Answer:
8 weeks
Step-by-step explanation:
Let x represent how many weeks they will be in France.
The tour in Britain can be represented by 2x, since it is twice as long as the one in France.
The tour in Germany can be represented by x - 2, since it is 2 weeks shorter.
Create an equation and solve for x:
(x) + (2x) + (x - 2) = 30
4x - 2 = 30
4x = 32
x = 8
So, they will be in France for 8 weeks
In a public opinion survey, 80 out of a sample of 100 high-income voters and 55 out of a sample of 80 low-income voters supported the introduction of a new national security tax.
a/ Estimate, with 95% confidence level, the true proportion of low-income people who will vote for the introduction of the tax.
b/ Can we conclude at the 5% level of significance that the proportion of high-income voters favoring the new security tax is 10% higher than that of low-income voters?
The confidence interval of the true proportion of low income people who will vote for the introduction of the tax is
Yes, we can conclude that at the 5% level of significance, the proportion of high income voters favoring the new security tax is 10% higher than that of low income voters using Test of Significance for Difference of Proportions.
What is confidence interval?
A confidence interval is the mean of your estimate plus and minus the variation in that estimate.
Proportion of high-income people who will vote for the introduction of the tax = p1 = [tex]\frac{80}{100} = \frac{4}{5}[/tex][tex]= 0.8[/tex]
Proportion of low-income people who will vote for the introduction of the tax = p2 = [tex]\frac{55}{80} = \frac{11}{16}[/tex] [tex]= 0.6875[/tex]
95% confidence interval of the true proportion of low income people who will vote for the introduction of the tax -
Upper confidence interval -
[tex]= p + 1.96 \sqrt{pq/n}[/tex]
[tex]=0.6875 + 1.96 \sqrt{(0.6875)(1-0.6875)/80} \\= 0.6875 + 1.96 \sqrt{0.00268} \\=0.789[/tex]
Lower confidence interval -
[tex]= p - 1.96 \sqrt{pq/n}[/tex]
[tex]=0.6875 - 1.96 \sqrt{(0.6875)(1-0.6875)/80} \\= 0.6875 - 1.96 \sqrt{0.00268} \\=0.586[/tex]
What is Test of Significance for Difference of Proportions?Test of Significance for Difference of Proportions is used when we want to compare two distinct populations with respect to the prevalence of a certain attribute, say A, among their members.
n1 = 100
X1 = 80
p1 = 0.8
n2 = 80
X2 = 55
p2 = 0.6875
H0: the proportion of high-income voters favoring the new security tax is 10% higher than that of low-income voters.(P1 - P2 = 0.1)
H1: the proportion of high-income voters favoring the new security tax isn't 10% higher than that of low-income voters. (P1 - P2 != 0.1)
[tex]z = \frac{(p1 - p2) - (P1 -P2)}{(\frac{X1+X2}{n1+n2})(1-\frac{X1+X2}{n1+n2})(\frac{1}{n1}+\frac{1}{n2} ) }[/tex]
[tex]z = \frac{(0.8 - 0.6875)- 0.1}{\sqrt{0.75*0.25*0.0225} } \\\\z = \frac{0.0125}{0.0649} \\\\z = 0.1926[/tex]
Since z = 0.1926 < 1.96, null hypothesis cannot be rejected. Thus, the proportion of high-income voters favoring the new security tax is 10% higher than that of low-income voters.
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ano ang area ng isang maliit na parisukat
Answer:
Area of square = Side²
Step-by-step explanation:
The area of a 2-D region, form, or flattened lamina in the planes is the quantity that represents its extent. On the 2-D surface or 3-D object, surface is its counterpart. A shape's area can be calculated by comparing it to squares of a specific size.
Area of square = Side²
solve the following function 3x^{2x-7}=9.
Answer:
3x-2x+7=-9
We simplify the equation to the form, which is simple to understand
3x-2x+7=-9
We move all terms containing x to the left and all other terms to the right.
+3x-2x=-9-7
We simplify left and right side of the equation.
+1x=-16
We divide both sides of the equation by 1 to get x.
x=-16
Find the equation of the exponential function represented by the table below:
х
y
03
1
1
9
2 27
3
81
Answer:
$53.07
Step-by-step explanation:
Delta Math
A family is planning to sell their home. If they want to be left with $116,100 after paying 10% of the selling price to a realtor as a commission, for how much must they sell the house?
The selling price is $129000
What is selling price?The selling price of an item is the price at which it is sold.
Given that 10% of selling price is the commission.
So the family gets 90% of the selling price, which is given as $116,100.
i.e (90/100) * Selling Price = 116100
Therefore, the selling price is (116100*100)/90 = 129000.
Hence, the family sell the house for the price of $129,000
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8a+6ab+5b,-6a-ab-8b and - 4a+2ab+3b
Pls answer this question
Answer:
4 a+8 ab+8b
Step-by-step explanation:
8 a-4 a+6ab+2ab+5 b+3 b
4 a+8 ab+8b
solve 4(8-2x)=2(7-x)
Answer and Step-by-step explanation:
Solve for x.
First, we divide both sides of the equation by 2.
2(8 - 2x) = 7 - x
Distribute the 2.
16 - 4x = 7 - x
Add 4x to and subtract 7 from both sides of the equation.
9 = 3x
Divide by 3 to both sides of the equation.
x = 3 <-- This is the answer.
#teamtrees #PAW (Plant And Water)
Answer:
x = 3
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightDistributive Property
Equality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityAlgebra I
Terms/CoefficientsStep-by-step explanation:
Step 1: Define
Identify
4(8 - 2x) = 2(7 - x)
Step 2: Solve for x
[Division Property of Equality] Divide 2 on both sides: 2(8 - 2x) = 7 - x[Distributive Property] Distribute 2: 16 - 4x = 7 - x[Addition Property of Equality] Add x on both sides: 16 - 3x = 7[Subtraction Property of Equality] Subtract 16 on both sides: -3x = -9[Division Property of Equality] Divide -3 on both sides: x = 3Use identities to simplify
(B)
Explanation:
[tex](\sec \beta + 1)(\tan \beta \csc \beta - 1)[/tex]
[tex]=\left(\dfrac{1}{\cos\beta} + 1 \right) \left(\dfrac{\sin \beta}{\cos \beta} \dfrac{1}{\sin \beta} - 1 \right)[/tex]
[tex]=\left(\dfrac{1}{\cos\beta} + 1 \right) \left(\dfrac{1}{\cos \beta} - 1 \right)[/tex]
[tex]= \left(\dfrac{1}{\cos^2 \beta} - 1 \right)[/tex]
[tex]= \left(\dfrac{1 - \cos^2 \beta}{\cos^2 \beta} \right)[/tex]
[tex]= \dfrac{\sin^2 \beta}{\cos^2 \beta}[/tex]
[tex]= \tan^2 \beta[/tex]
Choose the function whose graph is given by: A. y=tan(x+1)-pi B. y=tan(x-pi)-1 C. y=tan(x-pi)+1 D. y=tan(2(x+pi))-1
Aver si le entiendes bro
Help please!!!!!!!!!!!!!!
Answer:
Step-by-step explanation:
From Left (earliest) to Right (most recent)
First Pharaoh 3100 BC
First Babylon 1830 BC
First Mali 1235 CE
First US President 1789 CE
There are 750 identical plastic chips numbered 1 through 750 in a box. What is the probability of reaching into the box and randomly drawing a chip number that is smaller than 627
Answer:
0.8358 = 83.58% probability of reaching into the box and randomly drawing a chip number that is smaller than 627
Step-by-step explanation:
Uniform probability distribution:
An uniform distribution has two bounds, a and b.
The probability of finding a value of at lower than x is:
[tex]P(X < x) = \frac{x - a}{b - a}[/tex]
There are 750 identical plastic chips numbered 1 through 750 in a box
This means that [tex]a = 1, b = 750[/tex]
What is the probability of reaching into the box and randomly drawing a chip number that is smaller than 627?
[tex]P(X < x) = \frac{627 - 1}{750 - 1} = 0.8358[/tex]
0.8358 = 83.58% probability of reaching into the box and randomly drawing a chip number that is smaller than 627
17. Omar has a piece of rope. He ties a knot in the rope and measures the new length of the rope.
He then repeats this process several times. Some of the data collected are listed in the table
below.
Number of Knots
Length of Rope
(cm)
4 5 6 7 8
64 58 52 46 40
State, the linear equation that gives the length, y, of the rope after tying x knots.
Answer:
Step-by-step explanation: If I is intial height (y=I-6x) because Height = intial height + numbrt of knots -6 becuase as shown in the table every knot takes away 6 cm.
The linear equation that represents the length of the rope (y) after tying 'x' knots is: y = f(x) = 88 - 6x
What is a linear equation?"A linear equation is an equation in which the highest power of the variable is always 1. It is also known as a one-degree equation. The standard form of a linear equation in one variable is of the form Ax + B = 0. Here, x is a variable, 'A' is a coefficient and 'B' is constant".
Here, the number of knots are x = 4, 5, 6, 7, 8.
The length of the rope remains after each knots y = 64, 58, 52, 46, 40.
After tying 5th knot, the length of the rope decreases
= (64 - 58) cm
= 6 cm
After tying 6th knot, the length of the rope decreases
= (58 - 52) cm
= 6 cm
After tying 7th knot, the length of the rope decreases
= (52 - 46) cm
= 6 cm
After tying 5th knot, the length of the rope decreases
= (46 - 40) cm
= 6 cm
Initial length of the rope was = (64 + 4 × 6) cm = 88 cm
With the increase in value of 'x' by 1, the value of 'y' decreases by 6.
Therefore, the required equation: y = f(x) = 88 - 6x
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Anyone knows what the answer for this is I am really confused on it
what if cars did not exist plz be original
Answer:
If cars did not exist people could do as the did before they were invented. Such as walk to where they need to go or use a horse and buggy or carriage.
Step-by-step explanation:
determin 16x - 4y + 2 = 0
Answer:
16inches is your answer
the distance between Johannesburg and bloemfontein is estimated at 435km. if they travel at an average speed of 120km per hour,how long will it take them to travel from Johannesburg to bloemfontein? give answer in hours ,minutes and seconds
Answer:
3.625h,217.5min,13050sec
Step-by-step explanation:
S=vt
t=S/v
t=435/120 (km) /(km/h) =3.625h
t= 3.625*60 min = 217.5 min
t=217.5*60sec = 13050 sec
Answer:
t= 3.625 gio 217.5 phút = 13.050 giây
Step-by-step explanation:
s= vt
t=s/v
t= 435/120= 3.625 gio
t= 3.625*60=217.5 phút
t= 217.5*60 = 13.050 giây
If two systems of linear equations have the same solution set (in other words, the two systems are equivalent), then they must have the same number of equations.
a. True
b. False
Answer:
False.
Step-by-step explanation:
Equivalent systems of equations are those that have the same solutions or roots, although they have different numbers of equations. Equivalent systems of equations must have the same number of unknowns.
In other words, two systems of equations are said to be equivalent when they have the same solutions. Equivalent systems of equations do not have to have the same number of equations, although they do have to have the same number of unknowns.
So, the sentence is false.
A parallelogram has sides 8 ft and 6 ft and an area of 54 ft 2. What is the length of the
altitude to the 8-ft base?
Step-by-step explanation:
there is something wrong with your question.
there is no parallelogram with 8 and 6 ft side lengths that has an area of 54 ft².
the maximum area of a parallelogram with 8 and 6 ft side lengths is 48 ft². and that is a rectangle 8×6 as a special form of a parallelogram.
the area of any parallelogram is calculated
Ap = base length × height
and height is the length of the line perpendicular to the base line to one of the corners on the opposite side (as long as the base line).
if Ap = 54, and the base length is 8, this means
54 = 8 × height
height = 54/8 = 6.75 ft
but the height can only be the length of a side connected to the base line or less. not longer.
and in our example here, this connected side is 6. so, the height can only be 6 or less. not 6.75.
so, there must be something wrong with your numbers.
once you get the actual numbers, use my approach above with them (replace whatever number is wrong here by the true value).
When the demand for a good is highly elastic with respect to price, how should a producer want to increase revenue?
Answer:
When the demand for a good is highly elastic, the producer can increase revenue by reducing the price slightly.
Explanation:
Prices can either be Elastic, Inelastic, or Unitary.
The assumption is that the scenario in the question is in a perfect market. A perfect market is one where there are numerous buyers and sellers and there is little or no gap in information about market conditions such as cost of input, prices of the competition, etc.
When the demand for a product is elastic, it means that it is sensitive to changes in price. Price Elasticity is in degrees. When the demand for a product is highly elastic, it means that small changes in price lead to even greater changes in demand.
So for the producer to increase revenue in the short run (all things being equal) all they need to do is reduce the price slightly. This will increase revenue because it most likely will translate to a more than proportionate increase in quantity demanded.
Recall that markets are dynamic and the most predictable reaction of the other producers to this move will be an equal or even greater reduction in price in order to win back lost customers. Hence to sustainably maintain this position The producer will have to ensure that their product is sufficiently differentiated with unique value additions that are impossible or difficult to replicate.
Cheers
If C(-2, 4) and D(-6, -1), then what is the length of CD? Round to the nearest tenth.
9514 1404 393
Answer:
6.4
Step-by-step explanation:
The length is found from the distance formula:
d = √((x2 -x1)² +(y2 -y1)²)
d = √((-6 -(-2))² +(-1-4)²) = √((-4)² +(-5)²) = √(16 +25) = √41
d ≈ 6.4
Answer:
6.4Step-by-step explanation:
hope it helps
#GAUTHMATHIn a circle with a radius of 7.7, an angle intercepts an arc of length 29.6
Find the angle in radians, to the nearest tenth
9514 1404 393
Answer:
3.8 radians
Step-by-step explanation:
The length of an arc is given by ...
s = rθ . . . . . where r is the radius and θ is in radians
so the angle is ...
θ = s/r
θ = 29.6/7.7 ≈ 3.8
The angle is about 3.8 radians.
Inscribe a circle in a unit square and to r= 1000 random.
a. Suppose that 760 of those darts land in the circle.
b. What would our estimate be if we let n â oo and we applied the same ratio strategy?
Step-by-step explanation:
area of square = 1
area of a circle in square = [tex]\pi r^2 = \pi *(1/2)^2 = \frac{\pi }{4}[/tex]
bu estimate [tex]p^ = X/n = 760/1000 = 0.76
Therefore,
[tex]\frac{\pi }{4} \approx 0.76[/tex]
[tex]\pi \approx 0.76*4 =3.04[/tex]
b) if n tend to infinity
[tex]\pi will approach 3.14[/tex]
Answer:
uvfhmfa
Step-by-step explanation:
Determine the measure of
CD
from the diagram below.
Answer:
m(arc CD) = 112°
Step-by-step explanation:
Use the property of intersecting chords and angles between these chords,
m∠CED = [tex]\frac{1}{2}(\text{arc CD}+\text{arc}AB)[/tex]
m∠CED + m∠AED = 180°
80° + m∠CED = 180°
m∠CED = 100°
Now substitute the measure of angle CED and arc AB in the expression,
100° = [tex]\frac{1}{2}(88^{\circ}+\text{arc CD})[/tex]
200° = 88° + m(arc CD)
m(arc CD) = 112°
Which of the following types of data are likely to be normally distributed? Check all that apply.
A. The number of times Americans have been struck by lightning
B. The distance of an archer's shots from the center of a target
C. The time it takes for an airliner to fly from Los Angeles to New York
D. The outcomes of rolling a single fair die
Answer:
B. The distance of an archer's shots from the center of a target
C. The time it takes for an airliner to fly from Los Angeles to New York
Step-by-step explanation:
According to the Question,
B & C should each have a range of values that cover most occurrences with outlying values that decrease in number as they move further away from the dominant value range, which is the definition of a normal distribution.
Therefore, The answer is C the time it takes for an airliner to fly from Los Angeles to New York City, and B the distance of an archer's shot from the center of a target.Find the slope and recept of the line Y=7/5x-3
Answer:
The slope 7/5 and the y intercept is -3
Step-by-step explanation:
Y=7/5x-3
This equation is written in slope intercept form
y = mx+b where m is the slope and b is the y intercept
The slope 7/5 and the y intercept is -3
2x – 3(X + 8) = -21
Solve for x step by step
Please answer quickly
Answer:
x = -3
Step-by-step explanation:
2x – 3(x + 8) = -21
Distribute
2x - 3x - 24 = -21
Combine like terms
-x - 24 = -21
Add 24 to both sides
-x = 3
Multiply both sides by -1
x = -3
Suppose a group of 12 students consists of five freshmen and seven sophomores. How many six-student teams can be chosen that consist of three freshmen and three sophomores? Give your answer as an integer.
Answer:
350
Step-by-step explanation:
Can somebody help me? I feel like this is wrong
A fair coin is tossed 5000 times. What can you say about getting the outcome of exactly 2500 tails
Step-by-step explanation:
You can't expect to get exactly 2500 out of 5000 tosses more than a few times . You will come pretty close, but that's only good in horseshoes.
Of course I'm answering this on the basis of a computer language and not actually performinig this a million tmes, each part of a million consisting of 5000 tosses.
Simulations and not completely unbiased, but based on experience, 5000 is a very small number and getting 2500 more than a couple of times is unlikely
The probability of flipping a coin
coming up heads and tails is 1/2.
________⚛⚛⚛⚛⚛_________So, toss 5000 times 5000/2= 2500
heads: 2500
tails : 2500
Find x
x³ + 3x - 14 = 0
x³ + x² - x² - x + 4x + 4 = 18
x²(x + 1) - x(x + 1) + 4(x + 1) = 18
(x + 1)(x² - x + 4) = 18
x² - x + 4 = 18/(x + 1)
x² - x + 4 - 6 = 18/(x + 1) - 6
x² - x - 2 = 18/(x + 1) - 6
(x - 2)(x + 1) = (18 - 6(x + 1))/(x + 1)
(x - 2)(x + 1) = (18 - 6x - 6)/(x + 1)
(x - 2)(x + 1) = (12 - 6x)/(x + 1)
(x - 2)(x + 1) = (-6(x - 2))/(x + 1)
x + 1 = (-6(x - 2))/(x + 1)(x - 2)
x + 1 = -6/(x + 1)
(x + 1)² = -6
x² + 2x + 8 = 0
x = (-b +- √(b² - 4ac))/2a
x = (-2 +- √(4 - 32))/2
x = (-2 +- √(-28)/2
x = (-2 +- i√28)/2
Something's wrong.
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: x = - 1 \: + \: i \sqrt{6} \:(or) \: \: x = - 1 \: -\: i \sqrt{6} }}}}}}[/tex]
And[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {x\:=\:2}}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex] \: {x}^{3} + 3x - 14 = 0[/tex]
➺[tex] \: {x}^{2} (x + 1) - x(x + 1) + 4(x + 1) = 18[/tex]
➺[tex] \: (x + 1)( {x}^{2} - x + 4) = 18[/tex]
➺[tex] \: {x}^{2} - x + 4 = \frac{18}{(x + 1)} [/tex]
➺[tex] \: {x}^{2} - x + 4 - 6 = \frac{18}{(x + 1)} - 6[/tex]
➺[tex] \: (x - 2)(x + 1) = \frac{18 - 6(x + 1)}{(x + 1)} [/tex]
➺[tex] \: (x - 2)(x + 1) = \frac{18 - 6x - 6}{(x + 1)} [/tex]
➺[tex] \: (x - 2)(x + 1) = \frac{12 - 6x}{(x + 1)} [/tex]
➺[tex] \: (x - 2)(x + 1) = \frac{ - 6(x - 2)}{(x + 1)} [/tex]
➺[tex] \: (x + 1 )² = \frac{ - 6(x - 2)}{(x + 1)(x - 2)} [/tex]
➺[tex] \: (x + 1)² = \frac{ - 6}{(x + 1)} [/tex]
[tex]\sf\pink{Error\:corrected\:here. }[/tex]
➺[tex] \: {x}^{2} + 2x + 1 = - 6[/tex]
➺[tex] \: {x}^{2} + 2x + 7 = 0[/tex]
By quadratic formula, we have
➺[tex] \: x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]
➺[tex] \: x = \frac{ - 2± \sqrt{ {2}^{2} - 4.1.7} }{2 \times 1} [/tex]
➺[tex]x = \frac{ - 2± \sqrt{ - 24} }{2 } [/tex]
➺[tex] \: x = \frac{ - 2± \sqrt{ - 1 \times 4 \times 6} }{2} [/tex]
➺[tex] \: x = \frac{ - 2± \sqrt{ - 1} \times \sqrt{4} \times \sqrt{6} }{2} [/tex]
➺[tex] \: x = \frac{ - 2 \: ± \: i \times 2 \times \sqrt{6} }{2} [/tex]
➺[tex] \: x = \frac{ - 2 \: ± \:i \: 2 \sqrt{6} }{2} [/tex]
➺[tex] \: x = \frac{ 2 \: ( - 1 \: ± \: i \: \sqrt{6}) }{2} [/tex]
➺[tex] \: x = - 1 \: ± \: i \sqrt{6} [/tex]
Therefore, the two values of [tex]x[/tex] are ([tex] \: - 1 \: + \: i \sqrt{6}[/tex]) and ([tex] \: - 1 \: -\: i \sqrt{6}[/tex]).
Let us look at another method.[tex]x[/tex]³ + 3 [tex]x[/tex] - 14 = 0
➼ [tex]x[/tex]³ + 3 [tex]x[/tex] = 14
➼ [tex]x[/tex] ( [tex]x[/tex]² + 3 ) = 14
Factors of 14 = 1, 2, 7 and 14.
a) Substituting [tex]x\:=\:1[/tex], we have
➼ 1 ( 1 + 3 ) ≠ 14
➼ 1 x 4 ≠ 14
➼ [tex]\boxed{ 4\: ≠ \:14 }[/tex]
b) Substituting [tex]x\:=\:2[/tex], we have
➼ 2 ( 2² + 3 ) = 14
➼ 2 ( 4 + 3 ) = 14
➼ 2 x 7 = 14
➼ [tex]\boxed{ 14 \:= \:14 }[/tex]
c) Substituting [tex]x\:=\:7[/tex], we have
➼ 7 ( 7² + 3 ) ≠ 14
➼ 7 ( 49 + 3 ) ≠ 14
➼ 7 x 52 ≠ 14
➼ [tex]\boxed{ 364\: ≠ \:14 }[/tex]
d) Substituting [tex]x\:=\:14[/tex], we have
➼ 14 ( 14² + 3 ) ≠ 14
➼ 14 x 199 ≠ 14
➼ [tex]\boxed{ 2786\: ≠ \:14 }[/tex]
Hence, our only real solution is 2.
[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]