A radio broadcast antenna is located at the top of a steep tall mountain. The antenna is broadcasting 104.3 FM in Megahertz) with a mean power of 2.00 kilowatts. What is the intensity of the signal at a receiving antenna located 20.0 km away? What is the peak voltage generated in a straight wire antenna which is 1.20 m long (also located 20.0 km away)? What is the peak voltage generated in a circular loop antenna which is 24.0 cm in radius (also located 20.0 km away)?

Answers

Answer 1

The intensity of the radio signal at a receiving antenna located 20.0 km away is approximately 4.52 x 10⁻¹² W/m². The peak voltage generated in a straight wire antenna which is 1.20 m long is approximately 2.08 x 10⁻⁵ V. The peak voltage generated in a circular loop antenna which is 24.0 cm in radius is approximately 4.35 x 10⁻⁶ V.

The intensity of the radio signal at a distance r from the antenna is given by

I = P/(4πr²)

where P is the power of the broadcast, and r is the distance from the antenna.

Plugging in the given values, we get

I = (2.00 x 10³ W)/(4π(2.00 x 10⁴ m)²) = 4.52 x 10⁻¹² W/m²

The peak voltage generated in an antenna is given by

V_peak = E_peak x (2πr)

where E_peak is the electric field strength at a distance r from the antenna, and r is the distance from the antenna.

For a straight wire antenna, the electric field strength is given by

E_peak = (μ_0 x I_peak)/(2πr)

where μ_0 is the permeability of free space, and I_peak is the peak current in the antenna.

For a circular loop antenna, the electric field strength is given by

E_peak = (μ_0 x I_peak x R)/(2r²)

where R is the radius of the loop.

Plugging in the given values and using the appropriate equation, we get

For the straight wire antenna:

V_peak = (μ_0 x I_peak x length)/(2πr) = (4π x 10⁻⁷ Tm/A) x (4.00 A) x (1.20 m)/(2π x 2.00 x 10⁴ m) = 2.08 x 10⁻⁵ V

For the circular loop antenna:

V_peak = (μ_0 x I_peak x R)/(2r^2) = (4π x 10⁻⁷ Tm/A) x (4.00 A) x (0.24 m)/(2 x (2.00 x 10⁴ m)²) = 4.35 x 10⁻⁶ V

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Answer:

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Explanation:

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2, A rectangulv Container of base socmby 30cm is filled
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Answers

Correct question is;

2, A rectangular Container of base 50 cm by 30cm is filled with water to be depth of 5cm. how much is the pressure exerted at the base? (take pw= 1000kg /m3 and g=10m/s)​

Answer:

P = 500 N/m²

Explanation:

Pressure exerted at the base is the hydrostatic pressure and it is given by the formula;

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Radio waves - used for communication e.g. radios and TVs

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Answers

Answer:

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Answers

Answer:

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Answer:

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Answers

Answer:

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Explanation:

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how does a longshore current affect a beach?

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Longshore currents are affected by the velocity and angle of a wave. When a wave breaks at a more acute (steep) angle on a beach, encounters a steeper beach slope, or is very high, longshore currents increase in velocity. ... This process, known as “longshore drift,” can cause significant beach erosion.

Answer:

"Longshore currents are affected by the velocity and angle of a wave. When a wave breaks at a more acute (steep) angle on a beach, encounters a steeper beach slope, or is very high, longshore currents increase in velocity. ... This process, known as “longshore drift,” can cause significant beach erosion."

Credits to ocean service

Explanation:

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Answer:

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Answer:

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Explanation:

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Answers

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//

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Answers

The vertical component of the velocity at the starting is 12.5 m/s upwards.

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In kinematics, the area of classical mechanics that deals with the motion of bodies, velocity is a fundamental idea.

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= 25 × 1/2 m/s

= 12.5 m/s.

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popularized the cell theory in an 1855 essay entitled “Cellular Pathology.” (b) The idea that all cells originate from other cells was first published in 1852 by his contemporary and former colleague Robert Remak (1815–1865).

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Rudolf Virchow

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Answer:

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true

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We can’t see steps two or three so there isn’t a way to give you the answer that you need

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What is mass?

It is possible to define every mechanical quantity in terms of mass, length, and time. The SI unit for mass, denoted by the letter m, is the kilogram. While mass is typically thought of as an immutable feature of an item, relativistic mass must be taken into account when traveling at speeds close to the speed of light.

Given:

The mas of the paper clips are the same,

Assume the number of clips in step two is x and the mass is m, the mass in the third step is the same as in step 2,

Thus, the number of clips = Total mass of paper clip / mass of one clip,

The number of clips = m / x

As we can see, if the mass is equal, then the number of clips will also be equal.

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Answer:

false

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because Oxalic acid is present in spinach

MARK ME AS BRAINLIST

2x+1-2x=8. solve this problem math

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Answer:

x=7

Explanation:

2x+1-2x=8

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