The p-value from the given data is 0.1056. Therefore, the correct answer is option B.
We obtain the Z-score P-values directly from the standard normal table, where each area corresponds to the probability to the left under the bell-shaped curve. The standard process to reject the claim of the experimenter is to see whether the P-value is less than 0.05 or not.
Let p be the population proportion of people who favored Candidate A.
The null hypothesis is: H₀: p>0.75
The alternative hypothesis H₁: p>0.75
The sample proportion is,
[tex]\bar p[/tex] =80/100 =0.8
The standard deviation is
[tex]\sigma=\sqrt{\frac{p.(1-p)}{n} }[/tex]
= √[0.75×(1-0.75)/100]
= 0.04
The z test statistic is:
Z=(p-[tex]\bar p[/tex])/σ
= (0.75-0.8)/0.04
= -1.25
Using standard normal table we get the area to the left corresponding to the test statistic z=-1.25 is 0.1056.
Therefore, the correct answer is option B.
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"Your question is incomplete, probably the complete question/missing part is:"
A random sample of 100 people was taken. Eighty of the people in the sample favored Candidate A. We are interested in determining whether or not the proportion of the population in favor of Candidate A is significantly more than 75%.
The p-value is
A) 0.2112
B) 0.1056
C) 0.025
D) 0.1251
For a 0.05 significance level, what is the decision regarding the hypothesis that the training was effective in improving customer relationships
The decision regarding the hypothesis that the training was effective in improving customer relationships would depend on the results of the hypothesis test and the associated p-value.
To determine the decision regarding the hypothesis that the training was effective in improving customer relationships, a hypothesis test would need to be conducted. The null hypothesis, denoted as H0, would be that the training had no effect on improving customer relationships. The alternative hypothesis, denoted as Ha, would be that the training was effective in improving customer relationships.
Assuming a 0.05 significance level, if the p-value associated with the hypothesis test is less than or equal to 0.05, then the null hypothesis can be rejected in favor of the alternative hypothesis. This would indicate that there is evidence to suggest that the training was effective in improving customer relationships.
On the other hand, if the p-value is greater than 0.05, then the null hypothesis cannot be rejected. This would indicate that there is insufficient evidence to suggest that the training was effective in improving customer relationships.
Therefore, the decision regarding the hypothesis that the training was effective in improving customer relationships would depend on the results of the hypothesis test and the associated p-value.
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The reason why we perform an analysis of variance for comparing means rather than conducting multiple two-mean comparisons is Multiple choice question. because multiple two-mean comparisons increase the Type I error probability. simply because ANOVA has simpler calculations but otherwise offers no benefit over the multiple t-tests. power is compromised when using t-tests.
Instead of performing repeated two-mean comparisons, we conduct an analysis of variance to compare means because doing so reduces the likelihood of Type I errors. Here option A is the correct answer.
ANOVA is preferred over multiple two-mean comparisons because it reduces the Type I error probability and offers several benefits over conducting multiple t-tests.
When conducting multiple two-mean comparisons, the likelihood of making a Type I error (i.e., rejecting a true null hypothesis) increases with each comparison made. This is known as the multiple comparison problem, and it can lead to an inflated false positive rate.
In contrast, ANOVA uses a single test to compare multiple means simultaneously, reducing the likelihood of making a Type I error. ANOVA achieves this by partitioning the total variation in the data into different sources of variation and estimating the amount of variation due to random chance.
Additionally, ANOVA offers several benefits over multiple t-tests. One advantage is that it provides a statistical significance test for the overall difference among the groups, not just for pairwise comparisons. ANOVA also allows for the testing of interactions between factors that influence the mean differences. Furthermore, ANOVA calculations can be more efficient than conducting multiple t-tests, especially when the number of groups is large.
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Complete question:
The reason why we perform an analysis of variance for comparing means rather than conducting multiple two-mean comparisons is
A. Because multiple two-mean comparisons increase the Type I error probability.
B. Simply because ANOVA has simpler calculations but otherwise offers no benefit over the multiple t-tests.
C. Power is compromised when using t-tests.
Find a power series for f(x)= 5/2x-3 centered at c=-3 and determine the interval and radius of convergence.
The interval of convergence is (-∞,∞) and the radius of convergence is ∞.The power series for f(x) can be found using the formula:
f(x) = Σ(n=0 to ∞) [fⁿ(c)/n!]*(x-c)ⁿ
where fⁿ(c) represents the nth derivative of f evaluated at x=c.
In this case, we have:
f(x) = 5/2x-3
f'(x) = -5/2(x-3)⁻²
f''(x) = 5(x-3)⁻³
f'''(x) = -15(x-3)⁻⁴
and so on.
Evaluating these derivatives at c=-3, we get:
f(-3) = 5/2(-3)-3 = -15/2
f'(c) = -5/2(-3-3)⁻² = -5/36
f''(c) = 5(-3-3)⁻³ = 5/216
f'''(c) = -15(-3-3)⁻⁴ = -5/1296
and so on.
Substituting these values into the power series formula, we get:
f(x) = Σ(n=0 to ∞) [(-1)ⁿ*5/(2*3ⁿ)*(x+3)ⁿ]
This can be simplified to:
f(x) = Σ(n=0 to ∞) [(-1)ⁿ*5/(2*3ⁿ)*xⁿ] + Σ(n=0 to ∞) [(-1)ⁿ*5/(2*3ⁿ)*(-3)ⁿ]
The first sum represents the power series centered at 0, while the second sum is a constant term (-15/2) that is added to shift the series to be centered at -3.
To determine the interval and radius of convergence, we can use the ratio test:
|a(n+1)/a(n)| = |(-1)^(n+1)*5/(2*3^(n+1))/( (-1)^n*5/(2*3^n))|
= 3/2
Since this ratio is constant and less than 1, the power series converges for all values of x.
Therefore, the interval of convergence is (-∞,∞) and the radius of convergence is ∞.
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Write a word problem that uses a system of linear equations. Have your partner solve it. Then, check the solution.
A company produces two types of smartphones: Model X and Model Y. The profit from each Model X sold is $150, while the profit from each Model Y sold is $200. Last month,the company sold a total of 500 smartphones and made a total profit of $85,000.
How many Model X and Model Y smartphones did the company sell last month, if the total profit was $85,000 and they sold a total of 500 smartphones?Here's a word problem that uses a system of linear equations:
Sarah and John went to a coffee shop and ordered lattes and scones. Sarah ordered 2 lattes and 3 scones and paid $10. John ordered 3 lattes and 2 scones and paid $11.50. What is the cost of one latte and one scone?
Let x be the cost of one latte and y be the cost of one scone. We can set up a system of linear equations to solve for x and y:
2x + 3y = 10
3x + 2y = 11.5
Now, your partner can solve this system of equations using any method they prefer, such as substitution or elimination.
To solve the system of equations:
2x + 3y = 10
3x + 2y = 11.5
We can use elimination method, by multiplying the first equation by 2 and the second equation by -3 to eliminate y:
4x + 6y = 20
-9x - 6y = -34.5
Adding the two equations, we get:
-5x = -14.5
Dividing both sides by -5, we get:
x = 2.9
Substituting x = 2.9 into the first equation, we can solve for y:
2(2.9) + 3y = 10
5.8 + 3y = 10
3y = 4.2
y = 1.4
Therefore, one latte costs $2.9 and one scone costs $1.4.
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What is the smallest set of integers for which we are guaranteed there exist two whose difference is a multiple of 14
Therefore, The smallest set of integers guaranteed to have a difference that is a multiple of 14 is 15. This is due to the Pigeonhole Principle and the 14 possible remainders when dividing integers by 14.
The smallest set of integers for which we are guaranteed there exist two whose difference is a multiple of 14 is 15. This can be explained by considering the possible remainders when dividing integers by 14. There are 14 possible remainders (0 to 13), but if we choose 15 integers, then by the Pigeonhole Principle, at least two of them must have the same remainder when divided by 14. The difference between these two integers will be a multiple of 14, as their remainders are the same. Therefore, the smallest set of integers required is 15.
Therefore, The smallest set of integers guaranteed to have a difference that is a multiple of 14 is 15. This is due to the Pigeonhole Principle and the 14 possible remainders when dividing integers by 14.
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Even numbers are usually more powerful than odd numbers when presenting or designing a product or message. This statement is:
It is important to base design decisions on objective criteria such as user research, usability testing, and data analysis, rather than subjective biases or unfounded beliefs about numbers.
Not supported by any empirical evidence or logical reasoning. There is no inherent power or superiority associated with even numbers over odd numbers in the context of presenting or designing a product or message.
While some people may have personal preferences or cultural associations with even or odd numbers, the power or effectiveness of a product or message is determined by various factors such as its content, design, target audience, and context of use.
Therefore, it is important to base design decisions on objective criteria such as user research, usability testing, and data analysis, rather than subjective biases or unfounded beliefs about numbers.
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Jill can paint a bedroom in their house in 2 hours, and John can paint it in 3 hours. How long will it take Jill and John, working together, to complete the job?
It will take Jill and John [tex]$\frac{6}{5}$[/tex] hours or 1 hour and 12 minutes.
How much time will Jill and John to complete the job?To solve the problem, we can use the formula:
[tex]$ \frac{1}{x} = \frac{1}{a} + \frac{1}{b}$[/tex]
where x is the time it takes for Jill and John to complete the job working together, and a and b are the times it takes for Jill and John to complete the job individually, respectively.
Substituting the given values, we get:
[tex]$ \frac{1}{x} = \frac{1}{2} + \frac{1}{3}$[/tex]
Simplifying this expression, we get:
[tex]$ \frac{1}{x} = \frac{5}{6}$[/tex]
Multiplying both sides by 6x, we get:
[tex]$6 = 5x$[/tex]
Dividing both sides by 5, we get:
[tex]$x = \frac{6}{5} hours$[/tex]
Therefore, it will take Jill and John [tex]$\frac{6}{5}$[/tex] hours or 1 hour and 12 minutes (rounded to the nearest minute) working together to complete the job.
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You want to know the percentage of utility companies that earned revenue less than 3939 million or more than 6161 million dollars. If the mean revenue was 5050 million dollars and the data has a standard deviation of 77 million, find the percentage. Assume that the distribution is normal. Round your answer to the nearest hundredth.
The percentage of utility companies that earned revenue less than 3939 million or more than 6161 million dollars is 0.1484 or 14.84% (rounded to the nearest hundredth).
We can use the standard normal distribution to find the percentage of utility companies that earned revenue less than 3939 million or more than 6161 million dollars.
First, we need to standardize the values using the formula:
z = (x - μ) / σ
where x is the revenue value, μ is the mean revenue, and σ is the standard deviation.
For x = 3939 million:
z = (3939 - 5050) / 77 = -1.45
For x = 6161 million:
z = (6161 - 5050) / 77 = 1.44
Using a standard normal distribution table or calculator, we can find the probability of a value being less than -1.45 or greater than 1.44.
P(z < -1.45) = 0.0735
P(z > 1.44) = 0.0749
The percentage of utility companies that earned revenue less than 3939 million or more than 6161 million dollars is:
0.0735 + 0.0749 = 0.1484 or 14.84% (rounded to the nearest hundredth).
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Lydia tosses two six-sided number cubes. List the sample space. What is the probability of Lydia rolling pairs of the same number
So the probability of rolling pairs of the same number is 6/36, which simplifies to 1/6 or approximately 0.1667.
When Lydia tosses two six-sided number cubes, the sample space consists of all possible outcomes for each roll. There are 6 sides on each cube, resulting in 6 x 6 = 36 possible outcomes.
For pairs of the same number, there are 6 possible outcomes: (1,1), (2,2), (3,3), (4,4), (5,5), and (6,6).
To find the probability of Lydia rolling pairs of the same number, divide the number of favorable outcomes (pairs of the same number) by the total number of outcomes in the sample space:
Probability = (number of favorable outcomes) / (total number of outcomes) = 6 / 36 = 1/6 or approximately 16.67% or 0.1667.
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Brandon is competing in a long jump competition. He jumped 19.8 feet on his first jump. In his next two jumps, he jumped 19.98 feet and 18.77 feet. What is the total distance for all three jumps
Brandon's performance in the long jump competition was solid. While his third jump wasn't quite as long as his first two jumps, he still managed to jump almost 60 feet in total, which is no small feat.
To find the total distance for all three jumps, we need to add up the distance for each of Brandon's jumps. On his first jump, Brandon jumped 19.8 feet. On his second jump, he jumped 19.98 feet. And on his third jump, he jumped 18.77 feet.
To get the total distance, we simply add these three distances together:
19.8 + 19.98 + 18.77 = 58.55 feet
So the total distance for all three of Brandon's jumps is 58.55 feet.
It's important to note that in long jump competitions, the distance is measured from the takeoff line to the point where the athlete's body first breaks the plane of the landing area. This means that the actual distance that Brandon jumped may have been slightly longer or shorter than the distances recorded for each jump.
Overall, Brandon's performance in the long jump competition was solid. While his third jump wasn't quite as long as his first two jumps, he still managed to jump almost 60 feet in total, which is no small feat. Depending on the level of competition he was participating in, this distance could have been enough to earn him a medal or place him high in the rankings.
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Should my Mom get an Escalade or a Wagoneer
Answer:
Whatever she wants.
I'd say you probably want a Wagoneer, as your username is jeepwagoneer
A change in the unit of measurement of the dependent variable in a model does not lead to a change in: a. the standard error of the regression. b. the sum of squared residuals of the regression. c. the goodness-of-fit of the regression. d. the confidence intervals of the regression.
A change in the unit of measurement of the dependent variable in a model does not lead to a change in the goodness-of-fit of the regression. The correct option is c.
The goodness-of-fit, often measured by the coefficient of determination (R-squared), reflects the proportion of variance in the dependent variable that can be explained by the independent variable(s) in the model. This measure is unitless and ranges from 0 to 1, where a value closer to 1 indicates a better fit.
When the unit of measurement of the dependent variable changes, the standard error of the regression (option a) may change since it represents the dispersion of the observed values around the predicted values in the model. Similarly, the sum of squared residuals of the regression (option b) might also change, as it is the sum of the squared differences between the observed and predicted values.
Additionally, the confidence intervals of the regression (option d) may be affected by a change in the unit of measurement, as these intervals provide a range within which the true population parameters are likely to fall, and the range is dependent on the scale of the dependent variable.
In summary, while a change in the unit of measurement of the dependent variable can affect the standard error, sum of squared residuals, and confidence intervals of the regression, it does not impact c. the goodness-of-fit of the regression model.
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A store sells a 1 1/4 pound package of turkey for $9
.What is the unit price of the turkey in the package?
If 1(1/4) pound of turkey is sold for $9, then the unit-price of the turkey is $7.20 per pound.
The "Unit-Price" is defined as the price of a single unit or item of a product, typically expressed in terms of a standard unit of measurement, such as price per pound, price per liter, or price per piece.
To find the unit price of turkey in the package, we need to divide the total cost of the package by the weight of the turkey in the package.
First, we need to convert 1(1/4) pounds to a decimal, which is 1.25 pounds.
Then, we can find the unit price by dividing the total-cost of $9 by the weight of the turkey in the package:
⇒ Unit price = (Total cost)/(Weight of turkey in package),
⇒ Unit price = $9/1.25 pounds,
⇒ Unit price = $7.20 per pound,
Therefore, the unit price of turkey in the package is $7.20 per pound.
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The given question is incomplete, the complete question is
A store sells a 1(1/4) pound package of turkey for $9. What is the unit price of the turkey in the package?
82% of companies ship their products by truck. 47% of companies ship their product by rail. 40% of companies ship by truck and rail. What is the probability that a company ships by truck or rail
The probability that a company ships by truck or rail is 89%.
To calculate the probability that a company ships by truck or rail, we need to add the probability of shipping by truck to the probability of shipping by rail, and then subtract the probability of shipping by both truck and rail (to avoid double counting):
P(shipping by truck or rail) = P(shipping by truck) + P(shipping by rail) - P(shipping by both truck and rail)
We are given that:
P(shipping by truck) = 82%
P(shipping by rail) = 47%
P(shipping by both truck and rail) = 40%
Plugging in these values, we get:
P(shipping by truck or rail) = 82% + 47% - 40%
= 89%
Therefore, the probability that a company ships by truck or rail is 89%.
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A box contains three coins: two regular coins and one fake two-headed coin. You pick a coin at random and toss it. What is the probability that it lands heads up
The probability of getting heads up is 5/6, or approximately 0.833.
There are three coins in the box, so the probability of picking any one of them at random is 1/3.
Let's consider the probability of getting heads up for each of the three coins:
For the two regular coins, the probability of getting heads up is 1/2, since they are fair coins.
For the fake two-headed coin, the probability of getting heads up is 1, since both sides are heads.
So, the overall probability of getting heads up depends on which coin is selected.
If you select one of the regular coins, the probability of getting heads up is 1/2.
If you select the fake two-headed coin, the probability of getting heads up is 1.
The probability of selecting one of the regular coins is 2/3, since there are two regular coins out of the total of three coins.
Therefore, the overall probability of getting heads up when you pick a coin at random and toss it is:
(2/3) x (1/2) + (1/3) x (1) = 2/6 + 3/6 = 5/6.
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Find the total surface area of the following
cone. Leave your answer in terms of pi.
SA = [?]π cm²
Which number has the greatest possibility of showing up when rolling two dice and add the resulting values
Answer:
I'd say probably 6, as 3 + 3 = 6, and 3 is the middle number.
**EDIT**
It's a 7, because there are 6 ways of rolling this value, making it the most probable.
Find the approximate surface-area-to-volume ratio of a bowling ball with a radius of 5 inches. A. 0.6 B. 0.67 C. 1.67 D. 25 Please select the best answer from the choices provided A B C D
The approximate surface-area-to-volume ratio of a bowling ball with a radius of 5 inches is 0.6
To find the approximate surface-area-to-volume ratio of a bowling ball with a radius of 5 inches, we will first calculate the surface area (SA) and volume (V) of the ball, and then divide the surface area by the volume.
Step 1: Calculate the surface area (SA) using the formula for the surface area of a sphere:
[tex]SA = 4 πr^2[/tex]
[tex]SA = 4 π5^2[/tex]
[tex]SA = 4 π(25)[/tex]
[tex]SA=100π[/tex]
Step 2: Calculate the volume (V) using the formula for the volume of a sphere:
[tex]V = \frac{4}{3} π (r)^{3}[/tex]
[tex]V = \frac{4}{3} π (5)^{3}[/tex]
[tex]V = \frac{4}{3} π (125)[/tex]
V = 166.67 π cubic inches
Step 3: Calculate the surface-area-to-volume ratio (SA/V)
[tex]\frac{SA}{V} = \frac{100}{166.67}[/tex]
[tex]\frac{SA}{V}=\frac{100}{166.67}[/tex]
[tex]\frac{SA}{V}= 0.6[/tex]
So the approximate surface-area-to-volume ratio of a bowling ball with a radius of 5 inches is 0.6. The best answer from the choices provided is A.
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The travel time for a college student traveling between her home and her college is uniformly distributed between 40 and 90 minutes. The probability that her trip will take longer than 80 minutes is Group of answer choices 1.00. 0.40. 0.20. 0.80.]
The probability that her trip will take longer than 80 minutes is 0.20.
The probability that the trip takes longer than 80 minutes is equal to the area of the uniform distribution to the right of 80. Since the distribution is uniform, the area to the right of 80 is equal to the proportion of the total area that is to the right of 80.
The total area under the uniform distribution is equal to the length of the interval, which is (90 - 40) = 50.
The area to the right of 80 is equal to (90 - 80) = 10.
So the probability that the trip takes longer than 80 minutes is:
10 / 50 = 0.2
Therefore, the answer is 0.20.
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Marcos has 2003 pairs of shoes. In how many different ways can he select a left then a right shoe?
Answer:
4006
Step-by-step explanation:
pls explain me this
Complete the tree diagram as shown in the image attached.
The probability that he prepares chapattis and tea is 0.3
How to complete the tree diagram?Since He prepares either samosas or chapattis for the food and the probability that he prepares samosas is 0.4.
Thus, the probability that he prepares chapattis is: 1 - 0.4 = 0.6
Also, He prepares either tea or coffee for the drink and He is equally likely to prepare tea or coffee. Thus,
The probability that the prepare tea = 0.5
The probability that the prepare coffee = 0.5
Therefore, we can complete the tree diagram as shown in the image attached.
The probability that he prepares chapattis and tea is:
= P(chapattis) * P(tea)
= 0.6 * 0.5
= 0.3
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Find the sum of the convergent series 2(-1)-1 12n2 + 1 by using a well- known function. Round your answer to four decimal places. a. 0.0713 b. 0.0907 c. 0.8288 d. 0.0768 e. 0.0831
Upon calculating the sum up to the appropriate term, we find that the sum is approximately 0.0713. So, the correct answer is a. 0.0713
It seems like there is a typo in the series notation. I assume the series you are referring to is ∑(2(-1)^n-1)/(12n^2 + 1) from n=1 to infinity. In this case, we can determine the sum using a well-known function and round the answer to four decimal places. Since the given series is an alternating series, we can use the Alternating Series Estimation Theorem to determine an approximation for the sum. The theorem states that if the absolute difference between consecutive terms is decreasing and the limit of the terms as n approaches infinity is zero, the approximation for the sum is accurate up to the first term that is less than or equal to the desired error bound (in this case, 0.0001). For this series, we can see that the absolute difference between consecutive terms decreases as n increases and the limit as n approaches infinity is zero. So, we can find the smallest value of n for which the term is less than or equal to 0.0001 and calculate the sum up to that term.
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The mayor of a city believes that the city can maintain
adequate services only if the population density is reduced.
The city is 30 miles long and two-thirds as wide, and
555,000 citizens currently live there.
The mayor calculates that the minimum number of people
who would have to move outside the city for adequate
services to be maintained is 75,000.
Enter the maximum population density, in citizens per
square mile, that is assumed in the mayor's calculation.
From the calculation, the population density of the place is 800 people/[tex]mile^2[/tex].
What is the population density?We know that we can be able to obtain the population density by the use of the formula;
Population density = Population of people/ Area of the place;
The area is obtained from;
Length = 30 miles
Width = 2/3 * 30 = 20 miles
Area of the city = 30 miles * 20 miles = 600 [tex]miles^2[/tex]
Final population after the evacuation = 555,000 - 75,000
= 480,000
Then the population density = 480,000/600 [tex]miles^2[/tex]
= 800 people/[tex]miles^2[/tex]
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Let W = Span {[\begin{array}{ccc}2\\1\\-3\end{array}\right] , [\begin{array}{ccc}1\\-1\\2\end{array}\right]} Explain how to find a set of one or more homogenous equations for which the corresponding solution set is W and then do so.
Any solution to this equation is in the span of W. Conversely, any linear combination of v1 and v2 will satisfy this equation, so the solution set of this equation is exactly the span of W.
To find a set of homogeneous equations whose solution set is W, we need to find a set of equations that are satisfied by all linear combinations of the vectors in the span of W.
Let's call the vectors in the span of W, v1 and v2:
v1 = [\begin{array}{ccc}2\\1\\-3\end{array}\right]
v2 = [\begin{array}{ccc}1\\-1\\2\end{array}\right]
We want to find a set of homogeneous equations that are satisfied by all linear combinations of v1 and v2. We can do this by setting up an augmented matrix with v1 and v2 as its columns, and then row reducing the matrix to find a set of homogeneous equations.
[ v1 | v2 ] =
[\begin{array}{ccc|ccc}2 & 1 & 0 & 1 & 0 & 0\\1 & -1 & 0 & 0 & 1 & 0\\-3 & 2 & 0 & 0 & 0 & 1\end{array}\right]
Using elementary row operations, we can row reduce this matrix to reduced row echelon form:
[\begin{array}{ccc|ccc}1 & 0 & 0 & -5 & 3 & 0\\0 & 1 & 0 & -1 & 2 & 0\\0 & 0 & 0 & 0 & 0 & 1\end{array}\right]
The last row of the row reduced matrix corresponds to the equation 0x1 + 0x2 + 0x3 = 1, which is always false and has no solutions. Therefore, we can ignore this row and write down the remaining equations in terms of x1, x2, and x3:
x1 - 5x3 + 3x3 = 0
x2 - x3 + 2x3 = 0
Simplifying these equations, we get:
x1 - 2x2 + 4x3 = 0
So the set of homogeneous equations that correspond to W is:
x1 - 2x2 + 4x3 = 0
Therefore, any solution to this equation is in the span of W. Conversely, any linear combination of v1 and v2 will satisfy this equation, so the solution set of this equation is exactly the span of W.
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determine whether the integral g(x)=∫[infinity]8sin2(x) 4x−−√ 2dx diverges by comparing it to the integral f(x)=∫ [infinity]83x−−√ 2dx.
We can see that g(x) is less than or equal to h(x) for all x greater than or equal to 8, because sin^2(x) is always less than or equal to 1. Therefore, g(x) is also divergent, since h(x) is divergent.
To determine whether the integral g(x)=∫[infinity]8sin2(x) 4x−−√ 2dx diverges, we can compare it to the integral f(x)=∫ [infinity]83x−−√ 2dx. We know that f(x) is a divergent integral because the power of x in the denominator is greater than 1.
To compare g(x) to f(x), we need to find a function h(x) that is greater than or equal to g(x) and less than or equal to f(x) for all x greater than or equal to 8. One function that satisfies this condition is h(x) = √x.
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If begin alpha is changed from 0.01 to 0.05, which of the following is true? I. The probability of a Type I error goes up II. The p-value goes up.
The correct answer is I. The probability of a Type I error goes up
If the significance level, or begin alpha, is changed from 0.01 to 0.05, the probability of a Type I error increases. This is because the researcher is now more willing to reject the null hypothesis and declare a significant effect even when there isn't one.
However, changing the significance level does not necessarily affect the p-value. The p-value is a measure of the strength of evidence against the null hypothesis, and is calculated based on the data and the chosen significance level. It is possible for the p-value to go up or down depending on the data, even if the significance level remains constant.
Therefore, the correct option is I. The probability of a Type I error goes up.
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An investigator indicates that the POWER of his test (at a significance of 1%) of a sample mean resulting from his research is 0.87. What is the probability that he made a Type I error
The probability of making a Type I error is equal to 1 - 0.99 = 0.01, which is the same as the significance level.
To answer this question, we need to understand the concepts of statistical power and Type I error. Statistical power refers to the probability of correctly rejecting the null hypothesis when it is false. In other words, it is the ability of a statistical test to detect a true effect.
On the other hand, a Type I error occurs when we reject the null hypothesis even though it is true. This is also known as a false positive.
The investigator has indicated that the power of his test is 0.87 at a significance level of 1%. This means that if there is a true effect in the population, the test has an 87% chance of correctly detecting it. However, we are interested in the probability of making a Type I error, which is the probability of rejecting the null hypothesis when it is true.
To calculate the probability of making a Type I error, we need to use the complement of the significance level, which is 1 - 0.01 = 0.99. This represents the probability of not rejecting the null hypothesis when it is true. Therefore, the probability of making a Type I error is equal to 1 - 0.99 = 0.01, which is the same as the significance level.
In this case, the investigator has used a significance level of 1%, which means that there is a 1% chance of making a Type I error. This is a relatively low probability, which indicates that the investigator is being cautious in rejecting the null hypothesis.
However, it is important to note that the probability of making a Type I error depends on the significance level, the sample size, and the effect size. Therefore, it is important to consider these factors when interpreting the results of a statistical test.
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If you spin the spinner below twice, what is P(vowel, then P)?
A. one-third
B. one-ninth
C. start fraction 5 over 6 end fraction
D. Start fraction 5 over 12 End fraction
When the spinner is spun, the P ( vowel, then P ) would be B. one-ninth.
How to find the probability ?To find the probability of P ( vowel, then P ), on the spinner given, the formula would be :
= P ( vowel ) x P ( P )
We have six sides on the spinner which gives us:
P ( vowel ) = 4 / 6
P ( P ) = 1 / 6
The probability of P ( vowel, then P ) is :
= 4 / 6 x 1 / 6
= 4 / 36
= 1 / 9
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A lot of 30 watches is 20% defective. What is the probability that a sample of 3 will contain 2 defectives
To calculate the probability of obtaining 2 defective watches in a sample of 3 from a lot of 30 watches with a 20% defective rate, we can use the binomial probability formula.
The binomial probability formula is given by:
P(X = k) = (n C k) * p^k * (1 - p)^(n - k)
Where:
P(X = k) is the probability of getting exactly k successes (in this case, 2 defectives),
n is the sample size (3),
k is the number of successes (2),
p is the probability of success (defective rate, 20% or 0.2), and
(1 - p) is the probability of failure (1 - 0.2 = 0.8).
Using these values, we can calculate the probability as follows:
P(X = 2) = (3 C 2) * (0.2)^2 * (0.8)^(3 - 2)
(3 C 2) represents the number of ways to choose 2 out of 3 watches, which is calculated as 3! / (2! * (3 - 2)!), which simplifies to 3.
P(X = 2) = 3 * (0.2)^2 * (0.8)^(3 - 2)
= 3 * 0.04 * 0.8
= 0.096
Therefore, the probability that a sample of 3 watches from the lot of 30 watches contains 2 defectives is 0.096 or 9.6%.
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A bridge underpass in the shape of an elliptical arch, that is, half of an ellipse, is feet wide and feet high. An eight foot wide rectangular truck is to drive (safely) underneath. How high can it be
To find out how high the truck can safely be to drive underneath the bridge underpass in the shape of an elliptical arch, we need to use the dimensions given. First, we need to determine the equation of the ellipse, which is:
(x^2/a^2) + (y^2/b^2) = 1
Where "a" is the width of the ellipse (in feet) and "b" is half the height of the ellipse (in feet). Therefore, we can substitute the given values to get:
(x^2/(feet)^2) + (y^2/(feet/2)^2) = 1
Simplifying this equation, we get:
(x^2/(feet)^2) + 4(y^2/(feet)^2) = 1
Now, we know that the truck is 8 feet wide, so we need to find the height "y" that allows the truck to safely drive underneath. To do this, we need to find the maximum value of "y" that satisfies the equation above and also allows for a clearance of at least 8 feet (the width of the truck). We can set up an inequality as follows:
4(y^2/(feet)^2) <= 1 - (8/(2*feet))^2
Simplifying this inequality, we get:
4(y^2/(feet)^2) <= 1 - 16/(feet)^2
y^2 <= (1/4)(feet)^2 - 4
y <= sqrt((1/4)(feet)^2 - 4)
Therefore, the maximum height "y" that allows the truck to safely drive underneath is:
y <= sqrt((1/4)(feet)^2 - 4)
Note that we cannot simplify this expression further without knowing the value of "feet". So, the final answer will depend on the specific dimensions of the bridge underpass.
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