A skier (down a straight course) is able to enter the starting gate with a speed of 1 m/sec and the average acceleration down the hill was 3 m/s2. If
the skier covers the course in 10 sec, how fast was he moving at the bottom of the course?
O31 m
O 13 m/s
O-29 m/s
O 31 m/s

A Skier (down A Straight Course) Is Able To Enter The Starting Gate With A Speed Of 1 M/sec And The Average

Answers

Answer 1
He was moving at 31 m/s
Answer 2

If a skier (down a straight course) is able to enter the starting gate with a speed of 1 m/sec and the average acceleration down the hill was 3 m/s², then he was moving at  31 m / s at the bottom of the course.

What are the three equations of motion?

There are three equations of motion given by  Newton

v = u + at

S = ut + 1/2 × a × t²

v² - u² = 2 × a × s

As given in the problem, a skier (down a straight course) is able to enter the starting gate with a speed of 1 m/sec and the average acceleration down the hill was 3 m/s² .

By using the first equation of the motion,

v = u + at

v = 1 + 3 × 10

v = 31 m / s

Thus, he was moving at  31 m / s at the bottom of the course.

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Related Questions

The velocity of an object is it’s speed and __ of motion .

Answers

Answer:

direction should be the answer

velocity i’m pretty sure

What distance is required for a train to stop if its initial velocity is 23 m/s and its
deceleration is 0.25 m/s²? (Assume the train decelerates at a constant rate.)

Answers

-- The train starts at 23 m/s and slows down by 0.25 m/s every second.

So it'll take (23/0.25) = 92 seconds to stop.

-- Its average speed during that time will be (1/2)(23+0) = 11.5 m/s

-- Moving at an average speed of 11.5 m/s for 92 sec, the train will cover

(11.5 m/s) x (92 sec)  =  1,058 meters .

The distance required for the train to travel before stopping is 1,058 m.

The given parameters;

initial velocity of the train, u = 23 m/s

deceleration of the train, a = 0.25 m/s

The distance traveled by the train is calculated as follows;

[tex]v^2 = u^2 -2as[/tex]

where;

v is the final velocity of the train

The final velocity of the train is zero when the train stops

[tex]v^2 = u^2 -2as\\\\0 = 23^2 - 2(0.25)s\\\\0.5s = 529\\\\s = \frac{529}{0.5} \\\\s = 1,058 \ m[/tex]

Thus, the distance required for the train to travel before stopping is 1,058 m.

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Which sentence describes Newton's first law?
A. Forces always come in pairs that have the same magnitude.
B. The action force applied by one object to another is opposite in
direction to the reaction force.
C. It takes a larger net force to accelerate an object at a greater rate.
D. Unbalanced forces cause an object to move.
SM

Answers

[tex]\Large{\red{\bf{\blue{\dag} Answer:-}}}[/tex]

Newton's First Law of Motion :

An object stays in rest or in uniform motion unless and until compelled by an external unbalanced force . This is also known as " Law of Inertia " .

Here this statement is best represented by the statement : Unbalanced forces cause an object to move. [ option c ]

More to know :-

Newton's 3 laws of motion :-

Newton's First Law of Motion :-

It states that an object stays in rest or in uniform motion unless and until compelled by an external unbalanced force . This is also known as " Law of Inertia " .

Ex - (i) We tend to fall backwards while standing in the bus , when it starts suddenly.

(ii) We tend to fall forward while standing in the bus , when it stops suddenly.

Newton's Second Law of Motion :-

It states that the rate of change of momentum is directly proportional to the applied force in the direction of the force . That is ∆p [tex]\propto[/tex] Force .

Ex - (i) When we push car & a truck with same force the car will have Greater acceleration due to less mass . (Imaginary case ).

(ii) We feel easy to push a empty cart than a full cart .

Newton's Third Law of Motion :-

It states that every action has equal and opposite reaction .

Ex - (i) We are able to walk on ground due to Newton's third law of motion .

(ii) When we push wall it also applies equal and opposite force .

"Unbalanced forces cause an object to move " is the sentence that describes Newton's first law.

Describe Newton's first law.

   A body remains in the state of rest or uniform motion in a straight line unless and until an external force acts on it.

      The object is to be rest if the velocity and acceleration are zero.  When an object is in motion, velocity is not equal to zero (v ≠ 0) but acceleration (a = 0) is equal to zero. Therefore, the object will continue in motion with constant velocity in the same direction.

Example:

      If we jump from a bus while moving, our body will be like still moving in the same direction of the vehicle. When your feet hit the ground, the grounds act on your feet and stop moving. You will fall because the upper part of your body didn't stop and you will fall in the direction you were moving.

     If the object have the greater mass, then the object will have more inertia. Forces can change the object's motion.

Hence, Option D is the correct answer.

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Why is there no weather on the Moon?

Answers

Answer:

the moon has no atmosphere, and it cannot trap heat or insulate the surface.

Explanation:

the moon is too small. ... With weak gravity, gases that are emitted from the surface quickly are lost to outer space.

Which is the best estimate for the width of a typical adult hand?

Answers

Answer:

About 4-5in

Explanation:

5)
(64(6-2) =
A)
62
B)
8-9
C)
122

12-8

Answers

Answer:

B 8-9 because you had to subtract that number or simplify. then your answer is 8-9

Find the acceleration if the force is 10 N and the mass is 5 kg.

Answers

Explanation:

Hey there!

Given;

F = 10N

Mass = 5kg

Acceleration due to gravity (a)= 9.8m/s^2

We know that;

F = m*a

Put all values and solve for "m".

10 = m*9.8

Simplify it.

[tex]m = \frac{10}{9.8} [/tex]

Therefore, m= 1.0204kg.

Hope it helps...

Give reasons.
a. A stretched catapult has potential energy.
b A stone on ground has zero energy.
C. Rolling a drum is work against friction.
d. Lifting a stone is work against gravity.
e. Work and energy both have same unit.​

Answers

a. A stretched catapult can do work when released so it must have potential energy.

b. A stone on the ground will not move on its own ever again so it has zero energy.

c. In order to roll an object there must be a friction force between the object and the ground (otherwise it will slide)

d. To lift a stone you must overcome the weight which is the force due to gravity.

e. Work and energy are both measured in Joules.

You walk east for 30 m, then decide to walk north foranother 30 m. What is the angle of direction of your displacement?​

Answers

Answer:

Displacement is 42.426 m NE and the angle is opposite/adjacent or 30/30 which would equal 1 degree which doesn't seem right but hopefully its an answer.

Explanation:

What type of change is making water from H^2 and O^2 ?

A. chemical
B. physical

Answers

Answer: chemical

Explanation: To change from hydrogen to oxygen is a chemical change because if you change hydrogen to oxygen, it is still a chemical. The answer is chemical.

Answer:

chemical possibly

Explanation:

fact

How long would it take Jesse with an acceleration of -2.50 m/s2 to bring his bicycle with an initial velocity of 13.5 m/s to a complete stop?

Answers

Answer: 5.4 seconds

Explanation:

The time taken to stop the bicycle is 5.4 seconds. The final velocity is zero. Then, the distance travelled by the bicycle is 36.45 m.

What is acceleration ?

Acceleration is a physical quantity that, measures the rate of change in velocity. It is a vector quantity thus having both magnitude and direction. It can be defines as the ratio of change in velocity to the change in time.

Given initial velocity = 13.5 m/s

final velocity is zero since the bicycle is stopping.

then Δt = Δv/a

Δt = 13.5 m/s/ 2.50 m/s² = 5.4 seconds.

Hence, the bicycle will take 5.4 s to complete stop.

The distance covered within this time can be determined using the equation as follows:

s = ut + 1/2 at²

where u is the initial velocity

s =  (13 m/s × 5.4 s) + (-2.50 m/s² ×5.4 s ×5.4 s) = 36.4 m.

Therefore, the bicycle will travel up to 36.4 m before stopping.

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If an astronaut weighs 750 N on the ground, what will he weigh in earth orbit 400 km above the earth’s surface?
R_earth = 6.38 × 10^6 m,
m_earth=5.97×10^24 kg
G=6.674×10^−11 Nm^2/kg^2

Answers

Answer:

The weight of the astronaut in Earth's orbit 400 km above the Earth's surface is 664.115 N

Explanation:

The given parameters are;

The weight of the astronaut on the ground = 750 N

The height of the orbit above the Earths surface = 400 km

The radius of the Earth = 6.38 × 10⁶ m

The mass of the Earth = 5.97 × 10²⁴ kg

The universal gravitational constant G = 6.674 × 10⁻¹¹ Nm²/kg²

From Newton's law of universal gravitation, we have;

[tex]Weight \ on \ ground \ of \ astronaut \ F_W =G\times \dfrac{M_{Earth} \times m_{astronouat}}{R_{Earth}^{2}} = 750 \ N[/tex]

[tex]F_W =6.674 \times 10^{-11}\times \dfrac{5.97 \times 10^{24}\times m_{astronouat}}{(6.38 \times 10^6)^{2}} = 750 \ N[/tex]

[tex]m_{astronaut}[/tex] = ((6.38 × 10⁶)² × 750)/((6.674 × 10⁻¹¹) × (5.97 × 10²⁴)) ≈ 76.62 kg

The mass of the astronaut ≈ 76.62 kg

For the weight of the astronaut  in Earth orbit 400 km (400 × 10³ m) above the Earth's surface, we have;

[tex]F_{W \ in \ orbit} =6.674 \times 10^{-11}\times \dfrac{5.97 \times 10^{24}\times 76.62}{(6.38 \times 10^6 + 400 \times 10^3)^{2} } = 664.115 \ N[/tex]

The weight of the astronaut in Earth's orbit 400 km above the Earth's surface = 664.115 N.


A ship is travelling due east at
30 km/hr and boy runs across
the deck in a south east west
direction at 10 km/hr. Find the
veloocity of the boy relative to sea.​

Answers

Answer:

The relative velocity of the boy with respect to the sea is 37.7 km/hr

Explanation:

Answer:

37.7 km/hr I'd the velocity

Two fish swimming in a river have the following equations of motion:

X 1 = - 6.4 m + (- 1.2 m/s) t

X 2 = 1.3 m + (- 2.7 m/s) t

Which fish is moving faster? ​

Answers

Answer:

The second fish, X2, is moving faster than the first fish, X1

Explanation:

The given parameters for the equation of motion of the fishes are;

X1 = -6.4 m + (-1.2 m/s)×t

X2 = 1.3 m + (-2.7 m/s)×t

The given equation are straight line equations in the slope and intercept form, where the slope is the speed and in m/s and the intercept is the starting point of swimming of the fishes

For the first fish, the intercept = -6.4 m, the slope = the  speed = -1.2 m/s

For the second fish, the intercept = 1.3 m, the slope = the  speed = -2.7 m/s

Whereby the fishes are swimming in the opposite direction of the measurement of length, we have;

The magnitude of the speed of the second fish [tex]\left | -2.7 \ m/s \right | = 2.7 \ m/s[/tex], is larger than the magnitude of the speed of the first fish [tex]\left | -1.2 \ m/s \right | = 1.2 \ m/s[/tex]

Therefore, the second fish, X2, is moving faster than the first fish, X1.

(Please answer quickly!)
Force and energy aren't the same thing but they are closely related. explain how.

Answers

Answer:

Explanation:

Bigger pushes and pulls cause bigger changes in an object's motion or shape. When objects collide, contact forces transfer energy so as to change the objects' motions. When two objects interact, each one exerts a force on the other, and these forces can transfer energy between them.

difference between gravity and gravitation​

Answers

Answer:

Gravitation is the attractive force existing between any two objects that have mass. The force of gravitation pulls objects together. Gravity is the gravitational force that occurs between the earth and other bodies. Gravity is the force acting to pull objects toward the earth.

BRAINLIEST & 20 POINTS ANSWER THE BOTTOM TWO QUESTIONS PLEASE HURRY!!!!

Answers

Answer:

For 9 is 2,4,1 and 3.For 10 b-c moves 15 from each other and e-f moves 15 also from each other.

The air in a scuba tank is under more than 200 times the normal air pressure. Why should a filled scuba tank never be left in a hot car for an extended period of time?

Answers

Answer:

Burst open

Explanation:

it could create an explosion cause after some time the air wont be good anymore and staying inside a hot car is like someone sitting an oven it would burst open and create an explosion depending on the size of it

Which of the above beak depth vs time graphs represent the change in finch beak depth that would occur due to successive years of above average rainfall?

Answers

Answer:

A

Explanation:

I just did it :)

Answer:

It is A

Explanation:

I did it and got a 100

PLEASE HELP THIS IS DUE IN 10 MINUTES- (15 points!)
1st question- what are the weather fronts(use the pic for help)
2nd question- who has better weather— high pressure systems or low pressure systems and how do you know?
(Please add explanation)<3

Answers

Answer: I would say that B would have better weather because those dots on the right are cold fronts and the smooth side without the dots is a warm front. I hope this helps :)

Explanation:

What does gravity do to objects as they:

a) are thrown up:

b) fall toward earth:

Answers

Answer:

B

Explanation:

Gravity is when objects are pulled down to earth

Janel did an experiment to see which spices can kill bacteria. She mixed a spice with bacteria food called agar. She poured the agar and spice mix into a petri dish(a plate used for growing bacteria) and added bacteria. She did the same for five different spices. This is an example of

Answers

Answer:

Antibacterial activity

Explanation:

The antibacterial property does not allow bacterias to live in an environment. Many spices have the ability to show antibacterial activity, few of these spices can be named as cinnamon, turmeric, or clove. Because they have antimicrobial or antibacterial characteristics that is why they are used for food preservation, disease prevention, and provide many health benefits. But, not every spice has antibacterial characteristics, that is why Janel experimented with five different spices to see which amongst them possess antibacterial characteristics.

Hence the correct answer is Antibacterial activity.

An object with a charge of 1.2 C is located 4.5 m away from a second object that has a charge of 0.36 C. Find the electrical force that the objects exert on each other. Use 8.988×10 N⋅m2/C2 for the value of Coulomb's constant. Give your answer to two decimal places.

Answers

Answer:

[tex]1.917*10^8\ N[/tex]

Explanation:

Coulomb's law states that the electric force between two charges is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them. It is given by the formula:

[tex]F=k\frac{q_1q_2}{r^2}\\ \\q_1=first\ charge = 1.2C,q_2=second\ charge=0.36C,k=coulomb\ constant=8.988*10^9 N.m^2/C^2, r=distance=4.5m,F=force\\\\F=8.988*10^9*\frac{1.2*0.36}{4.5^2} =1.917*10^8\ N[/tex]

A soccer player applies a force of 48.4 N to a soccer ball while kicking it. If the ball has
a mass of 0.44 kg, what is the acceleration of the soccer ball?
A. 27.3 m/s2
B. 21.3 m/s2
C. 110 m/s2
D. 104 m/s2

Answers

Answer:

C. 110 m/s2

Explanation:

Force = Mass x Acceleration

Since we have the force and the mass, we can rearrange this equation to solve for acceleration by dividing both sides by mass:

Force/Mass = (Mass x Acceleration)/Mass

Acceleration = Force/Mass

Now we just have to plug in our values and calculate!

Acceleration = 48.4/0.44

Acceleration = 110m/s/s

It is option C. 110 m/s2

Hope this helped!

Yea C is the answer the first answer is right

m1=200g m2=150g
find the acceleration
the track is horizontal and frictionless

Answers

Answer:

50 or 1.3333

Explanation: Explanation you cancel out the mass and the force to see what your acceleration would be or you could divide F by M

Suppose a scientist conducts a series of experiments and the results are so amazing she wants to share them with other experts in her field Why would it be risky for her to make the results public on her own website before publishing them to a scientific journal

Answers

Answer:

The results have not been through the rigorous process of peer review

Explanation:

When a scientist conducts a study and obtains results, those results ought to be submitted to a reputable journal where the results would go through the rigorous protocol of peer review.

During this process, the reliability of the data presented is ascertained before the results are published for other scientists to see.

If the results are hurriedly published on the internet, many researchers who come in contact with the work may be fed with inaccurate information.

If a 3.1g ring is heated using 10.0 J, its temperature rises 19.7°C. Calculate
the specific heat capacity of the ring.

Answers

Answer:

Since 10 J / 4.19 J /cal = 2.39 cal     is the heat absorbed by the ring

Q = Cs * m * (T2 - T1)      heat absorbed by ring

Cs = 2.39 cal / (3.1 g * 19.7 deg C) = .039 cal / (gm deg C)

10 J / 4.19 J /cal = 2.39 cal     is the heat absorbed by the ring, Q = Cs * m * (T2 - T1)      heat absorbed by ring. Cs = 2.39 cal / (3.1 g * 19.7 deg C) = .039 cal / (gm deg C).

What is Specific heat capacity?

The amount of heat required to raise the temperature per unit mass is known as specific heat capacity. The heat in Joules required to increase the temperature of 1 gram of sample by 1 Kelvin or degree Celsius is typically stated.

Water is an excellent temperature regulator because it has a very high specific heat capacity.

The amount of heat in joules needed to raise 1 gram of a substance by 1 Kelvin is known as the specific heat capacity (symbol: c). It could also be written as J/kgK. Molar heat capacity, measured in J/mol K, and volumetric heat capacity, measured in J/m3 K, are comparable values.

Therefore, 10 J / 4.19 J /cal = 2.39 cal     is the heat absorbed by the ring, Q = Cs * m * (T2 - T1)      heat absorbed by ring. Cs = 2.39 cal / (3.1 g * 19.7 deg C) = .039 cal / (gm deg C).

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help do number 16 and 17​

Answers

Answer:

16 is d and i have no idea for 17

Classify each of the following chemical reactions. Upper S plus upper O Subscript 2 right arrow upper S upper O subscript 2. Upper C a upper C l subscript 2 plus 2 upper A g upper N upper O subscript 3 right arrow upper C a (upper n upper O subscript 3) subscript 2 plus 2 upper A g upper C l. Upper Z n plus upper C u upper S upper O subscript 4 right arrow upper C u plus upper Z n upper S upper O subscript 4. 2 upper N a subscript 2 upper O right arrow 4 upper N a plus upper O subscript 2.

Answers

Answer:

synthesis and combustion

double replacement

single replacement

decomposition only

in that exact order edge 2020

The presented reactions are:

S + O₂ ⇒ SO₂    Synthesis or combination

CaCl₂ + AgNO₃ = Ca(NO₃)₂ + 2 AgCl   Double displacement

Zn + CuSO₄ = Cu + ZnSO₄   Single displacement

2 Na₂O = 4 Na + O₂   Decomposition

Let's consider and classify the following reactions.

S + O₂ ⇒ SO₂

This is a synthesis or combination reaction. 2 compounds combine to form another.

CaCl₂ + AgNO₃ = Ca(NO₃)₂ + 2 AgCl

This is a double displacement reaction. Both compounds exchange their cations and anions.

Zn + CuSO₄ = Cu + ZnSO₄

This is a single displacement reaction. A metal displaces other metal from its salt.

2 Na₂O = 4 Na + O₂

This is a decomposition reaction. A compound decomposes into 2 other compounds.

The presented reactions are:

S + O₂ ⇒ SO₂    Synthesis or combination

CaCl₂ + AgNO₃ = Ca(NO₃)₂ + 2 AgCl   Double displacement

Zn + CuSO₄ = Cu + ZnSO₄   Single displacement

2 Na₂O = 4 Na + O₂   Decomposition

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A force applied to a 0.25 Kg hockey puck gives the puck an acceleration of 16 m/s2. What acceleration would the same force give to a 0.50 Kg baseball?

Answers

Answer:

8 m/s².

Explanation:

We'll begin by calculating the force applied to 0.25 Kg hockey puck. This is illustrated below:

Mass (m) = 0.25 Kg

Acceleration (a) = 16 m/s²

Force (F) =.?

Force (F) = mass (m) × acceleration (a)

F = ma

F = 0.25 × 16

F = 4 N

Therefore, a force of4 N was applied to the 0.25 Kg hockey puck.

Finally, we shall determine the acceleration in which the 4 N force will give to the 0.50 Kg baseball. This can be obtained as follow:

Mass (m) = 0.50 Kg

Force (F) = 4 N

Acceleration (a) =?

F = ma

4 = 0.5 × a

Divide both side by 0.5

a = 4 / 0.5

a = 8 m/s²

Therefore, the same force (i.e 4 N) applied to the hockey puck will give the 0.5 kg baseball an acceleration of 8 m/s².

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