes in q1 have used up their q1 quantum. The scheduler will move on to q2 and select the first process in that queue, which is process A. Since q2 has a quantum of 10s, process A will run for an additional 5s before being preempted and placed at the back of q3.

The next process in q2 is B. B will run for 10s before being preempted and placed at the back of q3.

Next, the scheduler will select process C from q2. C will run for 10s before being preempted and placed at the back of q3.

Now the scheduler has completed one round-robin cycle through q2, and all the processes in q2 have used up their q2 quantum. The scheduler will move on to q3 and select the first process in that queue, which is process A. Since q3 has a quantum of 20s, process A will run for an additional 10s before being preempted and placed at the back of q4.

The next process in q3 is B. B will run for 20s before being preempted and placed at the back of q4.

Next, the scheduler will select process C from q3. C will run for 20s before being preempted and placed at the back of q4.

Now the scheduler has completed one round-robin cycle through q3, and all the processes in q3 have used up their q3 quantum. The scheduler will move on to q4 and select the first process in that queue, which is process A. Since q4 has a quantum of 40s, process A will run for an additional 20s before completing its CPU burst.

The next process in q4 is B. B will run for 30s before completing its CPU burst.

Finally, the scheduler will select process C from q4. C will run for 40s before completing its CPU burst.

However, it's important to note that the exact behavior of the scheduler will depend on the length of time each process has been running and how many times it has already used each queue's.

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The residual sum of squared values is reduced using the least-squares method. The predicted weight of luggage for a flight with 57 passengers is 1511  Pounds.

What is meant by least-squares method?

The least-squares method is a statistical technique used to find the best fit line for a set of data points. It works by minimizing the sum of the squared differences between the observed values of a dependent variable and the values predicted by a linear function of one or more independent variables.

In other words, the least-squares method finds the line that best represents the relationship between two or more variables, such that the sum of the squared errors (the difference between the observed values and the predicted values) is minimized. The resulting line is known as the regression line or best-fit line, and it can be used to make predictions about future values of the dependent variable based on the values of the independent variable.

Based on the given least squares regression equation, we have:

To predict the weight of luggage for a flight with 57 passengers, we simply substitute x = 57 into the regression equation:

y = 200 + 23x

= 200 + 23(57)

= 200 + 1311

= 1511

Therefore, the predicted weight of luggage for a flight with 57 passengers is 1511 pound.

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The cost of the DVD player and the cost of the television will be $298 and $894, respectively.

An answer to a formula is any variable value that fulfills the equal outcomes, that is, it tends to make the Left Hand Side (LHS) and Right Hand Side (RHS) of the formula equal. To solve an equation, you must locate the feasible solution) to that formula.

A television and DVD player cost a total of $1192. The cost of the television is three times the cost of the DVD player.

Let 'x' be the cost of the DVD player and 'y' be the cost of the television. Then the equations are given as,

x + y = 1,192            ...1

y = 3x                     ...2

From equations 1 and 2, then we have

x + 3x = 1192

4x = 1192

x = $298

Then the value of 'y' is given as,

y = 3 (298)

y = $894

The cost of the DVD player and the cost of the television will be $298 and $894, respectively.

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The kinetic energy of a 1500 kg pick-up truck traveling at 31.0 m/sec will be 720 kJ.

If the body of the mass (m) is moving with a velocity (v), then the body possesses the energy which is known as kinetic energy. The SI unit of the kinetic energy is Joule. Then the formula is given as,

KE = 1/2 x mv²

The kinetic energy of a 1500 kg pick-up truck traveling at 31.0 m/sec is given as,

KE = 1/2 x 1500 x 31²

KE = 720,750 Joule

KE = 720 kJ

The kinetic energy of a 1500 kg pick-up truck traveling at 31.0 m/sec will be 720 kJ.

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The work required to pump the water which weighs 62.5 lb/ft3 out of the spout is 15000 foot-pounds.

To find the work required to pump the water out of the spout, we need to calculate the weight of the water in the tank and then multiply by the height of the spout to find the potential energy of the water.

First, we need to find the volume of the tank, which is given by:

V = a * b * c = 4 ft * 5 ft * 6 ft = 120 ft^3

Next, we can find the weight of the water in the tank, using the fact that water weighs 62.5 lb/ft^3:

W = V * ρ = 120 ft^3 * 62.5 lb/ft^3 = 7500 lb

So the weight of the water in the tank is 7500 pounds.

Now, we can find the potential energy of the water by multiplying the weight by the height of the spout. Let's assume the spout is 2 feet above the top of the tank:

PE = W * h = 7500 lb * 2 ft = 15000 ft-lb

So the work required to pump the water out of the spout is 15000 foot-pounds (ft-lb). This means that if we used a pump that was 100% efficient, it would require 15000 ft-lb of work to pump all the water out of the tank. However, in reality, pumps are not 100% efficient, so the actual work required would be greater than 15000 ft-lb.

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After 22 years the amount in the account will be 12,386.

Simple interest is an interest amount calculated on the principal amount with certain interest rate.  It is given by the formula,

                                   [tex]S.I.=\frac{P*n*r}{100}[/tex]

Where P is the principal amount, n is the number of years, r is the rate of interest.

4,400 is placed in an account i.e., Principal amount, P=4400

With an annual interest rate, r=8.25%

Number of years, n=22 years.

Amount in the account after 12 years will be,

By using simple interest formula,

[tex]S.I.=\frac{P*n*r}{100}[/tex]

      = [tex]\frac{4400*8.25*22}{100}[/tex]

      =7,986

Interest amount = 7,896.

Total amount after 22 years= interest amount + principal amount

                                              = 7896+4400

                                              = 12,386.

Hence, after 22 years the amount in the account will be 12,386.

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Answer:

the correct answer is 44

Step-by-step explanation:

22/5 = 4.4

44/ 10 = 4.4

The area of the isosceles triangle is 96 ft²

The formula for area of a triangle is expressed as

Area = 1/2bh

Where , b is the base and h is the height

We have that;

Base = 16ft

Using the Pythagorean theorem, we have;

20² - 16² =h²

Find the squares

h = √144

h= 12ft

Substitute the values

Area = 1/2 × 12 × 16

Multiply the values

Area = 96 ft²

Hence, the value is 96 ft²

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