A fifty-car train going 25 meters per second took 150 seconds to stop. What is the acceleration/deceleration?

When the ball experiences a net force of 0 newtons, its state of motion remains unchanged, that is, it will remain in rest or will move with same speed in same direction.

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

As  the ball experiences a net force of 0 newtons, it experiences balanced force and its state of motion remains unchanged.

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The phrase "like dissolves like" can be described as the compounds which have similar nature dissolve in each other that is polar dissolves polar and non-polar dissolves non-polar molecules.

Polarity is the separation of electric charge which is leading to a molecule or the chemical groups which are having an electric dipole moment, with a negatively charged end and a positively charged end as well. Polar molecules are the molecules which must contain one or more polar bonds which occur due to a difference in the electronegativities between the bonded atoms of the molecule.

A simple way to predict the compounds which will dissolve in other compounds is the phrase of the compound such as "like dissolves like". This means that the polar compounds dissolve in polar compounds, and the nonpolar compounds dissolve in nonpolar compounds, however, the polar and nonpolar molecules do not dissolve in each other.

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He ends up 17 meters to the left of the center position, according to the given question.

An object's location at any given time is known as its position (x), and its change in position is known as displacement. Both of these must be determined from the reference frame because they are vector values.

Suppose he is at a position which is 3 m. right from the center position

Given data :

Initial position = 3m to the right

Time = 10 sec.

Speed = 2m/s.

By using the formula -

speed = distance / time

distance = speed × time

distance = 2 × 10

distance = 20 m.

He end up at 17 m. to the left from the center position.

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The only exception is Mars, which is noticeably less brilliant at opposition compared to how apparent the other planets are on Earth.

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magnification m = -v/u  = -2

Concave mirrors can generate both real and virtual images. A virtual, magnified image of the object is produced when the concave mirror is positioned very near to it.

As the distance between the object and the mirror increases, the size of the image decreases and real images are produced. When an object's distance is less than the focal length in a concave mirror, the magnification will be higher than one. When the object's distance exceeds the focal length, the magnification is less than one.

Given focal length f = 18 cm

image distance v = 54 cm

then from lens equation

(1/f) = (1/u)+(1/v)

(1/18) = (1/u)+(1/54)

-(1/u) = (1/54)-(1/18)

object distance u = (18*54)/(18-54) = 27 cm

magnification m = -v/u = (-54)/(27) = -2

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Electrons do not follow specific paths, so describing the area where an electron is likely to be is more scientifically accurate and is actually an improvement over earlier models.

The first option is correct.

The electron is described as a subatomic particle with a negative one elementary electric charge.

Modern orbital theory predicts electron in specific orbitals which are three-dimensional in nature.

It is a quantum mechanical phenomenon where we can not apply classical mechanics to determine the exact position of electron.

The square of the amplitude wave function associated with the electron gives the probability of finding the electron in a particular region.

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Formed due to subduction, formed at a convergent boundary, and formed where mantle erupts through crust.

Subduction is the geologic process in which one tectonic plate moves beneath another and is forced downwards into the mantle. It is an important part of plate tectonics, as it is responsible for the formation of mountain ranges and volcanism. Subduction occurs at convergent boundaries, where two plates come together, and is usually accompanied by earthquakes, as the plates grind and slide against each other. Subduction zones are the areas where this process is occurring, and they are typically found in the world's oceans, along the margins of the continental plates.

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The sum of the potential energy and the kinetic energy of an object is called as mechanical energy.

An object's mechanical energy can be defined as the result of its motion (i.e., kinetic energy) and/or the result of its stored position energy (i.e., potential energy).

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The rate at which a certain balloon travels is inversely proportional to the amount of weight attached to it if the balloon travels at 10 in./s and then there is a 2nd g weight attached to it approximately the weight must be attached to the balloon for it to travel 18 in./s is 1.1 grams.

When 2 grams are added, the rate moves at 10 in/sec.

Since the weight and the distance traveled are inversely proportional, the expression can be written as

d= k/W

10 =k/2

k= 20

When 2 grams are attached, the rate moves at a speed of 10 in/second.

Given that the relationship between the weight and the traveled distance is inverse, this can be expressed as,

d= k/W

18= k/w

w= k/18

Substitute value of k in the above expression.

W= 20/18

W=1.11 gram

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The specific heat capacity of the air in the balloon is 125.88 J/kg °C.

Specific heat is the amount of energy required to raise the temperature of a unit mass of a substance by one degree. It is measured in joules per kilogram Kelvin (J/kgK). Specific heat is an important physical property of a substance, as it determines how much energy is required to change its temperature. It is also used to calculate the amount of energy released or absorbed during a chemical reaction. Specific heat is also known as heat capacity, and is often used to compare the heat capacity of different materials.

The specific heat capacity of a substance is the amount of energy required to raise the temperature of 1 kg of the substance by 1 °C.
To calculate the specific heat capacity of the air in the balloon, we can use the equation:
Q = m * c * ΔT
Where Q is the change in thermal energy, m is the mass of the air, c is the specific heat capacity, and ΔT is the change in temperature.
Rearranging the equation, we get:
c = Q / (m * ΔT)
Plugging in the values given, we get:
c = 860 J / (0.00320 kg * 215 °C)
c = 860 J / (0.0068 kg °C)
c = 125.88 J/kg °C
Therefore, the specific heat capacity of the air in the balloon is 125.88 J/kg °C.

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The mechanical advantage of the screwdriver is 0.208.

Mechanical advantage is the ratio of the output force produced by a machine (especially a simple machine) to the applied input force.

The efficiency of a simple machine is determined by calculating their mechanical advantage (MA). Mechanical advantage is a measure of the force amplification attained by the machine.

According to this question, the screwdriver has a radius from the center to the outermost edge of the tip of 50.0 mm, and the radius of the handle of 240 mm. The mechanical advantage can be calculated as follows:

M.A = 50/240

M.A = 0.208

Therefore, 0.208 is the mechanical advantage of the simple machine.

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By using kinematic equation, the height of the cliff would be 90.6 meters.

The kinematics equations are frequently used to analyze the free-falling motion of an object, in this case we are given that:

The time (t) = 4.3 seconds

Acceleration due to gravity (a) = 9.8 meters per second

Since we know that the time it takes for the stone to fall to the ground is 4.3 s, we can use the following formula to determine the height to which the stone will fall as a result of gravity:

x = v₀t + 1/2 at²

where x is the displacement, v is the velocity, t is the time, and a is the acceleration.

x = 0 + 1/2 (-9.8) (4.3)²

x = -90.6

As the result, the height of the cliff would be 90.6 meters.

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a) The force constant is 2.49 N/m

b) The amplitude is 1.65 m

We know that a spring can be said to be the kind of substance that has a potential energy that has been stored in it and this energy is released to do work when the spring has been pulled.

We have that;

T = 2π√m/K

T = period

m = mass

K = spring constant

Then;

0.84 = 2*3.14√0.447/K

0.84/2*3.14 = √0.447/K

(0.84/2*3.14)^2 = 0.447/K

K  = 0.447/0.0179

K = 2.49 N/m

Then the amplitude is obtained from;

W = 1/2 KA^2

A =√2W/K

A = √2 * 3.4/2.49

A = 1.65 m

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Answer:

Bernoulli's principle explains how objects heavier than air are able to fly

Explanation:

Basically, Bernoulli's principle states that faster-moving air has greater air pressure than slower-moving air

When an object has greater air pressure on its top surface than its lower surface it will create lift, or lift the object up

Thus in a tornado, with extremely high winds a roof could be easily lifted up if the air pressure is greater than the force of gravity

In accordance with the conservation of momentum law the 8-ball's final speed after a collision is 0.51 m/s.

momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both direction and magnitude.

Given data :

Mass of cue ball(m1) = 0.17 kg

Mass of 8-ball(m2) = 0.16 kg

Initial speed of cue ball (u1) = 0.48 m/s

Initial speed of 8-ball (u2) = 0 m/s

Final speed of cue ball (v1) = 0 m/s

Final speed of 8-ball (v2) = v2 m/s

The total momentum before and after a collision is equal, according to the conservation law of momentum.

Hence,

m1u1 + m2u2 = m1v1 + m2v2

0.17 × 0.48 + 0.16 × 0 = 0.17 × 0 + 0.16 × v2

0.0816 + 0 = 0 + 0.16v2

0.0816 / 0.16 = v2

0.51 m/s = v2

v2 = 0.51 m/s

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The amount of energy emitted by the light bulb is 600J.

Efficiency is the extent to which a resource is used for the intended purpose; the ratio of useful work to energy expended.

According to this question, a light bulb is 40% efficient. If it is supplied with 1000 joules of electrical energy, the amount of energy emitted can be calculated as follows:

40% of 1000J = 400J of energy used.

This means that 1000J - 400J = 600J of energy will be emitted.

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Answer:

Below

Explanation:

Find distance vehicle travels during this acceleration

d = vo t + 1/2 a t^2    

   a = change in velocity / change in time = 17.9/9.6 = 1.86458 m/s^2

   vo = 0    ( it starts from rest )

then  d = 1/2 ( 1.86458)* 9.6^2 = 85.92  meters

Now divide by the tire circumference to get the number of revs

     85.92 m / ( .38 m * pi )/rev = ~  71.97 revs

Answer: 64.5 rev. ✅

Explanation: The diameter of the tire is 38cm and the car accelerates uniformly from rest to reach a speed of 17.9m/s in 9.6s. The distance covered by the tire can be calculated by using the formula: distance = speed x time.

The distance covered by the tire is 17.9 x 9.6 = 171.84 meters. But when we convert it centimeters it is 17184 cm

The distance covered by the tire is equal to the circumference of the tire, which is equal to 2πd (d is the diameter of the tire). So we can calculate the number of revolutions by dividing the distance covered by the tire by the circumference of the tire.

Number of revolutions = distance covered / Circumference of the tire = 17184/ (2 x π x (38/100)) = 64.5 ✅

Answer:

11520

Explanation:

6.4×1800 wich is kw × 30 minutes in seconds

The angular acceleration of a spinning amusement park ride is 0.2 rad/s^2.

The pace at which an object moving in a circle changes angular velocity over time is referred to as angular acceleration. Rotational acceleration is another name for angular acceleration. It has both magnitude and direction, making it a vector quantity.

The rate of change in angular displacement is known as angular velocity, and the rate of change in angular velocity is known as angular acceleration.

Zero magnitude acceleration is still acceleration. Motion with uniform (i.e. zero) acceleration is a specific case of motion with constant velocity.

Given:

Initial acceleration = 0.50 rad/s

Final acceleration = 0.60 rad/s

Time = 0.50 s

Angular Acceleration:

α = Δω/Δt

[tex]\alpha = \frac{0.60-0.50}{0.50}[/tex]

[tex]\alpha =\frac{0.1}{0.50}[/tex]

[tex]\alpha =0.2rad/s^2[/tex]

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The story that describes the graph is, we  were accelerating from our starting point A to the next point B, then from point B started decelerating to our next point C, rested between point C and D, and finally we started our journey again by accelerating to point E.

A displacement time graph, is a type of graph that is used to describe the motion of an object with respect of how the object is changing its position with time.

The change in position with change in the time of motion of the object gives velocity of the object which is also equal to the slope of the graph.

v = Δx / Δt

where;

From the given graph we can conclude the following based on the motion;

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So, the magnitude of velocity concerning:

Hi! Here I will help you to solve problems related to the velocity vector. In this problem, we know that a particle moves at a certain speed with an angle ([tex] \sf{\theta} [/tex]) on the x-axis. Of course, with conditions like this, velocity can be described on the x or y-axis. The result of the x-axis velocity is horizontal movement. On the other hand, the y-axis velocity is vertical movement. See the equation below to know the magnitude of velocity concerning the x and y-axis.

[tex] \boxed{\sf{\bold{v_x = v_i \cdot \cos(\theta)}}} [/tex]

[tex] \boxed{\sf{\bold{v_y = v_i \cdot \sin(\theta)}}} [/tex]

With the following condition:

[tex] \sf{v_x = v_i \cdot \cos(\theta)} [/tex]

[tex] \sf{v_x = 20 \cdot \cos(275^{\circ})} [/tex]

[tex] \sf{\bold{v_x \approx 1.74 \: m/s}} [/tex]

[tex] \sf{v_y = v_i \cdot \sin(\theta)} [/tex]

[tex] \sf{v_y = 20 \cdot \sin(275^{\circ})} [/tex]

[tex] \sf{\bold{v_y \approx -19.92 \: m/s}} [/tex]

So, the magnitude of velocity concerning:

The distance between the ground directly underneath the balloon and the second rope is 36.37 feet.

The complete question is in the attachment. Look at the triangle ACD. For ∠ ACD = θ the trigonometric ratios

Look at the picture

tan θ = y/x

tan 30° = AD/AC

tan 30° = 21/AC

AC = 21 ÷ tan 30°

AC = 21 ÷ 0.577

AC = 36.37 feet

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MLA 9 in-text citation looks like: (Burke 3); (Best and Marcus 9); (Franck et al. 327).

In MLA 9th edition, in-text citations will be:

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The frequency of the damped oscillation is 24.6 Hz

The equation for frequency of the damped oscillation is as follows:

f = (1 / (2 × π)) × √((k - (b² / 4 × m)) / m)

where "π" is a mathematical constant approximately equal to 3.1415, "k" is the spring constant, "m" is the mass of the sphere, and "b" is the damping coefficient.

f = (1 / (2 × π)) × √((2.4×10⁴ N/m - (3.00 Ns/m² / 4 × 8.00 kg)) / 8.00 kg)

f = (1 / (2 × π)) × √((2.4×10⁴ N/m - (3.00 Ns/m² / 4 × 8.00 kg)) / 8.00 kg)

f = (1 / (2 × π)) × √((2.4×10⁴ N/m - (3.00 Ns/m² / 4 × 8.00 kg)) / 8.00 kg)

f = (1 / (2 × π)) × √(24000 - (3/32)) N/kg

f = (1 / (2 × π)) × √(23997) N/kg

f = (1 / (2 × π)) × 153.26 N/kg

f = 24.6 Hz

Therefore, the frequency of the damped oscillation is 24.6 Hz

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Your question seems to be missing, but I suppose the question was:

"A metal sphere with a mass of 8. 00 kg oscillate at the end of a vertical spring with a spring constant of 2. 40 ✕ 10^4 N/m. The motion is damped by air resistance, and the damping coefficient is b = 3. 00 Ns/m. Calculate the frequency of the damped oscillation."

The gravitational field strength on Oobla is 20.8 N/kg. It is greater than the gravitational field strength on Earth.

The gravitational field strength, also called acceleration due to gravity or free-fall acceleration, is the gravitational force that acts on a mass of object. It can be expressed as

g = F/m

Where

The gravitational force can be stated as weight of object W. The formula becomes W = mg. So, the weight of an object depends on the gravitational field strength on a place.

An object has a weight of 170 N on Earth. The weight becomes 360 N on Oobla. Find the gravitational field strength on Oobla!

We know that the gravitational field strength on Earth is 9.8 N/kg.

Let's say:

The mass of an object is always the same wherever it is.

So, the gravitational field strength on Oobla is

m = W/g

m₁ = m₂

W₁/g₁ = W₂/g₂

170/9.8 = 360/g₂

g₂ = (9.8×360)/170

g₂ = 20.8 N/kg

It is greater than the the value of g on Earth.

Hence, the planet Oobla has the gravitational field strength of 20.8 N/kg.

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The sodium electric charge ion on the right has a total charge of -1 and consists of 17 protons and 18 electrons.

Ions are any atoms or clusters of atoms with an electric charge. Cations are the name for positive-charged ions. Anion is the name for ions that have a negative charge. Several common compounds are present in the body as ions. Examples of typical salts are sodium, potassium, calcium, chloride, and bicarbonate.

Beyond scientific instruments, these charged particles have significant applications in home appliances like smoke detectors and air purifiers. By disrupting and neutralizing the airborne bacteria, ions can clean the air.

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Quartz and halite have different crystal shapes primarily because of the internal arrangement of atom.

Due to some reasons, quartz and halite have different crystal shapes. Primarily, the reasons are:

The very distinct key characteristics that make us can easily observe and differ between quartz and halite is that quartz crystals always make a pointed pencil shape. It has 6 sides on terminal ends as resembling a prism. Furthermore, halite tastes like salt, because halite is salt. The other characteristics that we could use to differentiate between two of them is that a quartz crystal is hexagonal in cross section, meanwhile a halite crystal is square in cross section.

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