A public health organization reports that 40%of baby boys 6-8 months old in the United
States weigh more than 20 pounds. A sample of 10 babies is studied. Round the answers to three decimal places.
what is the probability that more than 4 weigh more than 20 pounds
What is the probability that fewer than 3 weigh more than 20 pounds?
Would it be unusual if more than 7 of them weigh more than 20 pounds?

Answers

Answer 1

Using the binomial distribution, the probabilities are given as follows:

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

What is the binomial distribution formula?

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.

The values of the parameters for this problem are:

n = 10, p = 0.4.

The probability that more than 4 weigh more than 20 pounds is:

[tex]P(X > 4) = 1 - P(X \leq 4)[/tex]

In which:

[tex]P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)[/tex]

Then:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{10,0}.(0.4)^{0}.(0.6)^{10} = 0.0061[/tex]

[tex]P(X = 1) = C_{10,1}.(0.4)^{1}.(0.6)^{9} = 0.0403[/tex]

[tex]P(X = 2) = C_{10,2}.(0.4)^{2}.(0.6)^{8} = 0.1209[/tex]

[tex]P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.2150[/tex]

[tex]P(X = 4) = C_{10,4}.(0.4)^{4}.(0.6)^{6} = 0.2502[/tex]

Hence:

[tex]P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0061 + 0.0403 + 0.1209 + 0.2150 + 0.2502 = 0.6325[/tex]

[tex]P(X > 4) = 1 - P(X \leq 4) = 1 - 0.6325 = 0.3675[/tex]

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.

The probability that fewer than 3 weigh more than 20 pounds is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0061 + 0.0403 + 0.1209 = 0.1673

0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.

For more than 7, the probability is:

[tex]P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10)[/tex]

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 8) = C_{10,8}.(0.4)^{8}.(0.6)^{2} = 0.0106[/tex]

[tex]P(X = 9) = C_{10,9}.(0.4)^{9}.(0.6)^{1} = 0.0016[/tex]

[tex]P(X = 10) = C_{10,10}.(0.4)^{10}.(0.6)^{0} = 0.0001[/tex]

Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

More can be learned about the binomial distribution at https://brainly.com/question/24863377

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Answers

Step-by-step explanation:

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c

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edg 2021

no one bothers to read why anyways

The first column is labeled sum with entries 5, 7, 9, 11, 13, 15, 17.

The second column is labeled frequency with entries 1, 2, 3, 4, 3, 2, 1.

We have given,

Violet creates two spinners for a game.

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The table represents the sums of the spinners and the frequency of each sum.

A 2-column table with 7 rows.

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The sum is the forword counting of the numbers.

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The follow me to get 50 points.

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Answer:

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Answers

Answer:

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Step-by-step explanation:

The computation of the number of liters of water added is shown below:

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Answers

9514 1404 393

Answer:

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Step-by-step explanation:

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__

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__

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I hope this helps have a great day

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Answers

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