a 30.00-ml sample of 0.125 m hcooh is being titrated with 0.175 m naoh. what is the ph after 21.4 ml of naoh has been added? ka of hcooh

Answer:

chelated zinc is more easily absorbed than zinc on it's own.

The highest frequency of the lines that we have in the hydrogen atom will be line D

Frequency is inversely related to wavelength. The wavelength and frequency of a wave are related by the equation:

c = λf

where c is the speed of light, λ (lambda) is the wavelength of the wave, and f is the frequency of the wave. This equation is known as the wave equation.

If the wavelength of a wave increases, then the frequency of the wave must decrease to maintain the same speed. Conversely, if the wavelength of a wave decreases

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X = 2n, where n is the number οf stereο genic atοms in the mοIecuIe, is the fοrmuIa fοr determining the maximum number οf stereοisοmers.

The fοrmuIa X = 2n cοnsistentIy deIivers the maximum number οf stereοisοmers, but it faiIs tο prοduce the true number in circumstances with great symmetry. If a mοIecuIe cοntains twο stereοcenters, it shοuId have fοur stereοisοmers. If a mοIecuIe cοntains three stereοcenters, it shοuId have nο mοre than eight stereοisοmers.

Thus, fοr a given cοmpοsitiοn, the maximum number οf stereοisοmers is 2n, where n is the number οf chiraI centers. Therefοre there are fοur structuraI isοmers and fοur stereοisοmers. As a resuIt, οptiοn 'D' is the right answer. Chain isοmerism is a sοrt οf structuraI isοmerism in which the cοmpοnents οf these isοmers are branched in distinct ways.

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In  which way the Chain isomerism is a sort of structural isomerisam  andd what are the components of these isomers ?

When starch is treated with iodine solution, its color changes to Blue-black. Option c is correct.

This reaction is used as a test for the presence of starch in a sample. Iodine reacts with the helical amylose component of starch to form a dark blue complex, while amylopectin, which has a branched structure, forms a less intense blue color. This color change occurs due to the formation of an iodine-starch complex, which has a characteristic blue-black color. Therefore, the intensity of the color indicates the amount of starch present in the sample. Hence, option c is correct choice.

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--The complete question is, When starch is treated with iodine solution, its color changes to

(A) Yellow

(B) Red

(C) Blue-black

(D) Green--

Answer: d. H2O

Explanation: Electrons for the light reactions are found in water. These electrons are taken by a certain enzyme complex known as the water splitting complex

The answer that best defends Meika's position that there is a systematic error associated with the experiment where you qualitatively observed reactions and recorded observations is option C: your work needs to be of higher quality than you have previously demonstrated.

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A closely packed mineralized matrix, which comprises hydroxyapatite, collagen fibres, and osteocytes as well as trace quantities of other proteins and minerals, makes up the majority of compact bone.

Compact bone is one of the two types of osseous tissue that makes up bones in vertebrates. It forms the outer layer of bone and provides strength and support to the skeleton. The structure of compact bone is composed of a tightly packed mineralized matrix, which is made up of hydroxyapatite crystals and collagen fibers. The hydroxyapatite crystals provide hardness and rigidity to the bone while the collagen fibers give it flexibility and resilience. Osteocytes, or bone cells, are also found in the mineralized matrix, which are responsible for maintaining the bone tissue. Additionally, small amounts of other proteins and minerals are present in the matrix, including calcium, phosphate, and magnesium. Together, these components create a strong and durable structure that is able to support the body's weight and withstand stress and strain.

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Answer:

A - 9.6 mol.

Explanation:

Took the test.

To determine the volume of a 5% acetic acid by mass solution necessary to neutralize 25.0 ml of 0.10 m is 300 mL

To calculate the volume of the acetic acid solution necessary to neutralize, you will use the formula:

M₁V₁ = M₂V₂

Where,

M₁ = molarity of acetic acid

V₁ = volume of acetic acid

M₂ = molarity of sodium hydroxide

V₂ = volume of sodium hydroxideInitially

You need to calculate the moles of NaOH in 25 ml of 0.10 M NaOH;

Molarity (M) = 0.10 M

Moles (n) = M × Vn = 0.10 × 25/1000n = 0.0025 mol of NaOH

To neutralize NaOH, you need the same number of moles of acetic acid;

1 mol of NaOH reacts with 1 mol of acetic acid0.0025 mol NaOH reacts with 0.0025 mol acetic acid

Concentration of acetic acid = 5%

Mass of acetic acid in 100 ml of solution = 5 g

Density of solution = 1.0 g/ml

Therefore, volume of acetic acid solution that is necessary to neutralize 25.0 ml of 0.10 m

V = (0.0025 mol acetic acid) x (60.05 g acetic acid/1 mol acetic acid) x (1/5 g acetic acid in 100 ml of solution) x (1000 ml/1 L) x (1/1.0 g/ml)

V = 0.30 L of acetic acid solution

V = 300 mL of acetic acid solution (3 significant figures)

Hence, the volume of the acetic acid solution necessary to neutralize 25.0 ml of 0.10 m is 300 mL.

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H2O and CH4 are inorganic substances, whereas C3H6, C22H24, and NO2 are organic substances.

Compounds, which are objects, are created when two or more unique elements bond chemically. The components of a compound are held together by chemical bonds, which are created when atoms share or transfer electrons.

Given that it is made up of two covalently bound elements—hydrogen (H) and oxygen (O)—H2O is an inorganic compound.

Because its carbon (C) and hydrogen (H) atoms are covalently bound, the chemical C3H6 is considered to be organic. Propene, a significant ingredient in the manufacture of plastics and synthetic rubber, is an unsaturated hydrocarbon.

C22H24 is an additional chemical substance, specifically a triterpene hydrocarbon. It is a naturally occurring substance that can be found in a variety of plants and is frequently employed in conventional medicine.

Due to the fact that CH4 only has two elements—carbon (C) and hydrogen (H)—covalently bound to one another, it is an inorganic compound. It is generally referred to as methane and is the simplest and most prevalent hydrocarbon.

Due to the presence of two covalently bound elements—nitrogen (N) and oxygen (O)—NO2 is an inorganic molecule. It is a frequently occurring, highly reactive gas in the atmosphere and a significant source of air pollution.

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48 moles of CO2 were produced from 8 moles of glucose under aerobic conditions.

Eight moles of glucose have been oxidized under aerobic conditions, and we need to find the total moles of  CO2 produced.

For this purpose, we will utilize the balanced chemical equation for the complete combustion of glucose.

The balanced equation is given as below:  C6H12O6  + 6O2 → 6CO2 + 6H2O

From the above equation, we can see that one mole of glucose produces six moles of carbon dioxide.

Therefore, eight moles of glucose will produce 8 × 6 = 48 moles of carbon dioxide.

So, the total moles of CO2 produced are 48.

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The molarity of the solution is 1.0 m

The first step is to convert the mass of KCl to moles:

Number of moles of KCl = 74.5 g / 74.5 g/mol = 1.0 mol

Next, we need to calculate the mass of water in kilograms:

Mass of water = 1000 mL x 1 L/1000 mL x 1 kg/L = 1 kg

Now we can calculate the molality of the solution:

Molality = moles of solute / mass of solvent (in kg)

Molality = 1.0 mol / 1 kg = 1.0 m

Therefore, the molality of the solution is 1.0 m.

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The helium nucleus with two protons and two neutrons has the greatest mass. This is because protons and neutrons have much greater mass than electrons. The nucleus of a helium atom is made up of two protons and two neutrons, so it has a greater mass than four individual protons.
Out of the given groups of particles, a helium nucleus with two protons and two neutrons has the greatest mass.What is a nucleus?

A nucleus is the center of an atom, containing positively charged protons and uncharged neutrons. It's where almost all of an atom's mass is located. Electrons, which are negatively charged particles that orbit the nucleus in shells, are also present in an atom. The mass of an atom is largely determined by the mass of its nucleus, which is made up of positively charged protons and uncharged neutrons. Since the helium nucleus is composed of two protons and two neutrons, it is the group of particles with the greatest mass. Thus, out of the given groups of particles, a helium nucleus with two protons and two neutrons has the greatest mass.

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The metal that will respond to the added temperature by increasing is metal A because it has the lowest heat capacity.

The metal with the smallest heat capacity will have the largest increase in temperature if the same amount of heat is added to each of their systems. This is because metals with smaller heat capacities require less heat energy to increase their temperature compared to those with larger heat capacities.

Therefore, metal A with the heat capacity of 0.3 J/g°C will have the largest increase in temperature if the same amount of heat is added to each of their systems, followed by metal B with 0.4 J/g°C and metal C with 0.5 J/g°C.

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a) The total pressure of the mixture is 434 torr

b) The mass of each gas is, N₂ = 40.56 g, O₂ = 21.76 g, He = 3.20 g

a) The total pressure of the mixture is calculated by adding all the values of partial pressures of the N₂, O₂, and He

215 torrs of N₂ + 102 torr of O₂ + 117 torr of He

= 434 torr

Thus, the total pressure of the mixture is 434 torr

b) The mass of each gas in the 1.35 L sample of the mixture at 25.0 C can be calculated using the ideal gas law: PV = nRT.

The amount of each gas present is equal to the total moles of gas, n, in the sample.

n = (PV)/(RT)

where P is the partial pressure of the gas in the mixture,

V is the volume of the sample (1.35 L),

R is the ideal gas constant (0.08206 L atm mol⁻¹ K⁻¹), and

T is the temperature in Kelvin (298.15 K).

For N₂: n = (215 torr x 1.35 L)/(0.08206 L atm mol⁻¹ K⁻¹ x 298.15 K) = 1.45 moles
For O₂: n = (102 torr x 1.35 L)/(0.08206 L atm mol⁻¹ K⁻¹ x 298.15 K) = 0.68 moles
For He: n = (117 torr x 1.35 L)/(0.08206 L atm mol⁻¹ K⁻¹ x 298.15 K) = 0.80 moles

The mass of each gas is equal to the moles multiplied by the molar mass of the gas:

For N₂: 1.45 moles x 28.01 g/mol = 40.56 g
For O₂: 0.68 moles x 32.00 g/mol = 21.76 g
For He: 0.80 moles x 4.00 g/mol = 3.20 g

Thus, the mass of each gas is, N₂ = 40.56 g, O₂ = 21.76 g, He = 3.20 g.

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The total volume (in ml) of the titrant that has been dispensed from the burette is 13.75 ml.

A burette is a laboratory apparatus that is used in analytical chemistry to dispense a liquid reagent in a precise and controlled volume to conduct experiments. It consists of a graduated glass tube with a stopcock at the bottom and a funnel at the top that is attached to a burette stand.

Titrant refers to a solution of known concentration that is slowly added to a solution of unknown concentration until a reaction has been completed. When the reaction has been completed, the amount of titrant that has been added is calculated from the burette readings and used to determine the concentration of the unknown solution given that the reaction equation is known.

Here, initial burette reading (Vi) = 3.50 ml, final burette reading (Vf) after first addition = 12.75 ml

Volume of titrant used in the first addition = Vf - Vi = 12.75 ml - 3.50 ml = 9.25 ml

Final burette reading (Vf) after second addition = 15.60 ml

Volume of titrant used in the second addition = Vf - Vi = 15.60 ml - 12.75 ml = 2.85 ml

Final burette reading (Vf) after third addition = 17.25 ml

Volume of titrant used in the third addition = Vf - Vi = 17.25 ml - 15.60 ml = 1.65 ml

The total volume of titrant that has been dispensed from the burette is the sum of the volume of titrant used in all three additions. Therefore, Total volume of titrant = Volume of titrant in first addition + Volume of titrant in second addition + Volume of titrant in third addition= 9.25 ml + 2.85 ml + 1.65 ml= 13.75 ml

Hence, the total ml of titrant that has been dispensed from the burette is 13.75 ml.

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Volume difference between back titration and controlHCI neutralized by NaOH volume difference is 0.0056 moles.

Given,

* Mass of Antacid = 0.5g

* [HCl] = 1M

* [tex]V_{HCl}[/tex] = 5 ml (pipetted out)

* [NaOH] = 1M

* [tex]V_{NaOH}[/tex] - 1.2 ml (consumed)

* Amt. of HCl avaliable for neutralisation = 0.1825 g

* No. of moles of NaOH req. to reach eq. point = 0.0012

* Amt. of HCl neutralised by antalid = 0.1387 g

* Amt. of HCl neutralised by antalid = 0.1387 g

* Amt. of HCl neutralised per gram of antalid = 0.1387 g

Solution: [tex]([/tex][tex]N[/tex] × [tex]V[/tex][tex])_{HCl}[/tex] =  [tex]([/tex][tex]N[/tex] × [tex]V[/tex][tex])_{NaOH}[/tex]

               (1 x 5 ) =  [tex]([/tex][tex]1[/tex] × [tex]V[/tex][tex])_{NaOH}[/tex]

             = [tex]V(NaOH)[/tex] = ( 1 x 5) / 1 = 5ml

In control expt. data  [tex]V(NaOH)[/tex] = 5.6ml

But in given data, [tex]V(NaOH)[/tex] = 1.2ml

So, Volume diff. of NaOH between back titration and control = 5.6 - 1.2 = 4.4ml

So, given follows

So, 4.4 ml of HCl means,

its Conc. will be equal to, 4.4 x 36.5 / 1000 = 0.1606 g

This is correct in control expt. results

In control expt. data, [tex]V(NaOH)[/tex] = 5.6ml

This corresponds to 5.6 x 40 / 1000 = 0.224g

This correspond to 0.224 / 40 = 0.0056 moles

This is correct in control expt. results.

Titration is a laboratory technique used to determine the concentration of an unknown solution by reacting it with a known solution. It is a quantitative method used to determine the amount of a substance in a sample. Titration is often used in chemistry to determine the concentration of acids, bases, and salts.

In a titration, a measured amount of the unknown solution is slowly added to a known solution of a substance with a known concentration called the titrant. The titrant is added until the reaction is complete, and a color change or other observable change occurs. The point at which the reaction is complete is known as the endpoint, and it is usually determined using an indicator, which changes color when the reaction is complete.

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Answer: To obtain a 0.113 M HNO3 solution, you need to dilute 49 mL of 12 M HNO3 solution to a final volume of 5220 mL (or 5.22 L) by adding enough water to make up the difference.

Explanation: The stock HNO3 solution is 12 M and has a volume of 49 ml.

To get a 0.113 m HNO3 solution, we must dilute it to a certain volume. The volume to which it must be diluted is a mystery.

Let the final volume be V liters. The stock HNO3 solution's volume is 49 mL, which equals 0.049 L.

HNO3's molarity is 12 M.

We must use the formula to calculate the required volume of diluted solution, C1V1 = C2V2

where C1 is the concentration of the stock solution, V1 is the volume of the stock solution used, C2 is the desired concentration of the diluted solution, and V2 is the final volume of the diluted solution.

In this case, we have:

C1 = 12 M

V1 = 49 mL

C2 = 0.113 M

V2 = unknown

Let's do some math.

12 M x 49 mL = 0.113 M x V2

(12 x 0.049) / 0.113 = 5.22 L

The diluted volume is 5.22 L.

The stock HNO3 solution of 49 ml must be diluted to a volume of 5.22 L to obtain a 0.113 m HNO3 solution.

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From the balanced equation, we know that 3 moles of H₂ produces 2 moles of NH₃.Therefore, to find the moles of NH₃ produced from 4.8 moles of H₂, we can set up a proportion 3 moles H₂ / 2 moles NH₃ = x moles H₂ / 4.8 moles H₂.

In chemistry, mole is a unit of measurement used to express amounts of a chemical substance. It is defined as the amount of a substance that contains the same number of entities (such as atoms, molecules, or ions) as there are in 12 grams of pure carbon-12, which is approximately 6.022 x 10^23 entities. This number is known as Avogadro's number, and it is a fundamental constant in chemistry.

Moles are used to quantify chemical reactions and calculate the amount of reactants needed to produce a certain amount of product, or the amount of product that can be obtained from a given amount of reactants.

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6-step synthesis of a carboxylic acid.

This question requires a 6-step synthesis of a carboxylic acid from ethyne using the reagents provided. Here is the solution:

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Equilibrium shifts in the forward direction; Q< K. The equilibrium shifts in the direction with more moles of aqueous products.

The direction of an equilibrium shift can be predicted by applying Le Chatelier's principle, which states that when a system at equilibrium is subjected to a stress, the system will shift in a direction that counteracts the stress.

The direction of an equilibrium shift depends on the nature of the stress and the equilibrium constant of the reaction. The equilibrium constant can be used to determine the relative concentrations of the reactants and products at equilibrium, and can also be used to calculate the equilibrium concentrations of the species at a given set of conditions.

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Answer:

43.1gramms

Explanation:

change the temperatures to kelvin

90--363

40--313

50grams of water are saturated at 90 degree celcius.

then,

50___363

x_____313

then cross multiply

363x=15650

divide both sides by 363

x=43.1gramms

a) HCl is a stronger acid than H2S due to weak bond between hydrogen and sulfur.

b) H3PO4 is a stronger acid than H3AsO4 due to smaller size of phosphorous atom than the arsenic atom.

c) HBrO3 is a stronger acid than HBrO2 as the oxidation state of Br in HBrO3 is +5.

d) H2C2O4 is a stronger acid than HC2O−4 as HC2O−4 is a conjugate base of H2C2O4.

e) Benzoic acid, C6H5COOH, is a stronger acid than phenol, C6H5OH due to strong resonance structure.

The following observations can be explained as follows:

a) HCl is a stronger acid than H2SIn hydrogen sulfide (H2S). The bond between hydrogen and sulfur is relatively weak. As a result, this bond is more difficult to break than that between hydrogen and chlorine in hydrogen chloride (HCl). Therefore, HCl is a stronger acid than H2S.

b) H3PO4 is a stronger acid than H3AsO4. The phosphorous atom has a smaller size than the arsenic atom. As a result, the P–O bond is more stable than the As–O bond. This makes the H3PO4 a stronger acid than H3AsO4.

c) HBrO3 is a stronger acid than HBrO2. HBrO3 is a stronger acid than HBrO2 since the oxidation state of Br in HBrO3 is +5. In contrast, Br has an oxidation state of +3 in HBrO2. As a result, the bond between Br and oxygen in HBrO3 is weaker, resulting in a higher acidity than in HBrO2.

d) H2C2O4 is a stronger acid than HC2O−4. HC2O−4 is a conjugate base of H2C2O4. The conjugate base is less acidic than the original acid, according to the conjugate acid-base theory. As a result, H2C2O4 is a stronger acid than HC2O−4.

e) Benzoic acid, C6H5COOH, is a stronger acid than phenol, C6H5OH. Benzene ring has a strong resonance structure due to the presence of electron donating OH- group in phenol. Resonance delocalizes the negative charge formed by the loss of a proton, and it makes it less acidic. The absence of an electron-donating group in benzoic acid allows for more hydrogen ion dissociation, making it a stronger acid than phenol.

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Answer: Hot Rocks

Explanation:

Answer:

Because if we changed the subscript number we will change the identity of the compound and we Well creat a new compound  or substance different than what they gave us to balance also the law of conservation of mass states that the mass cannot be created nor destroyed.

Explanation:

Answer:

Explanation:

A lever is a simple machine that can be used to increase the force or distance of an applied effort. The three main parts of a lever are the fulcrum, resistance arm, and effort arm.

The mechanical advantage of a lever depends on the ratio of the length of the effort arm to the length of the resistance arm. A longer effort arm will require less force to lift a load, but will require more distance to be moved. Conversely, a shorter effort arm will require more force to lift a load, but will require less distance to be moved.

Methane and carbon dioxide are both greenhouse gases that are crucial in controlling the temperature of Earth's atmosphere.

Both natural processes like respiration and volcanic eruptions, as well as human activity like burning fossil fuels, emit carbon dioxide (CO2) into the atmosphere. It aids in keeping the planet warm enough to support life by retaining heat in the atmosphere. Carbon dioxide levels that are too high, however, can exacerbate climate change and global warming.

Methane (CH4) is another greenhouse gas that is emitted into the atmosphere as a result of human activity such as cattle husbandry and natural gas production as well as natural processes such as decomposition. Even though it decomposes more quickly in the atmosphere than carbon dioxide, it is even more efficient at trapping heat.

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An unknown gas effuses at a rate 0.667 times the rate of co₂. The molar mass of the unknown gas is 120 g/mol.

The rate of effusion for an ideal gas is proportional to the inverse square root of the gas' molar mass. It's known as Graham's law. Graham's Law explains the rate of effusion of a gas through a small hole into a vacuum. The rate of effusion for an ideal gas is proportional to the inverse square root of the gas' molar mass (relative molecular mass). According to the question, the effusion rate of the unknown gas is 0.667 times that of CO₂.

Let the molar mass of the unknown gas be "x".

Therefore, the effusion rate for the unknown gas is proportional to

.[tex]\[\frac{1}{\sqrt{x}}\].[/tex]

The effusion rate of CO₂ is proportional to \[\frac{1}{\sqrt{44}}\].

Now,

[tex]\[\frac{\text{Effusion rate of the unknown gas}}{\text{Effusion rate of CO}_2}=\frac{0.667}{1}\][/tex]

or,

\[tex]\[\frac{1}{\sqrt{x}}=\frac{0.667}{\sqrt{44}}\][/tex]]

or,

[tex]\[\sqrt{x}=\frac{\sqrt{44}}{0.667}\][/tex]

or,

[tex]\[x=\left ( \frac{\sqrt{44}}{0.667} \right )^{2}\][/tex]

Therefore, the molar mass of the unknown gas is 120 g/mol.

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