Answer:
Focal length (f) = 1/2 (Object distance + Image distance)
f = 1/2 (12.2 cm + 25.0 cm)
f = 18.6 cm
what is the full distance when an object is thrown at 35 m/s at an angle of 45 degrees
Okay, here are the steps to calculate the full distance traveled when an object is thrown at a certain speed and angle:
You have the initial velocity (v): 35 m/s
You have the launch angle (θ): 45 degrees
We need to split the initial velocity into its horizontal (vx) and vertical (vy) components.
To calculate vx (horizontal component):
vx = v * cosθ
vx = 35 * cos(45) = 24.7 m/s
To calculate vy (vertical component):
vy = v * sinθ
vy = 35 * sin(45) = 24.7 m/s
We can calculate the horizontal distance (d) traveled using:
d = vx * t (where t is time)
Since there is no air resistance, the vertical velocity (vy) will remain constant. This means the time the object is in the air is:
t = vy / g (where g is acceleration due to gravity, 9.8 m/s^2)
t = 24.7 / 9.8 = 2.52 seconds
Now we can calculate the full horizontal distance traveled:
d = vx * t
d = 24.7 * 2.52
= 62.3 meters
So the full distance the object will travel when thrown at 35 m/s at a 45 degree angle is approximately 62 meters.
Let me know if you have any other questions!
Answer:
To calculate the full distance traveled by an object thrown at a velocity of 35 m/s at an angle of 45 degrees, we need to consider the horizontal and vertical components of the motion separately.
The horizontal component of the motion remains constant throughout the trajectory and is given by:
Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)
In this case, the initial velocity is 35 m/s, the angle is 45 degrees, and we need to find the time of flight.
The time of flight can be calculated using the vertical component of the motion. The vertical motion can be described using the equation:
Vertical displacement = (Initial velocity * sin(angle))^2 / (2 * acceleration)
Where the initial velocity is 35 m/s, the angle is 45 degrees, and the acceleration is the acceleration due to gravity, approximately 9.8 m/s^2.
The vertical displacement is zero at the highest point of the trajectory since the object comes back down to the same height it was launched from. So we can solve the equation for the time of flight.
Using these calculations, we can find the horizontal distance traveled by the object.
Let's calculate step by step:
Step 1: Calculate the time of flight
Vertical displacement = 0 (at the highest point)
0 = (35 * sin(45))^2 / (2 * 9.8)
0 = (24.75^2) / 19.6
0 = 616.0125 / 19.6
0 = 31.43
Step 2: Calculate the time of flight
Vertical displacement = (Initial velocity * sin(angle)) * time - (1/2) * acceleration * time^2
0 = (35 * sin(45)) * time - (1/2) * 9.8 * time^2
0 = 24.75 * time - 4.9 * time^2
4.9 * time^2 - 24.75 * time = 0
time * (4.9 * time - 24.75) = 0
time = 0 (initial point) or 24.75 / 4.9
time = 5.05 seconds
Step 3: Calculate the horizontal distance
Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)
Horizontal distance = 35 * 5.05 * cos(45)
Horizontal distance = 35 * 5.05 * (sqrt(2)/2)
Horizontal distance = 88.96 meters
Therefore, when an object is thrown at 35 m/s at an angle of 45 degrees, the full distance traveled is approximately 88.96 meters.The lowest pitch that the average human can hear has a frequency of 28.0 Hz sound with this frequency travels through air with a speed of 331M/S what is the wave length?
In a case whereby the lowest pitch that the average human can hear has a frequency of 28.0 Hz sound with this frequency travels through air with a speed of 331M/S the wave length is
What is frequency?Frequency refers to the number of vibrations measured each second. A wave is a collection of vibrations known as energy. The top node is referred to as the trough, and the bottom node as the crest.
λ = wave velocity/frequency
λ = 331 m/s / 28 Hz
λ = 11.82 m
As a result, the lowest pitch that a typical person can hear is at a frequency of 29 Hz. The wavelength of sound at this frequency is 11.82 m as it moves through air at a speed of 331 m/s.
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An average force of magnitude 300 N exerted to compress a spring by 20 cm compute the work done by the force
Answer: 60 Joules (J)
Explanation:
To compute the work done by a force, you can use the formula:
Work = Force × Distance × cosθ
In this case, the force applied is 300 N, and the distance is 20 cm (which can be converted to meters by dividing by 100, giving us 0.20 m).
The angle θ represents the angle between the direction of the force and the direction of displacement. Since the force is used to compress the spring, the displacement is in the same direction as the force, and the angle θ is 0 degrees. The cosine of 0 degrees is 1, so we can omit the cosine term.
Now we can calculate the work done:
Work = 300 N × 0.20 m
Work = 60 Joules (J)
Therefore, the work done by the force in compressing the spring is 60 Joules (J).
Work is done on a wooden crate by pushing it across a floor. The work done is equal to the force applied parallel to the floor multiplied by the
A. force of friction
B. distance moved
C. mass of the crate
D. crate's direction
The work done is equal to the force applied parallel to the floor multiplied by the distance moves. Hence, option B is correct.
When a wooden crate is pushed across a floor, the work done on it is given by the product of the force applied parallel to the floor and the distance moved by the crate.
This is because work is defined as the product of force and displacement in the direction of the force, which in this case is the distance moved by the crate. The force of friction and the mass of the crate are not relevant to the calculation of work done in this scenario
It is important to understand the concept of work and the factors that influence it, as it is a fundamental concept in physics and is used in many real-world applications.
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6. Shortly after the Big Bang occurred, about 14 billion years ago, the Universe was very hot, about 3000 K, why then today, is the CMB at about 2.7 K ?
The CMB radiation's current temperature of 2.7 Kelvin is a result of the cooling and redshifting caused by the expansion of the Universe, which has been slowing down over time due to gravity.
The Cosmic Microwave Background (CMB) radiation is a remnant of the early hot and dense Universe. About 380,000 years after the Big Bang, the Universe cooled enough to allow the formation of neutral atoms, which made it transparent to radiation. This released the CMB radiation, which has been traveling through the Universe ever since, and its temperature has been cooling due to the expansion of the Universe. The CMB radiation is currently observed at a temperature of about 2.7 Kelvin, much cooler than the early Universe's temperature of 3000 Kelvin. This cooling is due to the expansion of the Universe, which causes the radiation to redshift to lower energies and longer wavelengths. This effect is known as the cosmological redshift. Moreover, the expansion of the Universe is not constant, but rather it is slowing down due to the gravitational pull of matter. This means that the early Universe's rate of expansion was faster than it is today, causing the CMB radiation to cool more rapidly in the past.
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A pizza delivery man has to lift a very large pizza a height of 3.85cm higher than he is already holding it to meet the outstretched arms of the customer. if it takes 116 kj of work on the pizza to lift it this high, what force does he exert on the pizza
The delivery man exerts a force of approximately 3,012,987 N on the pizza to lift it a height of 3.85 cm.
The work done on the pizza to lift it a level of 3.85 cm can be determined utilizing the equation W = Power*d, where W is the work done, F is the power applied, and d is the distance moved. We are given W = 116 kJ and d = 3.85 cm.
To find the power , we want to switch the distance over completely to meters and the work to joules. 3.85 cm is equivalent to 0.0385 m, and 116 kJ is equivalent to 116,000 J.
Presently we can substitute the qualities in the equation and address for F:
W = Power * d
116,000 J = F0.0385 m
F = 116,000 J/0.0385 m
F = 3,012,987.01 N
Hence, the conveyance man applies a power of roughly 3,012,987 N on the pizza to lift it a level of 3.85 cm.
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Particles q1 = +8.0 μC, q2= +3.5 μC, and
q3=-2.5 μC are in a line. Particles q1 and q2 are separated by 0.10 m and particles q2 and q3 are separated by 0.15 m. What is the net force on particle q2?
Remember: Negative forces (-F) will point Left Positive forces (+F) will point Right
Please answer bro I will do anything
The net force on particle q2 is a positive force pointing to the right.
To determine the net force on particle q2, we need to calculate the individual forces exerted on q2 by q1 and q3 and then add them vectorially.
The force between two charged particles can be calculated using Coulomb's law, which states that the force (F) between two charged particles is directly proportional to the product of their charges (q1 and q2) and inversely proportional to the square of the distance (r) between them:
F = k * (|q1| * |q2|) / r^2
where k is the electrostatic constant.
Given:
q1 = +8.0 μC
q2 = +3.5 μC
q3 = -2.5 μC
Distance between q1 and q2 (r12) = 0.10 m
Distance between q2 and q3 (r23) = 0.15 m
First, let's calculate the force between q1 and q2:
F12 = k * (|q1| * |q2|) / r12^2
Substituting the values:
[tex]F12 = (9 \times 10^9 N m^2/C^2) * ((8.0 \times 10^-6 C) * (3.5 \times 10^-6 C)) / (0.10 m)^2[/tex]
Calculating the force F12 will give us the magnitude of the force between q1 and q2. However, since q1 and q2 have the same charge sign, the force will be repulsive, pointing to the right.
Next, let's calculate the force between q2 and q3:
[tex]F23 = k * (|q2| * |q3|) / r_{23}^2[/tex]
Substituting the values:
F23 = (9 x 10^9 N m^2/C^2) * ((3.5 x 10^-6 C) * (2.5 x 10^-6 C)) / (0.15 m)^2
Calculating the force F23 will give us the magnitude of the force between q2 and q3. Since q2 and q3 have opposite charge signs, the force will be attractive, pointing to the left.
To find the net force on q2, we need to subtract the force F23 from F12 since they act in opposite directions:
Net force on q2 = F12 - F23
Finally, we need to consider the direction of the forces. Since F12 is repulsive (positive) and F23 is attractive (negative), the net force on q2 will be positive, pointing to the right.
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A concave mirror is used to ___
light and a convex mirror is used to___
light. PLEASE HELP
Answer:
reflect the light
refract the light
The resistance RT of a platinum varies with temperature T(°C), as measured on the constant-volume gas thermometer according to the equation RT = Ro(1+AT+BT^2). Where A = 3.8×10^-3°C^-1 and B = -5.6×10^-7°C^-2. Calculate the temperature that would be on indicated on a platinum thermometer, when the gas scale reads 200°C.
The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.
The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we will have to use the given formula. RT = Ro(1+AT+BT²) .....(i)We know that the gas scale reads 200°C. Therefore, we can substitute T = 200°C in equation (i).RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648)Thus, the resistance that the platinum thermometer would indicate is 1.648 times the reference resistance Ro at 0°C. This is the solution to the problem.In summary, The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we substituted T = 200°C in equation (i) to get RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648).For more questions on thermometer
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The most likely cause of excessive body lean and sway while cornering is:
O Worn upper control arm bushings.
OA broken stabilizer link
O Sagged coil springs
O Worn strut rod bushings
A broken stabilizer link is the most likely cause of excessive body lean and sway.
The most likely cause of excessive body lean and sway while cornering is worn or broken stabilizer (sway) bar links. The stabilizer bar, also known as the sway bar, plays a crucial role in reducing body roll and maintaining stability during cornering.
When the stabilizer bar links wear out or become broken, they lose their ability to effectively transfer forces between the suspension components, leading to increased body lean and sway. This can result in a less stable and potentially unsafe driving experience, as the vehicle may feel unstable and have reduced cornering capabilities.
In summary, while all the mentioned components can impact suspension performance, a broken or worn stabilizer bar link is the most likely cause of excessive body lean and sway while cornering. It is crucial to have the stabilizer bar links inspected and replaced if necessary to restore proper stability and handling during cornering maneuvers.
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Two glasses are filled with liquid to the same height . Glass W is filled with water and glass F is filled with fruit juice. Fruit juice has a higher density than water. Will the pressure in the glass of water be higher or smaller than the pressure in the glass of fruit juice.? Explain your answer
The weight at the foot of each glass will be the same because it is decided by the stature of the fluid column over it and the increasing speed due to gravity. Be that as it may, the weight applied by the fluid on the dividers of the holder will be diverse due to contrasts in thickness.
Since natural product juice incorporates a higher thickness than water, the mass of the same volume of natural product juice will be more noteworthy than that of water.
This implies that the constraint applied by the natural product juice on the dividers of the glass will be more prominent than the constraint applied by the water on the dividers of its glass, as the drive is straightforwardly corresponding to mass.
Subsequently, the weight of the glass of natural product juice will be higher than the weight of the glass of water.
In rundown, in spite of the fact that the weight at the foot of each glass will be the same, the weight applied by the fluid on the dividers of the holder will be diverse due to the contrasts in thickness, with the natural product juice applying a more noteworthy weight.
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How the government can ensure basic human dignity is maintained in relation to safe and healthy living
To ensure basic human dignity in relation to safe and healthy living, governments can implement various measures such as accessible healthcare, adequate housing, and sanitation and clean water.
How government can ensure basic human dignity is maintainedGovernments should place a high priority on ensuring that everyone has access to healthcare services, enabling them to receive the essential medical care without suffering financial difficulty. This entails providing access to necessary pharmaceuticals, cheap healthcare, and a strong healthcare system.
All citizens should have access to affordable and good housing, according to governments. Policies may include restrictions on rental costs, programs to expand the supply of affordable housing, and efforts to combat homelessness. Basic hygienic and safety criteria should be met by housing.
Governments must make sure that everyone has access to clean, safe drinking water and adequate sanitary facilities. The spread of diseases and the maintenance of sanitary living circumstances can be aided by investments in sewage systems, water treatment facilities, and public hygiene education.
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QUESTION 2
Technician A says when a vehicle pulls to one side; the problem may be caused by a pinion gear binding on the rack gear of a power rack and
pinion steering gear. Technician B says when a power steering rack and pinion steering gear spool valve binds it may cause a vehicle to pull to one
side. Who is correct?
O Technician A only
O Technician B only
O Both Technician A and Technician B
O Neither Technician A nor Technician B
Both Technician A and Technician B are correct.
option C.
What happens when pinion gear and pinion steering becomes binding?When the pinion gear of a power rack and pinion steering gear becomes binding or stuck on the rack gear, it can cause serious problem to the vehicle and one of the prolems is that the vehicle will pull to one side.
So if we consider the statement made by the technicians,
Technician A says when a vehicle pulls to one side; the problem may be caused by a pinion gear binding on the rack gear of a power rack and pinion steering gear.
Technician B says when a power steering rack and pinion steering gear spool valve binds it may cause a vehicle to pull to one side.
So both technicians are correct.
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if one food calorie which equals 1000 "chemistry" calories equals 4184 J, then how far could you go on one cookie containing 50 calories ?
On one cookie containing 50 calories, you could potentially go approximately 298 meters
How to calculate the valueGiven that one food calorie is equivalent to 4184 joules, we can calculate the total energy in joules contained in the 50 calorie cookie:
50 food calories * 4184 J/calorie = 209,200 joules
Assuming an average efficiency of around 25% (meaning 25% of the energy is effectively used for movement), and a body weight of 70 kilograms, we can use a rough estimation that it takes about 1 joule of energy to move 0.4 meters (based on the energy cost of walking).
Distance = (Energy obtained from the cookie * Efficiency) / (Energy cost per meter * Body weight)
Distance = (209,200 J * 0.25) / (1 J/m * 0.4 m/kg * 70 kg)
Distance ≈ 298 meters
Therefore, on one cookie containing 50 calories, you could potentially go approximately 298 meters
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radio waves bounce off objects and can be tracked. The photo shows one way this technology is used today
Doppler radars work by using radio waves that bounce off objects and thus the object can be tracked.
Doppler radars work by emitting a beam of energy from an antenna known as radio waves. The energy they release when they collide with airborne objects scatters in all directions, with some of it returning directly to the radar.
The quantity of energy returned to the radar increases with object size. We can now perceive raindrops in the atmosphere because of this.
The amount of time it takes for the energy beam to be delivered and returned to the radar also gives us the object's distance.
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a moterist travels 320km at 80km/h and then 320km at 100km/h what is the average speed of moterist for the entire trip
Answer:
88.89 km/h.
Explanation:
D = S + T
= 320km + 320km = 640km.
T = D/S
T1 = 320km / 80km/h = 4 hours
T2 = 320km / 100 km/h = 3.2 hours
Ttotal = T1 + T2 = 4 hours + 3.2 hours = 7.2 hours.
S = D/T
= 640km / 7.2 hours
= 88.89 km/h.
*Note:
S = Average speed.
D = Total distance.
T = Total time.
The average speed of the motorist for the entire trip is approximately 88.89 km/h.
To calculate the average speed of the motorist for the entire trip, we need to consider the total distance traveled and the total time taken. In this case, the motorist travels 320 km at 80 km/h and then another 320 km at 100 km/h.
First, let's calculate the time taken for each leg of the trip:
Time taken for the first 320 km at 80 km/h:
Time = Distance / Speed = 320 km / 80 km/h = 4 hours
Time taken for the second 320 km at 100 km/h:
Time = Distance / Speed = 320 km / 100 km/h = 3.2 hours
Now, let's calculate the total distance and total time for the entire trip:
Total distance = 320 km + 320 km = 640 km
Total time = 4 hours + 3.2 hours = 7.2 hours
Finally, we can calculate the average speed:
Average speed = Total distance / Total time = 640 km / 7.2 hours ≈ 88.89 km/h
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A block on the end of a spring is pulled to position x = A and released. In one full cycle of its motion, through what total distance does it travel? A. A / 2 B. A C24 ) 0.4A
The total distance traveled by the block in a one full or complete cycle is 2A.
option C.
What is the total distance travelled by the block?If a block on the end of a spring is pulled to position x = A and released. In one full cycle of its motion, it will travel the following distance as shown below;
x = A cos (ωt)
where;
A is the amplitude of the motionω is the angle speed of the block = 2πft is the period of the motionDuring a half cycle the block will travel a total distance of A.
During another half cycle the block will travel a total distance of A.
The total distance traveled by the block in a one full or complete cycle is calculated as follows;
distance = A + A
distance = 2A
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Mercury has a mass of
3.30 x 1023 kg, and a radius of
2.44 x 106 m. What is the acceleration
of gravity on its surface?
[?] m/s² Please help!!!
Answer:
The acceleration due to gravity on the surface of a planet or celestial body is given by the formula:
g = G M / R^2
where G is the gravitational constant, M is the mass of the planet, and R is the radius of the planet.
Plugging in the values for Mercury, we get:
g = (6.674 x 10^-11 m^3/kg s^2) (3.30 x 10^23 kg) / (2.44 x 10^6 m)^2
Simplifying this expression gives:
g = 3.70 m/s^2
Therefore, the acceleration due to gravity on the surface of Mercury is approximately 3.70 m/s^2.
Which statement describes the law of conservation of energy?
A. Energy cannot change forms.
B. Energy cannot be created or destroyed.
C. Air resistance has no effect on the energy of a system.
D. The total energy in a system can only increase.
Answer:
The correct answer is B. Energy cannot be created or destroyed.
The law of conservation of energy states that energy cannot be created or destroyed, but it can be transformed from one form to another. This means that in any physical process, the total amount of energy in a system remains constant. Energy can be converted from one form to another, such as from kinetic energy to potential energy or from electrical energy to light energy, but the total amount of energy in the system remains the same.
Option A is incorrect because energy can change forms, as mentioned above.Option C is incorrect because air resistance is a type of force that opposes the motion of an object, and therefore, it can cause a decrease in the kinetic energy of a system.Option D is incorrect because the law of conservation of energy states that the total energy in a system remains constant, it cannot increase or decrease without an external force acting on it.5. Refer to the lesson to explain the statement,
"all cells are not created equal."
The statement "all cells are not created equal" emphasizes that within a multicellular organism, cells differentiate and specialize to possess unique characteristics and perform distinct functions, contributing to the complexity and efficiency of the organism's overall functioning.
The statement "all cells are not created equal" emphasizes the idea that within a multicellular organism, different cells can possess unique characteristics and perform distinct functions. This concept is often discussed in the field of developmental biology, which explores how cells differentiate and specialize during the growth and maturation of an organism.
During early embryonic development, cells undergo a process called cell differentiation, where they acquire specific characteristics and functions. This process is regulated by various factors, such as gene expression patterns and signaling molecules. As a result, cells differentiate into various types, such as muscle cells, nerve cells, skin cells, and blood cells, among others.
Once cells have differentiated, they become specialized to perform specific tasks in different tissues and organs. For instance, muscle cells have contractile proteins that enable movement, while nerve cells have specialized extensions called axons and dendrites that facilitate communication between different parts of the body. Similarly, blood cells have diverse roles, including carrying oxygen (red blood cells), defending against infections (white blood cells), and facilitating blood clotting (platelets).
These specialized cells are adapted to carry out specific functions efficiently and effectively, and their structures and characteristics reflect their roles within the organism.
Therefore, the statement "all cells are not created equal" highlights the idea that cells within a multicellular organism are diverse and have distinct features and functions that contribute to the overall functioning and complexity of the organism.
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Which Of The Following Terms Best Describes Translational Motion Along A Curved Line?
The term that best describes translational motion along a curved line is option B. curvilinear.
The translational motion refers to the movement of an object in a straight line, where all points of the object move parallel to each other. However, when the motion occurs along a curved path, such as a circle, arc, or any other non-linear trajectory, it is referred to as curvilinear motion.
In curvilinear motion, the object follows a curved path, and the velocity and acceleration vectors change direction as the object moves along the curve. This is different from rectilinear motion, which refers to motion in a straight line.
The rotational motion refers to the movement of an object around an axis or a point, such as the spinning of a wheel or the rotation of a planet. Rotational motion involves objects rotating around a fixed axis rather than moving along a curved line.
General is a broad term that does not specifically describe the type of motion along a curved line. It does not provide any specific information about the nature or characteristics of the motion. Therefore, the correct answer is option B.
The Question was Incomplete, Find the full content below :
Which of the following terms best describes translational motion along a curved line?
A. rectilinear
B. curvilinear
C. rotational
D. general
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You will need to know that Force (N) is equal to mass (kg) multiplied by acceleration (m/s2) for this problem. A fearless space explorer has discovered a new planet with a frictionless surface! He pushes a large crate with a mass of 220kg a distance of 5.3 km, as he does so, it accelerates at a rate of 2m/s2. How much work has our intrepid hero done? PLSS helppp
The intrepid hero has done 2.332 x[tex]10^6[/tex] Joules of work in pushing the crate.
To ascertain the work done by the traveler, we first need to find the power he applied on the case. As per Newton's subsequent regulation, force is equivalent to mass times speed increase, so the power applied by the traveler on the container is:
Force = mass x speed increase
Force = 220 kg x 2 [tex]m/s^2[/tex] = 440 N
Then, we really want to work out the distance the case was moved. The pilgrim pushed the box a distance of 5.3 km, or 5,300 m.
At long last, we can compute the work done by the pioneer utilizing the equation:
Work = force x distance
Work = 440 N x 5,300 m
Work = [tex]2.332 x 10^6[/tex] Joules
Thusly, the valiant legend has done 2.332 x [tex]10^6[/tex] Joules of work in pushing the case.
The space pilgrim takes care of business on the case by applying a power that makes it speed up. The work done is equivalent to the power duplicated by the distance over which the power is applied. Involving the recipe for force, F=ma, and the given qualities for mass and speed increase, we can ascertain the power applied. Then, at that point, involving the recipe for work, W=Fd, and the given distance, we can ascertain the work done. The work done by the adventurer is 2.332 x [tex]10^6[/tex] J.
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calculate the mass of steam that will pass into the calorimeter of mass 60g containing 80g of water and 10g of ice at 0°c to raise the temperature to 30°c.Neglect the heat loss to the surrounding?
Approximately 5.88 grams of steam will pass into the calorimeter to raise the temperature of the system from 0°C to 30°C, assuming no heat loss to the surroundings.
To calculate the mass of steam that will pass into the calorimeter, we need to consider the heat exchange that occurs during the process.
First, we need to determine the heat required to raise the temperature of the water and ice from 0°C to 30°C. We can use the specific heat capacity (c) of water to calculate this:
Heat required for water: Q_water = m_water * c_water * ΔT_water
Where:
m_water = mass of water
c_water = specific heat capacity of water
ΔT_water = change in temperature of water
Given:
m_water = 80 g
c_water = 4.18 J/g°C (specific heat capacity of water)
ΔT_water = (30°C - 0°C) = 30°C
Q_water = 80 g * 4.18 J/g°C * 30°C = 9972 J
Next, we need to consider the heat required to melt the ice at 0°C into water at 0°C. This can be calculated using the heat of fusion (ΔH_fus) of ice:
Heat required for ice: Q_ice = m_ice * ΔH_fus
Where:
m_ice = mass of ice
ΔH_fus = heat of fusion of ice (334 J/g)
Given:
m_ice = 10 g
ΔH_fus = 334 J/g
Q_ice = 10 g * 334 J/g = 3340 J
Now, let's calculate the total heat required:
Total heat required = Q_water + Q_ice
Total heat required = 9972 J + 3340 J = 13312 J
Since we neglect heat loss to the surroundings, this total heat is equal to the heat gained by the steam when it condenses:
Heat gained by steam = m_steam * ΔH_vap
Where:
m_steam = mass of steam
ΔH_vap = heat of vaporization of steam (2260 J/g)
Given:
ΔH_vap = 2260 J/g
Substituting the known values into the equation, we can solve for m_steam:
13312 J = m_steam * 2260 J/g
m_steam = 13312 J / 2260 J/g ≈ 5.88 g
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Which of the following explanations represents why taste aversion breaks the rules of conditioning?
A. Taste aversion requires no cognitive processes in order to develop.
B. Taste aversion is a learned response that does not occur without cognition.
C. Taste aversion can develop after only one pairing of a stimulus and response.
D. Taste aversion cannot be explained by using conditioning processes.
Answer:
C. Taste aversion can develop after only one pairing of a stimulus and response.
Explanation:
Taste aversion is a unique type of learned response where an individual develops a strong aversion or avoidance to a specific taste or food after a single pairing of that taste with a negative reaction, such as nausea or illness. This is in contrast to traditional conditioning, where multiple pairings of a stimulus and response are typically required for learning to occur. Taste aversion demonstrates a unique rapidity and specificity in its development, which deviates from the general principles of conditioning.
On the upper surface of Jupiter's atmosphere, the attractive force of gravity is 2.5 times that on Earth. What would a bathroom scale show if a 50 kg person were weighed on Jupiter?
Explanation:
The weight of an object is the force of gravity acting on it. Therefore, we can use the formula:
where mass is the mass of the person and gravitational acceleration is the acceleration due to gravity on Jupiter.
On Earth, the acceleration due to gravity is approximately 9.8 m/s^2. On Jupiter, the acceleration due to gravity is 2.5 times that on Earth, so it is:
2.5 x 9.8 m/s^2 = 24.5 m/s^2
Therefore, the weight of a 50 kg person on Jupiter would be:
weight = 50 kg x 24.5 m/s^2 = 1225 N
So a bathroom scale on Jupiter would show a weight of approximately 1225 newtons (N) for a 50 kg person
The weight of a 50 kg person on Jupiter can be calculated using the following formula:
Weight on Jupiter = Mass x Gravity on Jupiter
where the mass of the person is 50 kg and the gravity on Jupiter is 2.5 times that on Earth, which is approximately 24.79 m/s^2.
Weight on Jupiter = 50 kg x 24.79 m/s^2
Weight on Jupiter = 1239.5 N
Therefore, a bathroom scale would show a weight of 1239.5 Newtons for a 50 kg person on the upper surface of Jupiter's atmosphere.
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Something established by authority as a rule for measurement is called a
standard
unit
The statement "Something established by authority as a rule for measurement is called a standard unit" is True.
Something established by authority as a rule for measurement is called a standard unit. Standard units provide a consistent and universally accepted basis for measuring quantities in various fields such as science, engineering, and commerce.
Standard units are essential because they ensure consistency and accuracy in measurements across different contexts and locations. They serve as a reference point for comparing and quantifying physical quantities. By establishing standardized units, authorities promote uniformity and facilitate effective communication and collaboration in scientific research, technological advancements, and global trade.
In the International System of Units (SI), which is the most widely used system of measurement, there are seven base units: meter (length), kilogram (mass), second (time), ampere (electric current), kelvin (temperature), mole (amount of substance), and candela (luminous intensity). These base units are defined based on fundamental physical constants or natural phenomena, providing a reliable and reproducible foundation for measurement.
Standard units are typically defined and maintained by internationally recognized organizations like the International Bureau of Weights and Measures (BIPM) to ensure global consistency. These organizations establish precise definitions, measurement protocols, and calibration procedures for standard units, often using advanced scientific techniques and technologies.
The use of standard units simplifies scientific research, enables accurate engineering designs, ensures fair trade practices, and facilitates international cooperation. It allows for the seamless exchange of information and data, promotes quality assurance, and supports the development of common standards and regulations in various industries.
In summary, a standard unit is a measurement rule established by authority to provide a consistent and universally accepted reference for quantifying physical quantities. It is a fundamental aspect of scientific progress, technological advancements, and global collaboration.
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Describe how the composition of gasses changes as you travel up through the Earth’s atmosphere.
Answer:
As you travel up through the Earth's atmosphere, the composition of gases changes. Near the Earth's surface, the atmosphere consists mainly of nitrogen (about 78%) and oxygen (about 21%) with traces of other gases like carbon dioxide and argon. As you go higher, the amount of oxygen decreases, and the concentration of other gases becomes more prominent, such as helium, hydrogen, and ozone.
Activity 1: UNITS OF MEASUREMENT
I. Identify the quantity described by the following units of measurement. Copy and write your answer on one whole sheet of paper.
1. meter per second = _________ 11. joule = ____________
2. meter = _________ 12. Kilogram = ____________
3. second = _________ 13. Cubic meter = _________
4. meter per second squared = ____ 14. Mole = ____________
5. square meter = _________ 15. Kilogram per cubic meter=
6. mass = _________ 16. Watt = ____________
7. newton = _________ 17. Ampere = ____________
8. kelvin = _________ 18. Hertz = ____________
9. volt = _________ 19. Coulomb = ____________
10. candela = __________ 20. Pascal = ____________
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When is an objects velocity different from its average velocity ?
Answer: An object's velocity can be different from its average velocity when the object's velocity is changing over time.
Average velocity is calculated by dividing the total displacement of an object by the total time taken. It represents the overall motion of an object during a given time interval. If the object's velocity remains constant during that time interval, then its velocity and average velocity will be the same.
However, if the object's velocity is not constant and changes during the given time interval, then its velocity at any specific moment may be different from its average velocity. This occurs when the object's speed or direction changes at different points in time, resulting in variations in its instantaneous velocity.
To summarize, an object's velocity can differ from its average velocity when there are changes in its speed or direction during the time interval under consideration
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The external force acting on the artillery shell is 2970 x 10⁴N, which is same as the force exerted by the shell on the ship. Both acts in the opposite directions.
Mass of the artillery shell, m = 1350
Acceleration of the artillery shell, a = 2.2 x 10⁴ m/s²
a) The mass of an object is inversely proportional to its acceleration, which is directly proportional to the net force acting onto it.
A moving object accelerates more quickly as the force pushing on it increases. A decline in acceleration is observed when the mass of the object increases.
So, the external force acting on the artillery shell is,
F = ma
F = 1350 x 2.2 x 10⁴
F = 2970 x 10⁴N
b) According to Newton's third law, the magnitude of force exerted by the shell on the ship will be equal to 2970 x 10⁴N, but it will be acting in the opposite direction.
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