Answer:
[tex]x_{He}=0.975\\x_{O_2}=0.025[/tex]
Explanation:
Hello.
In this case, since we know the mass of both helium and oxygen, in order to obtain the mole fractions we first need the compute the moles by using their atomic masses, 4.00 g/mol and 32.00 g/mol respectively as shown below:
[tex]n_{He}=23.6gHe*\frac{1molHe}{4.00gHe}=5.90molHe\\ \\n_{O_2}=4.85gO_2*\frac{1molO_2}{32.00gO_2}=0.152molO_2\\[/tex]
Therefore, the mole fractions are:
[tex]x_{He}=\frac{n_{He}}{n_{He}+n_{O_2}}=\frac{5.90}{5.90+0.152} \\\\x_{He}=0.975\\\\x_{O_2}=\frac{n_{O_2}}{n_{He}+n_{O_2}} =\frac{0.152}{5.90+0.152} \\\\x_{O_2}=0.025[/tex]
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Select from the drop-down menu to correctly complete the statement. Cells that perform a specific function in an organism Choose... .
A. Can survive on their own
B. Are specialized
C. Perform all of the. function
D. are all the same
Answer:
B :)
Explanation:
The cells that perform the specific function in an organism so it should be specialized.
What are specialized cells?
It is the cell that should be made up of tissued also with the system so that it should be working together in our bodies. It includes the examples like blood cells, nerve cells, reproductive cells. Also, they have their own functions.
Therefore, we can conclude that The cells that perform the specific function in an organism so it should be specialized.
Hence, the option b is correct.
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Calcium reacts with sulfur forming calcium sulfide. What is the theoretical yield (g) of CaS(s) that could be prepared from 7.19 g of Ca(s) and 2.67 g of sulfur(s)? Enter your answer with two decimal places. Do not type units with your answer.
Answer:
The theoretical yield of CaS is 6.01 g.
Explanation:
The balanced reaction is given as:
[tex]Ca+S\rightarrow CaS[/tex]
The molar mass of Ca and S is 40.08 and 32.065 g/mol respectively.
Number of moles = [tex]\frac{Mass}{Molar Mass}[/tex]
So, 7.19 g of Ca contains [tex](\frac{7.19}{40.08})[/tex] mol of Ca or 0.179 mol of Ca
Also, 2.67 g of S contains [tex](\frac{2.67}{32.065})[/tex] mol of S or 0.0833 mol of S
According to the balanced equation:
1 mol of Ca produces 1 mol of CaS
So, 0.179 mol of Ca produces 0.179 mol of CaS
According to the balanced equation:
1 mol of S produces 1 mol of CaS
So, 0.0833 mol of S produces 0.0833 mol of CaS
As the least number of mol of CaS (product) is produced from S , therefore, S is the limiting reactant.
So, thoretically, 0.0833 mol of CaS is produced.
The molar mass of CaS is 72.143 g/mol.
So, the mass of 0.0833 mol of CaS is [tex](0.0833\times 72.143)[/tex] g or 6.01 g
Hence, the theoretical yield of CaS is 6.01 g.
A solution of 0.050 M benzoic acid, HC7H5O2 , is 3.5% ionized. at 25 oC. a) What are the [H ] and pH of this solution
Answer:
[H⁺] = 0.00175 M
pH = 2.757
Explanation:
The ionization of benzoic acid is given below:
C₆H₅COOH ----> C₆H₅COO⁻(aq) + H⁺(aq)
1 mole of H⁺ ions are produced from the dissociation of 1 mole C₆H₅COOH.
Therefore 0.050 M benzoic acid produces 0.050 M H⁺.
However, the benzoic acid is only 3.5% ionized, therefore concentration of H+ ion, [H⁺] = 3.5/100 * 0.050 M
[H⁺] = 0.00175 M
pH = - log[H⁺]
pH = - log(0.00175)
pH = 2.757
What metalloid has commonly been used as an insecticide due
to its effectiveness as a poison.
Answer:
Arsenic.
Explanation:
Hello there!
In this case, since insecticides are substances that act as poisons to get rid of insects in order to prevent their presence and/or reproduction in houses, companies, crops and others, a substance that has been widely used is the metalloid arsenic due to its direct affection of the insect's body (movement, performance, cellular functions).
In addition, high levels of arsenic in food could cause arsenic poisoning in humans as well, that is why such practice must be properly performed and by using the correct security protocol.
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Answer:
As
Explanation:
hoffe das hilf jedem in der zukunft
Members of which group easily lose an electron to form a +1 cation?
halogens
alkaline earth metals
noble gases
alkali metal
The alkali metals easily loose an electron and form a +1 cation.
The periodic table is arranged in groups and periods. The elements in the same group have the same number of valence electrons and similar chemical reactivity. This is why groups of elements are also called families of elements.
The group of the periodic table which its members easily loose electrons and form a +1 cation are the alkali metals.
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True or false: BrF5(aq) is a good insulator.
Answer:
true
hope this helps :)
Explanation:
True, [tex]BrF_5[/tex] (aq) is a good insulator.
What is an insulator?A material or an object that does not easily allow heat, electricity, light, or sound to pass through it.
Bromine pentafluoride appears as a colourless, fuming liquid with a pungent odour. Used to make other chemicals and in rockets.
Hence, [tex]BrF_5[/tex] (aq) is a good insulator.
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Element X
Is a Solid at room temperature
Is a metalloid and semiconductor of heat and
electricity
Reacts with Oxygen to form XO2,
compounds and with chlorine to form XCI4,
compounds
Has an average atomic mass that is 2.34
times greater than the standard for atomic
mass(Carbon-12)
10. Predict the mass of nitrogen dioxide produced if 2.30 L of ammonia are allowed to react
with excess oxygen gas at STP?
Answer:
Mass of nitrogen dioxide produced = 4.6 g
Explanation:
Given data:
Volume of ammonia = 2.30 L
Mass of nitrogen dioxide produced = ?
Solution:
Chemical equation:
4NH₃ + 7O₂ → 4NO₂ + 6H₂O
Number of moles of ammonia at STP:
PV = nRT
n = PV/RT
n = 1 atm × 2.30 L / 0.0821 atm.L/K.mol × 273 K
n = 2.30 atm .L / 22.414 atm.L/mol
n = 0.1 mol
Now we will compare the moles of ammonia with nitrogen dioxide from balance chemical equation.
NH₃ : NO₂
4 : 4
0.1 : 0.1
Mass of NO₂:
Mass = number of moles × molar mass
Mass = 0.1 mol × 46 g/mol
Mass = 4.6 g
What is the percent of iron and oxygen in iron(III) oxide?
Answer:
69.94% iron by mass.
Explanation:
Given the mass of carbon on the periodic table (12.01 amu), which isotope do you think is the most abundant? Explain WHY in complete sentences. *
Answer:
Carbon-12
Explanation:
Carbon-12 is a carbon with 6 protons and 6 neutrons. Since the AMU for an element is calculated by averaging all naturally occurring isotopes, we can see that 12 in the most abundant. (Since 12.01 is very close to 12, the only reason it is not exactly 12 is because there are other isotopes like carbon-13 or carbon-14 but in low amounts)
Pls help, and fast plsssssssss
Answer:
The cell on the left is animal, The cell on the right is a plant cell.
Explanation:
1: cell membrane
2: chloroplast
3: cell wall
4: vacuole
5: mitochondria
6:nucleus
7: lysosome
8: cytoplasm
Things to remember, only plant cells have cell walls. Plant cells are the only ones that have chloroplast.
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Rank the following elements in order from least to most number of moles of atoms in a 10.0 g sample: Sn, Si, Se, S
Answer:
[tex]\rm Sn[/tex], [tex]\rm Se[/tex], [tex]\rm S[/tex], [tex]\rm Si[/tex].
Explanation:
The relative atomic mass of an element is numerically equal to the mass (in grams) of one mole of its atoms. This quantity can help estimate the number of moles of atoms in each of these four [tex]10.0\; \rm g[/tex] samples.
Look up the relative atomic mass for each of these four elements (on a modern periodic table.)
[tex]\rm Si[/tex]: [tex]28.085[/tex].[tex]\rm S[/tex]: [tex]32.06[/tex].[tex]\rm Se[/tex]: [tex]78.971[/tex].[tex]\rm Sn[/tex]: [tex]118.710[/tex].The relative atomic mass of [tex]\rm Si[/tex] is (approximately) [tex]28.085[/tex]. Therefore, the each mole of silicon atoms would have a mass of approximately [tex]28.085\; \rm g[/tex]. How many moles of silicon atoms would there be in a [tex]10.0\; \rm g[/tex] sample?
Given:
[tex]m(\rm Si) = 10.0\; \rm g[/tex]. [tex]M(\mathrm{Si}) = 28.085\; \rm g \cdot mol^{-1}[/tex].Number of mole of silicon atoms in the sample: [tex]\displaystyle n(\mathrm{Si}) = \frac{m(\mathrm{Si})}{M(\mathrm{Si})} = \frac{10.0\; \rm g}{28.085\; \rm g \cdot mol^{-1}}\approx 0.356\; \rm mol[/tex].
Similarly:
[tex]\displaystyle n(\mathrm{S}) = \frac{m(\mathrm{S})}{M(\mathrm{S})} = \frac{10.0\; \rm g}{32.06\; \rm g \cdot mol^{-1}}\approx 0.312\; \rm mol[/tex].
[tex]\displaystyle n(\mathrm{Se}) = \frac{m(\mathrm{Se})}{M(\mathrm{Se})} = \frac{10.0\; \rm g}{78.971\; \rm g \cdot mol^{-1}}\approx 0.127\; \rm mol[/tex].
[tex]\displaystyle n(\mathrm{Sn}) = \frac{m(\mathrm{Sn})}{M(\mathrm{Sn})} = \frac{10.0\; \rm g}{118.710\; \rm g \cdot mol^{-1}}\approx 0.0842\; \rm mol[/tex].
Therefore, among these [tex]10.0\; \rm g[/tex] samples:
[tex]n(\mathrm{Sn}) < n(\mathrm{Se}) < n(\mathrm{S}) < n(\mathrm{Si})[/tex].
It is not a coincidence that among these four samples, the one with the fewest number of atoms corresponds to the element with the largest relative atomic mass.
Consider two elements, with molar mass [tex]M_1[/tex] and [tex]M_2[/tex] each. Assume that [tex]n_1[/tex] moles and [tex]n_2[/tex] moles of atoms of each element were selected, such that the mass of both samples is [tex]m[/tex]. That is:
[tex]m = n_1\cdot M_1[/tex].
[tex]m = n_2\cdot M_2[/tex].
Equate the right-hand side of these two equations:
[tex]n_1 \cdot M_1 = n_2\cdot M_2[/tex].
[tex]\displaystyle \frac{n_1}{n_2} = \frac{M_2}{M_1} = \frac{1/M_1}{1/M_2}[/tex].
In other words, the number of moles atoms in two equal-mass samples of two elements is inversely proportional to the molar mass of the two elements (and hence inversely proportional to the formula mass of the two elements.) That explains why in this question, the sample containing the smallest number of atoms corresponds to element with the largest relative atomic mass among those four elements.
1. Determine the electron-domain geometry and molecular geometry for each of the following.a. SBr2b. PI4+c. IBr2−2. The following three compounds all have the same general formula, XF4. Compare the electron-domain geometries of these three compounds and explain what characteristic(s) of the central atom causes differences in geometry.a. SiF4:b. SeF4:c. XeF4:
Answer:
SBr2
Electron geometry-tetrahedral; molecular geometry-trigonal pyramidal
PI4+
Electron geometry-tetrahedral; moleculargeometry-tetrahedralr
IBr2
Electron geometry - tetrahedral ; molecular shape - bent
Explanation:
We have to carefully consider the issues in question 2.
First of all, the compound SiF4 is an AX4 molecule so both it's electron domain geometry and molecular geometry are tetrahedral. The molecule has no lone pairs.
For SeF4, the compound is a molecule of the type AX4E, its molecular geometry is trigonal bipyramid but its molecular geometry is see-saw because of the presence of a lone pair of electrons on the central atom, selenium.
For XeF4, the electron domain geometry is octahedral but its molecular geometry is square planar. The molecule is of the type AX4E2 and the two lone pairs are positioned above and below the plane of the square.
Level 1 01 Which correctly pairs the outside particles with their charge? A. Electrons: Positive B. Protons: Positive C. Neutrons: Neutral D. Electrons: Negative
Answer:
D. Electrons: Negative.
Explanation:
Hello, happy to help you today!
In this case, by considering the Bohr's atomic model in which atom is composed by a nuclei containing both protons and neutrons which are positively and neutrally charged respectively and surrounding electrons assembled in orbits or levels of energy which are negatively charged in order to provide a balance to the atom, the correct statement is: D. Electrons: Negative. Also consider the Bohr's model on the attached picture.
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Identify the correct net ionic equation for the reaction that occurs when solutions of Pb(NO3)2 and NH4Cl are mixed.
Answer:
Pb2+(aq) + 2Cl–(aq) ----> PbCl2(s)
Explanation:
The net ionic equation shows the main reaction that takes place in a system. Hence, a net ionic equation focusses only on those species that actually participate in the reaction.
For the reaction between Pb(NO3)2 and NH4Cl , the net ionic equation is;
Pb^+(aq) + 2Cl^-(aq) ---> PbCl2(s)
The correct net ionic equation for the reaction that occurs when solutions of Pb(NO₃)₂ and NH₄Cl are mixed is
Pb⁺(aq) + 2Cl¯(aq) —> PbCl₂(s)To know the the correct net ionic equation for the reaction that occurs when solutions of Pb(NO₃)₂ and NH₄Cl are mixed, we shall write the net ionic equation for the reaction. This is illustrated below:
Pb(NO₃)₂(aq) —> Pb⁺(aq) + NO₃¯(aq)
NH₄Cl(aq) —> NH₄⁺(aq) + Cl¯(aq)
Pb(NO₃)₂(aq) + NH₄Cl(aq) —>
Pb⁺(aq) + NO₃¯(aq) + NH₄⁺(aq) + Cl¯(aq) —> PbCl₂(s) + NO₃¯(aq) + NH₄⁺(aq)
Cancel the spectator ions (i.e NO₃¯ and NH₄⁺) and write 2 before Cl¯ to obtain the net ionic equation as shown below:
Pb⁺(aq) + 2Cl¯(aq) —> PbCl₂(s)Thus, the correct net ionic equation for the reaction that occurs when solutions of Pb(NO₃)₂ and NH₄Cl are mixed is
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17. What is the average atomic mass of the following isotopic mixture - 22.00% of 159.3 g/mole; 78.00% of
161.2g/mole?
The average atomic mass is given by the individual atomic masses of the isotope of the element and its percentage. The average atomic mass of the isotopic mixture is 159.8 g/mole.
What are isotopes?Isotopes are atoms of the same element that have the same number of protons in their nucleus but have a different number of neutrons that alters their atomic masses. The relative abundance of the isotope of the element affects the average atomic mass of the mixture.
The formula for average atomic mass for the mixture of isotopes is given as:
Average atomic mass = ∑ (mass × abundance)
Given,
Abundance of isotope 1 = 22.00 %
Mass of isotope 1 = 159.3 g/mole
Abundance of isotope 2 = 78.00 %
Mass of isotope 2 = 161.2g/mole
Substituting values in the formula of average atomic mass as:
Average atomic mass = isotope 1 (mass × abundance) + isotope 2 (mass × abundance)
= (0.22) × (159.3) + (0.78) × (161.2)
= 34.046 + 125.736
= 159.8 g/mole
Therefore, the average atomic mass of the mixture of the two isotopes is 159.8 g/mole.
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If an object has a density of 6.05 g/cm3 and a volume of 36.5 cm3, what is its mass?
Answer:
0.42 g/cm3
Explanation:
Answer:
20/40=0.5 g/cm^3 becuase, mass/volume=density
Explanation:
How many grams are in 9.97 moles of Be(NO3)2?
Use two digits past the decimal for all values.
Answer:
1,869.97 grams of Be(NO3)2
Explanation:
Be(NO3)2 = Be N2 O6
Be=9.012182g/mole
N2=28.0134g/mole
O6=96g/mole
therefore Be(NO3)2 gives you 187.56g in one mole
so 9.97 moles means there is 9.97 times more
9.97mole Be(NO3)2 * 187.56g Be(NO3)2/1mole Be(NO3)2 = 1,869.97g of Be(NO3)2
the egents erosion and explain how each of them causes erosion
Answer:
Wind, water, gravity, and ice
Explanation:
Water can erode soil material. Especially if the soil is bare, dry and erodible erosion via rain particles can occur. Wind is another factor that cause soil erosion. Dry soil particles( Especially if they are fine) can move to other areas if wind exists. Ice is another issue on erosion. Ice, when it is melting, can carry soil particles.
Balance the equations by inserting coefficients as needed.
equation 1:
PCl_{3} + Cl_{2} -> PCl_{5}
PCl3+Cl2⟶PCl5
equation 2:
Mg_{3}N_{2} + HCl -> MgCl_{2} + NH_{3}
Mg3N2+HCl⟶MgCl2+NH3
Answer:
first one is already balanced
2. MgN2+6HCl->3MgCl2+2NH3
Explanation:
To balance the equations, we need to ensure that the same number of each type of atom is present on both sides of the equation. Here's how we can balance the given equations:
Equation 1: PCl₃ + Cl₂ -> PCl₅
In this equation, there are 1 phosphorus (P) atom, 3 chlorine (Cl) atoms, and 5 chlorine (Cl) atoms. To balance the equation, we can put a coefficient of 2 in front of PCl₃ to have 2 phosphorus atoms, and a coefficient of 5 in front of Cl₂ to have 10 chlorine atoms:
2PCl₃ + 5Cl₂ -> PCl₅
Now the equation is balanced with 2 phosphorus atoms and 10 chlorine atoms on both sides.
Equation 2: Mg₃N₂ + HCl -> MgCl₂ + NH₃
In this equation, there are 3 magnesium (Mg) atoms, 2 nitrogen (N) atoms, 2 hydrogen (H) atoms, and 1 chlorine (Cl) atom.
To balance the equation, we can put a coefficient of 3 in front of HCl to have 3 hydrogen atoms, and a coefficient of 2 in front of NH3 to have 2 nitrogen atoms:
Mg₃N₂ + 3HCl -> MgCl₂ + 2NH₃
Now the equation is balanced with 3 magnesium atoms, 2 nitrogen atoms, 6 hydrogen atoms, and 2 chlorine atoms on both sides.
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Rank these systems in order of decreasing entropy. Rank from highest to lowest entropy.
a. 1 mol carbon tetrafluoride gas at 273k 40L
b. 1 mol krypton gas at 273K 40L
c. 1/2 mol krypton gas at 100k 20L
d. 1 mol krypton gas at 273K 20L
e. 1/2 mol krypton liquid at 100K
f. 1 mol fluorine gas 273 K 40L
g. 1/2 mol krypton gas at 273K 20L
Answer:
The answer is "order will be A > F > B> D > G > C > E".
Explanation:
Entropy is disunity, the greater the lack of organization the entropy. When two gases use the same moles, then more entropy is achieved for a larger number of atoms in the molecule (even with more macrostates). Its smaller your volume the less the molecules may circulate, reducing as well as the amount of potential different countries and thus the entropy. Molecules or atoms in colder gas are much less active so they do not actually take so many various energy states and therefore less entropy. In colder gas. A liquid is requested more so than gas and its randomness decreases.50 POINTS!
There are 5.5 L of a gas present at -38.0 C. What is the temperature if the volume of the gas has changed to 1.30 L?
Cations are always
Question Blank
than the neutral atom.
Which is not the name of a family on the periodic table
a) Halogens
b) Noble Gases
c) Alkali Earth Metals
d) Actinides
;
Explanation: Look at the scrrn shot and you can see what is on there or not. :)))))
Actinides are not the name of the family of the periodic table.
Explanation:
In the modern periodic table :
Elements are arranged on the basis of their atomic numbersThere are 18 groups(vertical groups) and 7 periods (horizontal rows)Groups are also called families of the periodic table.Metals are present from the middle to the left-hand side of the periodic tableNonmetals are present on the upper right-hand side of the periodic tableMetalloids divide the periodic table in a zig-zag line with nonmetals on the right and metals on the left.The alkali metals are present under group 1The alkaline earth metals are present under group 2The noble gases are present under group 18The halogens are present under group 17The elements in separate two horizontal rows in the bottom are lanthanides and actinides.So, from this, we can conclude that actinides are not the name of the family of the periodic table.
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As temperature decreases, what happens to particles in a material?
Particles become further apart / expand?
Particles become slippery / liquid?
Particles become closer together / contract?
Particles become sticky / plasma?
Answer:
Particles become closer together / contract?
Explanation:
as particles cool down in temp, the particles slow down and compress
Calculate the mass in grams for 3.28 moles of O2? Please show your work to receive credit.
Answer:
105 g O₂
Explanation:
Step 1: Define
Molar Mass O - 16.00 g/mol
Molar Mass O₂ - 2(16.00) = 32.00 g/mol
Step 2: Use Dimensional Analysis
[tex]3.28 \hspace{3} mol \hspace{3} O_2(\frac{32 \hspace{3} g \hspace{3} O_2}{1 \hspace{3} mol \hspace{3} O_2} )[/tex] = 104.96 g O₂
Step 3: Simplify
We are given 3 sig figs.
104.96 g O₂ ≈ 105 g O₂
hello I am working on naming compounds and wondering if you could help me figure out the name
Al2(SO4)3 aluminium sulfate
Antoine Lavoisier correctly characterize as an element?
__________ have the lowest ionization energies of the groups listed
PLZ HELP I'LL AWARD BRAINLIEST
Answer: have the lowest ionization energies of the groups listed
PLZ HELP I'LL AWARD BRAINLIEST
Explanation:
Plz help me with this if you give me a good answer i will give you eaxtra points plz help its do today
Answer:
Generally described, the input/output device includes a housing for one or more input components such as a keyboard and/or microphone, one or more output components such as a display screen or a speaker, a data storage device such as a hard drive, a processor, and a phone interface.
An input mechanism to allow the user to interact with the phone. The most common input mechanism is a keypad, but touch screens are also found in smartphones. Basic mobile phone services to allow users to make calls and send text messages. All GSM phones use a SIM card to allow an account to be swapped among devices.
The maximum possible power output of a handheld cellular phone is 0.6 watts. Like others have posted, the system controls the actual output of the phone and it is typically much less than that, usually less than 100 milliwatts.
Explanation: