$690 is invested in an account earning 2.2% interest (APR), compounded quarterly.
Write a function showing the value of the account after t years, where the annual growth rate can be found from a constant in the function. Round all coefficients in the function to four decimal places. Also, determine the percentage of growth per year (APY), to the nearest hundredth of a percent.

The two transformations applied to quadrilateral JKLM are rigid transformations, quadrilateral PQRS is congruent to quadrilateral JKLM, and the corresponding sides are proportional but not equal.

The dilation is a transformation in which all points are moved by the same scale factor, but the scale factor is different for each point. In this case, the dilation was centered at the origin and had a scale factor of . This means that all points were moved by the same scale factor of .

Quadrilateral PQRS is the image of quadrilateral JKLM after translating it 6 units down and 6 units to the right, followed by a dilation centered at the origin with a scale factor of . This means that quadrilateral PQRS is congruent to quadrilateral JKLM, and the corresponding sides are proportional but not equal.

In this case, the translation of quadrilateral JKLM was 6 units down and 6 units to the right.

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The function represented by the table is linear, as it has a constant rate of change and is represented by a straight line.

Function in mathematics is a relation between two sets, where one set is the input and the other set is the output. Functions are an important tool in mathematics and can be used to describe and model real-world phenomena. Functions take inputs, manipulate them and produce outputs. They can be used to represent relationships between two or more variables, or to represent a complex process. Functions allow us to break down complex problems into smaller, more manageable pieces and to study how changes in one variable affect other variables.

The function represented by the table is linear. It can be determined by the fact that the y-values change by the same amount every time the x-values increase by one unit. In this case, the y-values decrease by 2 each time the x-values increase by one unit. This is an example of a linear function.

Linear functions have the shape of a straight line and are characterized by having a constant rate of change. The constant rate of change is represented by the slope of the line, which in this case is -2. This means that for every one unit increase in the x-values, the y-values decrease by two.

A quadratic function is the opposite of a linear function, as it has a rate of change that is not constant. Quadratic functions are characterized by their parabolic shape and their rate of change increases as x-values increase. Exponential functions are characterized by their curved shape and increase exponentially as x-values increase.

In conclusion, the function represented by the table is linear, as it has a constant rate of change and is represented by a straight line.

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The value of x in the given equation is 15/23.

Two expressions are combined in an equation by an equal symbol ("="). The "left-hand side" and "right-hand side" of the equation are the two expressions on either side of the equals symbol. Typically, we consider an equation's right side to be negative. Since we can balance this by deducting the right-side expression from both sides' expressions, this won't decrease the generality.

in the given equation, 12x+6y=12y=x+15

12x+6y=12y

2x+y=2y

y=2x

now we have,

12y=x+15

12(2x)=x+15

24x=x+15

x=15/23

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Answer:

Step-by-step explanation:

Для решения задачи мы можем использовать свойства треугольников и окружностей.

Первое, что мы можем заметить, это что треугольник ABD является равносторонним, так как все его стороны имеют одинаковую длину 13. Это означает, что угол ABD также равен 60 градусам.

Также мы можем заметить, что точка O является центром окружности, вписанной в треугольник ABD, так как все ее стороны касаются окружности в точке D. Из свойств вписанных углов, мы знаем, что угол AOD равен половине угла ABD, то есть 30 градусам.

Далее, мы можем заметить, что треугольник AOC является равнобедренным, так как угол ACO равен углу OCA (они оба равны 75 - 30 = 45 градусов), а сторона AC имеет одинаковую длину с стороной AB.

Таким образом, мы можем найти длину стороны AC, используя теорему косинусов для треугольника AOC:

AC^2 = AO^2 + OC^2 - 2 * AO * OC * cos(45)

Заметим, что AO = DO, так как точка O является центром вписанной окружности, а DO является радиусом этой окружности. Из прямоугольного треугольника ADO мы можем выразить DO как DO = AD/2 = 6.5.

Также, мы можем выразить OC, используя равенство углов в треугольнике ACO (ACO и AOD являются вертикальными углами):

ACO = AOD = 30 градусов

Тогда, угол OCA равен 180 - 2 * 45 = 90 градусам, что означает, что треугольник OCA является прямоугольным, и мы можем использовать теорему Пифагора:

OC^2 + AC^2 = OA^2

OC^2 + AC^2 = DO^2

AC^2 = DO^2 - OC^2

Теперь мы можем подставить выражения для DO и OC, и получить:

AC^2 = 6.5^2 - (6.5/sqrt(2))^2

AC^2 = 42.25 - 22.5625

AC^2 = 19.6875

AC = sqrt(19.6875)

AC = 4.43 (с точностью до сотых)

Таким образом, длина стороны AC равна пр

Answer: The two positive numbers that satisfy the given requirements are 25 and 50.

Step-by-step explanation:

Let's call the two positive numbers x and y. We want to maximize their product while satisfying the condition that "the sum of the first and twice the second is 100", or mathematically:

x + 2y = 100

We can use algebra to solve for one of the variables in terms of the other:

x = 100 - 2y

Now we want to maximize the product xy:

xy = x(100 - 2y) = 100x - 2xy

Substituting x = 100 - 2y:

xy = (100 - 2y)y = 100y - 2y^2

To find the maximum value of this expression, we can take the derivative with respect to y and set it equal to zero:

d(xy)/dy = 100 - 4y = 0

Solving for y gives:

y = 25

Substituting y = 25 into the equation x + 2y = 100, we get:

x + 2(25) = 100

x = 50

Therefore, the two positive numbers that satisfy the given requirements are x = 50 and y = 25, and their product is:

xy = 50(25) = 1250

The vertex is found by finding the x-coordinate first:

   x = -b / 2a

   x = -0 /2(-2) = 0

Plug x=0 back in to find the y-coordinate of the vertex:

  y = -2(0)^2 = 0

The vertex is (0,0).

Now pick any two x-values to the left of 0 and any two to the right and calculate the y-values:

x = -1

   y = -2(-1)^2 = -2

   (-1, -2)

x = -2

   y = -2(-2)^2 = -8

   (-2, -8)

x = 1

   y = -2(1)^2 = -2

   (1, -2)

x = 2

   y = -2(2)^2 = -8

   (2, -8)

Plot those 5 points and you're done.

The probability of drawing three kings in a row from a standard deck of cards when the drawn card is not returned to the deck each time is 0.000055

The multiplication rule of probability can be used to determine the likelihood of drawing three kings consecutively from a standard deck of cards when the drawn card is not put back into the deck each time.

Since there are four kings in a deck of 52 cards, the likelihood of drawing a king from a standard 52-card deck is 4/52 or 1/13.

There are still 51 cards in the deck after the first king is drawn, and three of them are kings. Therefore, there is a 3/51 chance of drawing another king.

There are 50 cards left in the deck after drawing the second king, and two of them are kings. The likelihood of drawing a third king is therefore 2/50 or 1/25.

Therefore, the probability of drawing three kings in a row from a standard deck of cards when the drawn card is not returned to the deck each time is:

(1/13) x (3/51) x (1/25) = 3/54,600 or approximately 0.000055.

Hence, 0.000055 is the probability of drawing three kings in a row from a standard deck of cards when the drawn card is not returned to the deck each time.

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Answer:

[tex]a = \frac{20}{3}[/tex]

Step-by-step explanation:

The direction angle of the electric field at the point (x = 1.10 m, y = 0.400 m, z = 0) is approximately 74.5 degrees clockwise from the positive x-axis in the xy plane.

To calculate the electric field at the point (x = 1.10 m, y = 0.400 m, z = 0), we need to take the negative gradient of the electric potential V:

E = -∇V

where ∇ is the del operator, which is given by:

∇ = i(∂/∂x) + j(∂/∂y) + k(∂/∂z)

and i, j, k are the unit vectors in the x, y, and z directions, respectively.

To calculate the magnitude of the electric field at the point, we first need to find the partial derivatives of V with respect to x and y:

∂V/∂x = 2Axy - By^2

∂V/∂y = Ax^2 - 2Bxy

Substituting the values of A, B, x, and y, we get:

∂V/∂x = 2(5.00 V/m^3)(1.10 m)(0.400 m) - (8.00 V/m^3)(0.400 m)^2 = 0.44 V/m

∂V/∂y = (5.00 V/m^3)(1.10 m)^2 - 2(8.00 V/m^3)(1.10 m)(0.400 m) = -1.64 V/m

Next, we can calculate the magnitude of the electric field:

E = -∇V = -i(∂V/∂x) - j(∂V/∂y) - k(∂V/∂z)

= -i(0.44 V/m) + j(1.64 V/m) + 0k

= (0.44 i - 1.64 j) V/m

The magnitude of the electric field is given by:

|E| = sqrt((0.44 V/m)^2 + (-1.64 V/m)^2) = 1.70 V/m

Therefore, the magnitude of the electric field at the point (x = 1.10 m, y = 0.400 m, z = 0) is 1.70 V/m.

To calculate the direction angle of the electric field, we need to find the angle that the electric field vector makes with the positive x-axis in the xy plane.

The angle can be found using the arctan function:

θ = arctan(Ey/Ex)

Substituting the values of Ex and Ey, we get:

θ = arctan(-1.64 V/m / 0.44 V/m) = -1.30 radians

The negative sign indicates that the direction angle is measured counter clockwise from the negative x-axis, which is equivalent to measuring clockwise from the positive x-axis.

Converting to degrees, we get:

θ = -1.30 radians * (180 degrees / pi radians) = -74.5 degrees

Therefore, the direction angle is approximately 74.5 degrees clockwise in the xy plane.

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The population will be 482,720 in 405 years using exponential model that doubles its size every 81 years.

A form of growth known as exponential growth occurs when a quantity's rate of expansion is proportionate to its present value. In other words, the amount increases with time at a faster pace. Several natural and artificial processes, including population expansion, compound interest, and the spread of contagious illnesses, exhibit exponential growth.

The population increases using the exponential model given as:

[tex]P(t) = P_0 * 2^{(t/x)}[/tex]

Substituting the values P₀ = 15,085 and x = 81.

[tex]P(405) = 15,085 * 2^{(405/81)}\\P(405) = 15,085 * 2^5\\P(405) = 15,085 * 32\\P(405) = 482,720[/tex]

Hence, the population will be 482,720 in 405 years using exponential model, that doubles its size every 81 years.

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Answer:

Step-by-step explanation:

The inequality in the first equation is x > 8.

The inequality for the second graph is x ≤ -4 since it's a dot.

the definite integral of f(x) over the interval [5, 7] is (-5 / 600).

How to find?

The given function is:

f(x) = 1 / (x² + 10x + 25)

To find the definite integral of this function over the interval [5, 7], we can use the following steps:

Rewrite the function using partial fraction decomposition:

f(x) = 1 / (x² + 10x + 25)

= 1 / [(x + 5)²]

Using partial fraction decomposition, we can write this as:

f(x) = A / (x + 5) + B / (x + 5)²

where A and B are constants to be determined. Multiplying both sides by the common denominator (x + 5)², we get:

1 = A(x + 5) + B

Setting x = -5, we get:

1 = B

Setting x = 0, we get:

1 = 5A + B

= 5A + 1

Solving for A, we get:

A = 0

Therefore, the partial fraction decomposition is:

f(x) = 1 / [(x + 5)²]

= 0 / (x + 5) + 1 / (x + 5)²

Use the formula for the definite integral of a power function:

∫ xⁿ dx = (1 / (n + 1))× x²(n + 1) + C

where C is the constant of integration.

Using this formula, we can find the antiderivative of the function 1 / (x + 5)²:

∫ 1 / (x + 5)² dx = -1 / (x + 5) + C

Evaluate the definite integral over the interval [5, 7]:

∫[5,7] 1 / (x + 5)² dx

= [-1 / (x + 5)] [from 5 to 7]

= (-1 / 12) - (-1 / 10)

= (-5 / 600)

Therefore, the definite integral of f(x) over the interval [5, 7] is (-5 / 600).

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Because g(x) is continuous on the interval, we can see that the correct option is the last one (counting from the top)

Here we have the function g(x), and we know that it is continuous on the interval [1, 6], and that:

g(1) = 18

g(6) = 11

If it is continuous, then g(x) covers all the values between 18 and 11 in the given interval, this means that there must exist a value c in the given interval such that when we evaluat g(x) in that value c, we get the outcome 12, and we know this by the intermediate value theorem.

So the correct optionis the last one.

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The composite function is obtained applying the inner function as the input to the outer function.

The functions for this problem are defined as follows:

Hence the composite function is obtained replacing the two instances of T on the function N(t) by the definition of T(t), hence:

N(T(t)) = 20(6t + 1.2)² - 128(6t + 1.2) + 77

N(T(t)) =  720t² + 288t + 28.8 - 768t - 204.6.

N(T(t)) = 720t² - 480t - 175.8.

For a population of 18413 bacteria, we have that N(T(t)) = 18413, hence:

720t² - 480t - 175.8 = 18413

720t² - 480t - 18588.8 = 0.

The coefficients of the quadratic function are given as follows:

a = 720, b = 480, c = -18.588.8.

Using a quadratic function calculator, the positive solution is given as follows:

t = 4.76 hours.

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Dude he played for 1/2 of the game half of 60 is 30.

50%.

I'm I missing something?

B, No, they are not independent events because the probability of a student preferring logo B (0.78) is different from the overall probability of preferring logo B (0.89), which includes both students and teachers.

To determine whether being a student and preferring logo B are independent events, we need to compare the probability of a student preferring logo B (P(student logo B)) with the overall probability of preferring logo B (P(logo B)).

P(student logo B) = 0.78 (from the table)

P(logo B) = (86 + 11) / 125 = 0.89

If the two probabilities are equal, then the events are independent. However, in this case, P(student logo B) is not equal to P(logo B), indicating that being a student and preferring logo B are dependent events. Therefore, being a student and preferring logo B are dependent events.

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The pressure is lowest at the point 1 on the mountain.

The total weight of the air over a unit area at any elevation may be thought of as the pressure at any elevation in the atmosphere. A particular surface has fewer air molecules above it at higher elevations than it does at lower elevations. This suggests that as one climbs higher, air pressure falls. The majority of the molecules in the atmosphere are confined close to the earth's surface by the force of gravity, therefore air pressure first drops quickly before becoming more slowly as it rises.

From the figure we see that, point 1 on the mountain is the highest point.

We know that, the as height increases the pressure becomes low.

Hence, the pressure is lowest at the point 1 on the mountain.

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The complete question is:

Answer:

Step-by-step explanation:

To find the value of Z for a 95% confidence level, we can use a standard normal distribution table or a calculator that has a built-in function for finding Z values.

Using a calculator, we can use the following steps:

Determine the level of confidence, which is 95%. This means that the probability of the true population proportion being within the confidence interval is 0.95.

Find the critical value of Z using a Z-table or calculator. For a 95% confidence level, the critical Z value is 1.96.

Calculate the sample proportion, which is the number of married couples in the sample with at least one partner having a doctorate degree divided by the total sample size:

p-hat = 41/320 = 0.128125

Calculate the standard error of the sample proportion, which is the square root of the product of the sample proportion and the complement of the sample proportion, divided by the sample size:

SE(p-hat) = sqrt((p-hat)(1 - p-hat)/n) = sqrt((0.128125)(1 - 0.128125)/320) = 0.0248 (rounded to four decimal places)

Calculate the margin of error, which is the product of the critical Z value and the standard error:

Margin of error = Z * SE(p-hat) = 1.96 * 0.0248 = 0.0486 (rounded to four decimal places)

Calculate the lower and upper bounds of the confidence interval by subtracting and adding the margin of error to the sample proportion:

Lower bound = p-hat - margin of error = 0.128125 - 0.0486 = 0.0795 (rounded to four decimal places)

Upper bound = p-hat + margin of error = 0.128125 + 0.0486 = 0.1767 (rounded to four decimal places)

Therefore, the 95% confidence interval for the percentage of married couples in which at least one partner has a doctorate degree is (0.0795, 0.1767).

It ahs been proved by mathematical induction that the sum of the squares of 4 consecutive integers is an even integer.

To prove that the sum of the squares of 4 consecutive integers is an even integer.

Let x, (x + 1), (x + 2), (x + 3) be the four consecutive integers.

The sum of the squares of these integers are:

S = x² + (x + 1)² + (x + 2)² + (x + 3)²

Expanding this gives us:

S = 4x² + 12x + 14

Simplifying this gives:

S = 2(2x² + 6x + 7)

The number 2x² + 6x + 7 is either even number or odd number.

However, since it is multiplied by 2x² + 6x + 7, the sum will always be an even number.

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The statement " when account groups are created, they will determine the valid number interval for each of the groups of general ledger accounts " is  false because it incorrectly states that account groups determine the valid number intervals for each group of general ledger accounts

Account groups in themselves do not determine the valid number intervals for each group of general ledger accounts.

Rather, the number intervals for each group of general ledger accounts are defined by the chart of accounts, which is a structured list of all the accounts used by an organization to define its financial reporting.

Account groups, on the other hand, are used to group together accounts with similar characteristics or usage, and to assign authorizations for access and maintenance of the accounts.

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Transferring ownership of real property (land and buildings) can happen in a variety of ways, and it is not necessarily consensual.

A transfer can occur, for example, through eminent domain, in which the government takes private property for public use and compensates the owner for its worth. Transfers can also occur through foreclosure, which occurs when a borrower fails on a loan and the lender takes control of the property.

Regardless of the conditions, the legal steps for transferring ownership usually include execution, delivery, acceptance, and recording. The signing of a legal instrument that transfers ownership is referred to as execution. The transfer of custody or control of the property to the new owner is referred to as delivery. The new owner's agreement to accept the transfer is referred to as acceptance.

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The likelihood that one or more of the dice will land on an even number is 1296.

The likelihood of an event is quantified by its probability, which is a number. It is stated as a number between 0 and 1, or in percentage form, as a range between 0% and 100%. The likelihood of an event increasing with probability of occurrence.

Four 6-sided dice are rolled what is the probability that at least two dice show least 2 die the same.

For 2 of the same: 5×5×642) =900

For 3 of the same: 5×643) =120

For 4 of the same: 644) =6

Combined: 900+120+6=1026

Total possibilities: 64=1296

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The probability that at least one of the dice lands on an even number is 15/16 or approximately 0.938.

What is probability?

Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain to happen. The probability of an event can be calculated by dividing the number of favorable outcomes by the total number of possible outcomes.

We can solve this problem by finding the probability that all four dice land on odd numbers and then subtracting this probability from 1 to get the probability that at least one of the dice lands on an even number.

The probability that one dice lands on an odd number is 3/6 = 1/2, and the probability that all four dice land on odd numbers is:

(1/2) × (1/2) × (1/2) × (1/2) = 1/16

Therefore, the probability that at least one of the dice lands on an even number is:

1 - 1/16 = 15/16

So the probability that at least one of the dice lands on an even number is 15/16 or approximately 0.938.

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After 6 minutes, 266 grams of a radioactive form of krypton will still be present.

"A method to find a single unit value from a multiple unit value and to find a multiple unit value from a single unit value."

We always count the unit or amount value first and then calculate the more or less amount value.

For this reason, this procedure is called a unified procedure.

Many set values ​​are found by multiplying the set value by the number of sets.

A set value is obtained by dividing many set values ​​by the number of sets.

Since, its half-life is 3 minutes.

Hence, The amount of a radioactive kind of krypton after 6 minutes is,

⇒ 984 / 4

⇒ 246 grams

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Answer:

x = [tex]\frac{7\pi }{6}[/tex], [tex]\frac{11\pi }{6}[/tex]  or x = 210°, 330°

Step-by-step explanation:

4sin(x) + 2 = 0

4sin(x) = -2

sin(x) = -1/2

x = [tex]\frac{7\pi }{6}[/tex], [tex]\frac{11\pi }{6}[/tex]

let T be the linear transformation, then (T(A)a = (7, 11) where T defined by T(x) = Ax and a = (-1, 2), and A = (1 4 -1 6). [T(f(x))]a = (1, 3) where T defined by T(f(x)) = f(1) + f'(1)x, f(x) = 4-6x+3x^2 and a = (1, 3). (T(A))y = (5 5). [T(f(x))]y = (-1 -4 0).

Let T be the linear transformation defined by T(x) = A x, where A = 1 4 -1 6, and let a be the vector a = (-1, 2). To compute (T(A)a, we have:

T(A)a = Aa = 1 4 -1 6 * (-1) 2

= (1*-1 + 42) (-1-1 + 6*2)

= (7, 11)

Therefore, (T(A)a = (7, 11).

Let T be the linear transformation defined by T(f(x)) = f(1) + f'(1)x, where f(x) = 4 - 6x + 3x^2, and let a = (1, 3). To compute [T(f(x))]a, we have:

f(1) = 4 - 6 + 3 = 1

f'(x) = -6 + 6x

f'(1) = 0

So, T(f(x)) = f(1) + f'(1)x = 1, and [T(f(x))]a = 1 * (1, 3) = (1, 3).

Therefore, [T(f(x))]a = (1, 3).

Let T be the linear transformation defined by T(x, y) = (2x + y, x + 3y). We are given A = (1 3 2 4) and want to compute (T(A)]y.

First, we need to find the matrix of T with respect to the standard basis of R^2:

[T] = [T(1,0)] [T(0,1)] = [2 1] [1 3] = (2 1)

(1 3)

Now, we can compute (T(A)]y using Theorem 2.14:

(T(A)]y = [T]_y[A]_y = [T]_y[1 2] = (5 5)

Therefore, (T(A)]y = (5 5).

Let T be the linear transformation defined by T(p) = p' - p'', where p' and p'' are the first and second derivatives of p, respectively. We are given f(x) = 6 - x + 2x² and want to compute [T(f(x))]y.

First, we need to find the matrix of T with respect to the standard basis of P2 (the space of polynomials of degree at most 2):

[T] = [T(1)] [T(x)] [T(x²)] = [0 -1 2]

[0 0 -2]

[0 0 0]

Now, we need to find the coordinate vector of f(x) with respect to the standard basis of P2:

[f(x)] = [6 -1 2]

Using Theorem 2.14, we can compute [T(f(x))]y:

[T(f(x))]y = [T]_y[f(x)]_y = [T]_y[6 -1 2] = (-1 -4 0)

Therefore, [T(f(x))]y = (-1 -4 0).

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_____The given question is incomplete, the complete question is given below:

For each of the following parts, let T be the linear transformation defined in the corresponding part of Exercise 5 of Section 2.2. Use Theorem 2.14 to compute the following vectors: (a) (T(A)]a, where A = (1 4   -1 6), (b) [T(f(x))]a, where f(x) = 4 - 6x + 3x^2. 1 3, (c) (T(A))y, where A =(1 3   2 4)  (d) [T(F(x))]y, where f(x) = 6 - x + 2x².

The peak of the histogram appears at age 19, and its shape is approximately symmetric. This indicates that the students' ages are evenly distributed, with a mean age of around 19.

Probability is a gauge of how likely an occurrence is to take place. It is expressed as a number between 0 and 1, with 0 designating an impossibility and 1 designating a certainty for the occurrence.

For instance, if you flip an impartial coin, you could get either heads or tails. Because there is an equal possibility that the coin will land on its head or tails, the probability of getting heads on a single toss is [tex]0.5[/tex] , or 50%.

Given

c) To determine the likelihood that a pupil chosen at random is under 20 years old, we must add the probabilities of the top two bars in the histogram. Following are the results: P(age 20) = P(age = 17) + P(age = 18)  [tex]= 0.05 + 0.15 = 0.2[/tex]

The likelihood that a pupil chosen at random is under  [tex]20[/tex] years old is therefore  [tex]0.2, or 20%[/tex] .

d) We must add the probabilities of the bars between the ages of 19 and 21, inclusive, in order to determine the likelihood that an arbitrarily chosen student is older than 18 but not older than 21. P(18 age 21) equals P(age = 19) + P(age = 20) + P(age = 21)  [tex]= 0.35 + 0.25 + 0.1 = 0.7[/tex] .

Therefore,  [tex]0.7, or 70%[/tex] , of an arbitrarily chosen student having an age that is greater than 18 but not greater than [tex]21[/tex]  .

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Answer: x = 5

Step-by-step explanation:

To solve for x, we can first add 13 to both sides to isolate the variable term:

5x - 13 + 13 = 12 + 13

Simplifying the left side and evaluating the right side:

5x = 25

Then, divide both sides by 5 to isolate x:

5x/5 = 25/5

Simplifying:

x = 5

Therefore, the solution to the equation 5x - 13 = 12 is x = 5.

To solve for x in the equation 5x-13=12, we want to isolate the variable x on one side of the equation. We can do this by adding 13 to both sides of the equation:

5x-13+13 = 12+13

Simplifying, we get:

5x = 25

Finally, we can solve for x by dividing both sides of the equation by 5:

5x/5 = 25/5

Simplifying, we get:

x = 5

Therefore, the solution to the equation 5x-13=12 is x = 5.

Answer:

3:30

Step-by-step explanation:

We know

Jeni put a cake in the oven at 2:30. The cake takes 1 hour to bake.

What time should it be taken out of the oven?

We take

2:30 + 1 = 3:30

So, it should be taken out of the oven at 3:30

The discrete variable with the appropriate continuity correction is:

x > 25 should use the continuity correction of x > 25.5

x ≥ 25 should use the continuity correction of x ≥ 25.5

x < 25 should use the continuity correction of x < 24.5

x ≤ 25 should use the continuity correction of x ≤ 24.5

For the normal distribution approximation of a discrete variable, we use continuity correction. The continuity correction adjusts the boundaries of the discrete variable to match the boundaries of the continuous distribution.

x > 25 should use the continuity correction of x > 25.5

x ≥ 25 should use the continuity correction of x ≥ 25.5

x < 25 should use the continuity correction of x < 24.5

x ≤ 25 should use the continuity correction of x ≤ 24.5

The continuity correction adds or subtracts 0.5 from the boundary value, depending on whether the boundary is inclusive or exclusive.

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The given question is incomplete, the complete question is:

Match each discrete variable with the appropriate continuity correction to use with the normal distributio. x>25 x≥25 x<25 x≤25    x≥24.5 x>25.5 x≤25.5 x<24.5

The original ratio of oil to water in the pan is 3:5.

What do you mean by ratio?

The term ratio can be defined as the relative size of two quantities expressed as the quotient of one divided by the other. The ratio of a to b is written as a:b or a/b.

Let the original volume of oil and water be x and y respectively.

x / (y+2) = 1 / 2        

=> 2x= y+2          ------ (i)

(x+2) / (y+2) = 2 / 3      

=> 3x + 6 = 2y + 4

=> 3x = 2y - 2        ------- (ii)

Substituting (i) in (ii)

3x = 2 (2x-2) - 2

3x = 4x- 4 - 2

3x = 4x -6

3x - 4x = -6

-x = -6

Thus, x=6

Substituting value of x in (i)

2(6) = y +2

12 = y + 2

Thus, y = 10

=> Hence, the ratio is 6:10 or 3:5.

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