4 Hydrogen has three naturally occurring isotopes. H.1, H-2, and H-3 The atomie mass of Hydrogen is 1.097 Which isotope is most abundant in nature? Explain​

Answer:

octet rule

Explanation:

Answer:

None of these cause the correct answer is 9/-5

Answer:

168 g

Reaction:

[tex]Fe_{2}O_{3} + 3 CO >>> 2 Fe + 3CO_{2}[/tex]

Explanation:

First we need to figure out what is the formula mass (Mr) of Fe2O3 (Iron(III) oxide).

The atomic mass of Fe=56, O=16

Mr= 56+56+16+16+16=160 g/mol

We can now figure out the moles of the iron:

240/160 = 1.5 mol

Then we need to find the ratio to make Fe.

In the reaction, we know that 1 mole of Fe2O3 can make 2 moles of Fe. So 1.5 moles of Fe2O3 can make 3 moles of Fe.

And then we need to find the mass of the Fe.

3×56=168 g.

Hence 168g of the iron is made after the reaction.

The given question is incomplete. The complete question is:

Determine how many carbon dioxide molecules are produced if molecules of water are produced

[tex]C_2H_6(g)+O_2 (g)\rightarrow CO2(g)+H_2O(g)[/tex]

Answer: [tex]5.60\times 10^{23}[/tex] molecules of carbon dioxide are produced

Explanation:

The balanced chemical equation is:

[tex]2C_2H_6(g)+7O_2 (g)\rightarrow 4CO2(g)+6H_2O(g)[/tex]

[tex]\text{Moles of water}=\frac{\text{given molecules}}{\text{Avogadros number}}=\frac{8.45\times 10^{23}}{6.023\\times 10^{23}}=1.40moles[/tex]

Accoding to stoichiometry:

6 moles of water are produced along with = 4 moles of carbon dioxide

Thus 1.40 moles of water are produced along with = [tex]\frac{4}{6}\times 1.40=0.93[/tex] moles of carbon dioxide

Molecules of carbon dioxide = [tex]moles\times {\text {Avogadros number}}=0.93\times 6.023\times 10^{23}=5.60\times 10^{23}[/tex]

Answer:

True

Explanation:

Just like the Earth, half of the Moon is lit by the Sun while the other half is in darkness.

Answer:

Pretty sure it's true.

On Earth, we only see part of the moon that is illuminated or not, since it revolves around the Earth. However, the sun is stationary and doesn't move, meaning that one side of the moon is always lit by the sun as it revolves around the Earth.

The question is incomplete, the complete question is;

A 31 g sample of a compound that contains only the elements C,H and N is completely burned in O2 to produce 44.0 g of CO2, 45.0 g of H2O, and 92.0 g of NO2. Determine the empirical formula of the compound.

Answer:

CH5N2

Explanation:.

Mass of C = 44.0g/44.0 g/mol = 1 mol * 1 = 1 mole of C

Mass of H = 45.0 g/18 g/mol = 2.5 moles * 2  = 5 moles of H

Mass of N = 92.0 g/46 g/mol = 2 moles * 1 = 2  moles of N

Dividing through by the lowest mole ratio;

1/1, 5/1, 2/1

1 : 5 : 2

Hence the empirical formula is;

CH5N2

Answer:

H2O2

Explanation:

There's hydrogen and ox in the formula to represent

Answer:

hahahahhahhhahahaha

Explanation:

haahahahahhahahhaha

Answer:

okay but give me brainliest

Explanation:

A volcano is formed when hot molten rock, ash and gases escape from an opening in the Earth's surface. The molten rock and ash solidify as they cool, forming the distinctive volcano shape shown here. As a volcano erupts, it spills lava that flows downslope. Volcanic flows are called lahars.

Answer:

A) barium hydroxide

B) ethanol  

C) glucose

D) silver nitrate  

E) dichloromethane

F) postassium chloride

The other compounds ethanol and glucose  are also soluble in water but do not dissociate when dissolved in water.

Explanation:

Please mark this Brainilest.

These compounds will dissociate in water:

A) barium hydroxide

D) silver nitrate

F) potassium chloride

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Answer: 4.003 g/mol

Explanation:

So basically Molar mass is the atomic mass of an element and the atomic mass of Helium is 4.0026 or 4.003 g/mol

Answer:

There's no such thing as absolute zero

Answer:

I think number 1 but if wrong report me

The percentage yield of the reaction has been 46.74%.

Percentage yield can be given as the ratio of the actual yield to the theoretical yield.

For the theoretical yield, the balanced equation will be:

[tex]\rm 2\;ZnS\;+\;3\;O_2\;\rightarrow\;2\;ZnO\;+\;2\;SO_2[/tex]

Thus, 2 moles of ZnS will give 2 moles of ZnO.

The moles of 46.5 g ZnS:

Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]

ZnS = [tex]\rm \dfrac{46.5}{97.474}[/tex]

ZnS = 0.477 mol

The moles of 13.3 grams Oxygen:

Oxygen = [tex]\rm \dfrac{13.3}{32}[/tex]

Oxygen = 0.415 mol.

The moles of 18.14 grams ZnO:

ZnO = [tex]\rm \dfrac{18.14}{81.38}[/tex]

ZnO = 0.222 mol

According to the balanced chemical equation,

2 moles ZnO = 2 moles ZnS

0.222 mol ZnO = 0.222 mol ZnS

2 moles ZnO = 3 moles Oxygen

0.222 mol ZnO = 0.334 mol of Oxygen

Since, both the reactants are in enough concentration,

The theoretical yield can be calculated with any of the reactants. The theoretical yield of ZnO from 46.5 grams of ZnS can be given as:

1 mole ZnS = 1 mol ZnO

0.477 mol of ZnS = 0.477 mol of ZnO.

The mass of 0.477 mol of ZnO:

Mass = moles [tex]\times[/tex] molecular weight

Mass of ZnO = 0.477 [tex]\times[/tex] 81.38

Mass of ZnO = 38.818 grams.

The theoretical yield of ZnO = 38.818 g.

The actual yield of ZnO = 18.14 g.

Percentage yield = [tex]\rm \dfrac{18.14}{38.81}\;\times\;100[/tex]

Percentage yield = 46.74 %

The percentage yield of the reaction has been 46.74%.

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Answer:

3.9 L

First convert temperature to Kelvin

then use the ideal gas law

use algebra to solve for V

Since your solving for volume, your answer should be in Liters.

Answer:

The correct answer is - 66g.

Explanation:

Given:

molecules of CO2 = 9.03 x 10^23

We know:

1 mole of any substance = 6.02x10^23 molecules. (Avogadro's number)

M (CO2) = 12 + (2x16) = 12 + 32 = 44g

Solution:

The mass of CO2 with 9.03x10^23 molecules would be:

44g of CO2 = 6.02x10^23 molecules.

So, the mass in grams of CO2 (X) = 9.03x10^23 molecules

Xg of CO2 = (44x9.03x10^23)/6.02x10^23 = 66g

Thus, the correct answer would be - 66gm.

Answer:

1) The new pressure of the gas is 500 kilopascals.

2) The final volume is 1.44 liters.

3) Volume will decrease by approximately 67 %.

4) The Boyle's Laws deals with pressures and volumes.

Explanation:

1) From the Equation of State for Ideal Gases we construct the following relationship:

[tex]\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}}[/tex] (1)

Where:

[tex]P_{1}, P_{2}[/tex] - Initial and final pressure, measured in kPa.

[tex]V_{1}, V_{2}[/tex] - Initial and final pressure, measured in mililiters.

If we know that [tex]P_{1} = 100\,kPa[/tex], [tex]V_{1} = 500\,mL[/tex] and [tex]V_{2} = 1000\,mL[/tex], then the new pressure of the gas is:

[tex]P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}} \right)[/tex]

[tex]P_{2} = 500\,kPa[/tex]

The new pressure of the gas is 500 kilopascals.

2) Let suppose that gas experiments an isothermal process. From the Equation of State for Ideal Gases we construct the following relationship:

[tex]\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}}[/tex] (1)

Where:

[tex]P_{1}, P_{2}[/tex] - Initial and final pressure, measured in kPa.

[tex]V_{1}, V_{2}[/tex] - Initial and final pressure, measured in mililiters.

If we know that [tex]V_{1} = 3.60\,L[/tex], [tex]P_{1} = 10\,kPa[/tex] and [tex]P_{2} = 25\,kPa[/tex] then the new volume of the gas is:

[tex]V_{2} = V_{1}\cdot \left(\frac{P_{1}}{P_{2}} \right)[/tex]

[tex]V_{2} = 1.44\,L[/tex]

The final volume is 1.44 liters.

3) From the Equation of State for Ideal Gases we construct the following relationship:

[tex]\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}}[/tex] (1)

Where:

[tex]P_{1}, P_{2}[/tex] - Initial and final pressure, measured in kPa.

[tex]V_{1}, V_{2}[/tex] - Initial and final pressure, measured in mililiters.

If we know that [tex]\frac{P_{2}}{P_{1}} = 3[/tex], then the volume ratio is:

[tex]\frac{V_{1}}{V_{2}} = 3[/tex]

[tex]\frac{V_{2}}{V_{1}} = \frac{1}{3}[/tex]

Volume will decrease by approximately 67 %.

4) The Boyle's Laws deals with pressures and volumes.

Answer:

B C4H10 will be the empirical formulae.

Answer:

scared of bugs and dead things, or death itself?

Answer:

scared of bugs and dead things, or death itself?

Explanation:

Answer:

It will strengthen Electromagnetism

Answer: Answer:

Explanation:

Apparent magnitude does not take into account the fact that not all stars are the same distance from Earth.

Apparent magnitude is only on a comparative scale that determines how bright a star looks from a theoretical distance of 32 light-years from Earth. Therefore, the correct option is option D.

Any large, gaseous celestial body that is capable of producing its own light and illuminates through radiation. Only a very small portion of the tens of milliards of milliards of stars that make up the observable cosmos are readily visible to the eye.

When measuring the brightness of a star, what is a limitation of using apparent magnitude rather than absolute brightness. Apparent magnitude is only on a comparative scale that determines how bright a star looks from a theoretical distance of 32 light-years from Earth.

Therefore, the correct option is option D.

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Answer:

true ........

hope it is helpful

Answer:

Assignment Summary

For this assignment, you will develop a model that shows a roller coaster cart in four different positions on a track. You will then use this model to discuss the changes in potential and kinetic energy of the cart as it moves along the track.

Background Information

The two most common forms of energy are potential energy and kinetic energy. Potential energy is the stored energy an object has due to its position. Kinetic energy is the energy an object has due to its motion. An object’s kinetic energy changes with its motion, while its potential energy changes with its position, but the total energy stays the same. If potential energy increases, then kinetic energy decreases. If potential energy decreases, then kinetic energy increases.

Potential energy related to the height of an object is called gravitational potential energy. Gravitational potential energy is directly related to an object’s mass, the acceleration due to gravity, and an object’s height.

Materials

 One poster board per student  Drawing utensils

Assignment Instructions

Step 1: Prepare for the project.

a) Read the entire Student Guide before you begin this project.

b) If anything is unclear, be sure to ask your teacher for assistance before you begin.

c) Gather the materials you will need to complete this project.

Step 2: Create your poster.

a) On the poster board, draw a roller coaster track that starts with one large hill, then is followed by a valley and another, smaller hill.

b) Draw a cart in four positions on the track as outlined below.

i. Draw the first cart at the top of the first hill. Label it A.

ii. Draw the second cart going down the first hill into the valley. Label it B.

iii. Draw the third cart at the bottom of the valley. Assume that the height of the cart in this position is zero. Label it C.

iv. Draw the last cart at the top of the second, smaller hill. Label it D.

c) Make sure that your name is on the poster. Step 3: Type one to two paragraphs that describe the energy of the cart.

a) Type one to two paragraphs describing the changes in potential and kinetic energy of the cart. Be sure to discuss how the potential and kinetic energy of the cart changes at each of the four positions along the track, and explain why these changes occur.

b) Make sure your name is on the document.

c) Later, you will submit this document through the virtual classroom.

Step 4: Evaluate your project using this checklist.

If you can check each criterion below, you are ready to submit your project.

 Did you draw a model of a roller coaster track with one large hill, a valley, and a smaller hill?

 Did you draw a cart on the track in the four required positions A–D? Did you label the cart at each of the four positions?

 Did you type a paragraph describing the changes in potential and kinetic energy of the cart at each of the four positions on the roller coaster track? Did you explain why the changes in potential and kinetic energy occur?

Step 5: Revise and submit your project.

a) If you were unable to check off all of the requirements on the checklist, go back and make sure that your project is complete.

b) When you have completed your project, submit your poster to your teacher for grading. Be sure that your name is on it.

c) Submit the typewritten document through the virtual classroom. Be sure that your name is on it.

Step 6: Clean up your work space.

a) Clean up your work space. Return any reusable materials to your teacher and throw away any trash.

b) Congratulations! You have completed your project.

Explanation: