A cannon sits on top of a cliff that is 20 meters above an area of level ground. It fires a 5 kg cannonball horizontally (cannonball A) at 5 meters/second. At the same time, a second cannonball (cannonball B) is dropped from the same height. If air resistance is ignored, which cannonball will hit the ground first?
Note: The gravitational acceleration due to the Earth is 9.8 m/sec².
A. Cannonball A
B. Cannonball B
C. Both will hit the ground at the same time.
D. It can not be found from the given information.​

The structure of zinc telluride crystals is formed by a dense packing of anions, and cations occupy inter-nodes.

a) The structure of zinc telluride crystals is formed by a close packing of anions in a hexagonal close-packed (HCP) lattice. The stacking sequence of HCP lattice is ABABAB.

b) The cations occupy octahedral voids which are formed in between the closely packed anions.

c) In HCP lattice, there are 6 octahedral voids per unit cell. Each unit cell contains 2 zinc cations. Hence, the fraction of the available voids occupied by cations is 2/6 or 1/3.

d) Here is a depiction of two densely packed planes of anions stacked in the AB sequence with the voids filled with cations

 B           Cation in one octahedral void

  A       B       Cation in another octahedral void

        A           Anion

        A           Anion

  B       A       Cation in one octahedral void

        B           Cation in another octahedral void

The two densely packed planes of anions are labeled as A and B. Hence, The cations occupy the octahedral voids between these planes.

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Letter F shows the ball when it has the maximum kinetic energy.

Letter A shows the ball when it has the maximum potential energy.

Letter G shows the ball when it has the least kinetic energy.

Letter C shows the ball when it has the least potential energy.

The kinetic energy of an object is  described as the form of energy that it possesses due to its motion.

potential energy  on the hand is described as  the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.

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Answer and Explanation:

A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.

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A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.

Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body

Answer:

We can find the position of the center of mass of the system by using the formula:

Xcm = (m1x1 + m2x2 + m3x3 + m4x4) / (m1 + m2 + m3 + m4)

where Xcm is the x-coordinate of the center of mass, m1, m2, m3, and m4 are the masses of the point masses, and x1, x2, x3, and x4 are their respective x-coordinates.

Similarly, we can find the y-coordinate of the center of mass using the formula:

Ycm = (m1y1 + m2y2 + m3y3 + m4y4) / (m1 + m2 + m3 + m4)

where Ycm is the y-coordinate of the center of mass, m1, m2, m3, and m4 are the masses of the point masses, and y1, y2, y3, and y4 are their respective y-coordinates.

Let's label the masses and coordinates as follows:

m1 = 2kg, x1 = 0cm, y1 = 0cm

m2 = 4kg, x2 = 2cm, y2 = 0cm

m3 = 6kg, x3 = 2cm, y3 = 2cm

m4 = 8kg, x4 = 0cm, y4 = 2cm

Substituting these values into the formulas, we get:

Xcm = (2kg x 0cm + 4kg x 2cm + 6kg x 2cm + 8kg x 0cm) / (2kg + 4kg + 6kg + 8kg) = 2cm

Ycm = (2kg x 0cm + 4kg x 0cm + 6kg x 2cm + 8kg x 2cm) / (2kg + 4kg + 6kg + 8kg) = 1cm

Therefore, the center of mass of the system is located 2cm from corner A in the x-direction and 1cm from corner A in the y-direction.

Explanation:

To convert the equation  [tex]∆_{W}[/tex]= [tex]V_{ab}[/tex] I[tex]∆_t[/tex] to express power P for the circuit, we need to divide both sides of the equation by [tex]∆_t[/tex]. Option B is correct.

The power P for the circuit can be expressed using the equation;

P = [tex]∆_{W}[/tex]/[tex]∆_t[/tex]

where [tex]∆_{W}[/tex] is work done on the charge and [tex]∆_t[/tex] is time interval for which the work is done.

Starting with the equation [tex]∆_{W}[/tex]= [tex]V_{ab}[/tex] I[tex]∆_t[/tex], we can rearrange it as follows:

[tex]∆_{W}[/tex]/[tex]∆_t[/tex] = [tex]V_{ab}[/tex] I

Now, substituting the expression for power P, we get;

P = [tex]V_{ab}[/tex] I

Therefore, to convert the equation [tex]∆_{W}[/tex] = [tex]V_{ab}[/tex] I[tex]∆_t[/tex] to express power P for the circuit, we need to divide both sides of the equation by [tex]∆_t[/tex], as in option B;

[tex]∆_{W}[/tex]/[tex]∆_t[/tex] = [tex]V_{ab}[/tex] I

P = [tex]∆_{W}[/tex]/[tex]∆_t[/tex]

P = [tex]V_{ab}[/tex] I/[tex]∆_t[/tex]

Dividing both sides by [tex]∆_t[/tex], we get:

P =  [tex]V_{ab}[/tex]I

Hence, B. is the correct option.

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Paul Cezanne's Still Life with Apples in a Bowl (1879-83) represents a break with the tradition of using linear perspective in art.

One of the pioneers of modern art, Cezanne used a novel approach to painting at the time. In his still life paintings, Cezanne represented things utilizing a system of flattened planes and simplified forms rather than the conventional perspective techniques that provide the impression of depth and space.

Additionally, he played around with color, relying on color blocks rather than shading and modeling to convey a sense of volume and form.

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A student slides a block on a surface by applying a force of 11 newtons (N) toward the left. The friction force on the block is 4 N and which is in right direction. the Net force acting on the box is 11-4 = 7N.( towards left)

Force is responsible for the motion of an object. it produces acceleration in the body. According to newton's second law force is mass times acceleration i.e. F =ma. Its SI unit is N which is equivalent to kg.m/s². There are two types of forces, balanced force and unbalanced force. Balanced forces are those forces which are opposite in direction and equal in magnitude. When Net force acting on a body is zero then we call it as balanced force. Balanced force is not responsible for the motion of the body. ex. when two persons pulling rope on both end with equal magnitude which cause them to be balanced force have 0 net force. Unbalanced forces are those when resultant of all the forces is not equal to zero is called as unbalanced force. unbalanced force is responsible for the motion of the body.

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Answer:

46.5 N

Explanation:

attached is explanation

The power being dissipated by the appliance is approximately 0.182 W.

To determine the power being dissipated by the appliance, we need to use Ohm's Law and the formula for power:

Ohm's Law: V = IR

where V is the voltage, I is the current, and R is the resistance.

Power formula: P = IV

where P is the power, I is the current, and V is the voltage.

First, let's find the current through the circuit:

V_battery = V_appliance + V_voltmeter

where V_battery is the voltage of the battery, V_appliance is the voltage across the appliance, and V_voltmeter is the voltage across the voltmeter.

Rearranging this equation to solve for V_appliance:

V_appliance = V_battery - V_voltmeter

V_appliance = 15.0 V - 11.3 V

V_appliance = 3.7 V

Now we can use Ohm's Law to find the current:

I = V_appliance / R

I = 3.7 V / 75.0 Ω

I = 0.0493 A

Finally, we can use the power formula to find the power:

P = IV

P = 0.0493 A x 3.7 V

P = 0.182 W

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--The complete question is, An idealized voltmeter is connected across the terminals of a 15.0 V battery. A 75.0 Ω appliance is also connected across the battery terminals. When the voltmeter measures 11.3 V, how much power is being dissipated by the appliance?--

As thermal energy is added to a sample of water, the potential energy of its molecules increases, and then the kinetic energy of its molecules increases.

The sections of the heating curve illustrate this process  is B followed by D

Therefore option A is correct.

Thermal energy (also called heat energy) is described as being produced when a rise in temperature causes atoms and molecules to move faster and collide with each other.

some factors of thermal energy include:

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The current I through the 4 kΩ resistor in the original circuit is 0.199 mA.

Thévenin's theorem states that any linear network of voltage and current sources and resistors can be replaced by an equivalent circuit consisting of a single voltage source and a single resistor. The equivalent circuit provides the same output voltage and current as the original circuit for any external load connected to it.

To find the current I in the circuit using Thévenin's theorem, we need to follow these steps:

Step 1: Find the Thévenin equivalent voltage (Vth) across the 4 kΩ resistor.

To find Vth, we need to first find the open circuit voltage (Voc) across the 4 kΩ resistor. We can do this by removing the 4 kΩ resistor and finding the voltage between its two terminals using a voltage divider:

Voc = 6 kΩ/(2 kΩ + 6 kΩ) x 2 mA = 1.2 V

Next, we need to find the Thévenin equivalent resistance (Rth) across the 4 kΩ resistor. To do this, we need to short-circuit all the independent voltage sources (in this case, there is only one) and find the equivalent resistance seen from the terminals of the 4 kΩ resistor. With the 2 mA current source shorted out, the 2 kΩ and 4 kΩ resistors are in parallel:

Rth = 2 kΩ || 4 kΩ = 1.33 kΩ

Step 2: Replace the original circuit with the Thévenin equivalent circuit.

We can now replace the original circuit with the Thévenin equivalent circuit, which consists of a voltage source Vth = 1.2 V in series with a resistor Rth = 1.33 kΩ.

Step 3: Find the current I through the 4 kΩ resistor in the Thévenin equivalent circuit.

To find the current I, we can use Ohm's law:

I = Vth/(Rth + 4 kΩ) = 1.2 V/(1.33 kΩ + 4 kΩ) = 0.199 mA

Therefore, the current I through the 4 kΩ resistor in the original circuit is 0.199 mA.

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Answer:4 m/s

Explanation:

With a current shunt, the current is obtained by measuring voltage across the current shunt and calculating using Ohm's Law.

A current shunt is a device that is used to measure electric current. It is a small resistor placed in parallel with the load (or the element being measured), that creates a known small voltage drop proportional to the current flowing through it.

By measuring this voltage drop and using Ohm's law, the current flowing through the shunt (and the load) can be calculated. Current shunts are commonly used in high-current applications, such as in power plants, electrical distribution systems, and electric vehicles.

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With a current shunt, the current is obtained by measuring the voltage drop across the current shunt and calculating using Ohm’s Law. A current shunt is a device that creates a low-resistance path for electric current, to allow it to pass around another point in the circuit. In current measuring, shunts allow the measurement of high current values by placing a resistor of low, known resistance in parallel with a voltmeter.

The mass of the helium sample is approximately 0.187 g.

To solve this problem, we can use following formula:

w = nR(T2 - T1)

We can rearrange this formula to solve for n:

n = w / (R * (T2 - T1))

To find the mass of the helium sample, we can use following formula:

m = n * M

where m is the mass of the sample, n is  number of moles of gas, and M is the molar mass of helium.

Substituting the given values into the first equation, we get:

70 J = n * 8.31451 J/mol*K * (358 K - 283 K)

Simplifying this equation, we get:

n = 0.0467 mol

Substituting this value into the second equation, we get:

m = 0.0467 mol * 4 g/mol = 0.187 g

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The initial temperature of the water was 0°C and the original temperature of the ice was -78.8°C.

First, we need to determine how much heat was transferred from the water to the ice to melt the ice and raise its temperature to 0°C.

The heat is required to melt the ice will be;

Q₁ = m_ice x Lf

where m_ice is the mass of the ice and[tex]L_{f}[/tex] is the latent heat of fusion of ice.

Q₁ = 1.0 kg x 3.3 x 10⁵ J/kg

= 3.3 x 10⁵ J

The heat required to raise the temperature of the melted ice from -x°C to 0°C is;

Q₂ = m_ice x c_ice x ΔT

where c_ice is the specific heat capacity of ice and ΔT is the change in temperature.

Q₂ = 1.0 kg x 2093 J/kg.°C x (0 - (-x))°C

= 2093x J

The heat lost by the water will be equal to the heat gained by the ice;

Q₁ + Q₂ = m_water x Cw x ΔT

where m_water is the mass of the water and Cw is the specific heat capacity of water.

3.3 x 10⁵ J + 2093x J = 1.0 kg x 4186 J/kg.°C x (0 - T)°C

Solving for T, we get;

T = -[(3.3 x 10⁵ J + 2093x J)/(4186 J/kg.°C)]

= -78.8°C

Therefore, the original temperature of the ice was -78.8°C.

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The wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.

Frequency is the number of cycles of a periodic waveform that occur per unit of time. It is measured in Hertz (Hz).

We can use the equation λ=2L/n, where λ is the wavelength, L is the length of the string, and n is the harmonic number. Since the string has fixed ends, the harmonics must be odd-numbered, so we have n=1 for the fundamental frequency, n=3 for the second harmonic (315 Hz), and n=5 for the third harmonic (420 Hz).

Using n=1 and λ=2L/n, we get:

λ = 2L/1

λ = 2L

Using n=3 and λ=2L/n, we get:

λ = 2L/3

Using n=5 and λ=2L/n, we get:

λ = 2L/5

We can use the formula f=v/λ to relate the wave speed v, wavelength λ, and frequency f. For the two consecutive harmonics, we can write:

v/λ1 = f1

v/λ2 = f2

Since the two harmonics are consecutive, we can assume that they correspond to adjacent values of n, so we have:

λ1 = 2L/1 = 2L

λ2 = 2L/3

Substituting these values into the above equations and solving for v, we get:

v = f1λ1 = f2λ2 = (420 Hz)(2L) / (2L) = (315 Hz)(2L)/(2L/3) = 840 cm/s

To find the fundamental frequency, we use the formula f=v/λ1:

f = v/λ1 = 840 cm/s / 2L = (840 cm/s) / (0.75 m) = 1120 Hz

Therefore, the wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.

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The arrows are drawn in the figure which shows gravitational forces on each person on earth.

Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,

F∝ m₁.m₂

F ∝ 1/r²

F = G m₁,m₂÷r²

where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².

Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].

This is analogous with coulomb's law which gives force between two charges.

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Answer:

The velocity of the box is related to the angular velocity of the spool, which is given by the equation:

v = r * ω

where r is the radius of the spool and ω is the angular velocity of the spool. The angular velocity of the spool, in turn, is related to the torque applied to the spool by the tension in the string, which is given by the equation:

τ = I * α

where τ is the torque, I is the moment of inertia of the spool, and α is the angular acceleration of the spool.

The tension in the string is equal to the weight of the box, which is given by:

T = m * g

Putting all of these equations together, we can solve for the time it takes for the box to reach the floor. Here's how:

First, we can find the angular acceleration of the spool using the torque equation:

τ = I * α

T = m * g = τ

m * g = I * α

α = (m * g) / I

α = (35.30 kg * 9.81 m/s^2) / 4.00 kg*m^2

α = 86.53 rad/s^2

Next, we can find the angular velocity of the spool using the kinematic equation:

ω^2 = ω_0^2 + 2 * α * θ

where ω_0 is the initial angular velocity (which is zero), θ is the angle through which the spool has turned (which is equal to the distance the box has fallen divided by the radius of the spool), and ω is the final angular velocity (which is what we want to find). Solving for ω, we get:

ω^2 = 2 * α * θ

ω = sqrt(2 * α * θ)

ω = sqrt(2 * 86.53 rad/s^2 * (3.50 m / 0.10 m))

ω = 166.6 rad/s

Finally, we can find the time it takes for the box to reach the floor using the equation:

v = r * ω

v = 0.10 m * 166.6 rad/s

v = 16.66 m/s

t = d / v

t = 3.50 m / 16.66 m/s

t = 0.21 s

Answer:

An electromagnet is a type of magnet that is created by an electric current flowing through a coil of wire wrapped around a magnetic core. The core is usually made of a ferromagnetic or ferrimagnetic material, such as iron, that can increase the magnetic field strength by hundreds or thousands of times.

The effects on an electromagnet of removing or replacing the core depend on the properties of the core material. Here are some possible effects:

i) Removing the core: This will reduce the magnetic field strength of the electromagnet, as the core material is no longer concentrating the magnetic field lines. The electromagnet will become an air-core coil, which has a much lower magnetic permeability than a ferromagnetic or ferrimagnetic core. The electromagnet will also lose its ability to retain some magnetism when the current is switched off, as the core material is no longer magnetized.

ii) Replacing the iron core with a steel core: This will change the magnetic field strength and the magnetic behavior of the electromagnet, depending on the type and quality of steel used. Steel is an alloy of iron and other elements, such as carbon, manganese, nickel, chromium, etc. Some types of steel have higher magnetic permeability than iron, which means they can increase the magnetic field strength more than iron. However, some types of steel have lower magnetic permeability than iron, which means they can decrease the magnetic field strength. Steel also has higher coercivity and hysteresis than iron, which means it can retain more magnetism when the current is switched off, but it also requires more energy to magnetize and demagnetize. Steel can also be affected by temperature changes, corrosion, and mechanical stress, which can alter its magnetic properties over time.

(i) The work done on the point charge by the electric force when moved from A to B is 2.1 x 10⁻⁶ J.

(ii) The work done on the point charge by the electric force when moved from A to C is -5.5 x 10⁻⁶ J.

The work done by an electric force is equal to the negative of the change in potential energy, which is given by the product of the charge and the change in potential. The change in potential between two points is equal to the potential difference between those points.

For (i), the potential difference between A and B is 6 V, so the work done is (3.9 x 10⁻⁷ C) x (-6 V) = -2.1 x 10⁻⁶ J (negative because the charge moves from higher to lower potential).

For (ii), the potential difference between A and C is -15 V, so the work done is (3.9 x 10⁻⁷ C) x (-(-15 V)) = -5.5 x 10⁻⁶ J (negative because the charge moves from lower to higher potential).

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Answer:

3000 seconds

Explanation:

46)

Since air resistance is ignored, both cannonballs will fall with the same acceleration due to gravity, which is approximately 9.8 m/s^2. The horizontal velocity of cannonball A does not affect its vertical motion, so it will fall at the same rate as cannonball B.

The time it takes for an object to fall to the ground from a certain height is given by the formula t = sqrt(2h/g), where t is the time, h is the initial height, and g is the acceleration due to gravity.

For cannonball B, which is dropped from a height of 20 meters, the time it takes to reach the ground is:

t = sqrt(2h/g) = sqrt(2*20/9.8) = 2.02 seconds

For cannonball A, which is fired horizontally with a velocity of 5 m/s, the time it takes to reach the ground is also 2.02 seconds, since the vertical motion is the same as cannonball B.

Therefore, both cannonballs will hit the ground at the same time.

47)

The recoil speed of the cannon can be calculated using the principle of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it.

Before firing, the total momentum of the system is zero, since the cannon and cannonball A are at rest. After firing, the cannonball A has a momentum of 5 kg * 5 m/s = 25 kg m/s to the right, so the cannon must have an equal and opposite momentum to the left in order to conserve momentum.

The mass of the cannon is 500 kg, so its momentum after firing will be:

p = -25 kg m/s

The velocity of the cannon can be found using the equation:

p = mv

where p is the momentum, m is the mass, and v is the velocity. Solving for v, we get:

v = p/m = (-25 kg m/s) / (500 kg) = -0.05 m/s

Since the momentum of the cannon is negative, the recoil velocity is also negative, indicating that the cannon will move to the left after firing. The magnitude of the recoil velocity is 0.05 m/s, or approximately 0.18 km/h.

There will be no change in the ration of Q/V. Therefore the correct answer is (a).

The ratio of charge Q to voltage V across a capacitor is given by:

Q/V = C

Where C is the capacitance of the capacitor.

If the capacitance is doubled, the new capacitance C' becomes 2C. Substituting into the equation, we get:

Q/V = C

Q/V = 2C/2 = C'

So the ratio of Q to V remains the same, and there is no change in the ratio Q/V when the capacitance is doubled.

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Answer:

When you add 20 ml of vegetable oil to a beaker filled with half water and 20 ml of honey, the honey will settle at the bottom of the beaker, the vegetable oil will float on top of the water, and the honey will form a layer between the vegetable oil and the water. This happens because honey is denser than water, while vegetable oil is less dense than water. The difference in density causes the honey to sink to the bottom, while the vegetable oil floats to the top. Honey and vegetable oil are not miscible because they are not chemically compatible. They are both made up of different types of molecules, which do not mix together. Honey is made up of a complex mixture of sugars, while vegetable oil is made up of triglycerides. These different molecules do not dissolve into each other, which is why they separate into distinct layers in the beaker.

Hope this helps.

A hollow glass sphere has a density of 1.3g/cm at 20 C. Glycerine has a density of 1.26 g/cm at 20 C.

To determine the temperature at which the hollow glass sphere begins to float in glycerine, we need to calculate the density of glycerine at various temperatures and compare it to the density of the glass sphere.

The density of glycerine changes with temperature, so we need to use a density-temperature chart or equation to determine the density of glycerine at different temperatures.

Assuming the hollow glass sphere has a uniform wall thickness, we can calculate its volume by subtracting the volume of the hollow interior from the volume of the whole sphere

Volume of sphere = (4/3)π[tex]r^{3}[/tex]

Volume of hollow interior = (4/3)π[tex](r-t)^{3}[/tex]

Volume of glass wall = (4/3)π([tex]r^{3}[/tex] - [tex](r-t)^{3}[/tex]), where t is the thickness of the glass wall.

From the density and volume of the glass sphere, we can determine its mass

Mass of glass sphere = Density of glass sphere x Volume of glass sphere

Next, we can use Archimedes' principle to determine the volume of glycerine displaced by the glass sphere when it is submerged in the glycerine

Volume of glycerine displaced = Mass of glass sphere / Density of glycerine at the given temperature

When the glass sphere floats, the volume of glycerine displaced will be equal to the volume of the glass sphere. Thus, we can set the two volumes equal to each other and solve for the temperature at which the density of glycerine matches the density of the glass sphere

Volume of glass sphere = Volume of glycerine displaced

(4/3)π[tex]r^{3}[/tex] - (4/3)π[tex](r-t)^{3}[/tex] = Mass of glass sphere / Density of glycerine at the given temperature

Hence, for the temperature requires knowing the radius and thickness of the glass sphere and the mass of the sphere.

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Answer:0.65606 -> 0.66

Explanation:

Press 2nd on your calculator then hit sin, this will give you the inverse of sin. enter 0.61 in the ( ) and then enter.