A exerted by an object on another is a force

Answer:

EM

Explanation:

The index of refraction is a special property that shows how light travels through different medias. It does not concern itself with the spectrum, only what it will do to that spectrum under laboratory conditions.

Laser light is a very narrow concentrated light form. It is not the entire spectrum, but only a very small part of it.

The answer you want is EM Electromagnetic Radiation

Answer:

Option (c)

Explanation:

According to question,

R= 60 ohm

V=120 V

Current can be calculated as :

[tex]I=\frac{V}{R}[/tex]

Where,

I  is current

V is voltage

R is resistance

[tex]I=\frac{120}{60} \\I=2 A[/tex]

Current is flowing across 60 ohm will be 2.0 A

Therefore, option c is correct

Answer:

33.33j+6.67i km/hr

Explanation:

From the law of conservation of momentum,

Applying,

mu+m'u' = V(m+m')............... Equation 1

Where m = mass of the truck, m' = mass of the car, u = initial velocity of the truck, u' = initial velocity of the car, V = Final velocity.

Note: let j represent the north, and i  represent the east

From the question,

Given: m = 1500 kg, u = 60j, m' = 1200 kg, u' = 15i

Substitute these values into equation 1

1500*60j+1200*15i = V(1500+1200)

90000j+18000i = 2700V

V = (90000j+18000i)/2700

V = 33.33j+6.67i km/hr

Answer:

como assim qual a tarefa que educação física? se você me explicar melhor eu consigo te responder !!

Explanation:

Answer:

Explanation:

The sensor contains an LDR which has a resistance of 10kohlms in daylight and 100kohlms in the dark.

If the resistor in the circuit is 1 megaohlm, the total resistance in daylight and darkness will be 1.01 megaohms and 1.1 megaohlms.

The percentage difference = (1.1-1.01)/1.1*100% = 8.18%

If the resistor in the circuit is 25 kohlm, the total resistance in daylight and darkness will be 35 kohms and 125 kohlms.

The percentage difference = (125-35)/125*100% = 72%

With the input p.d to the sensing circuit fixed at 12 v, the sensing current will change according to the total resistance. A 72% difference is much more detectable. So the 25 kohm resistor is the better choice.

Answer:

Explanation:

V=IR

I=12/(R of resistor + R of LDR)

R of LDR = 10kohm in light and = 100kohm in dark

R1 =  25kohm

R2 = 1Mohm

solve 4 current

                       light                                       dark

R1        12/(25+10)=0.343mA          12/(25+100)=0.096mA

R2       12/(1000+10)=0.012mA       12/(1000+100)=0.011mA

so R1 is better as its easier 2 tell its light or dark

Answer:

Y

Explanation:

Acceleration = (v-u)/t

W = (29-11)/6 = 3

X = (34-10)/12 = 2

Y = (40-12)/7 = 4

Z = (28-20)/8 = 1

So the answer is Y = 4.

Hope this will help. Please mark me brainliest.

Explanation:

hope it helps

pls mark me as brainliest thanks❤

Answer:

I. Aceleración, a = -2 m/s²

II. Distancia, S = 100 metros

Explanation:

Dados los siguientes datos;

Velocidad inicial = 72 km / h

Tiempo = 10 segundos

Velocidad final = 0 m/s

Conversión:

72 km/h a metros por segundo = 72 * 1000/3600 = 72000/3600 = 20 m/s

I. Para encontrar la aceleración, usaríamos la primera ecuación de movimiento;

[tex] V = U + at[/tex]

Dónde;

Sustituyendo en la fórmula, tenemos;

[tex] 0 = 20 + a*10 [/tex]

[tex] -20 = 10a [/tex]

[tex] Aceleracion = \frac{-20}{10}[/tex]

Aceleración, a = -2 m/s²

Nota: el signo negativo indica desaceleración o retraso.

II. To find the acceleration, we would use the third equation of motion;

[tex] V^{2} = U^{2} + 2aS [/tex]

Dónde;

Sustituyendo en la fórmula, tenemos;

[tex] 0^{2} = 20^{2} + 2*(-2)*S [/tex]

[tex] 0 = 400 - 4S [/tex]

[tex] 4S = 400 [/tex]

[tex] S = \frac {400}{4}[/tex]

Distancia, S = 100 metros

Answer:it’s 400 meters

Explanation:

Answer:

Torque Of a Force: If The Force has tendency or Bends The Body about Longitudinal axis of the Body it is Torque. Moment Of a Force :If Force has Tendency to or Rotates the Body about Transverse asis the Body It is Moment .

Explanation:

Answer:

coefficient=1.09N/m×g

coefficient=1.09N/0.413g×10m/s square

coefficient=1.09N/4.13N

coefficent=0.263

f= uK

here f is force, u is cofficient of friction , k is normal force

k = mg

f = umg

1.09 = u × 0.41 × 10

u = 1.09 ÷ 4.1

u = 0.26

La respuesta correcta para esta pregunta abierta es la siguiente.

A pesar de que se te olvidó especificar el país al que te refieres y a la fecha específica para saber de qué época estás hablando, te podemos ayudar comentando lo siguiente.

¿Qué juegos se practicaban en esa Época?

Anterior al surgimiento de la era digital y la era de los "gammers," los niños y la juventud en general salían a la calle o al parque a realizar diferentes actividades físicas y recreativas. Había juegos de ronda, juegos deportivos, juegos de destreza, y juegos de mesa.

¿Qué nombre tenían los juegos?

Había juegos que se llamaba "Doña Blanca," "La Roña," "Lobo estás ahí," "Las escondidas," "canicas," el yoyo," "el trompo," "el burro castigado," "las cebollitas," "el látigo," además de las "cascaritas" que eran juegos de soccer o futbol americano en las calles y con equipos formados por tus amigos.

¿En qué consistía cada uno de los juegos?

Si jugabas canicas, tenías que golpear una canica con otra para desplazarla y llevarla a cierto lugar. O tenías que meterla en agujeros.

Si jugabas, "Doña Blanca," formabas un círculo entrelazado de las manos. Mientras cantabas la canción de Doña Blanca, alguien que estaba afuera del círculo trataba de romperlo, tratando de soltar algunas de las manos entrelazadas.

La verdad era sumamente divertido, creativo, te reías, mucho, y lo mejor de todo era que hacías ejercicio y no te quedabas sentado todo el día frente a una pantalla de computadora.

Answer:

The height jumped by the person on the moon is 6 times the height jumped by the person on earth.  

Explanation:

As we know that the acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth.

So, it is false.

Let the mass of man is m and the gravity on moon is g' = g/6.

Let the height jumped on earth is h and the height jumped on moon is h'.

So,

m x g' x h' = m x g x h

g/6 x h' = g x h

h' = 6 h  

So, the height jumped by the person is 6 times the height jumped by the person on earth.

Answer:

the work done by the woman is 6,000 J

Explanation:

Given;

force applied by the woman, F = 400 N

distance moved by the woman, d = 15 m

The work done by the woman is calculated as follows;

W = F x d

W = 400 N x 15 m

W = 6000 Nm = 6,000 J

Therefore, the work done by the woman is 6,000 J

Answer:

1 d

2c

3b

4a

5b

6 I think the answer is x-ray

7c

8d

10d( Immigration)

Answer:

[tex]g=16.31\ m/s^2[/tex]

Explanation:

Given that,

The length of the pendulum, l = 2 m

The period of the pendulum, T = 2.2 s

The formula for the time period of a pendulum is given by :

[tex]T=2\pi \sqrt{\dfrac{l}{g}}[/tex]

or

[tex]T^2=4\pi ^2\dfrac{l}{g}\\\\g=\dfrac{4\pi ^2l}{T^2}\\\\g=\dfrac{4\pi ^2\times 2}{(2.2)^2}\\\\g=16.31\ m/s^2[/tex]

So, the free fall acceleration is [tex]16.31\ m/s^2[/tex].

Whichever object has more mass will need more energy to slow it down.

We don't know the mass of the car or the mass of the large.

None of this has anything to do with "difficult". We don't know what's difficult for you, and we don't know the SI unit of "difficult".

Answer:

Time, t = 28.87 seconds

Explanation:

Given the following data;

Acceleration = 1.20 m/s²

Distance = 500 meters

Initial velocity = 0 m/s

To find the time to cover the distance, we would use the second equation of motion;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Where;

S represents the displacement or height measured in meters.

u represents the initial velocity measured in meters per seconds.

t represents the time measured in seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

[tex] 500 = 0*t + \frac {1}{2}*(1.2)*t^{2}[/tex]

[tex] 500 = 0 + 0.6*t^{2} [/tex]

[tex] 500 = 0.6t^{2} [/tex]

[tex] t^{2} = \frac {500}{0.6} [/tex]

[tex] t^{2} = 833.33 [/tex]

Taking the square root of both sides, we have;

[tex] t = \sqrt{833.33} [/tex]

Time, t = 28.87 seconds

Answer:

1- 31.25

2-?

3-?

Explanation:

Answer:

The correct option is A. a second action potential is generated until the interval reaches the absolute refractory period.

Explanation:

The inter-stimulus interval (ISI) is the temporal interval between two successive stimuli, measured from the offset of the first stimulus to the commencement of the second.

A cell's refractory period is the time during which it is unable to replicate an action potential. Therefore, the absolute refractory period is the amount of time it takes for a second action potential to be initiated, regardless of how large a stimulus is applied repeatedly.

A second action potential is generated when the gap between the stimuli decreases until the interval reaches the absolute refractory period.

Therefore, the correct option is A. a second action potential is generated until the interval reaches the absolute refractory period.

That is, when the interval between the stimuli decreases, a second action potential is generated until the interval reaches the absolute refractory period.

Answer:

c

Explanation:

Have a nice day

answer is c

(c)

Explanation:

is (c)

it is c

Answer:

At lift-off, hot burning gas is pushed downwards by the rocket motors. The hot gas pushes back on the rocket in an upwards direction. When this upwards push, or thrust, exceeds the weight of the rocket, the forces acting on the rocket are unbalanced and the rocket accelerates upwards

Explanation:

Answer:

A. Gases from burning fuel are pushed out of the bottom of the rocket, and these gases push back on the rocket with an equal amount of force.

Explanation:

Explanation:

Newton's second law of motion gives the relation between mass, force and acceleration.

We know that,

Force, F = mass (m) × acceleration (a)

or

[tex]m=\dfrac{F}{a}[/tex]

or

[tex]a=\dfrac{F}{m}[/tex]

Hence, this is the required solution.

Solution :

Let us consider the Gaussian surface that is in the form of a cylinder having a radius of r and a length of A which is [tex]$\text{coaxial with the charged cylinder}$[/tex].

The charged enclosed by the cylinder is given by,

[tex]$q=\rho V$[/tex]       (here, V = [tex]$\pi r^2l$[/tex]  is the volume of the cylinder)

  [tex]$=\pi r^2lp$[/tex]    

If [tex]$\rho$[/tex] is positive, then the electric field lines moves in the radial outward direction and is normal to Gaussian surface which is distributed uniformly.

Therefore, total flux through Gaussian cylinder is :

[tex]$\phi=EA_{cyl}$[/tex]

   [tex]$=E(2\pi rl)$[/tex]

Now using Gauss' law, we get

[tex]$2\pi \epsilon_0rlE = \pi r^2lp$[/tex]

or [tex]$E=\frac{\rho r}{2 \epsilon_0}$[/tex]

Therefore, the electric field is [tex]$E=\frac{\rho r}{2 \epsilon_0}$[/tex]

Hence, option (d) is correct.

Answer:

The answer answer is 150 km

Answer:

Explanation:

Distance =Speed×time

Speed=50km/hr

Time=3hours

Hence the Distance will be(50km/hr×3hours)

The answer is 150km

Answer:

A.

Explanation:Object b will get a negative charge .