(07.01 MC)
A potential energy diagram is shown.
200
Potential Energy (kJ)
150
Reactants
100
Products
50
0
Reaction Pathway
What is the activation energy of this reaction? (5 points)
O 50 kJ
100 kJ
O 150 kJ
O 200 kJ

For a 35.83 g sample of potassium chlorate,  the mass of potassium chloride is mathematically given as

M Kcl=21.62g

Generally, the equation for the Chemical Reaction  is mathematically given as

2KClO_3----->2KCl+2O_2

Therefore

[tex]Mole of KCl=\frac{35.57}{122.55}[/tex]

Mole of KCl=0.29mol

Mass of Kcl=0.29*74.55

Mass of Kcl=21.62g

In conclusion, Mass of Kcl

M Kcl=21.62g

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Answer:

It is Se.

hope this helps.

Answer:

2AgNO³(l) → 2Ag(s) + O²(g) + 2NO²(g)

Explanation:

I used powers ³,²,²

So change them to be down

When an electron moves from n = 2 to n = 1, it emits a photon of ultraviolet light.

During transition from n=2 to n=1 in a hydrogen atom, the electron emits energy in the form of photon. We know that when electron absorb energy, it moves from lower level to higher level and vice versa.

So we can conclude that when an electron moves from n = 2 to n = 1, it emits a photon of ultraviolet light.

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For a buffer that was prepared contain 0.50 M formic acid (HCOOH) and 0.50 M sodium formate (NaCOOH). the pH is mathematically given as

pH=3.95

Generally, the equation for the Hendersons equation   is mathematically given as

pH=pKa+log(SALT)/(ACID)

Where

moles of  (NaCOOH)=100*0.05/1000

moles of  (NaCOOH)=0.05moles

and  formic acid

moles of formic acid=100*0.05/1000

moles of  formic acid=0.05moles

Therefore

pKa=-logka

pKa=1.4*10*3.77

pH=3.77+log{0.06/0.04}

pH=3.95

In conclusion, the pH is

pH=3.95

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The molarity of the lead(II) nitrate solution if 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate is 1.2M.

The molarity of a solution can be calculated using the following formula:

CaVa/CbVb = na/nb

Where;

The balanced equation of the reaction is as follows:

Pb(NO3)2 (aq) + 2KI (aq) → 2KNO3 (aq) + PbI2 (s)

22 × 2/18 × Cb = 2/1

44/18Cb = 2

Cb = 44 ÷ 36

Cb = 1.2M

Therefore, the molarity of the lead(II) nitrate solution if 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate is 1.2M.

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Answer:

S orbital

Explanation:

no explanation, just a name you memorize

Answer:

BIKE riding, Watching yt, Hanging with friends, Food,Dogs

An ionic compound does dissociate to a large extent in water. The compound that will completely dissociate in water here is Ba(NO3)2.

A soluble compound is a compound that can dissociate to a large extent in water. Not all compounds are soluble in water. Only ionic compounds are soluble in water.

The compound that  would dissolve in water among the list of compounds here is Ba(NO3)2.

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Answer:

A) Ba(NO3)2

B) CaSO4

C) CO2

D) H2CO3

E) Mg3(PO4)2

Explanation:

Wish I could give a good explanation, but I am still learning myself. Try searching up a video explaining this concept!

The  metal cationic (+) atom to nonmetal anionic (-) atom ratio in the compound formed between hydrogen and fluorine is 1:1.

A compound is madeup of two or more atoms that are chemically combined together. In this case, we have the atoms; hydrogen and fluorine.

The electronic configuration of the atoms  are not shown here but the  metal cationic (+) atom to nonmetal anionic (-) atom ratio in the compound formed between hydrogen and fluorine is 1:1.

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Answer: The gas from an erupting volcano had the following composition: 494 torr CO₂, 0.054 atm HCI, 0.028 atm HF, 0.017 atm 50₂. 0.76 mmHg H₂5, and H₂. If the total pressure is 1.00 atm, what is the partial pressure of H₂?

Explanation:

Answer:

Alkali metals (Li, Na, K, Rb, Cs, and Fr)

Explanation:

Answer:

Group 1

Explanation:

337.92 moles of Ozone will be produced

1 Oxygen atom is 8 g

1 mole of ozone, O3 = 8 * 3 = 24 g

7.92 * 1024 = 8110.08 g

1 mole = 24 g

? moles = 8110.08 g

? = 337.92 moles

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Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, then 337.92 moles of ozone will produce.

Molecular formula is defined as an expression that defines a number of atoms of each element in one molecule of a compound.

It can also be defined as a chemical formula that gives the total number of atoms of each elements in each molecules of a substance.

Ozone is defined as a highly reactive gas composed of three oxygen atoms and form a layer above the earth surface called as ozone layer.

1 oxygen atom = 8 g

1 mole of ozone = 8 x 3 = 24 g

7.92 x 10²⁴ = 8110.08 g

24 g = 1 mole

So, 8110.08 g = 337.92 moles

Thus, Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, then 337.92 moles of ozone will produce.

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Answer:

water vapor is less dense than dry air

Taking into account the definition of molarity,  the concentration of Na₃PO₄ in solution is 0.192[tex]\frac{moles}{lliter}[/tex].

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]Molarity=\frac{number of moles}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{lliter}[/tex].

Being the molar mass of Na₃PO₄ 163.94 g/mole, that is, the amount of mass that a substance contains in one mole, the amount of moles that contains 23.6 g sample of Na₃PO₄ is calculated as:

[tex]23.6 gramsx\frac{1 mole}{163.94 grams} = 0.144 moles[/tex]

Then you know:

Replacing in the definition of molarity:

[tex]Molarity=\frac{0.144 moles}{0.750 L}[/tex]

Solving:

Molarity= 0.192[tex]\frac{moles}{lliter}[/tex]

Finally, the concentration of Na₃PO₄ in solution is 0.192[tex]\frac{moles}{lliter}[/tex].

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molar mass:

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Answer:

B

Explanation:

2.8.1 Na

2.8.2 Mg

and so on and so forth

The volume of the 1.75 M H₃PO₄ solution required to neutralize 50 ml of 3.5 M Ca(OH)₂ solution is 66.67 mL

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

MaVa / MbVb = nA / nB

(1.75 × Va) / (3.5 × 50) = 2/3

(1.75 × Va) / 175= 2/3

Cross multiply

1.75 × 3 × Va  = 175 × 2

5.25 × Va = 350

Divide both side by 5.25

Va = 350 / 5.25

Va = 66.67 mL

Thus, the volume of the H₃PO₄ solution needed is 66.67 mL

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The benzene molecule is flat and planar. As a result of this planarity, the substituent is also in the plane of molecule and do not show any directionality.

The benzene molecule is a flat and planar molecule owing to the fact that all the bond lengths and bond angles in the molecules are the same. This results from resonance in the molecule.

Hence, owing to the planarity of the molecule, the substituent is also in the plane of molecule and do not show any directionality.

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Answer:

Stacking storage sacks/ bags by interlocking, and placing heavier object on lower shelves.

Explanation:

Not sure what you meant exactly, but this is my best guess.

Answer: True

Explanation:

[tex]\mathrm{The\ balanced \ chemical \ equation\ is\ :}\\$2 \mathrm{Na}{(s)}+\mathrm{Cl}_{2}(g) \rightarrow 2 \mathrm{NaCl}(s)[/tex]

For Na

[tex]\\$Given mass $=20.4 \mathrm{~g}$ \ \ Molecular mass $=23 \mathrm{~g}\ \ $Number of moles $=\frac{\text { Given mass }}{\text { Molecular mass }}$$$\begin{aligned}&=\frac{20.4}{23} \\&=0.887 \text { moles }\end{aligned}$$Stoichiometric ratio of $\mathrm{Na}$ is same as that of $\mathrm{NaCl}$ i.e., $1: 1$.$\therefore$ Moles of $\mathrm{NaCl}=0.887$ motes[/tex]

For NaCl

[tex]$$\\\begin{aligned}\text { Molecular mass } &=23+35.5 \\&=58.5 \mathrm{~g}\end{aligned}$$[/tex]

[tex]\begin{aligned}\\& $\therefore$ Mass of $\mathrm{NaCl}$ produced will be=\text { No.of moles } \times \text { Molecular mass } \\&=0.887 \times 58.5 \\&=51.9 \\&\simeq 52 \mathrm{~g} \quad\end{aligned}$$[/tex]

Therefore, it is true that when 20.4g of sodium metal are mixed with chlorine gas, 52.0 g of sodium chloride is produced

Explanation:

The answer: True

I explained the answer to your question in the submitted photo

Answer:

A

Explanation:

iron, cobalt and nickel are all transition metals

Answer:

Hydrocarbons are insoluble in water because they are non-polar compounds while water is a polar solvent. By principle, like dissolves like. Nonpolar solvents dissolve nonpolar solutes and polar solvents dissolve polar solutes.

Explanation:

please brainliest me

hope it helps

Hydrocarbons are insoluble in water because :-

1)Hydrocarbons are nonpolar whereas water is polar. (like dissolves like).

2) Hydrocarbons and water do not exhibit appropriate solvent-solute interactions. Hydrocarbons only form very weak dispersion forces whereas water produces strong polar hydrogen bonding interactions.

Explanation:

Answer:

A.

Explanation:

Apply thermodynamics

[tex]\\ \rm\rightarrowtail Q=mc\delta T[/tex]

[tex]\\ \rm\rightarrowtail Q=1500(4.184)(27)[/tex]

[tex]\\ \rm\rightarrowtail Q=169452J[/tex]

When the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

The zinc metal will ionize as shown below;

Zn²₊ + 2e⁻ → Zn

The molar mass of zinc metal is given as 65.38 g/mol

Amount of charge that will deposite the given mass of zinc is calculated as follows;

e⁻ = 96500 C

2e⁻ = 2 x 96500 C = 193,000 C

65.38 g -------> 193,000 C

7.85 g -----------> ?

= (7.85 x 193,000)/(65.38)

= 23,173 C

Thus, when the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

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For 3.50 grams of an unknown metal was placed in a graduate cylinder containing 50.0mL water initially,  the density of this unknown meta  is mathematically given as

D= 0.23 g/ml

Generally, the equation for the Volume of water  is mathematically given as

Vw= Volume of water after metal addition - Volume of water initial

Therefore

Vw = 65 ml - 50 ml

Vw= 15 ml

In conclusion,

D= Mass of metal / Volume

D= 3.5 / 15

D= 0.23 g/ml

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Answer:

the enthalpy change of this is 5.02mol