A crate rests on a flatbed truck which is initially traveling at 13.6 m/s on a level road. The driver applies the brakes and the truck is brought to a halt in a distance of 38.1 m. If the deceleration of the truck is constant, what is the minimum coefficient of friction between the crate and the truck that is required to keep the crate from sliding

Answers

Answer 1

Answer:

0.248

Explanation:

Initial speed u = 13.6

Final speed v = 0

Distance s = 38.1

We have umg = ma

We make u subject of the formula

u = a/g

V² = u² + 2as

a = v²-u²/2s

We substitute the values into the above

a = 0-(13.6)²/2*38.1

a = 184.96/76.2

a = 2.427m/sec

Remember that

u = a/g

u = 2.427/9.8

= 0.2476

This is approximately 0.248

This is the minimum coefficient of friction required to keep the crate from sliding.


Related Questions

YALL PLEASE HELP I BARELY HAVE TIME
Which of the following is not a property of light?
Light travels in a straight line.
Light travels through empty space.
Light moves in a compressional wave.
All options are true

Answers

Answer:

All of then are true

I need brainliest so I can rank up

Explanation:

Answer:

I think all options are true is the right answer

Explanation:

Mark me the brainliest plzzz

The name of the SI unit for magnetic field strength, such as that created around a current-carrying wire, is the
.

Answers

Tesla. SI

The unit of magnetic field is tesla. It is the SI unit of magnetic field. Magnetic field is the measure of magnetic flux (Φ) per unit area. 1tesla=1wb/m
2
.

The name of the SI unit for magnetic field strength is Tesla. Magnetic fields are formed by moving electric charges.

What is Magnetic field strength?

Magnetic field strength alludes to an actual amount that is utilized as one of the essential proportions of the power of the attractive field.

The SI unit of attractive field is tesla (T). 1 Tesla is defined as the magnetic field that carries 1C charge at the speed of 1m/s which is perpendicular to the force of 1 N.

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What does a mass extinction look like in the fossil record?
O A. A layer of rock contains only fossils of living things that no longer
exist on Earth.
B. A layer of rock contains only fossils of species that presently exist
on Earth.
O C. A younger layer of rock contains a much greater variety of fossils
than a slightly older layer of rock does.
D. An older layer of rock contains a much greater variety of fossils
than a slightly younger layer of rock does.

Answers

Answer:

the answer is D

Explanation:

Mass extinctions were first identified by the obvious traces they left in the fossil record. ... Such dramatic changes in adjacent rock layers make it clear that mass extinctions were geologically rapid and suggest that they were caused by catastrophic events (e.g., a period of intense volcanic activity).

Mass extinction events wiped out many species at the same time resulting in older rock layers having more fossil variety than younger rock layers.

What are mass extinction events?

Mass extinction events are events which resulted in the mass death of many species of organisms.

Mass extinction events are presumed to have occurred in the past as seen from gaps in the fossils records.

Mass extinction events are thought to have occurred through intense volcanic activity in a particular area.

A mass extinction event in the fossil record will show an older layer of rock containing a much greater variety of fossils than a slightly younger layer of rock does.

Therefore, mass extinction events wiped out many species at the same time.

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An electrically charged object creates an electric field. The electric potential due to this object:Group of answer choicesis a vector that points either towards or away from the object, depending on the sign of the chargeis a vector that makes circular paths around the objectis a non-negative scalaris a scalar but will be positive or negative depending on the sign of the charge

Answers

Answer:

It's a scalar but will be positive or negative depending on the sign of the charge.

Explanation:

The electric potential, at a given point, can be defined as the work per unit charge needed to bring a positive test charge from infinity to this point.It's positive if the charge creating the potential is positive (because it's needed that an external force do work on the test charge against the electric field that repels the positive charge).It's negative if the charge creating the potential is negative, because in this case the field will attract the positive test charge.

HELP ITS FOR SCIENCE
1. Explain why a wrecking ball can destroy a building, but a yo-yo can’t. Use the term kinetic energy in your explanation.

2. How is speed related to kinetic energy?

Answers

Answer:

A wrecking ball has the capability to destroy a building due to the greater mass and kinetic energy than the yo-yo.

a man is trying to pull a box a distance of 3 m with a force of 20 N that makes a 35º with the horizontal.

Answers

Answer:

34.4Joules

Explanation:

Complete question

a man is trying to pull a box a distance of 3 m with a force of 20 N that makes a 35º with the horizontal. Find the workdone

Work done = Fdsin theta

Force F = 20N

distance d = 3m

theta = 35 degrees

Substitute

Workdone = 20(3)sin 35

Workdone = 60sin35

Workdone = 34.4Joules

Hence the workdone by the man is 34.4Joules

4. What is the acceleration of the car in each section?
b
с
d
a

Answers

Answer:

0-4 acceleration comes at 12 m/s where (B) stagnates at 12 m/s and remains for 4 seconds (C) is breaks being activated slowing the car to 6 m/s in 2 seconds and (D) over the course of 4 seconds brings the car to 10 m/s.

Explanation:

Acceleration is the slope of a velocity time graph.

Units are all m/s ^2

a) 3
b) 0
c) -3
d) 1 - doesn’t LOOK like a slope of 1, but if you look carefully at the Y axis, you can see it rises by 4 rather than 2.

Do you ever have a sensation of loneliness?

Answers

Answer:

nope

Explanation:

sige bigyan kitang Happy pills

How is a charged object created?

Charges are created when an object touches water.
Charges are created when the object is exposed to light.
Charges are transferred from one object to another.
Charges are transferred from the air to the object.

Answers

Answer:

Charges are transferred from one object to another.

Explanation:

The charges from one object to another are sharing there energy.

a 2kg bowling bowl is at a top of the hill with a speed of 9.8 m/s with a height of 40m. what is its potential energy

Answers

To calculate potential energy, use the formula

[tex]ep \: = mgh[/tex]

Where m is mass in kg, g is gravitational field strength in m s^-2 and h is height in metres.

So in this case, calculate

2kg × 9.8m/s × 40m

and you should find your answer.

The electric field 30cm from a van de Graaff generator is measured to be 28,300N/C. What is the charge of the van de Graaf?

Answers

Answer:

14

Explanation:

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How can you tell whether an object is neutral
or charged? What would you have to do to test
that object?

Answers

Answer:

The number of electrons that surround the nucleus will determine whether or not it is electrically charged or electrically neutral

Explanation:

how could you get the pancake to cook faster without burning it?

Answers

Answer:

put it in medium to full heat and set an alarm so that it doesn't burn

Answer:

when you're cooking  your pancakes, use clarified butter and cook on medium heat. 

A child holds a sled at rest on frictionless snow covered hill. if the sled weighs 77N,find the force T exerted by the rope on the sled and the force n exerted by the hill on the sled​

Answers

Answer:62

Explanation:

The weight of the sled is 77 N. The force by the hill on the sled is equal to its weight that is 77 N. Then the tension force exerted by the rope on the sled is being 77N sin θ, where θ be the angle of inclination.

What is force?

Force is an external agent acting on an object to change its motion or to deform it. There are various kinds of force like magnetic force, tension force, frictional force, gravitational force etc.

The weight that an object experience on earth is due to the gravitational force. The force that is exerted by a rope on an object is tension force since it is pulling from a side.

The normal force by the hill on the sled is equal to its weight that is 77 N. The tension force on the sled by the rope is dependent on the angle of inclination θ. If know the angle we can find T by the equation:

T = 77 sin θ.

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1 What is a vector field?





2 How do you know that potential energy is converted into kinetic energy in certain force fields?





3 What is the rule on electric charges attracting or repelling?
Opposites attract, equals repel



4 How can atoms use electric charges to bond?




5 Where is the potential energy of a magnet stored?




6 How can you tell which pole is the north and which pole is the south in a magnet?





7 How can you increase the potential energy of a magnetic field?




8 If you have two charges alone in space, what will they do to each other?



9 What must occur in magnets to have it generate a magnetic field?




10 What is an electromagnet? A magnet that is made from metal and electrified and with a coil

Answers

Answer:

1. a vector field is an assignment of a vector to each point in a subset of space.

2. The direct answer is that it happens through Newton’s second law. If an object is in a potential field that is different at different points in space, then the object will experience a force in the direction in which the potential energy decreases. Newton’s second law says that a force causes a change in motion, which changes the kinetic energy.

3. According to Coulomb, the electric force for charges at rest has the following properties: Like charges repel each other; unlike charges attract. Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges.

4. Ions are charged atoms that form when an atom donates or accepts one or more negatively charged electrons. Cations (ions with a positive charge) are attracted to anions (ions with a negative charge). This attraction is called an ionic bond.

5. Magnetic Field

Hope it Helps!!!!

You throw a small rock straight up from the edge of a highway bridge that crosses a river. The rock passes you on its way down, 5.00 s after it was thrown. What is the speed of the rock just before it reaches the water 22.0 m below the point where the rock left your hand? Ignore air resistance.

Answers

Answer:

Explanation:

for vertical movement , time to reach the top = time to reach the hand = 2.5 s

v = u - gt

At the top , v = 0 , time t = 2.5 s

0 = u - g x 2.5

u = 2.5 x 9.8 = 24.5 m /s

velocity of throw = 24.5 m /s

So , when it passes the hand on its way down , it will have velocity equal to 24.5 m /s and it will accelerate downwards . Let its velocity down by 22 m be v

v² = u² + 2 g s

= 24.5² + 2 x 9.8 x 22

= 600.25 + 431.2

= 1031.45

v = 32.11 m /s .

Honeybees accumulate charge as they fly, and they transfer charge to the flowers they visit. Honeybees are able to sense electric fields; tests show that they can detect a change in field as small as 0.77 N/C. Honeybees seem to use this sense to determine the charges on flowers in order to detect whether or not a flower has been recently visited, so they can plan their foraging accordingly. As a check on this idea, let's do a quick calculation using typical numbers for charges on flowers.If a bee is at a distance of 24 cm, can it detect the difference between flowers that have a +30 pC charge and a +40 pC charge?

Answers

Answer:

difference between the field  = 1.56 N/C

as; 1.56 N/C is greater than 0.77 N/C;

Hence, Honeybees can detected the difference

Explanation:

Given the data in the question;

distance r = 24 cm = 0.24 m

charge 1 Q1 = +30 pC = 30×10⁻¹² C

charge 2 Q2 = +40 pC = 40×10⁻¹² C

Now, electric field due to +30 pC charge

E1 = kQ1/r²

where coulomb constant k is 9 × 10⁹ N.m²/C²

so we substitute

E1 = [( 9 × 10⁹ ) × (30×10⁻¹²)] / (0.24)²

E1 = 0.27 / 0.0576

E1 = 4.69 N/C

electric field due to +40 pC charge

E2 = kQ1/r²

E2 = [( 9 × 10⁹ ) × (40×10⁻¹²)] / (0.24)²

E2 = [( 9 × 10⁹ ) × (40×10⁻¹²)] / (0.24)²

E2 = 0.36 / 0.0576

E2 = 6.25 N/C

Now,

E2 = E1 =  6.25 N/C - 4.69 N/C = 1.56 N/C

difference between the field  = 1.56 N/C

as; 1.56 N/C is greater than 0.77 N/C;

Hence, Honeybees can detected the difference

Select the correct answer.
The oceanic Nazca plate is being subducted beneath the continental South American plate. Which type of plate boundary is this?
OA continental-oceanic convergent
ОВ. oceanic-oceanic convergent
OC divergent
OD. strike-slip
ОЕ.
transform
Reset
Next

Answers

Answer:

A. continental-oceanic convergent

Explanation:

I knew it couldn't be B because it's oceanic and continental, not oceanic and oceanic.

Next, I noticed the word convergent, which implies "coming together" to me.

I looked it up and noticed the term convergent referred to a plate boundary where a plate slips under (subducted) another, so I knew it was A.

Hopefully, this helps you understand the question better. Have a great day!

Scientists have investigated how quickly hoverflies start beating their wings when dropped both in complete darkness and in a lighted environment. Starting from rest, the insects were dropped from the top of a 50 - cm tall box. In the light, those flies that began flying 200 m s after being dropped avoided hitting the bottom of the box 87 % of the time, while those in the dark avoided hitting only 25 % of the time.

Required:
a. How far would a fly have fallen in the 200 ms before it began to beat its wings?
b. How long would it take for a fly to hit the bottom if it never began to fly? In seconds.

Answers

Answer:

Explanation:

a )

Hoverfly will fall with acceleration equal to g .

Initial velocity of fall of hoverflies u = 0

displacement ( vertical ) h = ?

time t = 0.2 s

acceleration due to gravity g = 9.8 m / s²

h = ut + 1/2 g t²

= 0 + .5 x 9.8 x .2²

= .196 m

= 19.6 cm

b )

Time taken to fall by 50 cm or 0.5 m under free fall from initial position .

.5 = 0 + .5 x 9.8 t²

t² = .1020

t = .319 s = 319 ms .

Sketch the resultant field pattern around the following current carrying conductors and
show the direction of the forces acting on the conductor.​

Answers

Cccccccvvvvvcjjjjjjjjjjkllk ki e

A 150.0 g baseball has a velocity of 28.5 m/s. What is its kinetic energy in J

Answers

Answer:

KE = 60.91875 J

Explanation:

First, convert the mass of the ball into kg, since we want the answer in J (SI system):

150 g = 0.15 kg

then use the kinetic energy formula

[tex]KE=\frac{1}{2} m*v^{2} \\KE=\frac{1}{2} (0.15)*(28.5)^{2}\\KE=60.91875 J[/tex]

The power lines are at a high potential relative to the ground, so there is an electric field between the power lines and the ground. To maximize the potential difference between one end of the fluorescent tube and the other, how should the tube be held? Select the best answer from the choices provided. View Available Hint(s) Select the best answer from the choices provided. The potential difference between the ends of the tube does not depend on the tube's orientation. The tube should be held horizontally, parallel to the ground. The tube should be held vertically, perpendicular to the ground.

Answers

Answer:

The tube should be held vertically and perpendicular to the ground.

Explanation:

Answer: The tube should be held vertically and perpendicular to the ground. The reason is as follows:

Reasoning:

The power lines are parallel to the ground hence, their electric field will be perpendicular to the ground and equipotential surface will be cylindrical.

Hence, if you will put fluorescent tube parallel to the ground then both the ends of the tube will lie on the same equipotential surface and the potential difference will be zero.

So, to maximize the potential the ends of the tube must be on different equipotential surfaces. The surface which is near to the power line has high potential value and the surface which is farther from the line has lower potential value.

hence, to maximize the potential difference, the tube must be placed perpendicular to the ground.


A bicyclist accelerates from rest to a speed of
5.0 meters per second in 10 seconds. During the
same 10 seconds, a car accelerates from a speed
of 22 meters per second to a speed of 27 meters
per second. Compared to the acceleration of the
bicycle, the acceleration of the car is

Answers

Answer:

They have the same acceleration of 0.5m/s2 (please note m/s2 is the unit for acceleration and 2 is the power of s)

Explanation:

acceleration= velocity ÷ time

and the time is said to be 10seconds

velocity of car will be the new velocity- the initial velocity = 27-22= 5

acceleration= 5÷10

acceleration= 0.5

hope this helped

now hit that crown button :)

To increase the gravitational force between the two objects above, I could
Your answer:
A. increase the mass of the objects and decrease the distance between the objects.

B. increase BOTH the distance and the mass between the two objects

C. decrease the mass of the objects and increase the distance between the objects.

D. decrease BOTH the mass and distance between the two objects.

Answers

Answer:

Option A

Explanation:

Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end of a rope is attached to the bus and the other is tied around Magnus's waist. If a force gauge placed halfway down the rope reads out a constant 2100 Newtons while Magnus pulls the bus a distance of 1.30 meters, how much work does the tension force do on Magnus

Answers

Answer:

Workdone = -2730 J

Explanation:

Formula for workdone is;

W = Force × Displacement

Now, according to Newton's 3rd law of motion, to every action, there is an equal and opposite reaction.

In the question given, we are told that a force gauge placed halfway down the rope reads out a constant 2100 Newtons while Magnus pulls the bus. This means that the force exerted by the rope on Magnus acts in an opposite direction to that which Magnus does to the rope.

Therefore, the force will be in the negative direction.

So;

Workdone = -2100 N × 1.3 m

Workdone = -2730 J

Question 2 of 25
Which three statements are true about the wave shown?
A. The wave is a longitudinal wave.
B. The wave could be an electromagnetic wave.
C. The wave could be a sound wave.
D. The wave is a mechanical wave.

Answers

Answer:

ACD

Explanation:

according to it's description above

The wave is a mechanical wave and can also be sound wave also the wave is a longitudinal wave. The correct option is A, C, and D.

What is mechanical wave?

A mechanical wave is one whose energy cannot be transmitted via a vacuum. To transfer their energy from one place to another, mechanical waves need a medium.

A mechanical wave is something like a sound wave. A vacuum can not be traversed by sound waves.

Waves like mechanical waves require a medium to travel through. Non-mechanical waves are those that can travel through any medium.

Mechanical waves include, but are not limited to, sound waves, water waves, and seismic waves.

The three claims are accurate as follows: The wave is a longitudinal wave and can also be a mechanical wave or a sound wave.

Thus, the correct option is A, C, and D.

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Your question seems incomplete, the missing image is:

If your mass is 63.7kg and standing 7.5m away from a boulder with a mass of 9750.6kg what is the gravitational force?

Answers

The gravitational force is determined as 7.37 x 10⁻⁷ N.

What the gravitational force?

The gravitational force is determined by applying Newton's law of universal gravitation.

Mathematically, the formula for the Newton's law of universal gravitation is given as;

Fg = ( Gm₁m₂ ) / ( r² )

where;

G is universal gravitation constantm₁ is your massm₂ is the mass of the boulderr is the distance between you and the boulder

Fg = ( 6.67 x 10⁻¹¹ x 63.7 x 9750.6 ) / ( 7.5² )

Fg = 7.37 x 10⁻⁷ N

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What is the measure of minor arc AB?

Answers

the answer is b, you are correct. here’s why.

a is angle p which is 286

b is correct because it looks like it would fit based on what 286 looks like

c is too small

d is way too small

hope this helps brainlist would be much appreciated:)

Jack weighs 170 lbs and is 72 inches tall. He is pulling horizontally on a door handle situated at his shoulder height. Actually, it is his body weight and lean that creates this pulling action (a hint). His center of mass while standing erect is 61 percent of his body height, measured from the floor upwards. The door handle is 60 inches above the ground, and again he is pulling purely horizontally on this handle.

If Jack's lean angle is 20 degrees and he is leaning back - pivoting about his heels, how much force does he apply to the door handle?

Include units in your answer, lbs.

Express your answer to the nearest 0.1 lbs.

Answers

Answer:

He is pulling horizontally on a door handle situated at his shoulder height. ... His Center Of Mass While Standing Erect Is 61 Percent Of His Body Height, Measured ... Actually, it is his body weight and lean that creates this pulling action (a hint).

72ibs

Estimate the constant rate of withdrawal (in m3 /s) from a 1375 ha reservoir in a month of 30 days during which the reservoir level dropped by 0.75 m in spite of an average inflow into the reservoir of 0.5 Mm3 /day. During the month, the average seepage loss from the reservoir was 2.5 cm, total precipitation on the reservoir was 18.5 cm and the total evaporation was 9.5 cm

Answers

Answer:

Explanation:

1 ha = 10⁴ m²

1375 ha = 1375 x 10⁴ m² = 13.75 x 10⁶ m²

In flow in a month = .5 x 10⁶ x 30 m³ = 15 x 10⁶ m³

Net inflow after all loss = 18.5 - 9.5 - 2.5 cm = 6.5 cm = .065 m

Net inflow in volume = 13.75 x 10⁶ x .065 m³= .89375 x 10⁶ m³

Let Q be the withdrawal in m³

Q - 15 x 10⁶ - .89375 x 10⁶ = 13.75 x 10⁶ x .75 = 10.3125 x 10⁶

Q = 26.20 x 10⁶ m³

rate of withdrawal per second

= 26.20 x 10⁶ / 30 x 24 x 60 x 60

= 26.20 x 10⁶ / 2.592 x 10⁶

= 10.11 m³ / s

The rate of withdrawal is 10.11 cubic meter per second

Given-

Total reservoir is 1375 hectare. which is equal to [tex]1375\times 10^4[/tex] meter square.

The average seepage loss from the reservoir is 2.85 cm or 0.0285 m.

Total precipitation on the reservoir is 18.5 cm or 0.185 m.

Total evaporation is 9.5 cm or 0.085 m.

The average inflow into the reservoir is [tex]0.5\times10^6[/tex] cubic meter per day.

The total inflow in a month can be calculate is

[tex]=0.5\times 30=1500\times10^4[/tex]

Net inflow is equal to the total precipitation on the reservoir subtract by all the losses.It can be represent as,

[tex]Q_{net}=0.185 - 0.095 - 0.025[/tex]

[tex]Q_{net}=0.065[/tex]

Total volume inflow is equal to the product of net inflow and total reservoir,

[tex]V_{net} =1375\times 10^4\times Q_{net}[/tex]

[tex]V_{net} =1375\times 10^4\times 0.065[/tex]

[tex]V_{net} =89.375[/tex]

The constant rate of withdrawal in cubic meter can be calculated by adding the net inflow in a month, total volume inflow and the reservoir.

[tex]Q=1375\times 10^4\times 0.75+89.375\times 10^4+1500\times10^4[/tex]

[tex]Q=2620\times10^4[/tex]

For per second withdrawal,

[tex]Q=\dfrac{2620\times10^4}{30\times24\times60\times60}[/tex]

[tex]Q=10.11[/tex]

Hence, the rate of withdrawal is 10.11 cubic meter per second.

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